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  • How do I perform this MutliArray setup in Java?

    - by Andy Barlow
    I come from a PHP background and I'm just getting my teeth into some Java. I was wondering how I could implement the following in Java as simply as possible, just echoing the results to a terminal via the usual "System.out.print()" method. <?php $Results[0]['title'] = "No Country for Old Men"; $Results[0]['run_time'] = "122 mins"; $Results[0]['cert'] = "15"; $Results[1]['title'] = "Old School"; $Results[1]['run_time'] = "88 mins"; $Results[1]['cert'] = "18"; // Will basically show the above in order. foreach($Results as value) { echo $Results[$value]['title']; echo $Results[$value]['run_time']; echo $Results[$value]['cert']; } // Lets add some more as I need to do this in Java too $Results[2]['title'] = "Saving Private Ryan"; $Results[2]['run_time'] = "153 mins"; $Results[2]['cert'] = "15"; // Lets remove the first one as an example of another need $Results[0] = null; ?> I hear there are "list iterators" or something that are really good for rolling through data like this. Perhaps it could be implemented with that? A fully working .java file would be most handy in this instance, including how to add and remove items from the array like the above. P.S. I do plan on using this for an Android App in the distant future, so, hopefully it should all work on Android fine too, although, I imagine this sort of thing works on anything Java related :).

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  • Show values in TDropDownList in PRADO.

    - by Muhammad Sajid
    I m new to PRADO, I have a file Home.page with code: <%@ Title="Contact List" %> <h1>Contact List</h1> <a href="<%= $this->Service->constructUrl('insert')%>">Create New Contact</a> <br/> <com:TForm> <com:TDropDownList ID="personInfo"> <com:TListItem Value="value 1" Text="item 1" /> <com:TListItem Value="value 2" Text="item 2" Selected="true" /> <com:TListItem Value="value 3" Text="item 3" /> <com:TListItem Value="value 4" Text="item 4" /> </com:TDropDownList> </com:TForm> & Home.php with code <?php class Home extends TPage { /** * Populates the datagrid with user lists. * This method is invoked by the framework when initializing the page * @param mixed event parameter */ public function onInit($param) { parent::onInit($param); // fetches all data account information $rec = ContactRecord::finder()->findAll(); } } ?> the $rec contain array of all values. Now I want to show all name in Dropdown list. I tried my best but fail. Can anyone help me? Thanks

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  • Form submit capture into database not working

    - by kielie
    Hi guys, I have a form that has two buttons on it, one yes, one no, and at the moment I capture the clicked button into a database, but for some reason, it doesn't always capture the clicked button, I have gone through all my code and everything seems fine, here is the form <div id="mid_prompt"> <form action="refer.php" method="post" onsubmit="return submit_form()" > <div class="prompt_container" style="float: left;"> <span class="prompt_item"><input type="image" src="images/yes.jpg" alt="submit" name="refer" value="yes" /></span> </div> </form> <form action="thank_you.php" method="post" onsubmit="return submit_form()" > <div class="prompt_container" style="float: right;"> <span class="prompt_item"><input type="image" src="images/no.jpg" alt="submit" name="refer" value="no" /></span> </div> </form> </div> I am using sessions to carry the variables all the way to the end of the forms where I then write all the data to a database, I have checked my sessions and they seem to be working fine, the only one that is giving problems is the yes/no. So basically I need it to capture that yes/no everytime. Thanx in advance!

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  • how to return response from post in a variable? jQuery

    - by robertdd
    i use this function to return the response of post: $.sendpost = function(){ return jQuery.post('inc/operations.php', {'operation':'test'}, "json"); }, i want to make something like this: in: $.another = function(){ var sendpost = $.sendpost(); alert(sendpost); } but i get: [object XMLHttpRequest] if i print the object with: jQuery.each(sendpost, function(i, val) { $(".displaydetails").append(i + " => " + val + "<br/>"); }); i get: details abort => function () { x && h.call(x); g("abort"); } dispatchEvent => function dispatchEvent() { [native code] } removeEventListener => function removeEventListener() { [native code] } open => function open() { [native code] } setRequestHeader => function setRequestHeader() { [native code] } onreadystatechange => [xpconnect wrapped nsIDOMEventListener] send => function send() { [native code] } readyState => 4 status => 200 getResponseHeader => function getResponseHeader() { [native code] } responseText => mdaaa from php how to return only the response in the variable?

