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  • Brute force algorithm implemented for sudoku solver in C [closed]

    - by 0cool
    This is my code that I have written in C.. It could solve certain level of problems but not the harder one.. I could not locate the error in it, Can you please find that.. # include <stdio.h> # include "sudoku.h" extern int sudoku[size][size]; extern int Arr[size][size]; int i, j, n; int BruteForceAlgorithm (void) { int val; for (i=0; i<size; i++) { for (j=0; j<size; j++) { if (sudoku[i][j]==0) { for (n=1; n<nmax; n++) { val = check (i,j,n); if ( val == 1) { sudoku[i][j]=n; // output(); break; } else if ( val == 0 && n == nmax-1 ) get_back(); } } } } } int get_back (void) { int p,q; int flag=0; for ( p=i; p>=0; p-- ) { for (q=j; q>=0; q-- ) { flag=0; if ( Arr[p][q]==0 && !( p==i && q==j) ) { if ( sudoku[p][q]== nmax-1 ) sudoku[p][q]=0; else { n = sudoku[p][q]; sudoku[p][q]=0; i = p; j = q; flag = 1; break; } } } if ( flag == 1) break; } } Code description: Sudoku.h has definitions related to sudoku solver. 1. size = 9 nmax = 10 2. check(i,j,n) returns 1 if a number "n" can be placed at (i,j) or else "0". What does this code do ? The code starts iterating from sudoku[0][0] to the end... if it finds a empty cell ( we take cell having "0" ), it starts checking for n=1 to n=9 which can be put in that.. as soon as a number can be put in that which is checked by check() it assigns it and breaks from loop and starts finding another empty cell. In case for a particular cell if it doesn't find "n" which can be assigned to sudoku cell.. it goes back to the previous empty cell and start iterating from where it stopped and assigns the next value and continues, Here comes the function get_back(). it iterates back..

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  • Web Animations - the next generation

    Web Animations - the next generation The GDL event page for this event: developers.google.com Ask and vote for questions at www.google.com Browser developers are designing the next generation of animation features that will enhance HTML5 with rich, powerful new animation primitives. Designers and web app developers will all benefit from improved methods of animating content. Hear from developers of Google Chrome and Mozilla Firefox how this works, and learn how to try out the new animation features now in your favorite browser. From: GoogleDevelopers Views: 0 3 ratings Time: 30:00 More in Science & Technology

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  • FlyWeight

    You are developing some gaming software. Your write Web client and on each of response you are parsing entire XML to get your game Units. You have some set of types of Units, for example 50 different animals, but when you parse your XML you can get dozens of instances. Memory issue? - FLYWEIGHT will

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  • Release Notes for 8/16/2012

    Below are the release notes for today's deployment. Source Tab Improvements Revamped fork navigation to make it more clear that you are within a fork verses the parent project. Infrastructure Updated CodePlex to ASP.Net MVC 4.0. RTM+1 how's that for a turnaround? Bug Fixes Fixed a set of user experience issues with the in-line diff view experience. Fixed issue with date mismatches between UTC and local time for discussions and issue tracker Fixed issue where new issues would not show up in search results. Changed the default destination branch for pull requests to master. Have ideas on how to improve CodePlex? Please visit our suggestions page! Vote for existing ideas or submit a new one. As always you can reach out to the CodePlex team on Twitter @codeplex or reach me directly @mgroves84

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  • Singleton

    Imagine that you need some global logging system in your application.You need to be able log your messages to some file at any point of your application, but also you need to numerate your messages.How can you accomplish this? - SINGLETON

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  • WebService DIME Bridge

    The DIME Bridge transferring a web service response (any serializable object) in the binary format across the Internet. It's a full transparent loosely coupled solution between the web service and its consumer - just injecting the bridge in their config files.

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  • NullTransport for WCF

    This article describes design, implementation and the usage of the custom in-process transport for Microsoft Windows Communication Foundation (WCF) model.

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  • change texture at runtime

    - by user1509674
    How can I change the texture at runtime. I have done changing the label(text) at runtime. The following code is used using UnityEngine; using System.Collections; public class switchtime : MonoBehaviour { // Use this for initialization private bool showLabel = false; private bool showLabe2 = false; private bool showLabe3 = false; private bool showLabe4 = false; public void Start() { Invoke("ToggleLabel", 1); Invoke("ToggleLabel2", 3); Invoke("ToggleLabel3",6 ); Invoke("ToggleLabel4", 9); } public void ToggleLabel() { showLabel = !showLabel; } public void ToggleLabel2() { showLabe2 = !showLabe2; } public void ToggleLabel3() { showLabe3 = !showLabe3; } public void ToggleLabel4() { showLabe4 = !showLabe4; } public void OnGUI() { if (showLabel) { GUI.Label(new Rect(300, 200, 100, 20), "Copying window file.."); } if (showLabe2) { GUI.Label(new Rect(40, 40, 100, 20), "Epanding windows file.."); } if (showLabe3) { GUI.Label(new Rect(80, 80, 100, 20), "Installing Feature.."); } if (showLabe4) { GUI.Label(new Rect(100, 100, 100, 20), "Installing Updates"); } } } Now I need to change the GUITexture at runtime. How can do this? Can anybody help me in coding? Here is some changes I made. I worked on changing the gameObject when mouse is placed on it. This is the code I applied and its working for me using UnityEngine; using System.Collections; public class change : MonoBehaviour { // Use this for initialization public GameObject newSprite; private Vector3 currentSpritePosition; void update() { } void Start() { newSprite.renderer.enabled = false; currentSpritePosition = transform.position; //then make it invisible renderer.enabled = false; //give the new sprite the position of the latter newSprite.transform.position = currentSpritePosition; //then make it visible newSprite.renderer.enabled = true; } void OnMouseExit(){ //just the reverse process renderer.enabled = true; newSprite.renderer.enabled = false; } } Now the problem is that, in same code I need to set a time so that the text get loaded without the mouse click. I mean a particular time to load each text one after the another. Here is my screen shot Here I have placed the image one below the another,when the mouse is hovered on it it will change the text from bold to normal text.Changes process stated in (image 2,3).That code I posted is working for me.

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  • Release Notes for 3/8/2012

    Here are the notes for today’s release: Clarified the purpose of the fork name when creating a fork of a project. Added confirmation messages to deletion of system requirements when editing documentation. Deployed several bug fixes: Fixed an issue that was causing AppHarbor build notifications to fail. Thanks to claq2 for the bug report! Fixed several issues where extremely long titles or descriptions on items on the issues, discussions, profiles, and home pages would not wrap properly. Fixed a minor wrapping issue around the link to upload patches. Fixed an issue with viewing RSS feeds in Internet Explorer. Fixed an issue where replying to a discussion with a quote would push the content past the page margins. Have ideas on how to improve CodePlex? Visit our ideas page! Vote for your favorite ideas or submit a new one. Got Twitter? Follow us and keep apprised of the latest releases and service status at @codeplex.

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