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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • php web based portal authentication through IP.

    - by user434885
    i have a web portal running which involves basic data entry. The issue being that this is highly sensitive data. And the credibility of the data entry personel is very low. Therefore i have implemented recording of IP when an entry is made. The Problem i am facing is if this if this person starts forwarding his IP from a proxy server then i am unable to track authenticity of the data. How do i detect if the IP forwarding is happening/ get the real ip address of the person.

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  • PHP foreach help

    - by sea_1987
    Hello I have an array that looks like this, Array ( [cfi_title] => Mr [cfi_firstname] => Firstname [cfi_surname] => Lastname [cfi_email] => [email protected] [cfi_subscribe_promotional] => [cfi_tnc] => [friendsName] => Array ( [0] => Firstname 1 [1] => Firstname 2 [2] => Firstname 3 ) [friendsEmail] => Array ( [0] => [email protected] [1] => [email protected] [2] => [email protected] ) [submit_form] => Submit ) My dilema is I need to save the values from the friendsName and friendsEmail arrays into a database, I know I can loop through them but how can I send the matching data, for example I need to save [friendsName][0] and friendsEmail][0] on the same row of database? I know I need to use a foreach but I just cannot figure out the logic.

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  • PHP: Auto Updating subscriptions?

    - by Duncan Palmer
    Hey guys I am currently making a website and I am hopefully going to start a premium service for it. What I am currently looking into right now is how to make an "auto updating" shop which removes 1 day from how many days left the user has left on their premium status. so for example if the users purchases 30 days of premium, each day that 30 with negate 1 so.. 30, 29, 28, 27.. etc and then if the days gets to 0 in will remove premium status. The only way I can think of keeping track of this right now is by manually monitoring each persons premium status but that wouldnt be very practical. What would the best way for me to do this? (hopefully "automatically") Thanks.

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • How to outsource pieces of a web project

    - by Luke101
    I would like to outsource pieces of a new web application/site. I don't want one company working on the whole project because they can easily change a few things and sell the software to someone else. I will be using a freelenace website like elance or guru. A buddy of mine has given me this advice but he did not say how this can be done. Any ideas on how to go about this?

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  • mvc DataAnnotations how to make field no editable in 3.5

    - by frosty
    I have a few field in my entity that i wish to be non-editable. Looking in the docs it seems like "EditableAttribute" would do the trick. However this is only 4.0 Just wondering if there are other attributes that would have the desire effect. So be clear, i have a field called "DateRegistered" i wish to display this as string not text field using "Html.EditorFor"

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • [PHP] How to unset object's inherited properties ?

    - by vbklv
    I have an Object ( [id] => 1 [parent_id] => 0 [result:Database:private] => [db:Database:private] => mysqli Object ( [affected_rows] => 0 ... ) ) Obviously, the Object has inherited the 'db' and 'result' properties of the parent Database class. unset($object-result) nor unset($object-result:Database) nor unset($object-result:Database:private) work. How could I unset those properties when they are no longer needed (i.e. when the object properties are about to be output)? Is it a generally a good idea to have a database object as an inherited property of other classes (extend one Database class with all other classes that use database connections)?

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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • How to assign variable dynamically to php list function

    - by ravisoni
    What I am doing that I want to generate a list based on how many items are in an array, so I have counted the items and loop over them, create a number based var and construct a string $var which contains $a1,$a2.... and assigns the $var to list list($var) and tried to access $a1 but it gives me the error "Undefined variable: a1" Is there any other way to do it? Here is my code: $arr = array('1','2','3'); $listsize = count($arr); $var=''; for($i=1;$i<=$listsize;$i++){ $var.='$a'.$i; if($i!=$listsize){ $var.=','; } } list($var) = $arr; echo $a1;

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  • PHP Multiple form tokens

    - by Juddling
    I understand the idea of generating a form token and storing it in a session, and also putting it as a hidden input in my forms. But how could I make this work if I have pages with multiple forms, is it still safe to use the same token for each form? And I still feel weary about bots and stuff on my website, can these form tokens really safely replace CAPTCHAs?

