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  • woocommerce show attribute description when selecting a variable

    - by user2916995
    I'm trying to figure out a way to display custom text based on the users selection of the variable product. The attribute is 'pricing' and the tag is deposit - which I've added a text description to when adding the attribute. So I'm trying to make this text appear when the user selects 'deposit' But the code I'm using in 'content-single-product.php' is displaying the text all the time no matter what variable is selected or not. <?php $my_taxonomy = 'pa_pricing'; $terms = wp_get_post_terms( $post->ID, $my_taxonomy ); echo term_description($terms[0]->term_id, $my_taxonomy); ?> I only want the text to be displayed after the user has selected pricing 'deposit' Can someone help me with this?

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  • Beginner's Question about accessing mysql using OOP

    - by user345690
    I am reading the PHP and mySQL web development book and so far been doing all the PHP and mysql using procedural. But then it talks about accessing mysql with objects. This works for me: //I define $db so can connect $query="select * FROM testing"; $result=mysqli_query($db,$query); while($row=mysqli_fetch_array($result)){ //echo the data } But when I try to do it with classes, it doesn't $query="select * FROM testing"; $result=$db->query($query); $row=$result->fetch_assoc(); Do I have to write my own class so it defines what query and fetch_assoc does? Or what?

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  • weird problem..the exact xml work in one host and not working in another...

    - by Ofear
    hi all! i search alot for this but can't find an aswer... I have made a working xml parser using php. till today i host my files on a free web host, and everything works just fine. today i got access to my college server and i host my files there. now for some reason.. i can't make the parser work as i was in the free host... look on those files please: working site: xml file: [http://ofear.onlinewebshop.net/asce/calendar.xml] working parser is this: [http://ofear.onlinewebshop.net/asce/calendar.php] (the lower table is the xml,it's hebrew) not working site: xml file: [http://apps.sce.ac.il/agoda/calendar.xml] not working parser is this: [http://apps.sce.ac.il/agoda/calendar.php] anyone have idea why it's not working.. those are the same files and they should work. maybe it a server problem? calendar.xml: <?xml version="1.0" encoding="UTF-8" ?> <events> <record> <event>??? ???? ????? ???? ???</event> <eventDate>30/12/2010</eventDate> <desc>?????? ?? ????</desc> </record> <record> <event>??? ???? ??????? - 2 : ???? ??? ???? ??????</event> <eventDate>22/12/2010</eventDate> <desc>????? ???? ??????? ?????? ??? ???? ??????? ?????? ????? ?????? ?? ??? ???? ??????? 2 ??????? ????? ???????? 22-23 ?????? 2010. ???? ????? ???? ????? "?????? ????"</desc> </record> <record> <event>????? ???? ?????? ?????? - ?? ????</event> <eventDate>5/12/2010</eventDate> <desc>??? ????? 17:30-20:45</desc> </record> </events> parser: <?php $doc = new DOMDocument(); $doc->load( 'calendar.xml' ); $events = $doc->getElementsByTagName( "record" ); foreach( $events as $record ) { $events = $record->getElementsByTagName( "event" ); $event = $events->item(0)->nodeValue; $eventDates= $record->getElementsByTagName( "eventDate" ); $eventDate= $eventDates->item(0)->nodeValue; $descs = $record->getElementsByTagName( "desc" ); $desc = $descs->item(0)->nodeValue; echo "<tr><td>$event</td><td>$eventDate</td><td>$desc</td></tr>"; } ?> after a little debugging i saw that it's stop here: $doc = new DOMDocument(); and it's not doing anything after that. i think that the line above is the cos

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  • Warning: session_start(): Cannot send session cache limiter - headers already sent

    - by shyam
    I am receiving this warning in a page while I try starting the session. <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <title>Video</title> </head> -this is the part of the code. There are no characters (not even space) before the first line. This page is reached after logging in from another page, through redirection. Any help? (PHP version is 5.2)

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  • Export XML with only one MySQL request ?

    - by mere-teresa
    I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • User's Post count from specific category [Wordpress]

    - by morningglory
    Hello, I want to show user's post count from specific category. Currently, I can only be able to query all posts. My code is like this <?php $userpost_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->posts WHERE post_status = 'publish' AND post_type ='post' AND post_author = '".$curauth->ID."'");?> <?php echo "<span>Total post: </b></span>".$userpost_count.""?> I know that, I need to join two table which is post table and term_relationships, but i don't know how to get it. Please kindly help me with that. Thank you.

