Search Results

Search found 20931 results on 838 pages for 'mysql insert'.

Page 599/838 | < Previous Page | 595 596 597 598 599 600 601 602 603 604 605 606  | Next Page >

  • SQL Cartesian product joining table to itself and inserting into existing table

    - by Emma
    I am working in phpMyadmin using SQL. I want to take the primary key (EntryID) from TableA and create a cartesian product (if I am using the term correctly) in TableB (empty table already created) for all entries which share the same value for FieldB in TableA, except where TableA.EntryID equals TableA.EntryID So, for example, if the values in TableA were: TableA.EntryID TableA.FieldB 1 23 2 23 3 23 4 25 5 25 6 25 The result in TableB would be: Primary key EntryID1 EntryID2 FieldD (Default or manually entered) 1 1 2 Default value 2 1 3 Default value 3 2 1 Default value 4 2 3 Default value 5 3 1 Default value 6 3 2 Default value 7 4 5 Default value 8 4 6 Default value 9 5 4 Default value 10 5 6 Default value 11 6 4 Default value 12 6 5 Default value I am used to working in Access and this is the first query I have attempted in SQL. I started trying to work out the query and got this far. I know it's not right yet, as I’m still trying to get used to the syntax and pieced this together from various articles I found online. In particular, I wasn’t sure where the INSERT INTO text went (to create what would be an Append Query in Access). SELECT EntryID FROM TableA.EntryID TableA.EntryID WHERE TableA.FieldB=TableA.FieldB TableA.EntryID<>TableA.EntryID INSERT INTO TableB.EntryID1 TableB.EntryID2 After I've got that query right, I need to do a TRIGGER query (I think), so if an entry changes it's value in TableA.FieldB (changing it’s membership of that grouping to another grouping), the cartesian product will be re-run on THAT entry, unless TableB.FieldD = valueA or valueB (manually entered values). I have been using the Designer Tab. Does there have to be a relationship link between TableA and TableB. If so, would it be two links from the EntryID Primary Key in TableA, one to each EntryID in TableB? I assume this would not work because they are numbered EntryID1 and EntryID2 and the name needs to be the same to set up a relationship? If you can offer any suggestions, I would be very grateful. Research: http://www.fluffycat.com/SQL/Cartesian-Joins/ Cartesian Join example two Q: You said you can have a Cartesian join by joining a table to itself. Show that! Select * From Film_Table T1, Film_Table T2;

    Read the article

  • essential reading for php coding (including databases)?

    - by tombull89
    Hello. I'm more of a SU and SF but now I'm after some help from the SO community. I'm dabbling in a bit of php coding with databases and am getting a bit stuck with relationships and the like. Can anybody reccomend some books, online or real, that would be a good start for someone new(ish) to php and mysql databases? Cheers!

    Read the article

  • android SQLite vs Flat Files

    - by mixm
    hi. im creating a game right now and im a bit stuck on how to implement storage of levels. i need to be able to download level files from the internet ota. im not so familiar with transferring files ota, but i have some experience with databases (mysql). what would be a better way of storing the game's level data?

    Read the article

  • Pros and Cons of oursql [closed]

    - by S.Mark
    According to this python page, oursql looks very cool. oursql has real parameterization. oursql allows text or binary data to be streamed into the database and streamed out of the database, instead of requiring everything to be buffered in the client. oursql can both insert rows lazily and fetch rows lazily. oursql has unicode support on by default. So, Anyone start using it in the live projects and could share pros and cons over it?

    Read the article

  • Why am I unable to create a trigger using my SqlCommand?

    - by acidzombie24
    The line cmd.ExecuteNonQuery(); cmd.CommandText CREATE TRIGGER subscription_trig_0 ON subscription AFTER INSERT AS UPDATE user_data SET msg_count=msg_count+1 FROM user_data JOIN INSERTED ON user_data.id = INSERTED.recipient; The exception: Incorrect syntax near the keyword 'TRIGGER'. Then using VS 2010, connected to the very same file (a mdf file) I run the query above and I get a success message. WTF!

