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  • What is more interesting or powerful: Curry/Mercury/Lambda-Prolog/your suggestion.

    - by Bubba88
    Hi! I would like to ask you about what formal system could be more interesting to implement from scratch/reverse engineer. I've looked through some existing and rather open (open in the sense of free/open-source) projects of logical/declarative programming systems. I've decided to make up something similar in my free time, or at least to catch the general idea of implementation. It would be great if some of these systems would provide most of the expressive power and conciseness of modern academic investigations in logic and it's relation with computational models. What would you recommend to study at least at the conceptual level? For example, Lambda-Prolog is interesting particularly because it allows for higher order relations, but AFAIK (I might really be mistaken :)) is based on intuitionist logic and therefore lack the excluded-middle principle; that's generally a disatvantage for me.. I would also welcome any suggestions about modern logical programming systems which are less popular but more expressive/powerful. I guess, this question will need refactoring, but thank you in advance! :)

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  • 2 Questions 1.How to find differences in lists in prolog and 2. Determine if the lists are the same

    - by Alexander
    1.If i have two lists say A and B made upp of different letters. [b,a,c] in list A and [b,d,c,e] in list B how can i get prolog to give me C,which is a list of elements that A has which are not included in list B Ex. So if i type difference([b,a,c],[b,d,c,e],C). I want the answer to read: C=[a] If i have two lists where list A is made up off [a,b,c] and list B is [c,a,b] i want the result to be Yes if i type: same([a,b,c],[c,a,b]). since they contain the same elements the fact that they are in a different order does not matter. Also it should only answer yes if all of the elements are the same not if 3/4 are right.

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  • Recent programming language for AI?

    - by Eduard Florinescu
    For a few decades the programming language of choice for AI was either Prolog or LISP, and a few more others that are not so well known. Most of them were designed before the 70's. Changes happens a lot on many other domains specific languages, but in the AI domain it hadn't surfaced so much as in the web specific languages or scripting etc. Are there recent programming languages that were intended to change the game in the AI and learn from the insufficiencies of former languages?

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  • What is a recent programming language of choice for the AI?

    - by Eduard Florinescu
    For a few decades the programming language of choice for AI was either Prolog or LISP, and a few more others that are not so well known. Most of them were designed before the 70's. Changes happens a lot on many other domains specific languages, but in the AI domain it hadn't surfaced so much as in the web specific languages or scripting etc. Are there recent programming languages that were intended to change the game in the AI and learn from the insufficiencies of former languages?

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  • Default prolog for all ZSH scripts?

    - by Igor Spasic
    I have a file that contains several helper functions, meant to be used only in other ZSH scripts. I do not want them to be loaded with my profile. To make these functions available in my script, I would need to source this file. Is it somehow possible to have automatic prolog script (or pre-script) loaded before all my ZSH scripts? My current idea is to alias -s zsh extension to custom function that those all this for me: concatenate prolog file and current script calls zsh with such modified input but for now I am somehow not able to do this (haven't sleep for almost a day). Please, does anyone have a working solution?

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  • Can an XML prolog contain custom information?

    - by DaveJohnston
    Is it legal to add additional custom information somewhere in an XML prolog? For example, in my case, I would like to add an indicator of which serialiser version was used to create the XML, so that clients receiving the XML could automatically select the correct corresponding de-serialiser. I could add the information as an attribute of the root tag, but I thought it would be cleaner to add the information in the prolog, like the standard XML version: <?xml version="1.0"?> something like: <?serialiser version="1.0"?> or is the prolog reserved purely for those things specified by W3C?

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  • SWI-Prolog: how to load rdf triples using semweb/rdf_db library?

    - by Li Li
    Hi, I have a rdf file (file.trp) in n-triples format, where each line is: "subject predicate object ." I tried to use rdf_load in semweb/rdf_db to load it into memory, but failed. Here is what I tried: ?- rdf_load('file.trp'). ?- rdf_load('file.trp', [format(triples]). the manual says it supports xml and triples. But it only loads rdf xml files. How can I load such rdf triple file? Thanks, Li

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  • How to keep the first result of a function from Prolog?

