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  • How to run SQL that contains bind variables in the ODT Query Window?

    - by dnorthut
    How do you run SQL that contains one or more bind variables in the Oracle Developer Tools for Visual Studio Query Window? For example, the following works fine in SQL*Plus: variable x NUMBER; BEGIN :x := 0; END; / SELECT 1 FROM DUAL WHERE :x <> 1; When executed in the ODT Query Window, the following exception is raised in the Query output pane: ERROR ORA-01008: not all variables bound

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  • Why am I getting "Enter Parameter Value" when running my MS Access query?

    - by DanM
    In my query, I use the IIF function to assign either "Before" or "After" to a field named BeforeOrAfter using AS. When I run this query, however, the "Enter Parameter Value" dialog appears, requesting a value for BeforeOrAfter. If I remove BeforeOrAfter DESC from the ORDER BY clause, I don't get the dialog. Here is the offending query: SELECT d.Scenario, e.Event, IIF(d.LogTime < e.Time, 'Before','After') AS BeforeOrAfter, d.HeartRate FROM Data d INNER JOIN Events e ON d.Scenario = e.Scenario WHERE e.Include = Yes ORDER BY d.Scenario, e.Id, BeforeOrAfter DESC Question: Why is my AS BeforeOrAfter not being recognized by the ORDER BY clause? Why does it ask me to enter a parameter value for "BeforeOrAfter" when I run this query? Note: I tried using brackets, single quotes, double quotes, etc., but none of that made any difference.

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  • How can I execute a SQL query in emacs lisp?

    - by Chris R
    I want to execute an SQL query and get its result in elisp: (let ((results (do-sql-query "SELECT * FROM a_table"))) (do-something-with results)) I'm using Postgres, and I already know all of my connection information (host, username, password, db et al) I just want to execute the query and get the result back, synchronously.

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  • How do I use an Entity Framework 4 model without a real database?

    - by Ivan
    I don't need any data to be stored. I'd like an application to start, create an Entity Framework entities container based on the model I've designed but having no data records in it, then generate some data (from user input and other input sources), work with it and discard all the data on close, without propagating any data operations made with EF contect to a real database hosted on server or in a file. How do I implement such a pattern? I use Entity Framework 4 and Visual Studio 2010.

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  • When does a query/subquery return a NULL and when no value at all?

    - by AspOnMyNet
    a) If a query/subquery doesn’t find any matching rows, then it either returns NULL or no value at all, thus not even a NULL value. Based on what criteria does a query/subquery return a NULL and when doesn’t it return any results, not even a NULL value? b) I assume a scalar subquery will always return NULL, when no matching rows are found? I assume most-outer scalar query also returns NULL if no rows are found? c) SELECT FirstName, LastName, YEAR(BirthDate) FROM Persons WHERE YEAR(BirthDate) IN (SELECT YearReleased FROM Albums); If subquery finds no results, is then a WHERE clause of an outer query translated into WHERE YEAR(BirthDate) IN (null); ? If instead WHERE clause is translated into WHERE YEAR(BirthDate) IN(); then shouldn’t that be an error condition, since how can YEAR(BirthDate) value be compared to nothing? thanx

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  • What will the $result be when MySQL returns nothing?

    - by Teddy
    This might seem ridiculously simple, but I've been getting all kinds of error depending on how I handle a query that returns nothing. $query = "SELECT * FROM messages WHERE id > ".$messageId; $result =mysql_query($query); $time = time(); while(time()-$time<60 && $result==false) { $result = mysql_query($query); } if(result != false) //Encode response else //return nothing How do I check whether my mysql_query() returned anything?

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  • Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....

    - by user309381
    **mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56 The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) i have set the password for root and grant privilege all for root.Why it soes show like SYSTEM@localhost i dont have SYSTEM .** class MySQLDatabase { public $connection; function _construct() { $this-open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this-connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this-connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this-connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query($sql) { //$sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //$found_user = mysql_fetch_assoc($result); //echo $found_user; return $found_user; } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); ?

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  • How to emulate a real http request via cfhttp?

    - by maectpo
    Hi, I need to emulate a real http request via cfhttp. I was getting rss feed with ColdFusion, but tonight they started to block my request and send an index page in response instead of rss fead. I added useragent for cfhttp, but it doesn't help. Opera, Firefox and Chrome open feed correctly from the same computer.

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  • How to perform a non-polymorphic HQL query in Hibernate?

    - by Eli Acherkan
    Hi all, I'm using Hibernate 3.1.1, and in particular, I'm using HQL queries. According to the documentation, Hibernate's queries are polymorphic: A query like: from Cat as cat returns instances not only of Cat, but also of subclasses like DomesticCat. How can I query for instances of Cat, but not of any of its subclasses? I'd like to be able to do it without having to explicitly mention each subclass. I'm aware of the following options, and don't find them satisfactory: Manually filtering the instances after the query, OR: Manually adding a WHERE clause on the discriminator column. It would make sense for Hibernate to allow the user to decide whether a query should be polymorphic or not, but I can't find such an option. Thanks in advance!

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  • How does Android emulator performance compare to real device performance?

