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  • What is the most elegant way to implement a business rule relating to a child collection in LINQ?

    - by AaronSieb
    I have two tables in my database: Wiki WikiId ... WikiUser WikiUserId (PK) WikiId UserId IsOwner ... These tables have a one (Wiki) to Many (WikiUser) relationship. How would I implement the following business rule in my LINQ entity classes: "A Wiki must have exactly one owner?" I've tried updating the tables as follows: Wiki WikiId (PK) OwnerId (FK to WikiUser) ... WikiUser WikiUserId (PK) WikiId UserId ... This enforces the constraint, but if I remove the owner's WikiUser record from the Wiki's WikiUser collection, I recieve an ugly SqlException. This seems like it would be difficult to catch and handle in the UI. Is there a way to perform this check before the SqlException is generated? A better way to structure my database? A way to catch and translate the SqlException to something more useful? Edit: I would prefer to keep the validation rules within the LINQ entity classes if possible. Edit 2: Some more details about my specific situation. In my application, the user should be able to remove users from the Wiki. They should be able to remove any user, except the user who is currently flagged as the "owner" of the Wiki (a Wiki must have exactly one owner at all times). In my control logic, I'd like to use something like this: wiki.WikiUsers.Remove(wikiUser); mRepository.Save(); And have any broken rules transferred to the UI layer. What I DON'T want to have to do is this: if(wikiUser.WikiUserId != wiki.OwnerId) { wiki.WikiUsers.Remove(wikiUser); mRepository.Save(); } else { //Handle errors. } I also don't particularly want to move the code to my repository (because there is nothing to indicate not to use the native Remove functions), so I also DON'T want code like this: mRepository.RemoveWikiUser(wiki, wikiUser) mRepository.Save(); This WOULD be acceptable: try { wiki.WikiUsers.Remove(wikiUser); mRepository.Save(); } catch(ValidationException ve) { //Display ve.Message } But this catches too many errors: try { wiki.WikiUsers.Remove(wikiUser); mRepository.Save(); } catch(SqlException se) { //Display se.Message } I would also PREFER NOT to explicitly call a business rule check (although it may become necessary): wiki.WIkiUsers.Remove(wikiUser); if(wiki.CheckRules()) { mRepository.Save(); } else { //Display broken rules }

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  • Myself throwing NullReferenceException... needs help

    - by Amit Ranjan
    I know it might be a weird question and its Title too, but i need your help. I am a .net dev , working on platform for the last 1.5 years. I am bit confused on the term usually we say " A Good Programmer ". I dont know ,what are the qualities of a good programmer ? Is the guy who writes a bug free code? or Can develop applications solely? or blah blah blah...lots of points. I dont know... But as far i am concerned , I know I am not a good programmer, still in learning phase an needs a lot to learn in coming days. So you guys are requested to please help me with this two problems of mine My first problem is regarding the proper Error Handling, which is a most debatable aspect of programming. We all know we use ` try { } catch { } finally { } ` in our code to manage exception. But even if I use try { } catch(exception ex) { throw ex } finally { } , different guys have different views. I still dont know the good way to handle errors. I can write code, use try-catch but still i feel I lacks something. When I saw the codes generated by .net fx tools even they uses throw ex or `throw new Exception("this is my exception")`.. I am just wondering what will be the best way to achieve the above. All means the same thing but why we avoid something. If it has some demerits then it must be made obselete.Anyways I still dont have one [how to handle errors efficiently?]. I generally follow the try-catch(execoption ex){throw ex}, and usually got stucked in debates with leads why you follow this why not that... 2.Converting your entire code blocks in modules using Design patterns of some OOPs concepts. How do you guys decide what architeture or pattern will be the best for my upcoming application based on its working, flow etc. I need to know what you guys can see that I can't. Since I know , I dont have that much experience but I can say, with my experience that experience doesnot comes either from degree/certificates or success you made instead it cames from failures you faced or got stucking situations. Pleas help me out.

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  • Error with my Android Application httpGet

