In XSLT, how can you sort using an indirect key?
- by edholder
I am having trouble getting xsl:sort to understand the scope of the attributes I am referencing. Here is an XML sample document to illustrate:
<Root>
<DrinkSelections>
<Drink id=1000 name="Coffee"/>
<Drink id=1001 name="Water"/>
<Drink id=1002 name="Tea"/>
<Drink id=1003 name="Almost But Not Quite Entirely Unlike Tea"/>
</DrinkSelections>
<CustomerOrder>
<Drinks>
<Drink oid="1001"/>
<Drink oid="1002"/>
<Drink oid="1003"/>
</Drinks>
</CustomerOrder
</Root>
I want to produce a list of drinks (sorted by name) contained in the CustomerOrder. Here is the XSLT code I am fiddling with:
<xsl:for-each select="/Root/CustomerOrder/Drinks/Drink">
<xsl:sort select="/Root/DrinkSelections/Drink[@id = @oid]/@name"/>
<xsl:variable name=var_oid select="@oid"/>
<xsl:value-of select="/Root/DrinkSelections/Drink[@id = $var_oid]/@name"/>
</xsl:for-each>
Apparently, the xsl:sort command is trying to apply the "oid" attribute to the Drink elements in DrinkSelections, rather than local Drink element.
I can get around this using a variable, as in the xsl:value-of statement. But since xsl:sort must be the first statement after the xsl:for-each statement, I can't insert the xsl:variable statement before xsl:sort.
Is there a way to explicitly state that the attribute value should be taken from the "local" element?
