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  • Is there a single query that can update a "sequence number" across multiple groups?

    - by Drarok
    Given a table like below, is there a single-query way to update the table from this: | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | NULL | | 2 | 1 | 2010-04-27 | NULL | | 3 | 2 | 2010-04-28 | NULL | | 4 | 3 | 2010-04-28 | NULL | To this (note that created_at is used for ordering, and sequence is "grouped" by type_id): | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | 1 | | 2 | 1 | 2010-04-27 | 2 | | 3 | 2 | 2010-04-28 | 1 | | 4 | 3 | 2010-04-28 | 1 | I've seen some code before that used an @ variable like the following, that I thought might work: SET @seq = 0; UPDATE `log` SET `sequence` = @seq := @seq + 1 ORDER BY `created_at`; But that obviously doesn't reset the sequence to 1 for each type_id. If there's no single-query way to do this, what's the most efficient way? Data in this table may be deleted, so I'm planning to run a stored procedure after the user is done editing to re-sequence the table.

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  • How can I use an array within a SQL query

    - by ThinkingInBits
    So I'm trying to take a search string (could be any number of words) and turn each value into a list to use in the following IN statement) in addition, I need a count of all these values to use with my having count filter $search_array = explode(" ",$this->search_string); $tag_count = count($search_array); $db = Connect::connect(); $query = "select p.id from photographs p left join photograph_tags c on p.id = c.photograph_id and c.value IN ($search_array) group by p.id having count(c.value) >= $tag_count"; This currently returns no results, any ideas?

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  • Increment my id in my insert request

    - by Mercer
    hello, i have a table with some rows. idClient, name, adress,country,... i want to know how i can do an insert into this table with auto increment my idClient in my sql request..? Thx. edit: i want do a request like this insert into Client values((select max(idClient),...)

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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  • Change an autoincrementing field to one previous

    - by jlan
    One day, wordpress suddenly jumped from pots id 9110 to 890000000 post. Days later I'd like to move back new posts to continue from id 9111. I'm sure that id will never reach id 890000000, no problem here, but id is an autoincrement field and "ALTER TABLE wp8_posts AUTO_INCREMENT =9111" is not working. Can I force id to continue from 9111 ?

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  • Confusion using MYSQLI

    - by user1020069
    I just started using mysqli API for PHP. Apparently, every time an object of the class MYSQLI is instantiated, it can setup a connection to the database as it connects to the server unlike mysql_connect, which connects to the server first and then you are required to specify the database to query. Now this is a good problem if the db exists, in my case, the db does not exist on the first ever connection to the server/execution of the problem, hence I must connect without specifying the database, which is fine, since the msyqli constructor does not make this database mandatory. My challenge is essentially, how do I check if the database exists before attempting the first connection. The only way to really do this would be to establish a conection to the server and then use the result of the following query to gauge if the database exists: SELECT COUNT(*) AS `exists` FROM INFORMATION_SCHEMA.SCHEMATA WHERE SCHEMATA.SCHEMA_NAME="dbname" ; If this returns true, then the database exists, but now the challenge is how do I get the mysqli object to query this database rather than having to prefix the name of the database in the query. Thanks much

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  • Why does this SELECT ... JOIN statement return no results?

    - by Stephen
    I have two tables: 1. tableA is a list of records with many columns. There is a timestamp column called "created" 2. tableB is used to track users in my application that have locked a record in tableA for review. It consists of four columns: id, user_id, record_id, and another timestamp collumn. I'm trying to select up to 10 records from tableA that have not been locked by for review by anyone in tableB (I'm also filtering in the WHERE clause by a few other columns from tableA like record status). Here's what I've come up with so far: SELECT tableA.* FROM tableA LEFT OUTER JOIN tableB ON tableA.id = tableB.record_id WHERE tableB.id = NULL AND tableA.status = 'new' AND tableA.project != 'someproject' AND tableA.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' ORDER BY tableA.created ASC LIMIT 0, 10; There are currently a few thousand records in tableA and zero records in tableB. There are definitely records that fall between those timestamps, and I've verified this with a simple SELECT * FROM tableA WHERE created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' The first statement above returns zero rows, and the second one returns over 2,000 rows.