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  • French date format

    - by kwek-kwek
    I am a newbie in PHP & wordpress. I wanted to know how to make this codde renders the date formating in french (e.g. 5 Fev) when your on the french side but in english format in English (e.g. Jan 5) Here is my code: <?php if (strtolower(ICL_LANGUAGE_CODE) == 'en') {$sidePosts = get_posts('cat=3,4,5,19&posts_per_page=5&order=DESC&orderby=date');} if (strtolower(ICL_LANGUAGE_CODE) == 'fr') {$sidePosts = get_posts('cat=9,10,11,17&posts_per_page=5&order=DESC&orderby=date');} foreach($sidePosts as $sidePosts) { $array = (array) $sidePosts; print("<li>"); print("<span class='date'>".get_the_time('M j', $array[ID])."</span>"); print("<a href='".get_permalink($array[ID])."' title='".$array[post_title]."'>".$array[post_title]."</a>"); print("</li>"); } ?>

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  • How to change CSS color values in real-time off a javascript slider?

    - by bflora
    I'm making a page where the user gets a javascript slider that goes from 0 to 100 and can use it to set the opacity of a div on the page. I want the opacity of that div to change in real-time as they work the slider. I've not done this before. What's the best approach? There cursor in the slider displays the slider's current value as you move it. It seems to be that I just need to find a way to display that value in any arbitrary other place on the page so I can display it in the style settings for the div. The .js file that generates the slider has a line that (I think) is setting the current value in the cursor: $(this).children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); TO get this changing number to display somewhere else at the same time, do I just need to add a div somewhere and then add a line like this? $("#newDivId").children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); That seems like it would give me the number showing up in a div. How then would I get it into a form I could put into the style settings for a div? If this was a php variable, I would do something like this, style="opacity:<?php print $value ?>;" What would be the .js equivalent?

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  • Why does multiple sessions started on the same page gets the same session id?

    - by Calmarius
    I tryed the following: <?php session_name('user'); session_start(); // sets an 'user' cookie with session id. // This session stores the user's login data. // Its an ordinary session. $USERSESSION=$_SESSION; // saving this session $userSessId=session_id(); session_write_close(); //closing this session session_name('chatroom'); session_start(); // set a 'chatroom' cookie but contains the same session id and points to the same data :( . // This session would be used to store the chat text. This session would be // shared between all users joined in this chat room by setting the same session id for all members. // by calling session_regenerate_id would make a diffent session id for every user and it won't be a chat room anymore. ?> So I want to do a chat like thing with sessions. On the client side it would be done with ajax that polls this php page in every 5-10 seconds. Sessions may be cached in the server's memory so it can be accessible fast. I can store the chat in the database but my service runs on a free webhost which is limited, only 4 mysql connections allowed at a time which is almost nothing. I try to touch my database as least times as possible.

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  • $HTTP_RAW_POST_DATA and Wordpress media_handle_upload

    - by BaronVonKaneHoffen
    Hi there! So I'm making something for which users need to upload images from a canvas element (on the front end) using Wordpress's in-built Media Upload API. I've successfully uploaded images with the API from a file input in a form: <input type="file" name="async-upload" id="async-upload" size="40" /> ... <?php $new_attach_id = media_handle_upload( 'async-upload', $new_id ); ?> and I've saved images from the canvas using my own script: <script type="text/javascript"> ... var img = canvas.toDataURL("image/png"); ... ajax.send(img ); </script> ... <?php $imageData=$GLOBALS['HTTP_RAW_POST_DATA']; $filteredData=substr($imageData, strpos($imageData, ",")+1); $unencodedData=base64_decode($filteredData); $fp = fopen( 'saved_images/canv_save_test.png', 'wb' ); fwrite( $fp, $unencodedData); ... ?> Problem is, Wordpress's media_handle_upload() only accepts an index to the $_FILES array for the upload. So the question is: How can I pass the image data from HTTP_RAW_POST_DATA to it? Could I make the $_FILES['tmp-name'] point to it somehow? Could I use another script as an intermediate step somehow? Could I unleash the monkeys on the typewriter until they come up with the answer? Any help very very much appreciated! Thanks, Kane

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  • Storing Credit Card Numbers in SESSION - ways around it?

