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  • Getting all database entries into organized array

    - by Industrial
    Hi everyone, I have just made the update/add/delete part for the "Closure table" way of organizing query hierarchical data that are shown on page 70 in this slideshare: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back However, I have a bit of an issue getting the full tree back as an multidimensional array from a single query. Here's what I would like to get back: array ( 'topvalue' = array ( 'Subvalue', 'Subvalue2', 'Subvalue3' = array ('Subvalue 1', 'Subvalue 2', 'Subvalue 3' ) ); );

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  • What causes Python "Interpreter not Initialized" error?

    - by ?????
    I'm now on my third full day this week of trying to get OpenCV to work with Python. (I have been trying on and off for the past 6 months). I get this error Python 2.7.1 (r271:86882M, Nov 30 2010, 10:35:34) [GCC 4.2.1 (Apple Inc. build 5664)] on darwin Type "help", "copyright", "credits" or "license" for more information. dlopen("/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload/readline.so", 2); import readline # dynamically loaded from /Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload/readline.so >>> import cv dlopen("./cv.so", 2); Fatal Python error: Interpreter not initialized (version mismatch?) and then it crashes (core dumps). python -v gives nothing after the dlopen. Any ideas from anyone who actually knows about this error?

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  • Selecting first records of a type in a given period

    - by Emanuil Rusev
    I have a database table that stores user comments: comments(id, user_id, created_at) I want to get from it the number of users that have commented for the first time in the past week. Here's what I have so far: SELECT COUNT(DISTINCT `user_id`) FROM `comments` WHERE `created_at` BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND NOW() This would give the number of users that have commented, but it would not take into consideration whether these comments are first for these users.

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  • Force reload/refresh when pressing the back button

    - by FlyingCat
    I will try my best to explain this. I have an application that show the 50+ projects in my view page. The user can click the individual project and go to the update page to update the project information. Everything works fine except that after user finish updating the individual project information and hit 'back' button on the browser to the previous view page. The old project information (before update) is still there. The user has to hit refresh to see the updated information. It not that bad, but I wish to provide better user experience. Any idea to fix this? Thanks a lot.

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  • Referral System PHP

    - by Liam
    I have a membership based website and im planning on implementing a referral system. My website is credit based, the idea is that if User X refers User Y, then User X gets 100 bonus credits. Has anybody built a referral system before and if so what obstacles should I bear in mind? I've had a snoop round SO tonight but couldn't find any suitable answers. My theory is to give each user a random string which is generated and stored in the DB when they sign up, The user will then be presented with a URL incl. that string which when they pass to somebody (User Z), User Z is then sent to a page, the page then uses the GET method to gather the Random string and update the DB Row they currently occupy, does this sound feasible or could it easily be breached? Thanks

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  • Application logic for invoicing and subscriptions?

    - by Industrial
    Hi everyone, We're just in the planning stage of a web app that offers subscriptions to our customers. The subscription periods varies and can be prolonged indefinitely by our customers, but are always at least one month (30 days). When a customer signs up, the customer information (billing address, phone number and so on) are stored in a customers table and a subscription is created in the subscriptions table: id | start_date | end_date | customer_id -------------------------------------------------------- 1 | 2010-12-31 | 2011-01-31 | 1 Every month we'll loop through the subscriptions table (cronjob preferably) and create invoices for the past subscription period, which are housed in their own table - invoices. Depending on the customer, invoices are manually printed out and sent by mail, or just emailed to the customer. Due to the nature of our customers and the product, we need to offer a variety of different payment alternatives including wire transfer and card payments, hence some invoices may need to be manually handled and registered as paid by our staff. The 15th every month, the invoices table are looped through and if no payment has been marked for the actual invoice, the according subscription will be removed. If there's a payment registered, the end_date in the subscriptions table is incremented by another 30 days (or what now our period our customer has chosen). Are we looking at headaches by incrementing dates forwards and backwards to handle non-paying customers and extending subscriptions? Would it be a better idea to add new subscriptions as customers extends their subscription?