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  • 'An error occurred. Please try later' message on Facebook authentication dialog

    - by Eugene Zhuang
    I am a newbie who is trying to create a Facebook app using PHP and Facebook's PHP SDK. The app is hosted on Heroku, and the sample app that they provided is working fine. However, I am now trying to get the sample app to work on Apache 2.2, and I have encountered a lot of problems along the way. Well, straight to the point, my latest problem will be trying to do Facebook login on localhost, but the 'An error occurred. Please try later' appears on the popup dialog. This does not happen on Heroku. Will someone please enlighten me on if there's any steps that I can take to overcome this error? I don't think it got to do with any coding error since I am just following the provided sample app. Thanks!

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  • Seeking assistance with Escaping Data for MySQL queries

    - by JM4
    Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

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  • Upload files, form within form

    - by Alexd2
    Hello everyone and thanks in advance. I have a problem and I have 2 form into one another, the domestic form is to perform a file upload. As I can do to make when sending in internal form not run the main form. <form name="x" method="post" action="xxx.php"> .... <form action="" method="post" enctype="multipart/form-data" target="xxx"> <input type="file" /> <input type="submit" /> </form> <iframe id="xxx" src="process.php"> </iframe> .... <input type="submit" name="pro" value="Register user"/ > </form> Doing this does not work, as this within another form. Any help or possible solution.

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  • How to access constant defined in child class?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

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  • Placing .htaccess file in var/www folder messes my website up...

    - by Camran
    I am playing with mod_rewrite now, and have successfully enabled it. However, I need to put a htaccess file inside var/www/ in order to achieve what I want, which is to rename Urls simply... When I place it my website becomes very strange and nothing basically works... Is there any code I need to put into the htaccess file in order for things to act normally? Here is the htaccess file I have so far: Options +FollowSymLinks Options +Indexes RewriteEngine On RewriteCond %{REQUEST_URI} !^/ad\.php RewriteRule ^(.*)$ ad.php?ad_id=$1 [L] My DocumentRoot is also set to var/www/ and my entire website root is there... (index.html etc etc)... What am I missing about the htaccess? If you need more input let me know...

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  • Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

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  • Keeping some files private

    - by user490895
    Hi, I was trying to create a directory of private files that could only be accessed when a user logs in. To do this, I used a folder outside the web directory, and then php to access it, if allowed. Here's an example: function display_movie($file){ printf("<video id='movie' width='960' height='416' controls='controls' onerror='fix()'> <source src='movie.php?file=%s' type='video/ogg; codecs=\"theora, vorbis\"'> </video>", rawurlencode($file)); } This works great for images, but breaks the media player. Also, I've only tested this locally on a Linux machine. Any ideas? Thanks.

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  • Add a custom class name to Wordpress body tag?

    - by Scott B
    I'd like to place a directive in my theme's functions.php file which appends a classname to the wordpress body tag. Is there a built-in API method for this? For example, my body tag code is... <body <?php if(function_exists("body_class") && !is_404()){body_class();} else echo 'class="page default"'?>> And it results in the following being written to the body tag (depending on the context in which the page is presented (page, post, logged-in, etc) <body class="home blog logged-in"> Depending on the child theme I'm using at the time, I want it to be... <body class="home blog logged-in mychildthemename">

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  • Create a picture with GD containing other images

    - by Jensen
    Hi, I would like to create a picture in PHP with GD composed by different other pictures. For example I have 6 pictures (or more) and I would like to create ONE picture who contain these different pictures. The Difficulty is that my final picture must have a fixed width and height (304x179), so if the different pictures are too big they must be cut. This is an example from IconFinder : This picture is composed by 6 images, but the 3rd bird (green) is cutted, and the 4, 5 and 6 are cutted in the bottom. This is what I want, can you give me some help to write this code in PHP ? Thanks

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  • How to know if the website being scraped has changed?

