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  • How to properly test Hibernate length restriction?

    - by Cesar
    I have a POJO mapped with Hibernate for persistence. In my mapping I specify the following: <class name="ExpertiseArea"> <id name="id" type="string"> <generator class="assigned" /> </id> <version name="version" column="VERSION" unsaved-value="null" /> <property name="name" type="string" unique="true" not-null="true" length="100" /> ... </class> And I want to test that if I set a name longer than 100 characters, the change won't be persisted. I have a DAO where I save the entity with the following code: public T makePersistent(T entity){ transaction = getSession().beginTransaction(); transaction.begin(); try{ getSession().saveOrUpdate(entity); transaction.commit(); }catch(HibernateException e){ logger.debug(e.getMessage()); transaction.rollback(); } return entity; } Actually the code above is from a GenericDAO which all my DAOs inherit from. Then I created the following test: public void testNameLengthMustBe100orLess(){ ExpertiseArea ea = new ExpertiseArea( "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890"); assertTrue("Name should be 100 characters long", ea.getName().length() == 100); ead.makePersistent(ea); List<ExpertiseArea> result = ead.findAll(); assertEquals("Size must be 1", result.size(),1); ea.setName(ea.getName()+"1234567890"); ead.makePersistent(ea); ExpertiseArea retrieved = ead.findById(ea.getId(), false); assertTrue("Both objects should be equal", retrieved.equals(ea)); assertTrue("Name should be 100 characters long", (retrieved.getName().length() == 100)); } The object is persisted ok. Then I set a name longer than 100 characters and try to save the changes, which fails: 14:12:14,608 INFO StringType:162 - could not bind value '12345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890' to parameter: 2; data exception: string data, right truncation 14:12:14,611 WARN JDBCExceptionReporter:100 - SQL Error: -3401, SQLState: 22001 14:12:14,611 ERROR JDBCExceptionReporter:101 - data exception: string data, right truncation 14:12:14,614 ERROR AbstractFlushingEventListener:324 - Could not synchronize database state with session org.hibernate.exception.DataException: could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] //Stack trace 14:12:14,615 DEBUG GenericDAO:87 - could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] 14:12:14,616 DEBUG JDBCTransaction:186 - rollback 14:12:14,616 DEBUG JDBCTransaction:197 - rolled back JDBC Connection That's expected behavior. However when I retrieve the persisted object to check if its name is still 100 characters long, the test fails. The way I see it, the retrieved object should have a name that is 100 characters long, given that the attempted update failed. The last assertion fails because the name is 110 characters long now, as if the ea instance was indeed updated. What am I doing wrong here?

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  • Python4Delphi: Returning a python object in a function. (DelphiWrapper)

    - by Gabriel Fonseca
    I am using python4delphi. ow can I return an object from a wrapped Delphi class function? Code Snippet: I have a simple Delphi Class that i wrapped to Python Script, right? TSimple = Class Private function getvar1:string; Public Published property var1:string read getVar1; function getObj:TSimple; end; ... function TSimple.getVar1:string; begin result:='hello'; end; function TSimple.getObj:TSimple; begin result:=self; end; I made the TPySimple like the demo32 to give class access to the python code. My python module name is test. TPyDado = class(TPyDelphiPersistent) // Constructors & Destructors constructor Create( APythonType : TPythonType ); override; constructor CreateWith( PythonType : TPythonType; args : PPyObject ); override; // Basic services function Repr : PPyObject; override; class function DelphiObjectClass : TClass; override; end; ... { TPyDado } constructor TPyDado.Create(APythonType: TPythonType); begin inherited; // we need to set DelphiObject property DelphiObject := TDado.Create; with TDado(DelphiObject) do begin end; Owned := True; // We own the objects we create end; constructor TPyDado.CreateWith(PythonType: TPythonType; args: PPyObject); begin inherited; with GetPythonEngine, DelphiObject as TDado do begin if PyArg_ParseTuple( args, ':CreateDado' ) = 0 then Exit; end; end; class function TPyDado.DelphiObjectClass: TClass; begin Result := TDado; end; function TPyDado.Repr: PPyObject; begin with GetPythonEngine, DelphiObject as TDado do Result := VariantAsPyObject(Format('',[])); // or Result := PyString_FromString( PAnsiChar(Format('(%d, %d)',[x, y])) ); end; And now the python code: import test a = test.Simple() # try access the property var1 and everything is right print a.var1 # work's, but.. b = a.getObj(); # raise a exception that not find any attributes named getObj. # if the function returns a string for example, it's work.