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  • PHP preg_match image between html tags

    - by Alvins
    I've got an html template like this: <div class="cont"> <div class="..."> <p>...<p> <img alt="" class="popup" src="DESIRED IMAGE LINK" style="..." /></p><p>...</p> .... And i want to extract "DESIRED IMAGE LINK" inside the "" tag, currently i'm using this: $pattern = '<div class="cont">.*?src=["\']?([^"\']?.*?(png|jpg|jpeg|gif))["\']?/i'; if (preg_match($pattern, $content, $image)) ..... But it doesn't work, the error is: warning: preg_match() [function.preg-match]: Unknown modifier '.' How can i fix it? Thanks

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  • Saving PHP Table as CSV

    - by user2403705
    I have been looking everywhere for a way to do this. There are a lot of people that have asked the questions but when I try myself i cant seem to get it to work. Often I get the format correct but it inputs the information into a new page instead of saving it. I did manage to get one to work for google chrome but when i ran it in internet explorer it didnt work. I have a table being created from a MYSQL query and i would like the table to be able to be saved as a CSV. Could anyone help me out?

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  • PHP line break with file_put_contents()

    - by steve-o
    I can't seem to figure out why the following code doesn't produce a new line in my text file - neither does using \n etc either - any ideas what could be wrong? $data = $name . ' | ' . $_POST['comment'] . PHP_EOL; //write to file $f = file_put_contents('posts.txt', $data, FILE_APPEND);

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  • Select item in CascadingDropDown via JavaScript & invoke update

    - by akosch
    In code-behind I can do this to select something: // Select item in first DropDownList myCascadingDropDown_1.SelectedValue = itemValue_1+":::"+itemText_1; // Select item in second DropDownList myCascadingDropDown_2.SelectedValue = itemValue_2+":::"+itemText_2; How can I do this in JavaScript? (I'm aware, that I could search the list and set the selectedIndex property for each dropdown, but I have many items and i'm very lazy.) EDIT: npups answer works: I can select my desired item in the first dropdownlist. The problem is however, that new values based on that selected item (it is a CascadingDropDown, remember?) don't show in the second dropdown so I can't select anything there. I would need to somehow invoke the update method of the second dropdown manually: any suggestions?

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • MySQL/PHP Search Efficiency

    - by iMaster
    Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

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  • PHP using count() with array

    - by seb
    Hi there, Im trying to get the amount of elements in an array using the count() function, the result is a bit puzzling to me, considere the following example. Assume that the user ID provided is wrong, and therefore had no matches, wouldnt then the result of the count function be 0? yet it is 1. can you explain to me why? thanks $q = mysql_query("select password from users where user_name = '" . $userID . "'"); $check = mysql_fetch_array($q); $result = count($check); echo "RESULT:" . $result;

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  • Pass variable number of variables to a class in PHP

    - by user325282
    I need to pass a variable number of strings to instantiate different classes. I can always do a switch on the size of the array: switch(count($a)) { case 1: new Class(${$a[0]}); break; case 2: new Class(${$a[0]}, ${$a[1]}); break; etc... There has to be a better way to do this. If I have an array of strings ("variable1", "variable2", 'variable3", ...), how can I instantiate a Class without manually accounting for every possibility?

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  • PHP array minor problem

    - by Sennheiser
    I'm really not sure how to explain this. It's so simple I can't fathom why it's not working. I have a loop. It puts a bunch of strings into an array. If I fill a single variable with any given string, it will output it perfectly. But filling an array with the strings will make it give me the dreaded: Array Array Array Array Array Array Array Array Note: my strings are not all 'Array'. The way I loop is: while(...) { $arr[] = $resultFromLoop; } Here is my var_dump. array(1) { ["tagName"]=> string(5) "magic" } array(1) { ["tagName"]=> string(4) "nunu" } array(1) { ["tagName"]=> string(5) "books" } array(1) { ["tagName"]=> string(0) "" } array(1) { ["tagName"]=> string(3) "zzz" } array(1) { ["tagName"]=> string(4) "grey" } array(1) { ["tagName"]=> string(3) "new" } array(1) { ["tagName"]=> string(6) "flight" }

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