    - by zuhakasa
    I need to write a customized function that will be called many times by other fixed functions. In this function, at the first called time, it will return the total number of lines of a file. The second called time of this function, forward, will return the number of lines in small sections of this file. My question is how I keep the first returned result(total number of lines of a file) and use it for the next called times of my function. I need to write or declare any thing only in this function(not in the caller). Something like this: myFunction(Input, MyResult, FirstResult) :- calculateInputFunction(Input, Result), !, MyResult is Result, ... . The problem is, every time myFunction is called, it receives different Input and returns different MyResult. But I would like to keep the first MyResult to use for next called times of myFunction. How can I do that? Thanks very much for your answer in advance.

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  • "Content is not allowed in prolog" when parsing perfectly valid XML on GAE

    - by Adrian Petrescu
    Hey guys, I've been beating my head against this absolutely infuriating bug for the last 48 hours, so I thought I'd finally throw in the towel and try asking here before I throw my laptop out the window. I'm trying to parse the response XML from a call I made to AWS SimpleDB. The response is coming back on the wire just fine; for example, it may look like: <?xml version="1.0" encoding="utf-8"?> <ListDomainsResponse xmlns="http://sdb.amazonaws.com/doc/2009-04-15/"> <ListDomainsResult> <DomainName>Audio</DomainName> <DomainName>Course</DomainName> <DomainName>DocumentContents</DomainName> <DomainName>LectureSet</DomainName> <DomainName>MetaData</DomainName> <DomainName>Professors</DomainName> <DomainName>Tag</DomainName> </ListDomainsResult> <ResponseMetadata> <RequestId>42330b4a-e134-6aec-e62a-5869ac2b4575</RequestId> <BoxUsage>0.0000071759</BoxUsage> </ResponseMetadata> </ListDomainsResponse> I pass in this XML to a parser with XMLEventReader eventReader = xmlInputFactory.createXMLEventReader(response.getContent()); and call eventReader.nextEvent(); a bunch of times to get the data I want. Here's the bizarre part -- it works great inside the local server. The response comes in, I parse it, everyone's happy. The problem is that when I deploy the code to Google App Engine, the outgoing request still works, and the response XML seems 100% identical and correct to me, but the response fails to parse with the following exception: com.amazonaws.http.HttpClient handleResponse: Unable to unmarshall response (ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog.): <?xml version="1.0" encoding="utf-8"?> <ListDomainsResponse xmlns="http://sdb.amazonaws.com/doc/2009-04-15/"><ListDomainsResult><DomainName>Audio</DomainName><DomainName>Course</DomainName><DomainName>DocumentContents</DomainName><DomainName>LectureSet</DomainName><DomainName>MetaData</DomainName><DomainName>Professors</DomainName><DomainName>Tag</DomainName></ListDomainsResult><ResponseMetadata><RequestId>42330b4a-e134-6aec-e62a-5869ac2b4575</RequestId><BoxUsage>0.0000071759</BoxUsage></ResponseMetadata></ListDomainsResponse> javax.xml.stream.XMLStreamException: ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog. at com.sun.org.apache.xerces.internal.impl.XMLStreamReaderImpl.next(Unknown Source) at com.sun.xml.internal.stream.XMLEventReaderImpl.nextEvent(Unknown Source) at com.amazonaws.transform.StaxUnmarshallerContext.nextEvent(StaxUnmarshallerContext.java:153) ... (rest of lines omitted) I have double, triple, quadruple checked this XML for 'invisible characters' or non-UTF8 encoded characters, etc. I looked at it byte-by-byte in an array for byte-order-marks or something of that nature. Nothing; it passes every validation test I could throw at it. Even stranger, it happens if I use a Saxon-based parser as well -- but ONLY on GAE, it always works fine in my local environment. It makes it very hard to trace the code for problems when I can only run the debugger on an environment that works perfectly (I haven't found any good way to remotely debug on GAE). Nevertheless, using the primitive means I have, I've tried a million approaches including: XML with and without the prolog With and without newlines With and without the "encoding=" attribute in the prolog Both newline styles With and without the chunking information present in the HTTP stream And I've tried most of these in multiple combinations where it made sense they would interact -- nothing! I'm at my wit's end. Has anyone seen an issue like this before that can hopefully shed some light on it? Thanks!