    - by Coombes
    Basically I'm getting a strange issue with my Android application, it's supposed to grab a JSON Array and print out some values, the class looks like this: ShowComedianActivity.class package com.example.connecttest; public class ShowComedianActivity extends Activity{ TextView name; TextView add; TextView email; TextView tel; String id; // Progress Dialog private ProgressDialog pDialog; //JSON Parser class JSONParser jsonParser = new JSONParser(); // Single Comedian url private static final String url_comedian_details = "http://86.9.71.17/connect/get_comedian_details.php"; // JSON Node names private static final String TAG_SUCCESS = "success"; private static final String TAG_COMEDIAN = "comedian"; private static final String TAG_ID = "id"; private static final String TAG_NAME = "name"; private static final String TAG_ADDRESS = "address"; private static final String TAG_EMAIL = "email"; private static final String TAG_TEL = "tel"; public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.show_comedian); // Getting Comedian Details from intent Intent i = getIntent(); // Getting id from intent id = i.getStringExtra(TAG_ID); new GetComedianDetails().execute(); } class GetComedianDetails extends AsyncTask<String, String, String>{ protected void onPreExecute(){ super.onPreExecute(); pDialog = new ProgressDialog(ShowComedianActivity.this); pDialog.setMessage("Fetching Comedian details. Please wait..."); pDialog.setIndeterminate(false); pDialog.setCancelable(true); pDialog.show(); } @Override protected String doInBackground(String... params) { runOnUiThread(new Runnable(){ public void run(){ int success; try{ //Building parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("id",id)); // Getting comedian details via HTTP request // Uses a GET request JSONObject json = jsonParser.makeHttpRequest(url_comedian_details, "GET", params); // Check Log for json response Log.d("Single Comedian details", json.toString()); //JSON Success tag success = json.getInt(TAG_SUCCESS); if(success == 1){ // Succesfully received product details JSONArray comedianObj = json.getJSONArray(TAG_COMEDIAN); //JSON Array // get first comedian object from JSON Array JSONObject comedian = comedianObj.getJSONObject(0); // comedian with id found name = (TextView) findViewById(R.id.name); add = (TextView) findViewById(R.id.add); email = (TextView) findViewById(R.id.email); tel = (TextView) findViewById(R.id.tel); // Set text to details name.setText(comedian.getString(TAG_NAME)); add.setText(comedian.getString(TAG_ADDRESS)); email.setText(comedian.getString(TAG_EMAIL)); tel.setText(comedian.getString(TAG_TEL)); } } catch (JSONException e){ e.printStackTrace(); } } }); return null; } } } And my JSON Parser class looks like: package com.example.connecttest; public class JSONParser { static InputStream is = null; static JSONObject jObj = null; static String json = ""; // constructor public JSONParser() { } // function get json from url // by making HTTP POST or GET method public JSONObject makeHttpRequest(String url, String method, List<NameValuePair> params) { // Making HTTP request try { // check for request method if(method == "POST"){ // request method is POST // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); httpPost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); }else if(method == "GET"){ // request method is GET DefaultHttpClient httpClient = new DefaultHttpClient(); String paramString = URLEncodedUtils.format(params, "utf-8"); url += "?" + paramString; HttpGet httpGet = new HttpGet(url); HttpResponse httpResponse = httpClient.execute(httpGet); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputStreamReader( is, "iso-8859-1"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); json = sb.toString(); } catch (Exception e) { Log.e("Buffer Error", "Error converting result " + e.toString()); } // try parse the string to a JSON object try { jObj = new JSONObject(json); } catch (JSONException e) { Log.e("JSON Parser", "Error parsing data " + e.toString()); } // return JSON String return jObj; } } Now when I run a debug it's querying the correct address with ?id=1 on the end of the URL, and when I navigate to that url I get the following JSON Array: {"success":1,"comedian":[{"id":"1","name":"Michael Coombes","address":"5 Trevethenick Road","email":"[email protected]","tel":"xxxxxxxxxxxx"}]} However my app just crashes, the log-cat report looks like this: 03-22 02:05:02.140: E/Trace(3776): error opening trace file: No such file or directory (2) 03-22 02:05:04.590: E/AndroidRuntime(3776): FATAL EXCEPTION: main 03-22 02:05:04.590: E/AndroidRuntime(3776): android.os.NetworkOnMainThreadException 03-22 02:05:04.590: E/AndroidRuntime(3776): at android.os.StrictMode$AndroidBlockGuardPolicy.onNetwork(StrictMode.java:1117) 03-22 02:05:04.590: E/AndroidRuntime(3776): at libcore.io.BlockGuardOs.connect(BlockGuardOs.java:84) 03-22 02:05:04.590: E/AndroidRuntime(3776): at libcore.io.IoBridge.connectErrno(IoBridge.java:127) 03-22 02:05:04.590: E/AndroidRuntime(3776): at libcore.io.IoBridge.connect(IoBridge.java:112) 03-22 02:05:04.590: E/AndroidRuntime(3776): at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:192) 03-22 02:05:04.590: E/AndroidRuntime(3776): at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:459) 03-22 02:05:04.590: E/AndroidRuntime(3776): at java.net.Socket.connect(Socket.java:842) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.conn.scheme.PlainSocketFactory.connectSocket(PlainSocketFactory.java:119) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:144) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:360) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 03-22 02:05:04.590: E/AndroidRuntime(3776): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 03-22 02:05:04.590: E/AndroidRuntime(3776): at com.example.connecttest.JSONParser.makeHttpRequest(JSONParser.java:62) 03-22 02:05:04.590: E/AndroidRuntime(3776): at com.example.connecttest.ShowComedianActivity$GetComedianDetails$1.run(ShowComedianActivity.java:89) 03-22 02:05:04.590: E/AndroidRuntime(3776): at android.os.Handler.handleCallback(Handler.java:615) 03-22 02:05:04.590: E/AndroidRuntime(3776): at android.os.Handler.dispatchMessage(Handler.java:92) 03-22 02:05:04.590: E/AndroidRuntime(3776): at android.os.Looper.loop(Looper.java:137) 03-22 02:05:04.590: E/AndroidRuntime(3776): at android.app.ActivityThread.main(ActivityThread.java:4745) 03-22 02:05:04.590: E/AndroidRuntime(3776): at java.lang.reflect.Method.invokeNative(Native Method) 03-22 02:05:04.590: E/AndroidRuntime(3776): at java.lang.reflect.Method.invoke(Method.java:511) 03-22 02:05:04.590: E/AndroidRuntime(3776): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:786) 03-22 02:05:04.590: E/AndroidRuntime(3776): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553) 03-22 02:05:04.590: E/AndroidRuntime(3776): at dalvik.system.NativeStart.main(Native Method) From this I'm guessing the error is in the jsonParser.makeHttpRequest however I can't for the life of me figure out what's going wrong and was hoping someone brighter than I could illuminate me.

