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  • Translate sequence in macro parameters to separate macros

    - by Alex Tiger
    How to acces each element in macro if the definition is like MACRO(name, seq) and the code is like: MACRO("TheName", (Elem1) (Elem2) (Elem3) ) I want to generate the next code: MACRO("TheName", ELEMMACRO(Elem1) ELEMMACRO(Elem2) ELEMMACRO(Elem3) ) Or something like that. In other words, I want to process every parameter separately (I don't care of definition, even if it will be something like MACRO("TheName", Elem1, Elem2, Elem3 ) There could be more elements, there could be less. I have tried V_ARGS (I need it only for gcc), but I can only copy all the elements by that, not to process them separately. What can I do? P.S. Because of some reasons, I can't use Boost.

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  • Repositioning a label with mouseevents to anywhere on the screen

    - by user2947295
    I've created a label and used setPixmap to attach a .png image to the label. I've also setWindowFlags to disable the title bar and create a frameless window. Because I've disabled those, it also disables the ability to drag anything around, so I want to create mouseevents (unless there's a better method) to position my label anywhere on the screen exactly like dragging the frame of a window. How would I do that? An example and brief explanation would be greatly appreciated.

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  • Strange mod_rewrite problem; Website works partially

    - by Camran
    I have Ubuntu 9.10 Server... I need to get mod_rewrite working... the mod_rewrite module IS LOADED. On my server, the httpd.conf is empty, instead everything (almost) is in a file called apache2.conf. Anyways, I have also read I have to change the AllowOverride None to AllowOverride All in some file... My httpd.conf is empty as you know, but I have a folder called sites-enabled which contains a 000-default file. This is where I have set: AllowOverride All Now my goal as I stated in the last Q is to turn this link: http://mydomain.com/ad.php?ad_id=Bmw_nice_M3_497379462 into this: http://mydomain.com/Bmw_nice_M3_497379462 So as I got an answer in the last Q i inserted this into the htaccess file: Options +FollowSymLinks Options +Indexes RewriteEngine On RewriteCond %{REQUEST_URI} !^/ad\.php RewriteRule ^(.*)$ ad.php?ad_id=$1 [L] Now, this works (no fully) when entering the url manually in the adress bar, but my website isn't working now for some reason. It is like the website is locked down or something, and unless I change AllowOverride to None it will act like that. Any ideas why? Also another note, the links inside the rewritten url doesn't work properly (images are not shown, while some are shown)...

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  • reading root element in xml not the child

    - by Umesha MS
    Hi I am working on an application which reads XML file. Here I am trying to read the node under the not under the node . When I tried to read the I get both. Please help me to solve the problem. Bellow is the sample. "a" "x"..."/X" "b" "name" 123 "/name" "/b" "name" main "/name" "c".."/c" "/a" QDomDocument mDocument; QDomElement mDocumentElement; if (!mDocument.setContent(file.readAll())) { return ; } mDocumentElement = mDocument.documentElement(); QDomNodeList list = mDocumentElement.elementsByTagName("a").at(0).toElement().elementsByTagName("name"); int count = list.count(); for (int i = 0; i < count; i++) { QString str = list.at(i).nodeValue(); QMessageBox::information(this, "text", str, QMessageBox::Yes, 0); }

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  • Page does update with details from the database after i hit a button

    - by swathi
    I have a code and the way it should work is,when they click on NEW CUSTOMER,it takes them to test1.php where in they enter the details and they hit submit.it saves all the details in properly in the database and when i go back and hit REFRESH ,it should come up with the customer details which they had entered in previously. But what happens is, when i click on the REFRESH,it refreshes the same old page which is empty.I wanted to find out where am i missing the logic.Thanks in advance. The sample code would be <tr> <td class="tdvisitbig" colspan="5">THIS IS A TEST</td> </tr> <tr> <td class='tdvisitbig' colspan="5"><input type="button" onClick="openVisit('test1.php?id=<?=$key?>&name=<?=$name?>');return false;" value="NEW CUSTOMER" class="submit">&nbsp;<input type="button" value="REFRESH" name="add_xyz" class="submit" onClick="document.add.target='_self';document.add.action='test3.php?redirect=visit&section=test page';document.add.submit();"></td> </tr> <? $q = "SELECT address,customernum,status FROM customer WHERE name='$name' ORDER BY customernum"; $r = mysql_query( $q , $Link ); while( $rw = mysql_fetch_assoc( $r ) ) { extract( $rw ); ?> <tr> <? } ?>