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  • How do you make a Custom Data Generator for SQL XML DataType.

    - by Keith Sirmons
    Howdy, I am using Visual Studio 2010 and am playing around with the Database Projects. I am creating a DataGenerationPlan to insert data into a simple table, in which one of the column datatypes is XML. Out of the box, the generation plan uses the Regular Expression generator and generates something like this : HGcSv9wa7yM44T9x5oFT4pmBkEmv62lJ7OyAmCnL6yqXC2X.......... I am looking at creating a custom data Generator for this data type and have followed this site for the basics: http://msdn.microsoft.com/en-us/library/aa833244.aspx This example works if I am creating a string datatype and using it for a nvarchar datatype. What do I need to change to hook this Generator to the XML Datatype? Below are my code files. The string property works for nvarchar. The XElement property does not work for the xml datatype, and the RecordXMLDataGenerator is not listed as an option in the Generator column for the generation plan. CustomDataGenerators: using System; using System.Collections.Generic; using System.Linq; using System.Text; using Microsoft.Data.Schema.Tools.DataGenerator; using Microsoft.Data.Schema.Extensibility; using Microsoft.Data.Schema; using Microsoft.Data.Schema.Sql; using System.Xml.Linq; namespace CustomDataGenerators { [DatabaseSchemaProviderCompatibility(typeof(SqlDatabaseSchemaProvider))] public class RecordXMLDataGenerator : Generator { private XElement _RecordData; [Output(Description = "Generates string of XML Data for the Record.", Name = "RecordDataString")] public string RecordDataString { get { return _RecordData.ToString(SaveOptions.None); } } [Output(Description = "Generates XML Data for the Record.", Name = "RecordData")] public XElement RecordData { get { return _RecordData; } } protected override void OnGenerateNextValues() { base.OnGenerateNextValues(); XElement element = new XElement("Root", new XElement("Children1", 1), new XElement("Children6", 6) ); _RecordData = element; } } } XML Extensions File: <?xml version="1.0" encoding="utf-8" ?> <extensions assembly="" version="1" xmlns="urn:Microsoft.Data.Schema.Extensions" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="urn:Microsoft.Data.Schema.Extensions Microsoft.Data.Schema.Extensions.xsd"> <extension type="CustomDataGenerators.RecordXMLDataGenerator" assembly="CustomDataGenerators, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxx" enabled="true"/> </extensions> Table.sql: CREATE TABLE [dbo].[Record] ( id int IDENTITY (1,1) NOT NULL, recordData xml NULL, userId int NULL, test nvarchar(max) NULL, rowver rowversion NULL, CONSTRAINT pk_RecordID PRIMARY KEY (id) )

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  • Tag problem c# listbox

    - by Poppy
    Hi i'm trying to use the tag item of a listbox. heres my code. int number = 0; foreach (ListViewItem item in listBox1.Items) { Tag tag = (Tag) item.Tag; saveSlide(showid, tag.photoid, enumber); number++; } problem im havin is when i run the program i get an error message sayin cannot convert type string to system.ListView but i haven't declared item as a string anywher in my program

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  • Show loading image when pdf rendering

    - by Pankaj
    I am displaying pdf on my page like this <object data="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>" type="application/pdf" width="960" height="900" style="margin-top: -33px;"> <p> It appears you don't have a PDF plugin for this browser. No biggie... you can <a href="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>">click here to download the PDF file. </a> </p> </object> and Controller function are public FileStreamResult GetPricedMaterialPDF(string projID) { System.IO.Stream fileStream = GeneratePDF(projID); HttpContext.Response.AddHeader("content-disposition", "attachment; filename=form.pdf"); return new FileStreamResult(fileStream, "application/pdf"); } private System.IO.Stream GeneratePDF(string projID) { //create your pdf and put it into the stream... pdf variable below //comes from a class I use to write content to PDF files System.IO.MemoryStream ms = new System.IO.MemoryStream(); Project proj = GetProject(projID); List<File> ff = proj.GetFiles(Project_Thin.Folders.IntegrationFiles, true); string fileName = string.Empty; if (ff != null && ff.Count > 0 && ff.Where(p => p.AccessToUserID == CurrentCustomer.CustomerID).Count() > 0) { ff = ff.Where(p => p.AccessToUserID == CurrentCustomer.CustomerID).ToList(); foreach (var item in ff) { fileName = item.FileName; } byte[] bArr = new byte[] { }; bArr = GetJDLFile(fileName); ms.Write(bArr, 0, bArr.Length); ms.Position = 0; } return ms; } Now my problem is function on controller taking 10 to 20 second to process pdf, data="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>" at that time my page shows blank, which i don't want. i want to show loading image at that time. How can i do this...