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  • PHP export to text file - Only saving first line.

    - by wertz8090
    I'm trying to export some extracted $_POST information into a text file, however my code is only capturing the first variable and ignoring the rest. I'm saving the information to the text file in this manner: $values = "First Name: $fName\r\n"; $values .= "Last Name: $lName\r\n"; $values .= "Address: $address\r\n"; etc. This is the code I use to write to the text file: $fp = @fopen("person.data", "w") or die("Couldn't open person.data for writing!"); $numBytes = @fwrite($fp, $values) or die("Couldn't write values to file!"); @fclose($fp); Any ideas on why it would only save the first $values ($fName) variable but not the rest of them? It actually saves the first part of the $values string for all of them (so I see Last Name:, Address:, etc. on separate lines in the text file) but the called variables $lName and $address do not appear.

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  • Combining the value of GetLastError and a custom error message

    - by Jessica
    I have a function that returns a different DWORD value for each case there is an error. So I have the following defines: #define ERR_NO_DB_CONNECTION 0x90000 #define ERR_DB_NOT_OPEN 0x90001 #define ERR_DB_LOCKED 0x90002 #define ERR_DB_CONN_LOST 0x90003 Now, I return those values when an error occurs. I need to also return the value of GetLastError in the same return. No, I can't read it later. I tried combining it different ways, eg: return ERR_DB_NOT_OPEN + GetLastError(); and then extract the error by subtracting the value of ERR_DB_NOT_OPEN but since I need to use this in functions where there can be several return values it can get quite complex to do that. Is there any way to achieve this? I mean, combine the value + GetLastError and extract them later? Code is appreciated. Thanks Jess.

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  • Translate SQL statement into named_scope?

    - by keruilin
    How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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  • Scalably processing large amount of comlpicated database data in PHP, many times a day.

    - by Eph
    I'm soon to be working on a project that poses a problem for me. It's going to require, at regular intervals throughout the day, processing tens of thousands of records, potentially over a million. Processing is going to involve several (potentially complicated) formulas and the generation of several random factors, writing some new data to a separate table, and updating the original records with some results. This needs to occur for all records, ideally, every three hours. Each new user to the site will be adding between 50 and 500 records that need to be processed in such a fashion, so the number will not be steady. The code hasn't been written, yet, as I'm still in the design process, mostly because of this issue. I know I'm going to need to use cron jobs, but I'm concerned that processing records of this size may cause the site to freeze up, perform slowly, or just piss off my hosting company every three hours. I'd like to know if anyone has any experience or tips on similar subjects? I've never worked at this magnitude before, and for all I know, this will be trivial to the server and not pose much of an issue. As long as ALL records are processed before the next three hour period occurs, I don't care if they aren't processed simultaneously (though, ideally, all records belonging to a specific user should be processed in the same batch), so I've been wondering if I should process in batches every 5 minutes, 15 minutes, hour, whatever works, and how best to approach this (and make it scalable in a way that is fair to all users)?

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  • SQL: count days in date range?

    - by John Isaacks
    I have a query like this: SELECT COUNT(*) AS amount FROM daily_individual_tracking WHERE sales = 'YES' AND daily_individual_tracking_date BETWEEN '2010-01-01' AND '2010-03-31' I am selected from a date range. Is there a way to also get the total days in the date range?

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  • Having to insert a record, then update the same record warrants 1:1 relationship design?

    - by dianovich
    Let's say an Order has many Line items and we're storing the total cost of an order (based on the sum of prices on order lines) in the orders table. -------------- orders -------------- id ref total_cost -------------- -------------- lines -------------- id order_id price -------------- In a simple application, the order and line are created during the same step of the checkout process. So this means INSERT INTO orders .... -- Get ID of inserted order record INSERT into lines VALUES(null, order_id, ...), ... where we get the order ID after creating the order record. The problem I'm having is trying to figure out the best way to store the total cost of an order. I don't want to have to create an order create lines on an order calculate cost on order based on lines then update record created in 1. in orders table This would mean a nullable total_cost field on orders for starters... My solution thus far is to have an order_totals table with a 1:1 relationship to the orders table. But I think it's redundant. Ideally, since everything required to calculate total costs (lines on an order) is in the database, I would work out the value every time I need it, but this is very expensive. What are your thoughts?