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  • ajax form handling an array

    - by moata_u
    am trying to handle an array comes from php file after submitting the form data , the value of data after submitting the form is = ARRAY but i cant use this array in any way , any idea how can i handle this array !!!! Javascript : $('#file').live('change',function(){ $('#preview').html(''); $('#preview').html('<img src="loader.gif" />'); $('#data').ajaxForm(function(data){ $(data['toshow']).insertBefore('.pic_content').hide().fadeIn(1000); }).submit(); }); PHP : .... ....etc echo json_encode(array('toshow'=>somedata,'data'=>somedata)); data come from php file {"toshow":"\r\n\t\t\t\t\r\n\t\t<table class=\"out\">\r\n\t\t\t<tr ><td class=\"img\"><a title=\"2012-06-02 01-22-09\" rel=\"prettyPhoto\" href=\"img\/2012-06-02 01-22-09.284.jpg\"><img src=\"img\/thumb\/2012-06-02 01-22-09.284.jpg\"\/><\/a><\/td><\/tr>\r\n\t\t\t\r\n\t\t\t<td>\r\n\t\t\t\t<table cellSpacing=\"1\" cellPadding=\"0\">\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">2012-06-02 01-22-09<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">Download<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><a href=\"img\/2012-06-02 01-22-09.284.jpg\"><span class=\"click\">View<\/span><\/a><\/td><\/tr>\r\n\t\t\t\t<\/table>\r\n\t\t\t<\/td>\r\n\t\t\t<\/tr>\r\n\t\t<\/table>","span":"<span class='text'><img src='greencheck.png'\/>2012-06-02 01-22-09 Uploaded ,File Size =152Kb <\/span>"}

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  • Apache mod_rewrite : How to REWRITE (or whatever) child directories to parent?

    - by ????
    Actually i am trying to make a PHP MVC like application. A basic one. The current milestone i am reaching already includes: Basic RESTful Routing Means, if i type: www.example.com/items/book/8888 .. it properly just stays there as it is and i can already slice out the URL by slashes / and loads the responsible Controllers .... etc from the top single index.php file. I mean, so it is OK for the backend PHP. But the only problem is, it still CAN NOT process the REWRITES properly. For example, the CSS & JS are BROKEN as if i VIEW PAGE SOURCE of the page www.example.com/items/book/8888, the asset files are being called as: www.example.com/items/book/8888/css/main.css www.example.com/items/book/8888/js/jquery.js .. which really are PROBLEMS because in the code is like: <link type="text/css" rel="stylesheet" media="all" href="css/main.css"> <script type="text/javascript" src="js/jquery.js"></script> So the question is: How can i use Apache REWRITE (or whatever approach) to make sure every ASSET FILES to be correctly being called from the DOCROOT. For example, if i am in the URL: www.example.com/items/book/8888 My ASSET FILES should still be called as: www.example.com/css/main.css www.example.com/js/jquery.js Or is there any other methods i need to follow? Please kindly help suggest. Thank you.

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  • Sort the $_POST variables

    - by Jerry
    Hello guys Might be an easy for you guys. I am trying to sort the $_POST variables that were sent by a form and update the sorted result in mysql. I am not sure how to do it and appreciate it anyone can help me about it. My main.php //I have a loop here. (omitted) //$k will be increased by 1 every time the loop starts, so I will know the total times of the loops //the form will be submitted to update.php echo "<input type='hidden' name='pickTotal' value='".$k."' />"; echo "<input type='hidden' id='point' name='earnedPoint".$k."' value='".$point."' />"; echo "<input type='hidden' id='users' name='userName".$k."' value='".$userPick['user']."' />"; //loop ends My update.php if(isset($_POST['submit'])){ $pickTotal=$_POST['pickTotal']; //get the total loop for ($p=0;$p<=$pickTotal;$p++){ $userToBeUpdated=$_POST['userName'.$p]; $userPoint=$_POST['earnedPoint'.$p]; //sort the $userPoint here. //I need to find out who got the most points //and list user's place. 1st, 2nd, 3rd...etc. //update my mysql } Thanks for any helps.