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  • Please tell me what is error in my date comparison sql query

    - by Rajesh Rolen- DotNet Developer
    Please help me to find out error in my SQL query. I have created this query to compare dates select * from Joinplans jp where cast(convert(varchar,GETDATE(),103) AS datetime) BETWEEN CASE(convert(varchar,jp.planstartDate,103) AS datetime) AND CASE(convert(varchar,DATEADD(DAY,jp.planDays,jp.planstartDate),103) AS DATETIME) It's giving me the error: incorrect near 'AS' I am using SQL Server 2005.

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  • django i18n and translations problem

    - by Zayatzz
    Hello I have a problem with django translations. Problem 1 - i updated string in django.po file, but the change does not appear on the webpage. Problem 2 - i have created my own locale file with django-admin.py makemessages -l et, added the translation string into file, but they too do not appear on the page. I do not think this is setting problem, because the translations from django.po file do appear on the website, its just the changes and the translations from my own generated file that do not appear. Alan

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  • Please tell me what is error in my date comparision sql query

    - by Rajesh Rolen- DotNet Developer
    please help me to find out error in my sql query. i have created this query to compare dates select * from Joinplans jp where cast(convert(varchar ,GETDATE(),103) AS datetime) BETWEEN CASE(convert(varchar,jp.planstartDate,103) AS datetime) AND CASE(convert(varchar,DATEADD(DAY,jp.planDays,jp.planstartDate),103) AS DATETIME) It's giving me the error: incorrect near 'AS' I am using SQL Server 2005.

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  • Cannot run public class in one .java from another

    - by DIOS
    I have created a basic program that takes whatever is input into two textfields and exports them to a file. I would now like to encrypt that file, and alredy have the encryptor. The problem is that I cannot call it. Here is my code for the encryptor: import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.*; import javax.crypto.Cipher; import javax.crypto.CipherInputStream; import javax.crypto.CipherOutputStream; import javax.crypto.spec.SecretKeySpec; public class FileEncryptor { private String algo; private File file; public FileEncryptor(String algo,String path) { this.algo=algo; //setting algo this.file=new File(path); //settong file } public void encrypt() throws Exception{ //opening streams FileInputStream fis =new FileInputStream(file); file=new File(file.getAbsolutePath()); FileOutputStream fos =new FileOutputStream(file); //generating key byte k[] = "HignDlPs".getBytes(); SecretKeySpec key = new SecretKeySpec(k,algo.split("/")[0]); //creating and initialising cipher and cipher streams Cipher encrypt = Cipher.getInstance(algo); encrypt.init(Cipher.ENCRYPT_MODE, key); CipherOutputStream cout=new CipherOutputStream(fos, encrypt); byte[] buf = new byte[1024]; int read; while((read=fis.read(buf))!=-1) //reading data cout.write(buf,0,read); //writing encrypted data //closing streams fis.close(); cout.flush(); cout.close(); } public static void main (String[] args)throws Exception { new FileEncryptor("DES/ECB/PKCS5Padding","C:\\Users\\*******\\Desktop\\newtext").encrypt();//encrypts the current file. } } Here is the section of my file creator that is failing to call this: FileWriter fWriter = null; BufferedWriter writer = null; try{ fWriter = new FileWriter("C:\\Users\\*******\\Desktop\\newtext"); writer = new BufferedWriter(fWriter); writer.write(Data); writer.close(); f.dispose(); FileEncryptor encr = new FileEncryptor(); //problem lies here. encr.encrypt //public void that does the encryption. new complete(); //different .java that is working fine.

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  • assign operator to variable in python?

    - by abhilashm86
    Usual method of applying mathematics to variables is a * b Is it able to calculate and manipulate two operands like this? a = input('enter a value') b = input('enter a value') op = raw_input('enter a operand') then how do i connect op and two variables a and b?? i know i can compare op to +, -, %, $ and then assign and compute.... but can i do something like a op b , how to tell compiler that op is an operator?? any tweaks possible?

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  • How to solve this issues in URL?

