Javascript ( jQuery ) Error: SyntaxError: missing ) after argument list
- by Obmerk Kronen
I have the simplest function :
jQuery(document).ajaxSuccess(function(e, xhr, settings) {
var widget_id_base = '099_cf_samurai_widget';
if(settings.data.search('action=save-widget') != -1 &&
settings.data.search('id_base=' + widget_id_base) != -1) {
// alert(\'yay!'\);
my_function_chosen_099();
}
});
function my_function_chosen_099(){
jQuery(".chzn-select").chosen();
}
which works just fine , but When I add the width Parameter like so :
function my_function_chosen_k99(){
jQuery(".chzn-select").chosen(width:'95%');
}
it gives me an error of:
Error: SyntaxError: missing ) after argument list
Source File: http://localhost/my-path/js/o99.chosen.init.js?ver=k99
Line: 20, Column: 41
Source Code:
jQuery(".chzn-select").chosen(width:"95%");
.............................................|
I have tried escaping:
jQuery(".chzn-select").chosen(width:\"95%"\);
and even double
jQuery(".chzn-select").chosen(width:\\"95%"\\);
and in my desperation, even
jQuery(".chzn-select").chosen(
width:"95%"
);
I checked and rechecked the closing of brackets , and also tried with single quotes ' - but nothing .
There appear to be a lot of similar questions here , but all I saw was escaping problems, ANd I have tried all that I know ..
What is wrong here ?? I assume it is not a simple syntax error - or is it ? ( one which I can not find .. )