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  • preg_match to find the current directory in a URL

    - by Ian
    I'm trying to detect the current section of a site that a user is viewing by checking for the final directory in the URL. I'm using a PHP and regex to do it and I think I'm close but unfortunately not quite there yet. Here's what I currently have: <?php $url = $_SERVER['REQUEST_URI_PATH'] = preg_replace('/\\?.*/', '', $_SERVER['REQUEST_URI']); $one = '/one/'; $two = '/three/'; $three = '/three/'; $four = '/four/'; $five = '/five/'; echo $url; if (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($one)) == $one) { // URI path starts with "/one/" echo "The section is one."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($two)) == $two) { // URI path starts with "/two/" echo "The section is two."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($three)) == $three) { // URI path starts with "/three/" echo "The section is three."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($four)) == $four) { // URI path starts with "/four/" echo "The section is four."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($five)) == $five) { // URI path starts with "/five/" echo "The section is five."; } ?> I've placed in the echo before the if statements just to get confirmation of the value of $url. This outputs /currentdirectory/file.php However the conditions themselves don't match anything and my individual echo for each section never displays. Also if there's a simpler way of doing it then I'm open to suggestions. Thanks

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  • QFileDialog used as widget

    - by lvp
    Hi! My goal is: user can choose file (only *mp3) and after clicking twice on it it should play (so the QString to file should be send to play() funtion) Firstly I started to work with QTreeView, but it has signal when the file is selected. So I decided to create QFileDialog and used it as widget built-in into MainWindow. The only problem that I have, that after double-click it dissapers. It is possible to avoid it? Should I work with some QDialog::finished() signal or, QDialog::done()?

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  • Overload the behavior of count() when called on certain objects

    - by Tom
    In PHP 5, you can use magic methods, overload some classes, etc. In C++, you can implement functions that exist is STL as long as the argument types are different. Is there a way to do this in PHP? An example of what I'd like to do is this: class a { function a() { $this->list = array("1", "2"); } } $blah = new a(); count($blah); I would like blah to return 2. IE count the values of a specific array in the class. So in C++, the way I would do this might look like this: int count(a varName) { return count(varName->list); } Basically, I am trying to simplify data calls for a large application so I can call do this: count($object); rather than count($object->list); The list is going to be potentially a list of objects so depending on how it's used, it could be really nasty statement if someone has to do it the current way: count($object->list[0]->list[0]->list); So, can I make something similar to this: function count(a $object) { count($object->list); } I know PHP's count accepts a mixed var, so I don't know if I can override an individual type.

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  • Scan HTML for values with a special character before them.

    - by DogPooOnYourShoe
    Say I have values on my page, like #100 #246, What I want to do is scan the page for values with a # before them and then alter them to put a hyperlink on it $MooringNumbers = '#!' . $MooringNumbers . ' | ' . '#!' . $row1["Number"]; } $viewedResult = '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; preg_replace('/#!(\d\d\d)/', '<a href="update.php?id=${1}">${1}</a>', $viewedResult); echo $viewedResult; This is the broken code which doesnt work.

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  • Cannot Display Data from MySQL table

    - by MxmastaMills
    I've got a pretty standard call to a MySQL database and for some reason I can't get the code to work. Here's what I have: $mysqli = mysqli_connect("localhost","username","password"); if (!$mysqli) { die('Could not connect: ' . mysqli_error($mysqli)); } session_start(); $sql = "SELECT * FROM jobs ORDER BY id DESC"; $result = $mysqli->query($sql); $num_rows = mysqli_num_rows($result); Now, first, I know that it is connecting properly because I'm not getting the die method plus I added an else conditional in there previously and it checked out. Then the page displays but I get the errors: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 11 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 12 I've double-checked my database and there is a table called jobs with a row of "id" (it's the primary row). The thing that confuses me is this is code that I literally copied and pasted from another site I built and for some reason the code doesn't work on this one (I obviously copy and pasted it and then just changed the table name and rows accordingly). I saw the error and tried: $num_rows = $mysqli_result->num_rows; $row_array = $mysqli_result->fetch_array; and that fixed the errors but resulted in no data being passed (because obviously $mysqli_result has no value). I don't know why the error is calling for that (is it a difference in version of MySQL or PHP from the other site)? Can someone help me track down the problem? Thanks so much. Sorry if it's something super simple that I'm overlooking, I've been at it for a while.