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  • How to update csv column names with database table header

    - by user1523311
    I am facing this problem some past days and now frustrate because I have to do it. I need to update my CSV file columns name with database table header. My database table fields are different from CSV file. Now the problem is that first I want to update column name of CSV file with database table headers and then import its data with field mapping into database. Please help me I don't know how I can solve this. This is my php code: $file = $_POST['fileName']; $filename = "../files/" . $file; $list = $_POST['str']; $array_imp = implode(',', $list); $array_exp = explode(',', $array_imp); $fp = fopen("../files/" . $file, "w"); $num = count($fp); for ($c = 0; $c < $num; $c++) { if ($fp[c] !== '') { fputcsv($fp, $array_exp); } } fclose($fp);

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  • simple modification results in error

    - by lgwest
    When I tried to do a simple modification of the "hello android" program that eclipse adt plugin generates I get error and can't get the program to run again even if I restore the file to its original contents. The modification was that I changed a string in strings.xml. the line was: <string name="app_name">Todo List</string> and the app was runnable, then I changed it to <string name="app_name">Todo List1</string> and it was an error: [2010-04-21 23:18:03 - Todo_list] Error in an XML file: aborting build. And a new empty file also showed up called: strings.out.xml And then I can't get the prrogram back into runnable state even if I delete the empyt file and restore the original line, I'm a confused beginner of java, android and eclipse.

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  • Checking if user owns file before deleting it

    - by Martin Hoe
    I'm building an API for my site that allows users to delete the files they upload. Obviously, I want to check if the user owns that file before they delete it through the API. I have a files table and a users table, here's the schema: f_id, s_id, u_id, name, size, uploaded u_id, username, password, email, activated, activation_code u_id is a foreign key. The u_id field in the files table points to the u_id in the users table. Given the users username, I want to find the users u_id, and then check if they own the file through the file ID (f_id). I wrote this SQL: $sql = 'SELECT u.username FROM `users` u JOIN `files` f ON u.u_id = f.u_id WHERE f_id = ? AND u.u_id = ? LIMIT 1'; I'm assuming that'd work if I was given the users u_id in the API request, but alas I'm given only their username. How can I modify that SQL to find their user ID and use that? Thanks. Edit: Alright I've got this query but it's always returning an empty result set even though both the file ID and username exist. SELECT u.username FROM `users` u JOIN `files` f ON u.u_id = f.u_id WHERE f.f_id = ? AND u.username = ? LIMIT 1

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • select top 50 records from sql

    - by air
    i have following database table name tbl_rec recno uid uname points ============================ 1 a abc 10 2 b bac 8 3 c cvb 12 4 d aty 13 5 f cyu 9 ------------------------- ------------------------- i have about 5000 records in this table. i want to select first 50 higher points records. i can't use limit statement as i am already using limit for paging. Thanks

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  • Select rows where column LIKE dictionary word

    - by Gerve
    I have 2 tables: Dictionary - Contains roughly 36,000 words CREATE TABLE IF NOT EXISTS `dictionary` ( `word` varchar(255) NOT NULL, PRIMARY KEY (`word`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Datas - Contains roughly 100,000 rows CREATE TABLE IF NOT EXISTS `datas` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `hash` varchar(32) NOT NULL, `data` varchar(255) NOT NULL, `length` int(11) NOT NULL, `time` int(11) NOT NULL, PRIMARY KEY (`ID`), UNIQUE KEY `hash` (`hash`), KEY `data` (`data`), KEY `length` (`length`), KEY `time` (`time`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=105316 ; I would like to somehow select all the rows from datas where the column data contains 1 or more words. I understand this is a big ask, it would need to match all of these rows together in every combination possible, so it needs the best optimization. I have tried the below query, but it just hangs for ages: SELECT `datas`.*, `dictionary`.`word` FROM `datas`, `dictionary` WHERE `datas`.`data` LIKE CONCAT('%', `dictionary`.`word`, '%') AND LENGTH(`dictionary`.`word`) > 3 ORDER BY `length` ASC LIMIT 15 I have also tried something similar to the above with a left join, and on clause that specified the like statement.

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  • Relating text fields to check boxes in Java

    - by Finzz
    This program requires the user to login and request a database to access. The program then gets a connection object, searches through the database storing the column names into a vector for later use. The problem comes with implementing text fields to allow the user to search for specific values within the database. I can get the check boxes and text fields to appear using a gridlayout and add them to a panel. How do I relate the text fields to their appropriate check box? I've tried adding them to a vector, but then they can't also be added to the panel as well. I've searched for a way to name the text fields as the loop cycles through the column names, but it seems impossible to do without having them declared ahead of time. This can't be done either, as it's impossible to determine the attributes that the user will request. I just need to be able to know the names of the text fields so I can test to see if the user entered information and perform the necessary logic. Let me know if you have to see the rest of the code to give an answer, but hopefully you get the general idea of what I'm trying to accomplish. Picture of UI: try { ResultSet r2 = con.getMetaData().getColumns("", "", rb.getText(), ""); colNames1 = new Vector<String>(); columns1 = new Vector<JCheckBox>(); while (r2.next()) { colNames1.add(r2.getString(4)); JCheckBox cb = new JCheckBox(r2.getString(4)); JTextField tf = new JTextField(10); columns1.add(cb); p3.add(cb); p3.add(tf); } }

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  • How to access website CMS with only access to database

    - by user1741615
    I have a website that uses an "in-house" cms and I don't know the login details. The platform itself doesn't have the "reset your password" functionality. I do have access to ftp and phmyadmin and I found the SQL table containing the user details, but of course the password is MD5 encryption. I tried manually creating a user in php my admin and filling in a password encrypted in MD5 (used a md service online for that), but it still doesn't work. Does anybody know other tricks I can use? Thanks.