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  • jframe adding own design jinternal frame error

    - by Van Minh
    I designed a title bar color on my JInternal frame. Then I took attempt to add it to my JFrame, but I cannot. Here is the code of my title bar: public class MyIFtitleBar extends BasicInternalFrameTitlePane { public MyIFtitleBar(JInternalFrame jif) { super(jif); } protected void paintTitleBackground(Graphics g){ g.setColor(Color.pink); g.fillRect(0, 0, getWidth(), getHeight()); } } Here is my JInternal frame. I tried running it in its psvm method, that worked! public class FitnessProg_Frame extends javax.swing.JInternalFrame { public FitnessProg_Frame() { initComponents(); this.setUI(new BasicInternalFrameUI(this){ @Override protected JComponent createNorthPane(JInternalFrame jif) { return new MyIFtitleBar(jif); } }); } @SuppressWarnings("unchecked") private void initComponents() { setBackground(new java.awt.Color(255, 255, 255)); setBorder(new javax.swing.border.MatteBorder(null)); setTitle("Fitness Progarm"); setPreferredSize(new java.awt.Dimension(507, 304)); pack(); } } But when I add it to my JFrame I get an error: Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException Here is my JFrame code: public class NewJFrame extends javax.swing.JFrame { public NewJFrame() { initComponents(); FitnessProg_Frame ff = new FitnessProg_Frame(); ff.setVisible(true); mydes.add(ff); // this line made errors } @SuppressWarnings("unchecked") private void initComponents() { mydes = new javax.swing.JDesktopPane(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); javax.swing.GroupLayout mydesLayout = new javax.swing.GroupLayout(mydes); mydes.setLayout(mydesLayout); mydesLayout.setHorizontalGroup( mydesLayout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGap(0, 400, Short.MAX_VALUE) ); mydesLayout.setVerticalGroup( mydesLayout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGap(0, 300, Short.MAX_VALUE) ); getContentPane().add(mydes, java.awt.BorderLayout.CENTER); pack(); } public static void main(String args[]) { try { for (javax.swing.UIManager.LookAndFeelInfo info : javax.swing.UIManager.getInstalledLookAndFeels()) { if ("Nimbus".equals(info.getName())) { javax.swing.UIManager.setLookAndFeel(info.getClassName()); break; } } } catch (ClassNotFoundException ex) { java.util.logging.Logger.getLogger(NewJFrame.class.getName()).log(java.util.logging.Level.SEVERE, null, ex); } catch (InstantiationException ex) { java.util.logging.Logger.getLogger(NewJFrame.class.getName()).log(java.util.logging.Level.SEVERE, null, ex); } catch (IllegalAccessException ex) { java.util.logging.Logger.getLogger(NewJFrame.class.getName()).log(java.util.logging.Level.SEVERE, null, ex); } catch (javax.swing.UnsupportedLookAndFeelException ex) { java.util.logging.Logger.getLogger(NewJFrame.class.getName()).log(java.util.logging.Level.SEVERE, null, ex); } java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new NewJFrame().setVisible(true); } }); } private javax.swing.JDesktopPane mydes; }

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  • JavaScript regular expression literal persists between function calls