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  • Infrastructure for high transactional system (language & hosting suggestion help)

    - by RPS
    Some of our friends (University students) are trying to develop a twitter type application, I want to plan for at least 1000 transactions per second (I know it's wishful thinking) for initial launch. This involves several people connecting and getting updates and posting (text + images) to site. In the back end db will server the data and also calculates rankings of what to push to user based on complex algorithm on the fly real-time. Our group is familiar with Java and Tomcat/MySQL. We can also easily learn/code in PHP/MySQL. What is the best suited platform for our purpose ? Though Java seem to be easy to implement for us I am afraid that hosting will be a bit difficult. I could find cloud based php hosting services (like rackspace cloudsites) at reasonable cost. Amazon EC2 is a bit over our heads to manage on day-to-day. Also any recommendation on hosting ? (PHP or Java) We don't have millions in seed money but about $20K to start with. Any advice on above or any thing in general approach is much appreciated.

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  • How can I call these urls in jquery to display content on one page?

    - by Thorbis Website Design
    ok I figured out the jquery part but not the parameters of them all can anyone help figure out the parameters for each url string? this is the jquery I figured out! also would this work better then what the below answer? $.get('adminajax.php', {'action':'getUsers'}, function(data){ $('#users .users').html(data); }); He sent me this in an email: You can specify a page by adding: p=[page #] You can specify a file and it will add a checkbox next to the user which will be checked if the user has permission to download: file=[file location] adminajax.php?action=createDirectory&directory=[new directory location] adminajax.php?action=setAvailability&user=[username]&file=[filelocation]&available=[true or false] I'm trying to get it to display in these html tags: <div id="files"> <b>Files:</b> <ul class="files"></ul> </div> <div id="file_options"> <b>Options:</b> </div> <div id="users"> <b>Users:</b> <ul class="users"></ul> </div>

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  • Storing data from database [mysql_num_rows]

    - by user1717305
    So I have this code to pass items from database to my order table. When I'm echoing the session. The session variable contains something so there's no problem with that. But when I echo those variables under numrows, it only shows nothing. Is there something wrong? <?php error_reporting(E_ALL ^ E_NOTICE); session_start(); require("connect.php"); $UserID = $_SESSION['CustNum']; $UserN = $_SESSION['UserName']; $ProdGTotal = $_SESSION['ProdGTotal']; $queryord = mysql_query("SELECT * FROM customer WHERE UserName = '$UserN'"); $numrows = mysql_num_rows($queryord); if(numrows == 1){ $row = mysql_fetch_assoc($queryord)or die ('Unable to run query:'.mysql_error()); // fetch associated: get function from a query for a database $dbstreet = $row['Street']; $dhousenum = $row['HouseNum']; $dbcnum = $row['CelNum']; $dbarea = $row['Area']; $dbbuilding = $row['Building']; $dbcity = $row['City']; $dbpnum = $row['PhoneNum']; $dbfname = $row['FName']; $dblname = $row['LName']; } else die(mysql_error()); $query4=mysql_query("INSERT INTO orderdetails VALUES ('', '$UserID', Now(), '$dbhousenum', '$dbstreet', '$dbarea', '$dbbuilding', '$dbcity', '$dbfname', '$dblname', '$dbcnum', '$dbpnum', '$ProdGTotal')",$connect); if ($query4){ header("location:index.php"); } else die(mysql_error()); ?>

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  • Connection Reset on MySQL query