    Read the article

  • Howoto get id of new record after model.save

    - by tonymarschall
    I have a model with the following db structure: mysql> describe units; +------------+----------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+----------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(128) | NO | | NULL | | | created_at | datetime | NO | | NULL | | | updated_at | datetime | NO | | NULL | | +------------+----------+------+-----+---------+----------------+ 7 rows in set (0.00 sec) After creating a new record an saving i can not get the id of the record. 1.9.3p194 :001 > unit = Unit.new(:name => 'test') => #<Unit id: nil, name: "test", created_at: nil, updated_at: nil> 1.9.3p194 :002 > unit.save (0.2ms) BEGIN SQL (0.3ms) INSERT INTO `units` (`created_at`, `name`, `updated_at`) VALUES ('2012-08-31 23:48:12', 'test', '2012-08-31 23:48:12') (144.6ms) COMMIT => true 1.9.3p194 :003 > unit.inspect => "#<Unit id: nil, name: \"test\", created_at: \"2012-08-31 23:48:12\", updated_at: \"2012-08-31 23:48:12\">" # unit.rb class Unit < ActiveRecord::Base attr_accessible :name end # migration class CreateUnits < ActiveRecord::Migration def change create_table :units do |t| t.string :name, :null => false t.timestamps end end end Tried this with other models and have the same result (no id). Data is definitily saved and i can get data with Unit.last Another try with Foo.id = nil # /var/www# rails g model Foo name:string invoke active_record create db/migrate/20120904030554_create_foos.rb create app/models/foo.rb invoke test_unit create test/unit/foo_test.rb create test/fixtures/foos.yml # /var/www# rake db:migrate == CreateFoos: migrating ===================================================== -- create_table(:foos) -> 0.3451s == CreateFoos: migrated (0.3452s) ============================================ # /var/www# rails c Loading development environment (Rails 3.2.8) 1.9.3p194 :001 > foo = Foo.new(:name => 'bar') => #<Foo id: nil, name: "bar", created_at: nil, updated_at: nil> 1.9.3p194 :002 > foo.save (0.2ms) BEGIN SQL (0.4ms) INSERT INTO `foos` (`created_at`, `name`, `updated_at`) VALUES ('2012-09-04 03:06:26', 'bar', '2012-09-04 03:06:26') (103.2ms) COMMIT => true 1.9.3p194 :003 > foo.inspect => "#<Foo id: nil, name: \"bar\", created_at: \"2012-09-04 03:06:26\", updated_at: \"2012-09-04 03:06:26\">" 1.9.3p194 :004 > Foo.last Foo Load (0.5ms) SELECT `foos`.* FROM `foos` ORDER BY `foos`.`id` DESC LIMIT 1 => #<Foo id: 1, name: "bar", created_at: "2012-09-04 03:06:26", updated_at: "2012-09-04 03:06:26">

    Read the article

  • How to write my own global lock / unlock functions for PostgreSQL

    - by rafalmag
    I have postgresql (in perlu) function getTravelTime(integer, timestamp), which tries to select data for specified ID and timestamp. If there are no data or if data is old, it downloads them from external server (downloading time ~300ms). Multiple process use this database and this function. There is an error when two process do not find data and download them and try to do an insert to travel_time table (id and timestamp pair have to be unique). I thought about locks. Locking whole table would block all processes and allow only one to proceed. I need to lock only on id and timestamp. pg_advisory_lock seems to lock only in "current session". But my processes uses their own sessions. I tried to write my own lock/unlock functions. Am I doing it right? I use active waiting, how can I omit this? Maybe there is a way to use pg_advisory_lock() as global lock? My code: CREATE TABLE travel_time_locks ( id_key integer NOT NULL, time_key timestamp without time zone NOT NULL, UNIQUE (id_key, time_key) ); ------------ -- Function: mylock(integer, timestamp) DROP FUNCTION IF EXISTS mylock(integer, timestamp) CASCADE; -- Usage: SELECT mylock(1, '2010-03-28T19:45'); -- function tries to do a global lock similar to pg_advisory_lock(key, key) CREATE OR REPLACE FUNCTION mylock(id_input integer, time_input timestamp) RETURNS void AS $BODY$ DECLARE rows int; BEGIN LOOP BEGIN -- active waiting here !!!! :( INSERT INTO travel_time_locks (id_key, time_key) VALUES (id_input, time_input); EXCEPTION WHEN unique_violation THEN CONTINUE; END; EXIT; END LOOP; END; $BODY$ LANGUAGE 'plpgsql' VOLATILE COST 1; ------------ -- Function: myunlock(integer, timestamp) DROP FUNCTION IF EXISTS myunlock(integer, timestamp) CASCADE; -- Usage: SELECT myunlock(1, '2010-03-28T19:45'); -- function tries to do a global unlock similar to pg_advisory_unlock(key, key) CREATE OR REPLACE FUNCTION myunlock(id_input integer, time_input timestamp) RETURNS integer AS $BODY$ DECLARE BEGIN DELETE FROM ONLY travel_time_locks WHERE id_key=id_input AND time_key=time_input; RETURN 1; END; $BODY$ LANGUAGE 'plpgsql' VOLATILE COST 1;