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  • Joining 3 tables - doing joins how to

    - by Kieran
    This is my current query - its not getting the required result. I want it do display all of the "resources" even if they dont have a connection. SELECT * FROM (`user_permissions`) JOIN `user_groups` ON `user_groups`.`id` = `user_permissions`.`role` JOIN `user_resources` ON `user_resources`.`id` = `user_permissions`.`resource` WHERE `role` = '4' When I try left join or right join it still returns the same result. The result I get is: id | role | resource | name 5 | 4 | 2 | Changelog I want id | role | resource | name 5 | 4 | 2 | Changelog null | null | null | Resource2 null | null | null | Resource3 Is this possible?

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  • cakephp: how to make NOW() work in search condition ?

    - by kaklon
    I'm trying to get all records with date greater then now. I tried this but it doeasnt work: $all_dates = $this->TourDate->find('all', array('conditions' => array('TourDate.date >=' => 'NOW()'), 'order' => array('TourDate.date ASC'))); If I replace NOW() with the current date it works. Why's that?

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  • Comparing date range quarters sql server

    - by CR41G14
    I have a policies in a system PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 POL214 23/08/2012 29/09/2012 I am asking a user for a reporting date, the user enters 24/10/2012 this becomes @StartDate From this I derive what the quarter is by the month: set @currentMonth = Month(@StartDate) if @currentMonth = 1 or @currentMonth = 2 or @currentMonth = 3 begin set @startmonth = 1 set @endmonth = 3 end if @currentMonth = 4 or @currentMonth = 5 or @currentMonth = 6 begin set @startmonth = 4 set @endmonth = 6 end if @currentMonth = 7 or @currentMonth = 8 or @currentMonth = 9 begin set @startmonth = 7 set @endmonth = 9 end if @currentMonth = 10 or @currentMonth = 11 or @currentMonth = 12 begin set @startmonth = 10 set @endmonth = 12 end I then get a date range: @quarterStartDate = CAST(CAST(YEAR(@StartDate) AS varchar) + '-' + CAST(@startMonth AS varchar) + '-' + '01') AS Date) @quarterEndDate = CAST(CAST(YEAR(@EcdDate) AS varchar) + '-' + CAST(@endMonth AS varchar) + '-' + '31') AS Date) This will give me 01-10-2012 and 31-12-2012. Basically I need a script to only bring back the policies that are in this quarter. The policy doesn't have to span the entire quarter date range, just exist in the quarter date range. The results expected would be PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 Pol123 appears because it spans over the quarterly date range. Pol212 is there because it expires in that quarter date range. Pol214 does not appear because it neither spans, expires or starts in this quarter. Any help would be greatly appreciated

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  • Specify fields in a recursive find with cakephp

    - by Razor Storm
    Suppose I have a table Recipe that hasmany ingredients. I do a recursive find to grab recipes with their associated ingredients: $this->Recipe->find('all', array('fields' => array('id','title','description'))); Here I can use the 'fields' attribute to specify that I only want it to return id, title, and description. However, despite this, cakephp still returns ALL columns from the ingredients table. How do I tell cakephp that I only want ingredient table's id and name fields? btw ingredient model is "Ingredient" and the table is ingredients, and the aggregation table is recipes_ingredients.

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  • Translate SQL statement into named_scope?

    - by keruilin
    How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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  • Storing "binary" data type in C program

    - by puchu
    I need to create a program that converts one number system to other number systems. I used itoa in Windows (Dev C++) and my only problem is that I do not know how to convert binary numbers to other number systems. All the other number systems conversion work accordingly. Does this involve something like storing the input to be converted using %? Here is a snippet of my work: case 2: { printf("\nEnter a binary number: "); scanf("%d", &num); itoa(num,buffer,8); printf("\nOctal %s",buffer); itoa(num,buffer,10); printf("\nDecimal %s",buffer); itoa(num,buffer,16); printf("\nHexadecimal %s \n",buffer); break; } For decimal I used %d, for octal I used %o and for hexadecimal I used %x. What could be the correct one for binary? Thanks for future answers!

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