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  • RDP session re-locks right after login

    - by Jon Bailey
    For some reason, after users do the initial authentication, the system logs in (or unlocks) and locks the screen again within a few seconds (without dropping the RDP session). I've seen this on XP SP3 and Server 2k3. Clients are both major versions of the MS client, and rdesktop. Update: We've seen the issue on a range of machines from 2k3 server (no logon/post logon scripts on servers) to XP SP3. Multiple machines have the same issue - even coming from a fresh and fully patched install.

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  • Are PHP session files ever deleted?

    - by GetFree
    I see there are thousands of files in my "/tmp" directory (a CentOS machine) and almost all of them are PHP session files. I'm worried about the possible impact this might have on my system. Are those files ever deleted either by the OS, Apache or PHP? or I have to take care of it myself?

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  • Force Windows 7 to store thumbnails locally

    - by kotekzot
    I want Windows 7 to store thumbnails cache files in the same folder as the files (thumbs.db) instead of using the centralized location for all thumbnails (By default %userprofile%\AppData\Local\Microsoft\Windows\Explorer). How would one achieve this effect? Alternatively, if the former is implausible, I'd settle for no thumbnail caching at all, forcing Windows to regenerate thumbnails each time a folder is accessed.

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  • Store ESX5 images on a NAS?

    - by Cylindric
    I have a basic NAS device (Buffallo LinkStation Duo) that can only present SMB fileshares to the network. For testing annd for getting a dying physical machine working I would like to store my VMDK on here. Is that possible, or will I have to find some way of presenting this as an iSCSI target of some sort? I've only used iSCSI or local storage in the past, but this isn't possible at the moment. Thanks.

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  • Prevent one user from disconnecting an active remote desktop session

    - by Nick R
    I've got a server where a number of users are sharing user logins for a short period of time to prevent too many people from logging in at the same time. The users are connecting over remote desktop, but the problem is that when one user is busy doing something, another user logs in as the same user and disconnects the active session. Is there any way of preventing one user from logging in and disconnecting the same username who is already connected to somewhere else?

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  • Best practice when using WebMethods and session

    - by Abdel Olakara
    Hi all, I want to reduce postback in one of my application page and use ajax instead. I used the WebMethod to do so.. I have a static WebMethod that needs to access the session variables and modify. and on the client side, i am calling this method using jQuery. I tried accessing the session as follows: [WebMethod] public static void TestWebMethod() { if (HttpContext.Current.Session["pitems"] != null) { log.Debug("Using the existing list"); Product prod = (Product)HttpContext.Current.Session["pitems"]; List<Configs> confs = cart.GetConfigs(); foreach (Configs citem in confis) { log.Info(citem.Description); } } log.Info("Inside the method!"); } The values are displayed correctly and seems to work.. but i would like to know if this practice is allowed as the method is a static methods and would like to know how it will behave if multiple people access the application. I would also like to know how developers do these kind of tasks in ASP if this is not the right method. Thanks in advance for your suggestions and ideas, Abdel Olakara

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  • Best way to store list of numbers and to retrieve them

    - by bingoNumbers
    Hi. What is the best way to store a list of random numbers (like lotto/bingo numbers) and retrieve them? I'd like to store on a Database a number of rows, where each row contains 5-10 numbers ranging from 0 to 90. I will store a big number of those rows. What I'd like to be able is to retrieve the rows that have at least X number in common to a newly generated row. Example: [3,4,33,67,85,99] [55,56,77,89,98,99] [3,4,23,47,85,91] Those are on the DB I will generate this: [1,2,11,45,47,88] and now I want to get the rows that have at least 1 number in common with this one. The easiest (and dumbest?) way is to make 6 select and check for similar results. I thought to store numbers with a large binary string like 000000000000000000000100000000010010110000000000000000000000000 with 99 numbers where each number represent a number from 1 to 99, so if I have 1 at the 44th position, it means that I have 44 on that row. This method is probably shifting the difficult tasks to the Db but it's again not very smart. Any suggestion?