    - by Charles Anderson
    I have this piece of code: function func1(text) { var pattern = /([\s\S]*?)(\<\?(?:attrib |if |else-if |else|end-if|search |for |end-for)[\s\S]*?\?\>)/g; var result; while (result = pattern.exec(text)) { if (some condition) { throw new Error('failed'); } ... } } This works, unless the throw statement is executed. In that case, the next time I call the function, the exec() call starts where it left off, even though I am supplying it with a new value of 'text'. I can fix it by writing var pattern = new RegExp('.....'); instead, but I don't understand why the first version is failing. How is the regular expression persisting between function calls? (This is happening in the latest versions of Firefox and Chrome.) Edit Complete test case: <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <title>Test Page</title> <style type='text/css'> body { font-family: sans-serif; } #log p { margin: 0; padding: 0; } </style> <script type='text/javascript'> function func1(text, count) { var pattern = /(one|two|three|four|five|six|seven|eight)/g; log("func1"); var result; while (result = pattern.exec(text)) { log("result[0] = " + result[0] + ", pattern.index = " + pattern.index); if (--count <= 0) { throw "Error"; } } } function go() { try { func1("one two three four five six seven eight", 3); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } try { func1("one two three four five six seven eight", 99); } catch (e) { } try { func1("one two three four five six seven eight", 2); } catch (e) { } } function log(msg) { var log = document.getElementById('log'); var p = document.createElement('p'); p.innerHTML = msg; log.appendChild(p); } </script> </head> <body><div> <input type='button' id='btnGo' value='Go' onclick='go();'> <hr> <div id='log'></div> </div></body> </html> The regular expression continues with 'four' as of the second call on FF and Chrome, not on IE7 or Opera.

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  • VB.NET 2008, Windows 7 and saving files

    - by James Brauman
    Hello, We have to learn VB.NET for the semester, my experience lies mainly with C# - not that this should make a difference to this particular problem. I've used just about the most simple way to save a file using the .NET framework, but Windows 7 won't let me save the file anywhere (or anywhere that I have found yet). Here is the code I am using to save a text file. Dim dialog As FolderBrowserDialog = New FolderBrowserDialog() Dim saveLocation As String = dialog.SelectedPath ... Build up output string ... Try ' Try to write the file. My.Computer.FileSystem.WriteAllText(saveLocation, output, False) Catch PermissionEx As UnauthorizedAccessException ' We do not have permissions to save in this folder. MessageBox.Show("Do not have permissions to save file to the folder specified. Please try saving somewhere different.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error) Catch Ex As Exception ' Catch any exceptions that occured when trying to write the file. MessageBox.Show("Writing the file was not successful.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error) End Try The problem is that this using this code throws an UnauthorizedAccessException no matter where I try to save the file. I've tried running the .exe file as administrator, and the IDE as administrator. Is this just Windows 7 being overprotective? And if so, what can I do to solve this problem? The requirements state that I be able to save a file! Thanks.

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  • Correct way to close database connection in event of exception.

    - by lowlyintern
    /I have some code of of the following form. Does this mean the connection is left open if there is an exception? Note, I am using a Microsoft SQL compact edition database./ try { SqlCeConnection conn = new SqlCeConnection(ConnectionString); conn.Open(); using (SqlCeCommand cmd = new SqlCeCommand("SELECT stuff FROM SomeTable", conn)) { // do some stuff } conn.Close(); } catch (Exception ex) { ExceptionManager.HandleException(ex); } /*Surely a better way would be to declare a connection object before the try, establish a connection inside the try block and close it in a finally block? */ SqlCeConnection conn = null; try { conn = new SqlCeConnection(ConnectionString); conn.Open(); using (SqlCeCommand cmd = new SqlCeCommand("SELECT stuff FROM SomeTable", conn)) { // do some stuff } } catch (Exception ex) { ExceptionManager.HandleException(ex); } finally { if( conn != null ) conn.Close(); }

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  • Find the closest palindrome number C#

    - by user294837
    Hi All, I am trying to create a console application that reads number from a file all underneath each other like so: 101 9 and then outputs into another file the closest palindrome number. So far what I have is not quite rightm i.e. I don't think I can put the class inside a method which is a bit more Java I was wandering if anyone could help at all? Thanks :) namespace PalidromeC { class Program { static public void Main(string[] args) { #region WriteAnswers try { StreamWriter sw = new StreamWriter("C://Temp/PalindromeAnswers.txt"); sw.WriteLine("Answers"); sw.Close(); }//try catch (Exception e) { Console.WriteLine("Exception: " + e.Message); }//catch #endregion #region ReadFile try { string numbers; StreamReader sr = new StreamReader("C://Temp/Palindrome.txt"); numbers = sr.ReadLine(); while (numbers != null) { Console.WriteLine(numbers); numbers = sr.ReadLine(); }//while sr.Close(); Console.ReadLine(); }//try catch (Exception e) { Console.WriteLine("Exception: " + e.Message); }//catch #endregion NearPalindromeFinder f = new NearPalindromeFinder(); int palindrome = f.findNearPalindrome(n); Console.WriteLine("Nearest Palindrome = " + palindrome); }//main public static void testFindNearestPalindrome(int n) { class NearPalindromeFinder { int findNearPalindrome(int start) { if (testPalindrome(start)) return start; else { int neg = start; int pos = start; for (int i = 0; i < start; i++) { if (testPalindrome(start-i)) { neg = start-i; break; }//if if (testPalindrome(start+i)) { pos = start+i; break; }//if }//for return (start == neg) ? pos : neg; }//else }//findNearPalindrome bool testPalindrome(int start) { if (start == 0 || start == 1) return true; String str = String.valueOf(start); String rev = new if (str.equals(rev)) return true; else return false; }//testPalindrome }//NearPalindromeFinder class }//testFindNearestPalindrome }//Program Class