    - by Lost_in_code
    I'm using PHP to scrape a website and collect some data. It's all done without using regex. I'm using php's explode() method to find particular HTML tags instead. It is possible that if the structure of the website changes (CSS, HTML), then wrong data may be collected by the scraper. So the question is - how do I know if the HTML structure has changed? How to identify this before storing any data to my database to avoid wrong data being stored.

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  • How to handle un-assigned records

    - by Mico
    I have this PHP page where the user can select and un-select items. The interface looks like this: Now I'm using these code, when the user hit the save changes button: foreach( $value as $al_id ){ //al_id is actually location id //check if a record exists //if location were assigned and leave it as is $assigned_count = $this->AssignedLoc->checkIfAssigned( $tab_user_id, $al_id ); if( $assigned_count == 0 ){ //else if not, insert this new record $this->insertAssigned( $tab_user_id, $company_id, $al_id ); } } Now my question is, how do I delete the un assigned locations? For example in the screenshot above, there are 4 assigned locations, if I'm gonna remove (or unassign) "Mercury Morong" and "GP Hagonoy" from the assigned locations, only two must remain. What are the possible solutions using PHP? Thanks for any help!

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  • Error in header function

    - by user1178695
    I'm using the php header function for the redirection but it is not working.I'm using the following code. $sql=mysql_query("select * from password where username='$email' and password1 = '$pwd'"); //echo "selct * from password where username='$email' and password = '$pwd'"; $row=mysql_fetch_row($sql); $fieldset=mysql_num_rows($sql); $host=$_SERVER['HTTP_HOST']."/beta/"; if($fieldset>0 && $conEmail !="") { $_SESSION['email']=$email; $_SESSION['Email']=$email; $_SESSION['memberID']=$id; $_SESSION['status']='Admin'; header("location:http://".$host."member.php"); }

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  • which one consume less resources? opening text file or make an sql query,both a thousand times ?

    - by imin
    hi I've a php website which displays recipes www.trymasak.my, to be exact. The recipes being displayed at the index page is updated about once a day. To get the latest recipes, I just use a mysql query which is something like "select recipe_name, page_views, image from table order by last_updated". So if I got 10000 visitors a day, obviously the query would be made 10000 times a day. A friend told me a better way (in terms of reducing server load) is when I update the recipes, I just put in the latest recipe details (names,images etc) into a text file, and make my page instead of querying a same query for 10,000 times, just get the data from the text file. Is his suggestion really better? If yes, which is the best php command should I use to open, read and close the text file? thanks

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  • Apache crashes after installing mysqli

    - by Marco P.
    System: Apache 2.2 running on Windows 2008 Server with PHP 5.2.17 VC6 Thread-Safe as a Module and MySQL 5.5.17 - all working fine. After installing mysqli using the php package, Apache won't start anymore. There is no error message in the log. What I have tried: Make sure Windows PATH points to libmysql.dll: Yes, done. Make sure extension_dir points to the right point: Yes. Other extensions load fine. Try without mysqli: Yes, Apache loads fine then. Try without mysql: Yes, does not help. Test mysql itself: Restarts server! Overwrite libmysql: Yes, does not help. It seems to me that there is some general problem with MySql, but the DB server seems to be running fine. I'm really out of ideas of things I could try, so I'm desperate for any hints or tricks.

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  • Is there any way to use imagegrabwindow() with Firefox or Chrome?

    - by patternsofchaos
    I'm trying to generate website thumbnails programatically in PHP. To do this, I'm using imagegrabwindow() with a COM object: $browser = new COM("InternetExplorer.Application"); $handle = $browser->HWND; $browser->Visible = true; $browser->Navigate($pre.$URL); while ($browser->Busy) { com_message_pump(4000); } $img = imagegrabwindow($handle); What I'm wondering is if there is any way to do the same thing with Firefox or Chrome? Can I invoke either of them with PHP COM?

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  • How can I store and access SQLite databases from a central location?

    - by Brian Ramsay
    I have installed SQLite on my UNIX system, and am planning on accessing it from PHP. However, the database is created in the directory I initialize it in, and if a script runs in a different directory a new database is created in the same directory. Is there an option for SQLite (or the PHP wrappers) to create the databases in one location, and have those databases accessible just by name outside of that directory? Ideally, I'd like to be able to do something like $db=new SQLiteDatabase("db.test"); in any directory and have it reference the same database, if that makes sense.

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