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  • GRID is not properly rendered in ExtJS 4 by using Store

    - by user548543
    Here is the Src code for HTML file <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4 /strict.dtd"> <html> <head> <title>MVC Architecture</title> <link rel="stylesheet" type="text/css" href="/bh/extjs/resources/css/ext-all.css" /> <script type="text/javascript" src="extjs/ext-debug.js"></script> <script type="text/javascript" src="Main.js"></script> </head> <body> </body> </html> File path: /bh/Main.js [Main File] Ext.require('Ext.container.Viewport'); Ext.application({ name: 'App', appFolder: 'app', controllers: ['UserController'], launch: function() { Ext.create('Ext.container.Viewport', { layout: 'border', items: [ { xtype: 'userList' } ] }); } }); File path: /app/controller/UserController.js [Controller] Ext.define('App.controller.UserController',{ extend: 'Ext.app.Controller', stores: ['UserStore'], models:['UserModel'], views:['user.UserList'], init: function() { this.getUserStoreStore().load(); } }); File path: /app/store/UserStore.js Ext.define('App.store.UserStore', { extend: 'Ext.data.Store', model: 'App.model.UserModel', proxy: { type: 'ajax', url: 'app/data/contact.json' } }); File path: /app/model/UserModel.js [Model] Ext.define('App.model.UserModel',{ extends:'Ext.data.Model', fields:[ {name: 'name', type: 'string'}, {name: 'age', type: 'string'}, {name: 'phone', type: 'string'}, {name: 'email', type: 'string'} ] }); File path: /app/view/UserList.js [View] Ext.define('App.view.user.UserList' ,{ extend: 'Ext.grid.Panel', alias:'widget.userList', title:'Contacts', region:'center', resizable:true, initComponent: function() { this.store = 'UserStore'; this.columns = [ {text: 'Name',flex:1,sortable: true,dataIndex: 'name'}, {text: 'Age',flex:1,sortable: true,dataIndex: 'age'}, {text: 'Phone',flex:1,sortable: true,dataIndex: 'phone'}, {text: 'Email',flex:1,sortable: true,dataIndex: 'email'} ]; this.callParent(arguments); } }); In fire bug it shows the JSON response as follows: [{ "name": "Aswini", "age": "32", "phone": "555-555-5555", "email": "[email protected]" }] Why the Data has not been displayed although I have a valid json response. Please help!!!

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  • new Statefull session bean instance without calling lookup

    - by kislo_metal
    Hi! Scenario: I have @Singleton UserFactory (@Stateless could be) , it`s method createSession() generating @Statefull UserSession bean by manual lookup. If I am injecting by DI @EJB - i will get same instance during calling fromFactory() method(as it should be) What I want - is to get new instance of UserSession without preforming lookup. Q1: how could I call new instance of @Statefull session bean? Code: @Singleton @Startup @LocalBean public class UserFactory { @EJB private UserSession session; public UserFactory() { } @Schedule(second = "*/1", minute = "*", hour = "*") public void creatingInstances(){ try { InitialContext ctx = new InitialContext(); UserSession session2 = (UserSession) ctx.lookup("java:global/inferno/lic/UserSession"); System.out.println("in singleton UUID " +session2.getSessionUUID()); } catch (NamingException e) { e.printStackTrace(); } } @Schedule(second = "*/1", minute = "*", hour = "*") public void fromFactory(){ System.out.println("in singleton UUID " +session.getSessionUUID()); } public UserSession creatSession(){ UserSession session2 = null; try { InitialContext ctx = new InitialContext(); session2 = (UserSession) ctx.lookup("java:global/inferno/lic/UserSession"); System.out.println("in singleton UUID " +session2.getSessionUUID()); } catch (NamingException e) { e.printStackTrace(); } return session2; } } As I understand, calling of session.getClass().newInstance(); is not a best idea Q2 : is it true? I am using glassfish v3, ejb 3.1.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • nhibernate : Repository Session Management