    Read the article

  • [CakePHP] htmlspecialchars

    - by user198003
    hi all, if i submit data like my string using form on insert/edit view, on a list view i'll get my string as italic (like here). how can i avoid that, and to have my string (with visible all html tags) on all forms? tnx in adv!

    Read the article

  • Handling apostrophes, php and pgsql

    - by running4surival
    For my forms, I'm using pg_escape_string on every field before I insert them into the database. So I get something like firstname='O''reilly'. But when I try to print that out, I get O''reily, 2 apostrophes. Shouldn't it only 1 apostrophe, O'reilly? This isnt a debugging problem, im just wondering if you have firstname='O''reilly', how do you print that so it is just O'reilly instead of O''reilly?

    Read the article

  • Problem with computed column with NDBUnit

    - by jess
    Hi, I am loading data for tests in tables using xml and ndbunit.But,for a table having computed column,I am having problem.I get this error The column "xyz" cannot be modified because it is either a computed column or is the result of a UNION operator. I have modified the INSERT and UPDATE commands(removed the computed column) of sqladapter in xsd file,but still face the issue. thanks

    Read the article

  • How to create a database deadlock using jdbc and JUNIT

    - by Isawpalmetto
    I am trying to create a database deadlock and I am using JUnit. I have two concurrent tests running which are both updating the same row in a table over and over again in a loop. My idea is that you update say row A in Table A and then row B in Table B over and over again in one test. Then at the same time you update row B table B and then row A Table A over and over again. From my understanding this should eventually result in a deadlock. Here is the code For the first test. public static void testEditCC() { try{ int rows = 0; int counter = 0; int large=10000000; Connection c=DataBase.getConnection(); while(counter<large) { int pid = 87855; int cCode = 655; String newCountry="Egypt"; int bpl = 0; stmt = c.createStatement(); rows = stmt.executeUpdate("UPDATE main " + //create lock on main table "SET BPL="+cCode+ "WHERE ID="+pid); rows = stmt.executeUpdate("UPDATE BPL SET DESCRIPTION='SomeWhere' WHERE ID=602"); //create lock on bpl table counter++; } assertTrue(rows == 1); //rows = stmt.executeUpdate("Insert into BPL (ID, DESCRIPTION) VALUES ("+cCode+", '"+newCountry+"')"); } catch(SQLException ex) { ex.printStackTrace(); //ex.getMessage(); } } And here is the code for the second test. public static void testEditCC() { try{ int rows = 0; int counter = 0; int large=10000000; Connection c=DataBase.getConnection(); while(counter<large) { int pid = 87855; int cCode = 655; String newCountry="Jordan"; int bpl = 0; stmt = c.createStatement(); //stmt.close(); rows = stmt.executeUpdate("UPDATE BPL SET DESCRIPTION='SomeWhere' WHERE ID=602"); //create lock on bpl table rows = stmt.executeUpdate("UPDATE main " + //create lock on main table "SET BPL="+cCode+ "WHERE ID="+pid); counter++; } assertTrue(rows == 1); //rows = stmt.executeUpdate("Insert into BPL (ID, DESCRIPTION) VALUES ("+cCode+", '"+newCountry+"')"); } catch(SQLException ex) { ex.printStackTrace(); } } I am running these two separate JUnit tests at the same time and am connecting to an apache Derby database that I am running in network mode within Eclipse. Can anyone help me figure out why a deadlock is not occurring? Perhaps I am using JUnit wrong.