    - by Ayyappan.Anbalagan
    I am doing billing project.i am passing invoice number to another .aspx page. /default.aspx?editid=5 its my url. if i changed my editid no=4 then the records also changes.how to solve this issue?? page1: LinkButton InvoiceEdit = sender as LinkButton; string EditId = InvoiceEdit.CommandArgument.ToString(); Response.Redirect("edit invoice.aspx?EditId=" + EditId); page2: String invoiceId = Request.QueryString["InvoiceId"].ToString();

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  • BerkeleyDB vs. Tokyo Cabinet

    - by vsedach
    I'm looking for general experiences from people who have used both, particularly on how the two compare on handling large numbers of records, transaction/concurrency/deadlock handling, and juicy stories about database corruption and backup procedures.

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  • How can i learn file name and create a folder?

    - by Phsika
    i try to make TCP/Ip Application to listen any other roemote computer to recieve any file. So i try to get files. i can do that. on the other hand every sample on google about giving SaveDialogBox to recived path folder.Forexample my old server.cs is that: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; using System.Net; using System.Net.Sockets; using System.Threading; namespace Server3 { public partial class Form1 : Form { Thread kanal; public Form1() { InitializeComponent(); try { kanal = new Thread(new ThreadStart(Dinle)); kanal.Start(); kanal.Priority = ThreadPriority.Normal; this.Text = "Kanal Çalisti"; } catch (Exception ex) { this.Text = "kanal çalismadi"; MessageBox.Show("hata:" + ex.ToString()); kanal.Abort(); throw; } } void Dinle() { TcpListener server = null; try { Int32 port = 51124; IPAddress localAddr = IPAddress.Parse("127.0.0.1"); server = new TcpListener(localAddr, port); server.Start(); Byte[] bytes = new Byte[1024 * 250000]; // string ReceivedPath = "C:/recieved"; while (true) { MessageBox.Show("Waiting for a connection... "); TcpClient client = server.AcceptTcpClient(); MessageBox.Show("Connected!"); NetworkStream stream = client.GetStream(); if (stream.CanRead) { saveFileDialog1.ShowDialog(); string pathfolder = saveFileDialog1.FileName; StreamWriter yaz = new StreamWriter(pathfolder); string satir; StreamReader oku = new StreamReader(stream); while ((satir = oku.ReadLine()) != null) { satir = satir + (char)13 + (char)10; yaz.WriteLine(satir); } oku.Close(); yaz.Close(); client.Close(); } } } catch (SocketException e) { Console.WriteLine("SocketException: {0}", e); } finally { // Stop listening for new clients. server.Stop(); } Console.WriteLine("\nHit enter to continue..."); Console.Read(); } private void Form1_Load(object sender, EventArgs e) { Dinle(); } } } i want to give automatically folder without SAVEDIALOGBOX. Also i want to learn my file name om my stream.Like that: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; using System.Net; using System.Net.Sockets; using System.Threading; namespace Server3 { public partial class Form1 : Form { Thread kanal; public Form1() { InitializeComponent(); try { kanal = new Thread(new ThreadStart(Dinle)); kanal.Start(); kanal.Priority = ThreadPriority.Normal; this.Text = "Kanal Çalisti"; } catch (Exception ex) { this.Text = "kanal çalismadi"; MessageBox.Show("hata:" + ex.ToString()); kanal.Abort(); throw; } } void Dinle() { TcpListener server = null; try { Int32 port = 51124; IPAddress localAddr = IPAddress.Parse("127.0.0.1"); server = new TcpListener(localAddr, port); server.Start(); Byte[] bytes = new Byte[1024 * 250000]; string ReceivedPath = "C:/recieved"; while (true) { MessageBox.Show("Waiting for a connection... "); TcpClient client = server.AcceptTcpClient(); MessageBox.Show("Connected!"); NetworkStream stream = client.GetStream(); if (stream.CanRead) { saveFileDialog1.ShowDialog(); string pathfolder = " i have to give property creating path and want to learn file name"; StreamWriter yaz = new StreamWriter(pathfolder); string satir; StreamReader oku = new StreamReader(stream); while ((satir = oku.ReadLine()) != null) { satir = satir + (char)13 + (char)10; yaz.WriteLine(satir); } oku.Close(); yaz.Close(); client.Close(); } } } catch (SocketException e) { Console.WriteLine("SocketException: {0}", e); } finally { // Stop listening for new clients. server.Stop(); } Console.WriteLine("\nHit enter to continue..."); Console.Read(); } private void Form1_Load(object sender, EventArgs e) { Dinle(); } } } Also i need : FileStream fs; FileInfo fi = new FileInfo(@"c:/recieved"); if (fi.Exists) fs = new FileStream(fi.FullName, FileMode.Append); else fs = new FileStream(fi.FullName, FileMode.Create); StreamWriter yazici = new StreamWriter(fs); How can i do that. Creating C:/recieved if it does not exist. And how can i learn File name on my network stream sending File Name.