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  • php search database for row

    - by Brenden Morley
    Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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  • Joining 3 tables - doing joins how to

    - by Kieran
    This is my current query - its not getting the required result. I want it do display all of the "resources" even if they dont have a connection. SELECT * FROM (`user_permissions`) JOIN `user_groups` ON `user_groups`.`id` = `user_permissions`.`role` JOIN `user_resources` ON `user_resources`.`id` = `user_permissions`.`resource` WHERE `role` = '4' When I try left join or right join it still returns the same result. The result I get is: id | role | resource | name 5 | 4 | 2 | Changelog I want id | role | resource | name 5 | 4 | 2 | Changelog null | null | null | Resource2 null | null | null | Resource3 Is this possible?

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  • How do I set ORDER BY params using prepared PDO statement?

    - by Marlorn
    I'm having problems using params in the ORDER BY section of my SQL. It doesn't issue any warnings, but prints out nothing. $order = 'columnName'; $direction = 'ASC'; $stmt = $db->prepare("SELECT field from table WHERE column = :my_param ORDER BY :order :direction"); $stmt->bindParam(':my_param', $is_live, PDO::PARAM_STR); $stmt->bindParam(':order', $order, PDO::PARAM_STR); $stmt->bindParam(':direction', $direction, PDO::PARAM_STR); $stmt->execute(); The :my_param works, but not :order or :direction. Is it not being internally escaped correctly? Am I stuck inserting it directly in the SQL? Like so: $order = 'columnName'; $direction = 'ASC'; $stmt = $db->prepare("SELECT * from table WHERE is_live = :is_live ORDER BY $order $direction"); Is there a PDO::PARAM_COLUMN_NAME constant or some equivalent? Thanks!

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • Why does this SELECT ... JOIN statement return no results?

    - by Stephen
    I have two tables: 1. tableA is a list of records with many columns. There is a timestamp column called "created" 2. tableB is used to track users in my application that have locked a record in tableA for review. It consists of four columns: id, user_id, record_id, and another timestamp collumn. I'm trying to select up to 10 records from tableA that have not been locked by for review by anyone in tableB (I'm also filtering in the WHERE clause by a few other columns from tableA like record status). Here's what I've come up with so far: SELECT tableA.* FROM tableA LEFT OUTER JOIN tableB ON tableA.id = tableB.record_id WHERE tableB.id = NULL AND tableA.status = 'new' AND tableA.project != 'someproject' AND tableA.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' ORDER BY tableA.created ASC LIMIT 0, 10; There are currently a few thousand records in tableA and zero records in tableB. There are definitely records that fall between those timestamps, and I've verified this with a simple SELECT * FROM tableA WHERE created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' The first statement above returns zero rows, and the second one returns over 2,000 rows.

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  • simple modification results in error

    - by lgwest
    When I tried to do a simple modification of the "hello android" program that eclipse adt plugin generates I get error and can't get the program to run again even if I restore the file to its original contents. The modification was that I changed a string in strings.xml. the line was: <string name="app_name">Todo List</string> and the app was runnable, then I changed it to <string name="app_name">Todo List1</string> and it was an error: [2010-04-21 23:18:03 - Todo_list] Error in an XML file: aborting build. And a new empty file also showed up called: strings.out.xml And then I can't get the prrogram back into runnable state even if I delete the empyt file and restore the original line, I'm a confused beginner of java, android and eclipse.