    - by sunwukung
    OK, I'm flummoxed.(i've asked this question over on Stack too - but I need to get it fixed so I'm asking here too - any help is GREATLY appreciated) I'm trying to execute a query on a database (locally) and I keep getting a connection reset error. I've been using the method below in a generic DAO class to build a query string and pass to Zend_Db API. public function insert($params) { $loop = false; $keys = $values = ''; foreach($params as $k => $v){ if($loop == true){ $keys .= ','; $values .= ','; } $keys .= $this->db->quoteIdentifier($k); $values .= $this->db->quote($v); $loop = true; } $sql = "INSERT INTO " . $this->table_name . " ($keys) VALUES ($values)"; //formatResult returns an array of info regarding the status and any result sets of the query //I've commented that method call out anyway, so I don't think it's that try { $this->db->query($sql); return $this->formatResult(array( true, 'New record inserted into: '.$this->table_name )); }catch(PDOException $e) { return $this->formatResult($e); } } So far, this has worked fine - the errors have been occurring since we generated new tables to record user input. The insert string looks like this: INSERT INTO tablename(`id`,`title`,`summary`,`description`,`keywords`,`type_id`,`categories`) VALUES ('5539','Sample Title','Sample content',' \'Lorem ipsum dolor sit amet, consectetur adipiscing elit. In et pellentesque mauris. Curabitur hendrerit, leo id ultrices pellentesque, est purus mattis ligula, vitae imperdiet neque ligula bibendum sapien. Curabitur aliquet nisi et odio pharetra tincidunt. Phasellus sed iaculis nisl. Fusce commodo mauris et purus vehicula dictum. Nulla feugiat molestie accumsan. Donec fermentum libero in risus tempus elementum aliquam et magna. Fusce vitae sem metus. Aenean commodo pharetra risus, nec pellentesque augue ullamcorper nec. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Nullam vel elit libero. Vestibulum in turpis nunc.\'','this,is,a,sample,array',1,'category title') Here are the parameters it's getting before assembling the query (var_dump): array 'id' => string '1' (length=4) 'title' => string 'Sample Title' (length=12) 'summary' => string 'Sample content' (length=14) 'description' => string '<p>'Lorem ipsum dolor sit amet, consectetur adipiscing elit. In et pellentesque mauris. Curabitur hendrerit, leo id ultrices pellentesque, est purus mattis ligula, vitae imperdiet neque ligula bibendum sapien. Curabitur aliquet nisi et odio pharetra tincidunt. Phasellus sed iaculis nisl. Fusce commodo mauris et purus vehicula dictum. Nulla feugiat molestie accumsan. Donec fermentum libero in risus tempus elementum aliquam et magna. Fusce vitae sem metus. Aenean commodo pharetra risus, nec pellentesque augue'... (length=677) 'keywords' => string 'this,is,a,sample,array' (length=22) 'type_id' => int 1 'categories' => string 'category title' (length=43) The next port of call was checking the limits on the table, since it seems to insert if the length of "description" is around the 300 mark (it varies between 310 - 330). The field limit is set to VARCHAR(1500) and the validation on this field won't allow anything past bigger than 1200 with HTML, 800 without. The real kicker is that if I take this sql string and execute it via the command line, it works fine - so I can't for the life of me figure out what's wrong. I've tried extending the server parameters i.e. http://stackoverflow.com/questions/1964554/unexpected-connection-reset-a-php-or-an-apache-issue So, in a nutshell, I'm stumped. Any ideas?

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  • Varnish + Nginx + multiple IP addresses

    - by adnan
    This is my first shot at making Varnish work on my dedicated server which hosts 2 domains with 2 separate IP-addresses. My simplified setup is as follows: Nginx conf server { listen ip-address-1:8080; } server { listen ip-address-2:8080; } Varnish vcl backend default { .host = "127.0.0.1"; .port = "80"; } And in the varnish conf I have defined VARNISH_LISTEN_PORT=80 Varnish and Nginx (and php-fpm) are running properly but when I try to go to my website it shows the welcome to nginx page. The headers don't have the x-varnish in it. It seems that for some reason varnish is not listening to port 80. I'm suspecting this has to do with the vcl file where it is listening to the 127.0.0.1 host. I'm running two wordpress sites. Where should I look for to get Varnish working properly? Cheers, Adnan EDIT: Nginx seems to be in 8080 correctly but Varnish is not listening to the right ip address. Using Jens multiple varnish ip addresses netstat -lnp yields: Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 46.105.40.241:8080 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 5.135.166.39:8080 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 0.0.0.0:80 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 127.0.0.1:53 0.0.0.0:* LISTEN 2544/named tcp 0 0 0.0.0.0:21 0.0.0.0:* LISTEN 1195/vsftpd tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN 1184/sshd tcp 0 0 127.0.0.1:953 0.0.0.0:* LISTEN 2544/named tcp 0 0 46.105.40.241:443 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 5.135.166.39:443 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 127.0.0.1:6082 0.0.0.0:* LISTEN 21350/varnishd tcp 0 0 :::80 :::* LISTEN 21351/varnishd tcp 0 0 ::1:53 :::* LISTEN 2544/named tcp 0 0 :::22 :::* LISTEN 1184/sshd tcp 0 0 ::1:953 :::* LISTEN 2544/named udp 0 0 127.0.0.1:53 0.0.0.0:* 2544/named udp 0 0 ::1:53 :::* 2544/named default.vcl backend ikhebeenbril { .host = "5.135.166.39"; .port = "8080"; } backend sunculture { .host = "46.105.40.241"; .port = "8080"; } sub vcl_recv { if (server.ip == "5.135.166.39") { set req.backend = ikhebeenbril; } else { set req.backend = sunculture; } ... } sub vcl_hash { hash_data(server.ip); if (req.http.host) { hash_data(req.http.host); } hash_data(req.url); if (req.http.Accept-Encoding) { hash_data(req.http.Accept-Encoding); } return (hash); } nginx server blocks server { listen 5.135.166.39:80; listen 5.135.166.39:443 default ssl spdy; server_name www.ikhebeenbril.nl; } server { listen 46.105.40.241:80; listen 46.105.40.241:443 default ssl spdy; server_name www.thesunculture.com; }