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  • run shell command from java

    - by Aykut
    Hi, I am working on an application an have an issue about running shell command from java application. here is the code: public String execRuntime(String cmd) { Process proc = null; int inBuffer, errBuffer; int result = 0; StringBuffer outputReport = new StringBuffer(); StringBuffer errorBuffer = new StringBuffer(); try { proc = Runtime.getRuntime().exec(cmd); } catch (IOException e) { return ""; } try { response.status = 1; result = proc.waitFor(); } catch (InterruptedException e) { return ""; } if (proc != null && null != proc.getInputStream()) { InputStream is = proc.getInputStream(); InputStream es = proc.getErrorStream(); OutputStream os = proc.getOutputStream(); try { while ((inBuffer = is.read()) != -1) { outputReport.append((char) inBuffer); } while ((errBuffer = es.read()) != -1) { errorBuffer.append((char) errBuffer); } } catch (IOException e) { return ""; } try { is.close(); is = null; es.close(); es = null; os.close(); os = null; } catch (IOException e) { return ""; } proc.destroy(); proc = null; } if (errorBuffer.length() > 0) { logger .error("could not finish execution because of error(s)."); logger.error("*** Error : " + errorBuffer.toString()); return ""; } return outputReport.toString(); } but when i try to exec command like : /export/home/test/myapp -T "some argument" myapp reads "some argument" as two seperated arguments.but I want to read "some argument" as only a argument. when i directly run this command from terminal, it executed successfully. I tried '"some argument"' ,""some argument"" , "some\ argument" but did not work for me. how can i read this argument as one argument. Thnaks.

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  • xstream handles non-english character

    - by Yan Cheng CHEOK
    I have the following code : /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package helloworld; import com.thoughtworks.xstream.XStream; import java.io.File; import java.io.FileOutputStream; import java.io.InputStream; import java.io.OutputStream; import javax.swing.JOptionPane; /** * * @author yccheok */ public class Test { @SuppressWarnings("unchecked") public static <A> A fromXML(Class c, File file) { XStream xStream = new XStream(); InputStream inputStream = null; try { inputStream = new java.io.FileInputStream(file); Object object = xStream.fromXML(inputStream); if (c.isInstance(object)) { return (A)object; } } catch (Exception exp) { exp.printStackTrace(); } finally { if (inputStream != null) { try { inputStream.close(); inputStream = null; } catch (java.io.IOException exp) { exp.printStackTrace(); return null; } } } return null; } @SuppressWarnings("unchecked") public static <A> A fromXML(Class c, String filePath) { return (A)fromXML(c, new File(filePath)); } public static boolean toXML(Object object, File file) { XStream xStream = new XStream(); OutputStream outputStream = null; try { outputStream = new FileOutputStream(file); xStream.toXML(object, outputStream); } catch (Exception exp) { exp.printStackTrace(); return false; } finally { if (outputStream != null) { try { outputStream.close(); outputStream = null; } catch (java.io.IOException exp) { exp.printStackTrace(); return false; } } } return true; } public static boolean toXML(Object object, String filePath) { return toXML(object, new File(filePath)); } public static void main(String args[]) { String s = "\u6210\u4EA4\u91CF"; // print ??? System.out.println(s); // fine! show ??? JOptionPane.showMessageDialog(null, s); toXML(s, "C:\\A.XML"); String o = fromXML(String.class, "C:\\A.XML"); // show ??? JOptionPane.showMessageDialog(null, o); } } I run the following code through command prompt in Windows Vista. 1) May I know why System.out.println unable to print out Chinese Character in console? 2) I open up the xstream file. The saved value is <string>???</string> How can I make xstream save Chinese Character correctly? Thanks.

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  • How do I run a sudo command in Emacs?

    - by Inaimathi
    I tried using shell-command, but it just does something like this: Sudo password: incorrect, try again. Sudo password: incorrect, try again. Sudo password: incorrect, try again. Failed three attempts. without actually asking for a password. I don't want to have to start up Emacs using sudo emacs, but I guess that's an option if nothing else will work.