    - by JM4
    I am well aware of PCI Compliance so don't need an earful about storing CC numbers (and especially CVV nums) within our company database during checkout process. However, I want to be safe as possible when handling sensitive consumer information and am curious how to get around passing CC numbers from page to page WITHOUT using SESSION variables if at all possible. My site is built in this way: Step 1) collect Credit Card information from customer - when customer hits submit, the information is first run through JS validation, then run through PHP validation, if all passes he moves to step 2. Step 2) Information is displayed on a review page for customer to make sure the details of their upcoming transaction are shown. Only the first 6 and last 4 of the CC are shown on this page but card type, and exp date are shwon fully. If he clicks proceed, Step 3) The information is sent to another php page which runs one last validation, sends information through secure payment gateway, and string is returned with details. Step 4) If all is good and well, the consumer information (personal, not CC) is stored in DB and redirected to a completion page. If anything is bad, he is informed and told to revisit the CC processing page to try again (max of 3 times). Any suggestions?

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  • XML and HTML = need help using HTML code

    - by whitstone86
    I'm converting my static HTML site to a dynamic PHP/XML-driven one. This is my current code: <div class="divider"></div> <div class="main" style="width: 552px;"> <div class="time">00:00</div> <div class="show"><h3><b>Radio Show</b></h3> <p>Description</p></div> <div class="footer"></div> </div> and my XML file: <?xml version="1.0"?> <show> <showdesc> <divider1></divider1> <divmain></divmain> <airtime></airtime> <presenter></presenter> <showinfo></showinfo> <divfooter></divfooter> </showdesc> which is the above HTML, that I'm trying to get into the XML file. I don't know how to get it to get the info in, I can display a simple XML page, as suggested here: http://www.kirupa.com/web/xml_php_parse_intermediate.htm but I am trying to in PHP get this to display what's in the XML pages or display this output: "Sorry. No schedule page is available" if the XML is blank, as above. Anyone able to help me fix this? I've tried and tried but it's baffling me... Thanks.

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  • Codeigniter Session Data not available in other pages after login

    - by jswat
    So, I have set up a login page that verifies the user's credentials, and then sets codeigniter session data 'email' and 'is_logged_in' and a few other items. The first page after the login, the data is accessible. After that page, I can no longer access the session data. In fact, if I try reloading that first page, the session data is gone. I have tried storing it in the database, storing it unencrypted (bad idea I know, but it was for troubleshooting), and storing it encrypted. I have autoloaded the session library in config.php. Here's an example of the code I'm using to set the session data: $data = array( 'email' => $this->input->post('username'), 'is_logged_in' => true ); $this->session->set_userdata($data); And to retrieve it, I'm using : $this->session->userdata('email'); Or $this->session->userdata('is_logged_in'); I've done lots of work with PHP and cookies, and sessions before, but this is my first project with Codeigniter and I'm perplexed. Could it have something to do with directory issues? I have the login page and process controlled by a 'login' controller, and then it redirects to a 'site' controller. Thanks for your help, and please let me know if I need to clarify anything.

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  • how to go to the same page after login in PHP

    - by Fero
    Hi all, For example, STEP 1: I am browsing a page without logging in and my last page before logging in is beforeLogin.php STEP 2: Now my prob is when i logged in i am redirecting to the index.php page. Instead i should be redirected to the last page what i had browsed. That is from the above example is should redirected to beforeLogin.php How should this can be done. Any help will be appreciable. thanks in advance

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  • Folder permission and submit button

    - by bob
    I want to create a simple installation script. Below are simple code. <ul> <?php function check_perms($path,$perm) { clearstatcache(); $configmod = substr(sprintf('%o', fileperms($path)), -4); $css = (($configmod != $perm) ? " class='error r2'" : " class='none'"); echo "<li".$css.">\n"; echo '<span style="float:left; padding-right:20px;">'.$path.'</span>'; echo '<span style="float:right; width:100px; text-align:right;"> <strong>'.$perm.'</strong></span>'; echo '<span style="float:right; padding-right:100px;"><strong>'.$configmod.'</strong></span>'; echo '<div class="clear"></div>'; echo "</li>"; } check_perms("config.php","0777"); check_perms("themes","0777"); check_perms("themes/images","0777"); check_perms("useruploads","0777"); ?> </ul> How to make if all file and folder is valid permission to 777 will appear Submit button. <input type='submit' name='submit' value='Submit' /> If there still have incorrect permission do not show the Submit button Let me know.