    - by frosty
    At the moment my repository has 2 constructors. When i call these from my mvc website i am alway calling first constructor and thus opening a new session. Should i been passing in the session. How should i be doing this. public CompanyRepository() { _session = NHibernateHelper.OpenSession(); } public CompanyRepository(ISession session) { _session = session; } public class NHibernateHelper { private static ISessionFactory _sessionFactory; private static ISessionFactory SessionFactory { get { if (_sessionFactory == null) { var configuration = new Configuration(); configuration.Configure(); configuration.AddAssembly(typeof(UserProfile).Assembly); configuration.SetProperty(NHibernate.Cfg.Environment.ConnectionStringName, System.Environment.MachineName); _sessionFactory = configuration.BuildSessionFactory(); } return _sessionFactory; } } public static ISession OpenSession() { return SessionFactory.OpenSession(); } } I'm using the Ninject IOC container ( very new to me ). I have the following container. How would i bind the ISession to the CompanyRepository. private class EStoreDependencies : NinjectModule { public override void Load() { Bind<ICompanyRepository>().To<CompanyRepository>(); Bind<IUserProfileRepository>().To<UserProfileRepository>(); Bind<IAddressRepository>().To<AddressRepository>(); Bind<IRolesService>().To<AspNetRoleProviderWrapper>(); Bind<IUserService>().To<AspNetMembershipProviderWrapper>(); Bind<ICurrentUserSerivce>().To<DefaultCurrentUserSerivce>(); Bind<IPasswordService>().To<AspNetMembershipProviderWrapper>(); Bind<IStatusResponseRepository>().To<StatusResponseRepository>(); Bind<ICategoryRepository>().To<CategoryRepository>(); Bind<IProductRepository>().To<ProductRepository>(); } }

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  • new Stateful session bean instance without calling lookup

    - by kislo_metal
    Scenario: I have @Singleton UserFactory (@Stateless could be) , its method createSession() generating @Stateful UserSession bean by manual lookup. If I am injecting by DI @EJB - i will get same instance during calling fromFactory() method(as it should be) What I want - is to get new instance of UserSession without preforming lookup. Q1: how could I call new instance of @Stateful session bean? Code: @Singleton @Startup @LocalBean public class UserFactory { @EJB private UserSession session; public UserFactory() { } @Schedule(second = "*/1", minute = "*", hour = "*") public void creatingInstances(){ try { InitialContext ctx = new InitialContext(); UserSession session2 = (UserSession) ctx.lookup("java:global/inferno/lic/UserSession"); System.out.println("in singleton UUID " +session2.getSessionUUID()); } catch (NamingException e) { e.printStackTrace(); } } @Schedule(second = "*/1", minute = "*", hour = "*") public void fromFactory(){ System.out.println("in singleton UUID " +session.getSessionUUID()); } public UserSession creatSession(){ UserSession session2 = null; try { InitialContext ctx = new InitialContext(); session2 = (UserSession) ctx.lookup("java:global/inferno/lic/UserSession"); System.out.println("in singleton UUID " +session2.getSessionUUID()); } catch (NamingException e) { e.printStackTrace(); } return session2; } } As I understand, calling of session.getClass().newInstance(); is not a best idea Q2 : is it true? I am using glassfish v3, ejb 3.1.

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  • How to extract byte-array from one xml and store it in another in Java

    - by grobartn
    So I am using DocumentBuilderFactory and DocumentBuilder to parse an xml. So it is DOM parser. But what I am trying to do is extract byte-array data (its an image encoded in base64) Store it in one object and later in code write it out to another xml encoded in base64. What is the best way to store this in btw. Store it as string? or as ByteArray? How can I extract byte array data in best way and write it out. I am not experienced with this so wanted to get opinion from the group. UPDATE: I am given XML I do not have control of incoming XML that comes in binary64 encoded < byte-array > ... base64 encoded image ... < /byte-array > Using parser I have I need to store this node and question is should that be byte or string and then writing it out to another node in new xml. again in base64 encoding. thanks