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  • What are some good code optimization methods?

    - by esac
    I would like to understand good code optimization methods and methodology. How do I keep from doing premature optimization if I am thinking about performance already. How do I find the bottlenecks in my code? How do I make sure that over time my program does not become any slower? What are some common performance errors to avoid (e.g.; I know it is bad in some languages to return while inside the catch portion of a try{} catch{} block

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  • How do I detect server status in a port scanner java implementation

    - by akz
    I am writing a port scanner in Java and I want to be able to distinct the following 4 use cases: port is open port is open and server banner was read port is closed server is not live I have the following code: InetAddress address = InetAddress.getByName("google.com"); int[] ports = new int[]{21, 22, 23, 80, 443}; for (int i = 0; i < ports.length; i++) { int port = ports[i]; Socket socket = null; try { socket = new Socket(address, port); socket.setSoTimeout(500); System.out.println("port " + port + " open"); BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream())); String line = reader.readLine(); if (line != null) { System.out.println(line); } socket.close(); } catch (SocketTimeoutException ex) { // port was open but nothing was read from input stream ex.printStackTrace(); } catch (ConnectException ex) { // port is closed ex.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (socket != null && !socket.isClosed()) { try { socket.close(); } catch (Exception e) { e.printStackTrace(); } } } } The problem is that I get a ConnectionException both when the port is closed and the server cannot be reached but with a different exception message: java.net.ConnectException: Connection timed out: connect when the connection was never established and java.net.ConnectException: Connection refused: connect when the port was closed so I cannot make the distinction between the two use cases without digging into the actual exception message. Same thing happens when I try a different approach for the socket creation. If I use: socket = new Socket(); socket.setSoTimeout(500); socket.connect(new InetSocketAddress(address, port), 1000); I have the same problem but with the SocketTimeoutException instead. I get a java.net.SocketTimeoutException: Read timed out if port was open but there was no banner to be read and java.net.SocketTimeoutException: connect timed out if server is not live or port is closed. Any ideas? Thanks in advance!

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  • WCF FaultContracts not working for Silverlight Client Proxy

    - by sarwara
    We have a Silverlight application client and a WCF Service hosted as Managed Window Service and exposing Service Contracts on BasicHttpBinding. We are sending FaultContract on the wire in case of exception is caught with the WCF Service Code. We are facing following problem as: A. If we have Synconized proxy call (in case of Window or Web Client), we are able to catch the Fault Contract. B. If we are using Silverlight Client which uses Asyncronized calls, we are unable to catch the Fault Contract. We need help on later problem (B.), Thanks in advance

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  • hi all here is another problem of Ajax , strange but ...

    - by Dumbledore of flash
    when i put ajax on my code I send a group of variable via post but when i received the data it is in a obj.responseText ie TEXT format. say i have two files "form.php" and "index.php" ajax is implemented in form.php while index.php returns the text. but my problem is index.php also generates a variable named "tarriff_count" i want to catch systematically and separately this variable, Is there any systematic way to catch variable.also keep in mind "obj.responseText" is very complicated to get a variable from "preg_match" ?

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  • Java: Multithreading & UDP Socket Programming

    - by Ravi
    I am new to multithreading & socket programming in Java. I would like to know what is the best way to implement 2 threads - one for receiving a socket and one for sending a socket. If what I am trying to do sounds absurd, pls let me know why! The code is largely inspired from Sun's tutorials online.I want to use Multicast sockets so that I can work with a multicast group. class server extends Thread { static protected MulticastSocket socket = null; protected BufferedReader in = null; public InetAddress group; private static class receive implements Runnable { public void run() { try { byte[] buf = new byte[256]; DatagramPacket pkt = new DatagramPacket(buf,buf.length); socket.receive(pkt); String received = new String(pkt.getData(),0,pkt.getLength()); System.out.println("From server@" + received); Thread.sleep(1000); } catch (IOException e) { System.out.println("Error:"+e); } catch (InterruptedException e) { System.out.println("Error:"+e); } } } public server() throws IOException { super("server"); socket = new MulticastSocket(4446); group = InetAddress.getByName("239.231.12.3"); socket.joinGroup(group); } public void run() { while(1>0) { try { byte[] buf = new byte[256]; DatagramPacket pkt = new DatagramPacket(buf,buf.length); //String msg = reader.readLine(); String pid = ManagementFactory.getRuntimeMXBean().getName(); buf = pid.getBytes(); pkt = new DatagramPacket(buf,buf.length,group,4446); socket.send(pkt); Thread t = new Thread(new receive()); t.start(); while(t.isAlive()) { t.join(1000); } sleep(1); } catch (IOException e) { System.out.println("Error:"+e); } catch (InterruptedException e) { System.out.println("Error:"+e); } } //socket.close(); } public static void main(String[] args) throws IOException { new server().start(); //System.out.println("Hello"); } }