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  • Object Oriented Programming Problem

    - by Danny Love
    I'm designing a little CMS using PHP whilst putting OOP into practice. I've hit a problem though. I have a page class, whos constructor accepts a UID and a slug. This is then used to set the properties (unless the page don't exist in which case it would fail). Anyway, I wanted to implement a function to create a page, and I thought ... what's the best way to do this without overloading the constructor. What would the correct way, or more conventional method, of doing this be? My code is below: <?php class Page { private $dbc; private $title; private $description; private $image; private $tags; private $owner; private $timestamp; private $views; public function __construct($uid, $slug) { } public function getTitle() { return $this->title; } public function getDescription() { if($this->description != NULL) { return $this->description; } else { return false; } } public function getImage() { if($this->image != NULL) { return $this->image; } else { return false; } } public function getTags() { if($this->tags != NULL) { return $this->tags; } else { return false; } } public function getOwner() { return $this->owner; } public function getTimestamp() { return $this->timestamp; } public function getViews() { return $this->views; } public function createPage() { // Stuck? } }

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  • problem with enable/disable button using javascript

    - by LiveEn
    Im am trying to add a check box that will enable/disable the edit button. Im retrieving a price list and displaying it inside a table. When i add the javascript into the php code it doesn't work. Below is my code <table border="1"> <tr> <td width="100">Fee % </td> <td width="100">Price</td> <td width="100">Total</td> <td width="102">&nbsp;</td> </tr> <tr> <?php $sql1="select * from pricelist"; $result1=mysql_query($sql1) or die(mysql_error()); while ($row=mysql_fetch_array($result1)) { $id=$row['id']; $price=$row['h_price']; $a=0; print "<form id='form1' name='$a+' method='post' action=''>"; print "<td><input name='fees' value ='$fees' type='text' size='4' /></td>"; print "<td><input name='price' value ='$price' type='text' size='15' /></td>"; echo "<td><input type='checkbox' onclick='this.$a+.disabled = !this.checked;'><td>"; print"<td><input type='submit' name='$a+' value='Submit' disabled='disabled' /></td>"; print "</tr>"; print "</form>"; } ?> </table> Can someone please tell me what am i doing wrong? Thanks

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • Creating a RESTful API - HELP!

    - by Martin Cox
    Hi Chaps Over the last few weeks I've been learning about iOS development, which has naturally led me into the world of APIs. Now, searching around on the Internet, I've come to the conclusion that using the REST architecture is very much recommended - due to it's supposed simplicity and ease of implementation. However, I'm really struggling with the implementation side of REST. I understand the concept; using HTTP methods as verbs to describe the action of a request and responding with suitable response codes, and so on. It's just, I don't understand how to code it. I don't get how I map a URI to an object. I understand that a GET request for domain.com/api/user/address?user_id=999 would return the address of user 999 - but I don't understand where or how that mapping from /user/address to some method that queries a database has taken place. Is this all coded in one php script? Would I just have a method that grabs the URI like so: $array = explode("/", ltrim(rtrim($_SERVER['REQUEST_URI'], "/"), "/")) And then cycle through that array, first I would have a request for a "user", so the PHP script would direct my request to the user object and then invoke the address method. Is that what actually happens? I've probably not explained my thought process very well there. The main thing I'm not getting is how that URI /user/address?id=999 somehow is broken down and executed - does it actually resolve to code? class user(id) { address() { //get user address } } I doubt I'm making sense now, so I'll call it a day trying to explain further. I hope someone out there can understand what I'm trying to say! Thanks Chaps, look forward to your responses. Martin p.s - I'm not a developer yet, I'm learning :)

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  • Sample twitter application

    - by Jack
    I have installed WAMP and running PHP scripts on localhost. I have enabled cURL. Here is my code. <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> Here's my output Operation completed without any errors Error: 404 Here's what error 404 means 404 Not Found: The URI requested is invalid or the resource requested, such as a user, does not exists. Please help.

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  • What is the best way to identify which form has been submitted?