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  • Best practice how to store HTML in a database column

    - by tbrandao
    I have an application that modifies a table dynamically, think spreadsheet), then upon saving the form (which the table is part of) ,I store that changed table (with user modifications) in a database column named html_Spreadhseet,along with the rest of the form data. right now I'm just storing the html in a plain text format with basic escaping of characters... I'm aware that this could be stored as a separate file, the source table (html_workseeet) already is. But from a data handling perspective its easier to save the changed html table to and from a column so as to avoid having to come up with a file management strategy (which folder will this live in, now must include folder in backups, security issues now need to apply to files, how to sync db security with file system etc.), so to minimize these issues I'm only storing the ... part in the database column. My question is should I gzip the HTML , maybe use JSON, or some other format to easily store and retrieve the HTML from the database column, what is the best practice to store HTML content in a datbase? Or just store it as I currently am as an escaped text column?

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  • How can I find the jdbc connection timeout of a hibernate session

    - by StevenWilkins
    I currently have a long running thread which uses a hibernate session to perform many updates. We currently have our c3p0 connection timeout set to 20 minutes and it's timing out sometimes because of the number of updates we're performing. The solution I have is to periodically return the connection to the pool via closing the session (we have hibernate configured this way) and get a new one. Upping the timeout is not desirable because the same pool is used for the entire application. The problem is I don't know when to return the connection to the pool because I don't know what the timeout of the connection is. I know what the current setting is in our property file, but that can be changed without my knowledge at any time so it's fragile. Having a counter and returning the connection based on the number of updates I've performed is not ideal but could be my option of last resort. I have a hibernate session, how can I retrieve the connection timeout of the jdbc connection which backs the session? Using the SessionFactory and SessionFactoryImpl classes are perfectly acceptable.

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  • Array to Array pushing in Zend Session object

    - by kate-koopy
    Hello! I have some example of pushing array to array in session object: class someClass extends someOtherOne { ...////// some other code here that starts session and creates namespace public function __add2Session($a,$b) { $namespc = $this -> __getnewNameSpace(); //returns a Zend Session Namesapce (object) if (!isset($namespc -> {$a})) { $namespc -> {$a} = array(); } array_push($namespc -> {$a}, $b); } } ...///////////// $item=array(1=>"one",2=>"two",3=>"three",4=>"four",5=>"five",6=>"six",7=>"seven"); $k = new someClass(); $cart = new Zend_Session_Namespace('Cart'); $k -> __add2Session("items",$item); The result is when I reload the page several times - the value of $cart -> items in the session gets overwritten and not populated. Can somebody explain why it occurs and how do I fix this? I want to have $cart -> items to be an "array in array" like: $cart -> items = array(array(1=>"one",2=>"two"), array(1=>"two",2=>"three"));

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  • Store multiple values in a session variable

    - by user458790
    Hi, Before I ask my doubt, please consider this scenario that a user on my website have a profileID. With this profileID are associated some pluginID's. For eg: User1 might have 2, 3 and 5 plugins associated with its profile. When the user logs in, I store the profileID of the user in a session variable cod. At a certain page, the user tries to edit the plugins associated with his profile. So, on that page, I have retrieve those pluginID's from the DB. I have applied this code but this fetches only the maximum pluginID from the DB and not all the pluginID's. SqlCommand cmd1 = new SqlCommand("select plugin_id from profiles_plugins where id=(select id from profiles_plugins where profile_id=" + Convert.ToInt32(Session["cod"]) + ")", con); SqlDataReader dr1 = cmd1.ExecuteReader(); if (dr1.HasRows) { while (dr1.Read()) { Session["edp1"] = Convert.ToInt32(dr1[0]); } } dr1.Close(); cmd1.Dispose(); I was trying to figure out how can I store multiple pluginID's in this session variable? Thanks

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