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  • Bogus WPF / XAML errors in Visual Studio 2010

    - by epalm
    There are bogus errors hanging around, but at runtime everything works. Right now, I'm getting Cannot locate resource 'img/icons/silk/arrow_refresh.png'. I've got a simple UserControl called ImageButton (doesn't everyone?): <UserControl x:Class="WinDispatchClientWpf.src.controls.ImageButton" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d"> <Button Name="btnButton" Click="btnButton_Click"> <StackPanel Orientation="Horizontal"> <Image Name="btnImage" Stretch="None" /> <TextBlock Name="btnText" /> </StackPanel> </Button> </UserControl> Which does what you'd expect: [ContentProperty("Text")] public partial class ImageButton : UserControl { public String Image { set { btnImage.Source = GuiUtil.CreateBitmapImage(value); } } public String Text { set { btnText.Text = value; } } public double Gap { set { btnImage.Margin = new Thickness(0, 0, value, 0); } } public bool ToolBarStyle { set { if (value) { btnButton.Style = (Style)FindResource(ToolBar.ButtonStyleKey); } } } public bool IsCancel { set { btnButton.IsCancel = value; } } public bool IsDefault { set { btnButton.IsDefault = value; } } public event RoutedEventHandler Click; public ImageButton() { InitializeComponent(); } private void btnButton_Click(object sender, RoutedEventArgs e) { if (Click != null) { Click(sender, e); } } } Where CreateBitmapImage is the following: public static BitmapImage CreateBitmapImage(string imagePath) { BitmapImage icon = new BitmapImage(); icon.BeginInit(); icon.UriSource = new Uri(String.Format("pack://application:,,,/{0}", imagePath)); icon.EndInit(); return icon; } I can't see the design view of any xaml file that uses an ImageButton like such: <Window foo="bar" xmlns:wpfControl="clr-namespace:MyProj.src.controls"> <Grid> <wpfControl:ImageButton ToolBarStyle="True" Gap="3" Click="btnRefresh_Click" Text="Refresh" Image="img/icons/silk/arrow_refresh.png" /> </Grid> </Window> Why is VS complaining?

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  • How do I check mysql user have privileges like root user

    - by Devara Gudda
    I use mysql c++ wrapper in client side to connect to mysql server. When user establishes connection to mysql server I want to know whether the user have privileges like root (i.e. GRANT ALL PRIVILEGES ON . TO 'username'@'%' WITH GRANT OPTION).The 'SHOW GRANTS FOR CURRENT_USER' query gives grants for current user, but i need to parse the string and compare to know whether the current user have privileges like root. I am looking for an alternative options. Regards, Devara Gudda

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  • asp.net cannot update database

    - by tom
    string ConnectionString = WebConfigurationManager.ConnectionStrings["dbnameConnectionString"].ConnectionString; SqlConnection myConnection = new SqlConnection(ConnectionString); myConnection.Open(); try { string qry = "UPDATE customers SET firstname=@firstname WHERE cid=1"; SqlCommand insertQuery = new SqlCommand(qry, myConnection); insertQuery.Parameters.Add(new SqlParameter("@firstname", txtFirstname.Text)); insertQuery.ExecuteNonQuery(); myConnection.Close(); } catch (Exception ee) { } Any suggestions?

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  • TortoiseSVN : Good 'patch file' viewer ?

    - by mishal153
    Hi, The default patch file viewer is messy (ie. no side by side diff view etc). I tried setting the path of beyondCompare exe in "Settings-Unified Diff Viewer-custom", but beyond compare also behaves same as default diff tool. Is there a way to atleast allow side by side diff in patch files ? If so, what is the method ? My aim is to allow emailing of changes so that they can be reviewed before I commit them :) Mishal

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  • Python3k ctypes printf

    - by dsaccount1
    printf returns 1 instead of Hello World! which is the desired result. I googled it and think its because of the changes in the way sequences are treated. Python-3000 Possible py3k problem resolved. import ctypes msvcrt=ctypes.cdll.msvcrt string=b"Hello World!" msvcrt.printf("%s", string)

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