    - by Rupert
    Currently, when I design my forms, I like to keep the name of the submit button equal to the id of the form. Then, in my php, I just do if(isset($_POST['submitName'])) in order to check if a form has been submitted and which form has been submitted. Firstly, are there any security problems or design flaws with this method? One problem I have encountered is when I wish to overlay my forms with javascript in order to provide faster validation to the user. For example, whilst I obviously need to retain server side validation, it is more convenient for the user if an error message is displayed inline, upon blurring an input. Additionally, it would be good to provide entire form validation, upon clicking the submit button. Therefore, when the user clicks on the form's submit button, I am stopping the default action, doing my validation, and then attempting to renable the traditional submit functionality, if the validation passes. In order to do this, I am using the form.submit() method but, unfortunately, this doesn't send the submit button variable (as it should be as form.submit() can be called without any button being clicked). This means my PHP script fails to detect that the form has been submitted. What is the correct way to work around this? It seems like the standard solution is to add a hidden field into the form, upon passing validation, which has the name of form's id. Then when form.submit() is called, this is passed along in place of the submit button. However, this solution seems very ungraceful to me and so I am wondering whether I should: a) Use an alternative method to detect which form has been submitted which doesn't rely rely on passing the submit button. If so what alternative is there? Obviously, just having an extra hidden field from the start isn't any better. b) Use an alternative Javascript solution which allows me to retain my non-Javascript design. For example, is there an alternative to form.submit() which allows me to pass in extra data? c) Suck it up and just insert a hidden field using Javascript.

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  • YouTube - Encrypted cookie string

    - by Robertof
    Hello! I'm new to Stack Overflow. I'm building a YouTube Downloader in PHP. But YouTube have some IP-checks. Because the PHP file is on a remote server, the ip of the server != the ip of the user and the video-download fails. So, maybe I've found a solution. YouTube sends a cookie with an encrypted string, which is the user IP. I need to know the encrypted-string algorithm and know how to crypt a string with this. Here there is the string: nQ0CrJmASJk . It could be base64, but when I try to decode it with base64_decode, it gives me strange characters. You could check the cookie by requesting the main page of youtube, and check the headers "Set-Cookie". You will found a cookie with the name "VISITOR_INFO1_LIVE". Here there is the encrypyed string. Anyone knows what is the algorithm? Thanks. PS: sorry for my bad english. Cheers, Roberto.

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  • Why Firebug pretends that my stylesheet is calling my xmlrpc ?

    - by Rebol Tutorial
    Firebug shows a request which causes a huge delay to http://reboltutorial.com/wp-content/themes/minaflow/none Details below but I don't understand why it says it comes from xmlrpc and the stylesheet: Date Sun, 04 Apr 2010 16:10:02 GMT Server Apache X-Powered-By PHP/5.2.13 X-Pingback http://reboltutorial.com/xmlrpc.php Expires Wed, 11 Jan 1984 05:00:00 GMT Cache-Control no-cache, must-revalidate, max-age=0 Pragma no-cache Set-Cookie wordpress_test_cookie=WP+Cookie+check; path=/; domain=.reboltutorial.com Last-Modified Sun, 04 Apr 2010 16:10:03 GMT Vary Accept-Encoding Content-Encoding gzip Keep-Alive timeout=2, max=94 Connection Keep-Alive Transfer-Encoding chunked Content-Type text/html; charset=UTF-8 Requêtemise en page impression GET /wp-content/themes/minaflow/none HTTP/1.1 Host: reboltutorial.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; fr; rv:1.9.2) Gecko/20100115 Firefox/3.6 Accept: image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language: fr,fr-fr;q=0.8,en-us;q=0.5,en;q=0.3 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://reboltutorial.com/wp-content/themes/minaflow/style.css Cookie: _csoot=1267966575980; _csuid=4b6f27395991a2ff; wp-settings-1=editor%3Dhtml%26align%3Dleft%26m0%3Do%26m1%3Do%26m2%3Do%26m3%3Dc%26m4%3Do%26m5%3Dc%26m6%3Do%26m7%3Do%26m8%3Dc%26m9%3Dc%26m10%3Dc%26m11%3Do%26m12%3Dc%26m13%3Dc%26m14%3Dc%26m15%3Dc; wp-settings-time-1=1270384700; subscribe_checkbox_=unchecked; PHPSESSID=o70hjpjf7uj2hb4doe4k0o5co5; wordpress_test_cookie=WP+Cookie+check; xumgeqhxmhohxipF=Erjixxeeskfgnlba; SJECT=CKON; wordpress_=admin%7C1271592539%7C392c555d9051c6fa184074d8441cc472; wordpress_logged_in_=admin%7C1271592539%7C0e7a92bda53cc2f5afc32962237a1037; rcBDvgtspmuEsyzp=rmqjtFbCfheGCjBw; prli_click_15=creatingstandard; prli_visitor=m7928r