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  • SQl Server error handling pattern

    - by Patrick Honorez
    Hi all. I am not an expert on SQl Server. Is this a valid pattern for handling errors in a batch of SELECT, INSERT...in SQl SERVER ? (I use v.2008) BEGIN TRANSACTION BEGIN TRY -- statement 1 -- statement 2 -- statement 3 COMMIT TRANSACTION END TRY BEGIN CATCH ROLLBACK TRANSACTION END CATCH Thanks

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  • Write to text file using ArrayList

    - by Ugochukwutubelum Chiemenam
    The program is basically about reading from a text file, storing the current data into an ArrayList, then writing data (from user input) into the same text file. Kindly let me know where I am going wrong in this sub-part? The data inside the text file is as follows: abc t1 1900 xyz t2 1700 The compiler is showing an error at the line output.format("%s%s%s%n", public class justTesting { private Scanner input; private Formatter output; private ArrayList<Student> tk = new ArrayList<Student>(); public static void main(String[] args) { justTesting app = new justTesting(); app.create(); app.writeToFile(); } public void create() { Text entry = new Text(); Scanner input = new Scanner(System.in); System.out.printf("%s\n", "Please enter your name, ID, and year: "); while (input.hasNext()) { try { entry.setName(input.next()); entry.setTelNumber(input.next()); entry.setDOB(input.next()); for (int i = 0; i < tk.size(); i++) { output.format("%s%s%s%n", tk.get(i).getName(), tk.get(i) .getTelNumber(), tk.get(i).getDOB()); } } catch (FormatterClosedException fce) { System.err.println("Error writing to file."); return; } catch (NoSuchElementException nsee) { System.err.println("Invalid input. Try again: "); input.nextLine(); } System.out.printf("%s\n", "Please enter your name, ID, and year: "); } } public void writeToFile() { try { output = new Formatter("testing.txt"); } catch (SecurityException se) { System.err .println("You do not have write access permission to this file."); System.exit(1); } catch (FileNotFoundException fnfe) { System.err.println("Error opening or creating file."); System.exit(1); } } }

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  • I've caught an exception!! Now what?

    - by Jonesy
    Hi folks, I've started using try catch blocks (bit late i know!) but now im not sure what to do with the exception once i've caught it. What do people usually do here? -- Jonesy Try connection.Open() Dim sqlCmd As New SqlCommand("do some SQL", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) Catch ex As SQLException ' ahhhh what to do now!!!? Finally connection.Close() End Try

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  • How to stop live network traffic displayed in terminal?

    - by Jakobud
    For our network we are working on building a new firewall box and we just installed Smoothwall on it to test it out. When I start up the box, before the login prompt even appears, all of the live IP traffic is appearing in the terminal (source/destination IPs, MACs, Ports, etc). I wait for the boot sequence to finish, but all I see is this IP traffic. The login prompt never comes up. I finally get sick of waiting and press CTRL + C and it says "Entering Run Level 3" and then I get a login prompt finally. Once I login, the IP traffic continues to fly through the terminal even as I'm trying to type commands. How do I turn this stuff off? Is this the default setting for Smoothwall to have all this IP traffic going by on the screen? It essentially renders using the terminal to being useless.

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  • Segmentation fault, shared library

    - by user1306184
    I get Segmentation Fault when I try to run my program. Can someone please help me find out what Im doing wrong? Compiling with this: g++ sms_out.cpp -o sms_out g++ -c -fPIC SMSDispatch.cpp g++ -shared SMSDispatch.o -o libSMSDispatch.so It should be a shared library and dynamic linking. I get Segmentation Fault when I try to run sms_out. //sms_out.cpp #include <iostream> #include<cstdlib> #include<fstream> #include<sstream> #include<string> #include "SMSDispatch.h" using namespace std; string sms = ""; void sendSMS(string sms) { SMSDispatch* sPtr=0; sPtr->sendSMS(sms); } int main(int argc, char *argv[]) { if(argv[1]) { string input = argv[1]; string test = "--author"; if(input == test) { cout << "s149113" << endl; return 0; } } string line = ""; string file = "sms_out.txt"; ifstream myfile(file.c_str()); while(getline(myfile, line)) { string idnr, landcode, number, error; istringstream linestream(line); unsigned short errorcode; //Split the sentence getline(linestream, idnr, '\t'); getline(linestream, landcode, ':'); getline(linestream, number, '\t'); getline(linestream, error); if(idnr == "") break; //Make string to int try { errorcode = atoi(error.c_str() ); } catch (exception &) { } //Put together landcode and tlfnumber string nr = landcode + number; string txt = "Thank you for your vote!"; if(errorcode == 100) txt = "Invalid question, please try again"; else if(errorcode == 110) txt = "Sorry, only one vote pr. number"; else if(errorcode == 200) txt = "Invalid alternative, please try again"; else if(errorcode == 300) txt = "Missing a statement after other, please try again"; else if(errorcode == 999) txt = "An error occurred, please try again"; sms += "{\"ID\":" + idnr + ",\"nr\":" + nr + ",\"txt\":" + "\"" + txt + "\"" + "}\n"; } cout << sms << endl; sendSMS(sms); } //SMSDispatch.h #include <string> #ifndef SMSDISPATCH_H #define SMSDISPATCH_H using namespace std; class SMSDispatch{ public: virtual void sendSMS(string json); }; #endif //SMSDispatch.cpp #include <iostream> #include <fstream> #include "SMSDispatch.h" using namespace std; /*virtual*/void SMSDispatch::sendSMS(string json) { ofstream myfile; myfile.open ("sms_out.log"); myfile << json; myfile.close(); } int main() { }