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  • Problem with creating a deterministic finite automata (DFA) - Mercury

    - by Jabba The hut
    I would like to have a deterministic finite automata (DFA) simulated in Mercury. But I’m s(t)uck at several places. Formally, a DFA is described with the following characteristics: a setOfStates S, an inputAlphabet E <-- summation symbol, a transitionFunction : S × E -- S, a startState s € S, a setOfAcceptableFinalStates F =C S. A DFA will always starts in the start state. Then the DFA will read all the characters on the input, one by one. Based on the current input character and the current state, there will be made to a new state. These transitions are defined in the transitions function. when the DFA is in one of his acceptable final states, after reading the last character, then will the DFA accept the input, If not, then the input will be is rejected. The figure shows a DFA the accepting strings where the amount of zeros, is a plurality of three. Condition 1 is the initial state, and also the only acceptable state. for each input character is the corresponding arc followed to the next state. Link to Figure What must be done A type “mystate” which represents a state. Each state has a number which is used for identification. A type “transition” that represents a possible transition between states. Each transition has a source_state, an input_character, and a final_state. A type “statemachine” that represents the entire DFA. In the solution, the DFA must have the following properties: The set of all states, the input alphabet, a transition function, represented as a set of possible transitions, a set of accepting final states, a current state of the DFA A predicate “init_machine (state machine :: out)” which unifies his arguments with the DFA, as shown as in the Figure. The current state for the DFA is set to his initial state, namely, 1. The input alphabet of the DFA is composed of the characters '0'and '1'. A user can enter a text, which will be controlled by the DFA. the program will continues until the user types Ctrl-D and simulates an EOF. If the user use characters that are not allowed into the input alphabet of the DFA, then there will be an error message end the program will close. (pred require) Example Enter a sentence: 0110 String is not ok! Enter a sentence: 011101 String is not ok! Enter a sentence: 110100 String is ok! Enter a sentence: 000110010 String is ok! Enter a sentence: 011102 Uncaught exception Mercury: Software Error: Character does not belong to the input alphabet! the thing wat I have. :- module dfa. :- interface. :- import_module io. :- pred main(io.state::di, io.state::uo) is det. :- implementation. :- import_module int,string,list,bool. 1 :- type mystate ---> state(int). 2 :- type transition ---> trans(source_state::mystate, input_character::bool, final_state::mystate). 3 (error, finale_state and current_state and input_character) :- type statemachine ---> dfa(list(mystate),list(input_character),list(transition),list(final_state),current_state(mystate)) 4 missing a lot :- pred init_machine(statemachine :: out) is det. %init_machine(statemachine(L_Mystate,0,L_transition,L_final_state,1)) :- <-probably fault 5 not perfect main(!IO) :- io.write_string("\nEnter a sentence: ", !IO), io.read_line_as_string(Input, !IO), ( Invoer = ok(StringVar), S1 = string.strip(StringVar), (if S1 = "mustbeabool" then io.write_string("Sentenceis Ok! ", !IO) else io.write_string("Sentence is not Ok!.", !IO)), main(!IO) ; Invoer = eof ; Invoer = error(ErrorCode), io.format("%s\n", [s(io.error_message(ErrorCode))], !IO) ). Hope you can help me kind regards

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  • Python or Ruby for webbased Artificial Intelligence?

    - by Pieter Kubben
    A new web application may require adding Artificial Intelligence (AI) in the future, e.g. using ProLog. I know it can be done from a Java environment, but I am wondering about the opportunities with modern web languages like Ruby or Python. The latter is considered to be "more scientific" (at least used in that environment), but using Google there seems to be a preliminary ProLog implementation for both. Any suggestions on modern (open source) web languages (like Python or Ruby) in combination with AI?

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  • What is the best AI language/framework for .NET?

    - by Eduardo Cobuci
    I'm building an academic work that consists in a turn-based strategy game. I'm using XNA 3 for the graphics but didn't decide what to use for AI. I was considering to use P#, a Prolog interpreter for .NET but i found it a bit poor. Do you anything better for game AI than Prolog (maybe Haskell?) or a better interpreter then P#?