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  • select top 50 records from sql

    - by air
    i have following database table name tbl_rec recno uid uname points ============================ 1 a abc 10 2 b bac 8 3 c cvb 12 4 d aty 13 5 f cyu 9 ------------------------- ------------------------- i have about 5000 records in this table. i want to select first 50 higher points records. i can't use limit statement as i am already using limit for paging. Thanks

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  • Loop results executing twice

    - by ozzysmith
    I creating a simple site with PHP where the users can submit blogs and other users (who are logged in) can post comments on them. I have made a link called "comments" below each blog that when clicked will show / hide all the comments relevant to the specific blog (also if the user is logged in, it will show a form field in which they can submit new comments). So basically each blog will have multiple comments. I have done two different codes for this but they both have the same problem that each comment appears twice (everything else works fine). Could anyone point out why? mysql_select_db ("ooze"); $result = mysql_query ("select * from blog") or die(mysql_error()); $i = 1; while($row = mysql_fetch_array($result)) { echo "<h1>$row[title]</h1>"; echo "<p class ='second'>$row[blog_content]</p> "; echo "<p class='meta'>Posted by .... &nbsp;&bull;&nbsp; $row[date] &nbsp;&bull;&nbsp; <a href='#' onclick=\"toggle_visibility('something$i'); return false\">Comments</a><div id='something$i' style='display: none;'>"; $i++; $a = $row["ID"]; $result2 = mysql_query ("select * from blog, blogcomment where $a=blogID") or die(mysql_error()); while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username]</p><p>said:</p> <p>$sub[comment]</p>"; } if ( isset ($_SESSION["gatekeeper"])) { echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn); //second version of inner loop:// if ( isset ($_SESSION["gatekeeper"])) { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn);

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  • How to pass an array of objects trough a jquery $.post?

    - by majc
    Hi, I want to pass the result of a query trough a $.post. function GetAllTasks() { $sql = "select t.id as task_id, description, createdat, createdby, max_requests, max_duration, j.name as job_name from darkfuture.tasks t, darkfuture.jobs j where t.job_id = j.id"; $sqlresult = mysql_query($sql) or die("The list of works failed: ".mysql_error($this->con)); $result = array(); while($row = mysql_fetch_assoc($sqlresult)) { $task = new TasksResult(); $task->id = $row["task_id"]; $task->description = $row["description"]; $task->createdat = $row["createdat"]; $task->createdby = $row["createdby"]; $task->max_requests = $row["max_requests"]; $task->max_duration = $row["max_duration"]; $task->job_id = $row["job_name"]; array_push($result, $task); } mysql_free_result($sqlresult); return $result; } Here is how i call it: $tasksDB = new TasksDB(); $tasks = $tasksDB->GetAllTasks(); Now i want to pass $tasks through here: $.post("views/insert_tasks.php",{'tasks[]': $tasks}, function(data) { }); I know this {'tasks[]': $tasks} it's wrong but i don't know how to do it right. Some help will be appreciated. Thanks in advance!

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  • Saving data that is in a table efficiently and also is easy to retrieve and echo back out

    - by Harry
    Information I currently have a table which image is below, Problem I have made this table using ul & li Here is the code http://jsfiddle.net/8j2qe/1/ Question What would be the best way of storing the data in the image and easily displaying it? Keeping in mind that each column can only have 1 entry. Thank you! And any questions will be answered ASAP! EDIT Sorry, I dont think I was clear enough in my initial question. What I am asking is, what is the best way to store and then display this type of data. I want to DISPLAY data from my database to show like it would in the image. Should I have a column in my database for each column on the table, then say either A,B,C or D depending on what column it is in but then how would I display it using PHP in my code provided? Im struggling to find a good way of explaining this, I am sorry.

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  • Query to add a column depending of outcome of there columns

    - by Tam
    I have a user table 'users' that has fields like: id first_name last_name ... and have another table that determines relationships: user_id friend_id user_accepted friend_accepted .... I would like to generate a query that selects all the users but also add another field/column say 'network_status' that depends on the values of user_accepted and fiend_accepted. For example, if user_accepted is true friend_accepted is false I want the 'network_status' field to say 'request sent'. Can I possibly do this in one query? (I would prefer not to user if/else inside the query but if that's the only way so be it)

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