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  • Sonata Media Bundle sortBy created_at

    - by tony908
    I use SonataMediaBundle and i would like sort Gallery by created_at field. In repository class i have (without orderBy working good!): $qb = $this->createQueryBuilder('m') ->orderBy('j.expires_at', 'DESC'); $query = $qb->getQuery(); return $query->getResult(); and this throw error: An exception has been thrown during the rendering of a template ("[Semantical Error] line 0, col 80 near 'created_at D': Error: Class Application\Sonata\MediaBundle\Entity\Gallery has no field or association named created_at") so i add this field to Gallery class: /** * @var \DateTime */ private $created_at; /** * Set created_at * * @param \DateTime $createdAt * @return Slider */ public function setCreatedAt($createdAt) { $this->created_at = $createdAt; return $this; } /** * Get created_at * * @return \DateTime */ public function getCreatedAt() { return $this->created_at; } but now i have error: FatalErrorException: Compile Error: Declaration of Application\Sonata\MediaBundle\Entity\Gallery::setCreatedAt() must be compatible with Sonata\MediaBundle\Model\GalleryInterface::setCreatedAt(DateTime $createdAt = NULL) in /home/tony/www/test/Application/Sonata/MediaBundle/Entity/Gallery.php line 32 GalleryInterface: https://github.com/sonata-project/SonataMediaBundle/blob/master/Model/GalleryInterface.php So... how can i use sortBy in my example?

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  • Upload file onto Server from the IPhone using ASIHTTPRequest

    - by Nick
    I've been trying to upload a file (login.zip) using the ASIHTTPRequest libraries from the IPhone onto the inbuilt Apache Server in Mac OS X Snow Leopard. My code is: NSString *urlAddress = [[[NSString alloc] initWithString:self.uploadField.text]autorelease]; NSURL *url = [NSURL URLWithString:urlAddress]; ASIFormDataRequest *request; NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *dataPath = [documentsDirectory stringByAppendingPathComponent:@"login.zip"]; NSData *data = [[[NSData alloc] initWithContentsOfFile:dataPath] autorelease]; request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease]; [request setPostValue:@"login.zip" forKey:@"file"]; [request setData:data forKey:@"file"]; [request setUploadProgressDelegate:uploadProgress]; [request setShowAccurateProgress:YES]; [request setDelegate:self]; [request startAsynchronous]; The php code is : <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> I don't quite understand why the file is not uploading. If anyone could help me. I've stuck on this for 5 days straight. Thanks in advance Nik

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  • making html table columns optionally sortable

    - by jdamae
    I have an html table that is populated from a text file, formatted and semi colon separated. I would like the user to have the option of sorting alphabetically with either of the columns when clicking on the column name (header). How do I do this in php?? Or is there another way of doing this? Thanks for your help. Sample raw data/input looks like this: TYPE=abc;PART=georgetown;FILE=goog_abc.dat.2010122211.gz TYPE=xyz;PART=ucny;FILE=aol_xyz.dat.2010122209.gz Php code for table: $lines = preg_split('~\s*[\r\n]+\s*~', file_get_contents('/temp/tab.txt')); foreach($lines as $i => $line) { $pairs = explode(';', $line); foreach($pairs as $pair) { list($column, $value) = explode('=', $pair, 2); $columns[$column] = true; $rows[$i][$column] = $value; } } $columns = array_keys($columns); echo '<table><thead><tr>'; foreach($columns as $column) { echo '<th>'.$column.'</th>'; } echo '</tr></thead><tbody>'; foreach ($rows as $row) { echo '<tr>'; foreach($columns as $column){ echo '<td>'.$row[$column].'</td>'; } echo '</tr>'; } echo '</tbody></table>';

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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