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  • Instantiate type variable in Haskell

    - by danportin
    EDIT: Solved. I was unware that enabling a language extension in the source file did not enable the language extension in GHCi. The solution was to :set FlexibleContexts in GHCi. I recently discovered that type declarations in classes and instances in Haskell are Horn clauses. So I encoded the arithmetic operations from The Art of Prolog, Chapter 3, into Haskell. For instance: fac(0,s(0)). fac(s(N),F) :- fac(N,X), mult(s(N),X,F). class Fac x y | x -> y instance Fac Z (S Z) instance (Fac n x, Mult (S n) x f) => Fac (S n) f pow(s(X),0,0) :- nat(X). pow(0,s(X),s(0)) :- nat(X). pow(s(N),X,Y) :- pow(N,X,Z), mult(Z,X,Y). class Pow x y z | x y -> z instance (N n) => Pow (S n) Z Z instance (N n) => Pow Z (S n) (S Z) instance (Pow n x z, Mult z x y) => Pow (S n) x y In Prolog, values are insantiated for (logic) variable in a proof. However, I don't understand how to instantiate type variables in Haskell. That is, I don't understand what the Haskell equivalent of a Prolog query ?-f(X1,X2,...,Xn) is. I assume that :t undefined :: (f x1 x2 ... xn) => xi would cause Haskell to instantiate xi, but this gives a Non type-variable argument in the constraint error, even with FlexibleContexts enabled.

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  • Find all clauses related to an atom

    - by Luc Touraille
    This is probably a very silly question (I just started learning Prolog a few hours ago), but is it possible to find all the clauses related to an atom? For example, assuming the following knowledge base: cat(tom). animal(X) :- cat(X). , is there a way to obtain every possible information about tom (or at least all the facts that are explicitly stated in the base)? I understand that a query like this is not possible: ?- Pred(tom). so I thought I could write a rule that would deduce the correct information: meta(Object, Predicate) :- Goal =.. [Predicate, Object], call(Goal). so that I could write queries such as ?- meta(tom, Predicate). but this does not work because arguments to call are not sufficiently instantiated. So basically my question is: is this at all possible, or is Prolog not design to provide this kind of information? And if it is not possible, why?

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  • StaX: Content not allowed in prolog

    - by RalfB
    I have the following (test) XML file below and Java code that uses StaX. I want to apply this code to a file that is about 30 GB large but with fairly small elements, so I thought StaX is a good choice. I am getting the following error: Exception in thread "main" javax.xml.stream.XMLStreamException: ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog at com.sun.org.apache.xerces.internal.impl.XMLStreamReaderImpl.next(XMLStreamReaderImpl.java:598) at at.tuwien.mucke.util.xml.staxtest.StaXTest.main(StaXTest.java:18) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:601) at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120) <?xml version='1.0' encoding='utf-8'?> <catalog> <book id="bk101"> <author>Gambardella, Matthew</author> <title>XML Developer's Guide</title> <price>44.95</price> <description>An in-depth look at creating applications with XML.</description> </book> <book id="bk102"> <author>Ralls, Kim</author> <title>Midnight Rain</title> <price>5.95</price> <description>A former architect battles corporate zombies, an evil sorceress, and her own childhood to become queen of the world.</description> </book> </catalog> Here the code: package xml.staxtest; import java.io.*; import javax.xml.stream.*; public class StaXTest { public static void main(String[] args) throws Exception { XMLInputFactory xif = XMLInputFactory.newInstance(); XMLStreamReader streamReader = xif.createXMLStreamReader(new FileReader("D:/Data/testFile.xml")); while(streamReader.hasNext()){ int eventType = streamReader.next(); if(eventType == XMLStreamReader.START_ELEMENT){ System.out.println(streamReader.getLocalName()); } //... more to come here later ... } } }

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  • Backtracking Problem

    - by Joshua Green
    Could someone please guide me through backtracking in Prolog-C using the simple example below? Here is my Prolog file: likes( john, mary ). likes( john, emma ). likes( john, ashley ). Here is my C file: #include... term_t tx; term_t tv; term_t goal_term; functor_t goal_functor; int main( int argc, char** argv ) { argv[0] = "libpl.dll"; PL_initialise( argc, argv ); PlCall( "consult( swi( 'plwin.rc' ) )" ); PlCall( "consult( 'likes.pl' )" ); tv = PL_new_term_ref( ); PL_put_atom_chars( tv, "john" ); tx = PL_new_term_ref( ); goal_term = PL_new_term_ref( ); goal_functor = PL_new_functor( PL_new_atom( "likes" ), 2 ); PL_cons_functor( goal_term, goal_functor, tv, tx ); PlQuery q( "likes", ??? ); while ( q.next_solution( ) ) { char* solution; PL_get_atom_chars( tx, &solution ); cout << solution << endl; } PL_halt( PL_toplevel() ? 0 : 1 ); } What should I replace ??? with? Or is this the right approach to get all the backtracking results generated and printed? Thank you,

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  • Looking for a good semantic parser for the Russian language.