    Read the article

  • Setting 0/1-to-1 relationship in SQLAlchemy?

    - by Timmy
    is there a proper way of setting up a 0/1-to-1 relationship? i want to be able to check if the related item exists without creating it: if item.relationship is None: item.relationship = item2() but it creates the insert statements on the if statement

    Read the article

  • Is there a way to make PHP's SplHeap recalculate? (aka: add up-heap to SplHeap?)

    - by md2k7
    I am using an SplHeap to hold graph nodes of a tree with directed edges that will be traversed from the leaves to the root. For this, I precalculate the "fan-in" of nodes and put them into the heap so that I can always retrieve the node with the smallest fan-in (0) from it. After visiting a node, I reduce the fan-in of its successor by 1. Then obviously, the heap needs to be recalculated because the successor is now in the wrong place there. I have tried recoverFromCorruption(), but it doesn't do anything and keeps the heap in the wrong order (node with larger fanIn stays in front of smaller fanIn). As a workaround, I'm now creating a new heap after each visit, amounting to a full O(N*log(N)) sort each time. It should be possible, however, to make up-heap operations on the changed heap entry until it's in the right position in O(log(N)). The API for SplHeap doesn't mention an up-heap (or deletion of an arbitrary element - it could then be re-added). Can I somehow derive a class from SplHeap to do this or do I have to create a pure PHP heap from scratch? EDIT: Code example: class VoteGraph { private $nodes = array(); private function calculateFanIn() { /* ... */ } // ... private function calculateWeights() { $this->calculateFanIn(); $fnodes = new GraphNodeHeap(); // heap by fan-in ascending (leaves are first) foreach($this->nodes as $n) { // omitted: filter loops $fnodes->insert($n); } // traversal from leaves to root while($fnodes->valid()) { $node = $fnodes->extract(); // fetch a leaf from the heap $successor = $this->nodes[$node->successor]; // omitted: actual job of traversal $successor->fanIn--; // will need to fix heap (sift up successor) because of this //$fnodes->recoverFromCorruption(); // doesn't work for what I want // workaround: rebuild $fnodes from scratch $fixedHeap = new GraphNodeHeap(); foreach($fnodes as $e) $fixedHeap->insert($e); $fnodes = $fixedHeap; } } } class GraphNodeHeap extends SplHeap { public function compare($a, $b) { if($a->fanIn === $b->fanIn) return 0; else return $a->fanIn < $b->fanIn ? 1 : -1; } }

    Read the article

  • Update multiple table column values using single query

    - by Dave Jarvis
    How would you update data in multiple tables using a single query? In MySQL it would be: UPDATE party p LEFT JOIN party_name n ON p.party_id = n.party_id LEFT JOIN party_details d ON p.party_id = d.party_id LEFT JOIN incident_participant ip ON ip.party_id = p.party_id LEFT JOIN incident i ON ip.incident_id = i.incident_id SET p.employee_id = NULL, c.em_address = '[email protected]', c.ad_postal = 'x', n.first_name = 'x', n.last_name = 'x' WHERE i.confidential_dt IS NOT NULL What is the equivalent SQL statement using Oracle 11g? (Is ANSI SQL possible?) Thank you!

    Read the article

  • SQL Server Query Command

    - by Scott Jackson
    Hi, I have an SQL database table, I want to find everything in a table where the 'Room' says 'DISPOSED', Insert 'DISPOSED' into the 'Status' field and then delete the entry in 'Room'. Basically moving the entry from one field to another (if the 'Room' field has 'DISPOSED' in it) Hope this makes sense. Thanks for any help.

    Read the article

  • SQL, problem with OrderBy / GroupBy

    - by Tristan
    Hi, In my table I have two fields among others : article_id and *version* *example: article_id : 5 // version 1 aricle_id: 5 // version 2 article_id: 6 // version 1* What i want to do is to retrieve the latest version for each article id (in my example i want to retrieve the article 5 version 2 object and article 6 and version 1 object). The problem is that mysql is doing the groupBy instead of the OrderBy so it returns to me the FIRST version of each article, but i want the opposit. Do you have an idea please ?

    Read the article

< Previous Page | 595 596 597 598 599 600 601 602 603 604 605 606  | Next Page >