    - by uj2
    I'm looking into writing an Android game, tough I don't curerntly own an Android device. For those of you who own a device, how does the performance on the emulator relate to real device performance? I'm especially interested in graphics related tasks. This obviously depends on both the machine running the emulator, and the specific device in question, but I'm talking rough numbers here. This question is a duplicate, but since that post is heavily outdated, I figured it's irrelevant by now.

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  • Single Query returning me 4 tables, How to get all of them back into dataset ?

    - by Shantanu Gupta
    How to fill multiple tables in a dataset. I m using a query that returns me four tables. At the frontend I am trying to fill all the four resultant table into dataset. Here is my Query. Query is not complete. But it is just a refrence for my Ques Select * from tblxyz compute sum(col1) suppose this query returns more than one table, I want to fill all the tables into my dataset I am filling result like this con.open(); adp.fill(dset); con.close(); Now when i checks this dataset. It shows me that it has four tables but only first table data is being displayed into it. rest 3 dont even have schema also. What i need to do to get desired output

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  • (Oracle) How get total number of results when using a pagination query?

    - by BestPractices
    I am using Oracle 10g and the following paradigm to get a page of 15 results as a time (so that when the user is looking at page 2 of a search result, they see records 16-30). select * from ( select rownum rnum, a.* from (my_query) a where rownum <= 30 ) where rnum > 15; Right now I'm having to run a separate SQL statement to do a "select count" on "my_query" in order to get the total number of results for my_query (so that I can show it to the user and use it to figure out total number of pages, etc). Is there any way to get the total number of results without doing this via a second query, i.e. by getting it from above query? I've tried adding "max(rownum)", but it doesn't seem to work (I get an error [ORA-01747] that seems to indicate it doesnt like me having the keyword rownum in the group by). My rationale for wanting to get this from the original query rather than doing it in a separate SQL statement is that "my_query" is an expensive query so I'd rather not run it twice (once to get the count, and once to get the page of data) if I dont have to; but whatever solution I can come up with to get the number of results from within a single query (and at the same time get the page of data I need) should not add much if any additional overhead, if possible. Please advise. Here is exactly what I'm trying to do for which I receive an ORA-01747 error because I believe it doesnt like me having ROWNUM in the group by. Note, If there is another solution that doesnt use max(ROWNUM), but something else, that is perfectly fine too. This solution was my first thought as to what might work. SELECT * FROM (SELECT r.*, ROWNUM RNUM, max(ROWNUM) FROM (SELECT t0.ABC_SEQ_ID AS c0, t0.FIRST_NAME, t0.LAST_NAME, t1.SCORE FROM ABC t0, XYZ t1 WHERE (t0.XYZ_ID = 751) AND t0.XYZ_ID = t1.XYZ_ID ORDER BY t0.RANK ASC) r WHERE ROWNUM <= 30 GROUP BY r.*, ROWNUM) WHERE RNUM > 15

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  • Search sort by parameter match count in the query? PostgreSQL

    - by Ben Dauphinee
    I am working on a search query in PostgreSQL, and one of the things I do is sort my query results by the number of parameters matched. I have no clue how this can be done. Does anyone have a suggestion or solution? Table brand color type engine Ford Blue 4-door V8 Maserati Blue 2-door V12 Saturn Green 4-door V8 GM Yellow 1-door V4 Current Query SELECT brand FROM table WHERE color = 'Blue' or type = '4-door' or engine = 'V8' Result Should Be Ford (3 match) Saturn (2 match) Maserati (1 match)

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  • Why notify listeners in a content provider query method?

    - by cbrulak
    Vegeolla has this blog post about content providers and the snippet below (at the bottom) with this line: cursor.setNotificationUri(getContext().getContentResolver(), uri); I'm curious as to why one would want to notify listeners about a query operation. Am I missing something? Thanks @Override public Cursor query(Uri uri, String[] projection, String selection, String[] selectionArgs, String sortOrder) { // Uisng SQLiteQueryBuilder instead of query() method SQLiteQueryBuilder queryBuilder = new SQLiteQueryBuilder(); // Check if the caller has requested a column which does not exists checkColumns(projection); // Set the table queryBuilder.setTables(TodoTable.TABLE_TODO); int uriType = sURIMatcher.match(uri); switch (uriType) { case TODOS: break; case TODO_ID: // Adding the ID to the original query queryBuilder.appendWhere(TodoTable.COLUMN_ID + "=" + uri.getLastPathSegment()); break; default: throw new IllegalArgumentException("Unknown URI: " + uri); } SQLiteDatabase db = database.getWritableDatabase(); Cursor cursor = queryBuilder.query(db, projection, selection, selectionArgs, null, null, sortOrder); // Make sure that potential listeners are getting notified cursor.setNotificationUri(getContext().getContentResolver(), uri); return cursor; }

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • How can I loop over a query for a specific number of times that may be greater than the result?

    - by JS
    I need to loop over a query exactly 12 times to complete rows in a form but rarely will the query return 12 rows. The cfquery endRow attribute doesn't force the loop to keep going if the result is < 12. If it did that would be ideal to use something like cfloop query="myQuery" endRow="12"... The 2 options that I have now are to skip the loop and write out all 12 rows but that results in a lot of duplicate code (there are 20 columns), or do a query of queries for each row which seems like a lot of wasted processing. Thanks for any ideas.

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