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  • Apache config that uses two document roots based on whether the requested resource exists in the first

    - by mattalexx
    Background I have a client site that consists of a CakePHP installation and a Magento installation: /web/example.com/ /web/example.com/app/ <== CakePHP /web/example.com/app/webroot/ <== DocumentRoot /web/example.com/app/webroot/store/ <== Magento /web/example.com/config/ <== Site-wide config /web/example.com/vendors/ <== Site-wide libraries The server runs Apache 2.2.3. The problem The whole company has FTP access and got used to clogging up the /web/example.com/, /web/example.com/app/webroot/, and /web/example.com/app/webroot/store/ directories with their own files. Sometimes these files need HTTP access and sometimes they don't. In any case, this mess makes my job harder when it comes to maintaining the site. Code merges, tarring the live code, etc, is very complicated and usually requires a bunch of filters. Abandoned solution At first, I thought I would set up a new subdomain on the same server, move all of their files there, and change their FTP chroot. But that wouldn't work for these reasons: Firstly, I have no idea (and neither do they remember) what marketing materials they've sent out that contain URLs to certain resources they've uploaded to the server, using the main domain, and also using abstract subdomains that use the main virtual host because it has ServerAlias *.example.com. So suddenly having them only use static.example.com isn't feasible. Secondly, The PHP scripts in their projects are potentially very non-portable. I want their files to stay in as similar an environment as they were built as I can. Also, I do not want to debug their code to make it portable. Half-baked solution After some thought, I decided to find a way to section off the actual website files into another directory that they would not touch. The company's uploaded files would stay where they were. This would ensure that I didn't break any of their projects that needed HTTP access. It would look something like this: /web/example.com/ <== A bunch of their files are in here /web/example.com/app/webroot/ <== 1st DocumentRoot; A bunch of their files are in here /web/example.com/app/webroot/store/ <== Some more are in here /web/example.com/site/ <== New dir; Contains only site files /web/example.com/site/app/ <== CakePHP /web/example.com/site/app/webroot/ <== 2nd DocumentRoot /web/example.com/site/app/webroot/store/ <== Magento /web/example.com/site/config/ <== Site-wide config /web/example.com/site/vendors/ <== Site-wide libraries After I made this change, I would not need to pay attention to anything except for the stuff within /web/example.com/site/ and my job would be a lot easier. I would be the only one changing stuff in there. So here's where the Apache magic would happen: I need an HTTP request to http://www.example.com/ to first use /web/example.com/app/webroot/ as the document root. If nothing is found (no miscellaneous uploaded company projects are found), try finding something within /web/example.com/site/app/webroot/. Another thing to keep in mind is, the site might have some problems if the $_SERVER['DOCUMENT_ROOT'] variable reads /web/example.com/app/webroot/ but the actual files are within /web/example.com/site/app/webroot/. It would be better if the DOCUMENT_ROOT environment variable could be /web/example.com/site/app/webroot/ for anything within the /web/example.com/site/app/webroot/ directory. Conclusion Is my half-baked solution possible with Apache 2.2.3? Is there a better way to solve this problem?

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