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  • Release Notes for 8/16/2012

    Below are the release notes for today's deployment. Source Tab Improvements Revamped fork navigation to make it more clear that you are within a fork verses the parent project. Infrastructure Updated CodePlex to ASP.Net MVC 4.0. RTM+1 how's that for a turnaround? Bug Fixes Fixed a set of user experience issues with the in-line diff view experience. Fixed issue with date mismatches between UTC and local time for discussions and issue tracker Fixed issue where new issues would not show up in search results. Changed the default destination branch for pull requests to master. Have ideas on how to improve CodePlex? Please visit our suggestions page! Vote for existing ideas or submit a new one. As always you can reach out to the CodePlex team on Twitter @codeplex or reach me directly @mgroves84

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  • Aggro with Images

    - by Will
    I have three UIImageViews. enemy1, enemy1AggroBox and mainSprite. What I want to do is when mainSprite and enemy1AggroBox interect, I want enemy1 to start moving towards mainSprite. Basically creating aggro for a game. if(CGRectIntersectsRect(mainSprite.frame, enemy1AggroBox.frame)){ //Code here// } My plan would be to call this method in viewDidLoad. I'm not using any sort of framework like cocos2d or OpenGLES. If you need to see any more code just ask.

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  • State

    Imagine that you need to develop application for shipping Orders. Your Orders could be in few states: New Order, Registered, Granted, Shipped, Invoiced, Cancelled. And there are some rules which allow your Order to migrate to another state. How to encapsulate states and rules logic? - STATE

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  • WS-Eventing for WCF (Indigo)

    This article describes the design, implementation and usage of the WS-Eventing for distributed applications driven by new MS communication model WCF (Windows Communication Foundation)

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  • Release Notes for 3/8/2012

    Here are the notes for today’s release: Clarified the purpose of the fork name when creating a fork of a project. Added confirmation messages to deletion of system requirements when editing documentation. Deployed several bug fixes: Fixed an issue that was causing AppHarbor build notifications to fail. Thanks to claq2 for the bug report! Fixed several issues where extremely long titles or descriptions on items on the issues, discussions, profiles, and home pages would not wrap properly. Fixed a minor wrapping issue around the link to upload patches. Fixed an issue with viewing RSS feeds in Internet Explorer. Fixed an issue where replying to a discussion with a quote would push the content past the page margins. Have ideas on how to improve CodePlex? Visit our ideas page! Vote for your favorite ideas or submit a new one. Got Twitter? Follow us and keep apprised of the latest releases and service status at @codeplex.

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  • WebService DIME Bridge

    The DIME Bridge transferring a web service response (any serializable object) in the binary format across the Internet. It's a full transparent loosely coupled solution between the web service and its consumer - just injecting the bridge in their config files.

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  • Brute force algorithm implemented for sudoku solver in C [closed]

    - by 0cool
    This is my code that I have written in C.. It could solve certain level of problems but not the harder one.. I could not locate the error in it, Can you please find that.. # include <stdio.h> # include "sudoku.h" extern int sudoku[size][size]; extern int Arr[size][size]; int i, j, n; int BruteForceAlgorithm (void) { int val; for (i=0; i<size; i++) { for (j=0; j<size; j++) { if (sudoku[i][j]==0) { for (n=1; n<nmax; n++) { val = check (i,j,n); if ( val == 1) { sudoku[i][j]=n; // output(); break; } else if ( val == 0 && n == nmax-1 ) get_back(); } } } } } int get_back (void) { int p,q; int flag=0; for ( p=i; p>=0; p-- ) { for (q=j; q>=0; q-- ) { flag=0; if ( Arr[p][q]==0 && !( p==i && q==j) ) { if ( sudoku[p][q]== nmax-1 ) sudoku[p][q]=0; else { n = sudoku[p][q]; sudoku[p][q]=0; i = p; j = q; flag = 1; break; } } } if ( flag == 1) break; } } Code description: Sudoku.h has definitions related to sudoku solver. 1. size = 9 nmax = 10 2. check(i,j,n) returns 1 if a number "n" can be placed at (i,j) or else "0". What does this code do ? The code starts iterating from sudoku[0][0] to the end... if it finds a empty cell ( we take cell having "0" ), it starts checking for n=1 to n=9 which can be put in that.. as soon as a number can be put in that which is checked by check() it assigns it and breaks from loop and starts finding another empty cell. In case for a particular cell if it doesn't find "n" which can be assigned to sudoku cell.. it goes back to the previous empty cell and start iterating from where it stopped and assigns the next value and continues, Here comes the function get_back(). it iterates back..

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