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  • Exceptions not being caught

    - by Thomas Freudenberg
    We have following code: try { // some code throwing MyException } catch (MyException ex) { // [1] // no (re)throw here } catch (Exception ex) { if (ex is MyException) { // [2] } } If we run the code without a debugger attached, everything runs fine. However, IF we debug the code, we don't get to point [1] but [2]. As far as I understand the language specification this should not be possible. Even weirder, this code used run fine even while debugging. The strange behavior started only a few days ago.

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  • paypal create app giving unknown error

    - by user1241438
    On the developer.paypal.com i login using my ID. When i click on Applications-My App i see the following error We’re sorry, but something went wrong. Please try again. [Error code: LVAPPSGET400-20140608081651] When i click on create apps and try to create an app it gives the following error We’re sorry, but something went wrong while creating the application. Please try again. I could not find how to contact paypal to get this resolved so i thought i come to stackoverflow. please help

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  • SharePoint List Service Recursive not working

    - by stranger001
    Hi, I am using the following code to retrieve the documents in a list. Its working fine. However, it only returns documents and folders in root of the doc library. Is there any thing wrong I am doing here? I am looking for files in sub folders with recursive mode. Service service = new Service(); service.setMaintainSession(true); call = (Call) service.createCall(); call.setTargetEndpointAddress( new java.net.URL("<host>/_vti_bin/lists.asmx") ); call.setOperationName(new QName("http://schemas.microsoft.com/sharepoint/soap/","GetListItems")); call.setProperty(Call.SOAPACTION_USE_PROPERTY, new Boolean("true")); call.setProperty(Call.SOAPACTION_URI_PROPERTY,"http://schemas.microsoft.com/sharepoint/soap/GetListItems"); call.addParameter(new javax.xml.namespace.QName("http://schemas.microsoft.com/sharepoint/soap/", "listName"), new javax.xml.namespace.QName("http://www.w3.org/2001/XMLSchema", "string"), java.lang.String.class, javax.xml.rpc.ParameterMode.IN); MessageElement me = new MessageElement(new QName("QueryOptions")); me.addChildElement(new MessageElement(new QName( "IncludeMandatoryColumns"))).addTextNode("true"); me.addChildElement(new MessageElement(new QName( "ViewAttributes"))).addAttribute(javax.xml.soap.SOAPFactory.newInstance().createName("Scope"), "Recursive"); MessageElement[] me1 = {me}; String strMyString = "" + "<Query>" + "<OrderBy><FieldRef Name=\"ows_Modified\" Ascending=\"TRUE\" /></OrderBy>" + "</Query>"; MessageElement[] meArray = { getMeFromString(strMyString) };// Array call.addParameter("query",org.apache.axis.Constants.XSD_SCHEMA, javax.xml.rpc.ParameterMode.IN); call.addParameter("queryOptions",org.apache.axis.Constants.XSD_SCHEMA, javax.xml.rpc.ParameterMode.IN); call.setReturnType(org.apache.axis.Constants.XSD_SCHEMA); Schema ret = (Schema)call.invoke(new Object[] {"listGUID",meArray, me1 }); public org.apache.axis.message.MessageElement getMeFromString(final String strMyString) { DocumentBuilder docBuilder = null; try { docBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); } catch (final ParserConfigurationException e) { e.printStackTrace(); } catch (final FactoryConfigurationError e) { e.printStackTrace(); } final StringReader reader = new StringReader(strMyString); final InputSource inputsource = new InputSource(reader); Document doc = null; try { doc = docBuilder.parse(inputsource); } catch (final SAXException e) { e.printStackTrace(); } catch (final IOException e) { e.printStackTrace(); } final Element ele = doc.getDocumentElement(); final MessageElement msg = new MessageElement(ele); return msg; }

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