    - by Gregory Gelfond
    Does anyone known of a semantic parser for the Russian language? I've attempted to configure the link-parser available from link-grammar site but to no avail. I'm hoping for a system that can run on the Mac and generate either a prolog or lisp-like representation of the parse tree (but XML output is fine as well). Thank you kindly in advance, Gregory Gelfond

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  • Can you do Logic Programming in Scala?

    - by Alex R
    I read somewhere that Pattern Matching like that supported by the match/case feature in Scala was actually borrowed from Logic languages like Prolog. Can you use Scala to elegantly solve problems like the Connected Graph problem? e.g. https://www.csupomona.edu/~jrfisher/www/prolog_tutorial/2_15.html

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  • What are the pros and cons of using manual list iteration vs recursion through fail

    - by magus
    I come up against this all the time, and I'm never sure which way to attack it. Below are two methods for processing some season facts. What I'm trying to work out is whether to use method 1 or 2, and what are the pros and cons of each, especially large amounts of facts. methodone seems wasteful since the facts are available, why bother building a list of them (especially a large list). This must have memory implications too if the list is large enough ? And it doesn't take advantage of Prolog's natural backtracking feature. methodtwo takes advantage of backtracking to do the recursion for me, and I would guess would be much more memory efficient, but is it good programming practice generally to do this? It's arguably uglier to follow, and might there be any other side effects? One problem I can see is that each time fail is called, we lose the ability to pass anything back to the calling predicate, eg. if it was methodtwo(SeasonResults), since we continually fail the predicate on purpose. So methodtwo would need to assert facts to store state. Presumably(?) method 2 would be faster as it has no (large) list processing to do? I could imagine that if I had a list, then methodone would be the way to go.. or is that always true? Might it make sense in any conditions to assert the list to facts using methodone then process them using method two? Complete madness? But then again, I read that asserting facts is a very 'expensive' business, so list handling might be the way to go, even for large lists? Any thoughts? Or is it sometimes better to use one and not the other, depending on (what) situation? eg. for memory optimisation, use method 2, including asserting facts and, for speed use method 1? season(spring). season(summer). season(autumn). season(winter). % Season handling showseason(Season) :- atom_length(Season, LenSeason), write('Season Length is '), write(LenSeason), nl. % ------------------------------------------------------------- % Method 1 - Findall facts/iterate through the list and process each %-------------------------------------------------------------- % Iterate manually through a season list lenseason([]). lenseason([Season|MoreSeasons]) :- showseason(Season), lenseason(MoreSeasons). % Findall to build a list then iterate until all done methodone :- findall(Season, season(Season), AllSeasons), lenseason(AllSeasons), write('Done'). % ------------------------------------------------------------- % Method 2 - Use fail to force recursion %-------------------------------------------------------------- methodtwo :- % Get one season and show it season(Season), showseason(Season), % Force prolog to backtrack to find another season fail. % No more seasons, we have finished methodtwo :- write('Done').

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  • XML/PHP : Content is not allowed in prolog

    - by Tristan
    Hello, i have this message error and i don't know where does the problem comes from: <?php include "DBconnection.class.php"; $sql = DBConnection::getInstance(); $requete = "SELECT g.siteweb, g.offreDedie, g.coupon, g.only_dedi, g.transparence, g.abonnement , s.GSP_nom as nom , COUNT(s.GSP_nom) as nb_votes, TRUNCATE(AVG(vote), 2) as qualite, TRUNCATE(AVG(prix), 2) as rapport, TRUNCATE(AVG(serviceClient), 2) as serviceCli, TRUNCATE(AVG(interface), 2) as interface, TRUNCATE(AVG(services), 2) as services FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ INNER JOIN gsp AS g ON s.GSP_nom = g.nom WHERE s.valide = 1 GROUP BY s.GSP_nom"; $sql->query($requete); $xml = '<?xml version="1.0" encoding="UTF-8" ?>'; $xml .='<GamerCertified>'; while($row = $sql->fetchArray()){ $moyenne_services = ($row['services'] + $row['serviceCli'] + $row['interface'] ) / 3 ; $moyenne_services = round( $moyenne_services, 2); $moyenne_ge = ($row['services'] + $row['serviceCli'] + $row['interface'] + $row['qualite'] + $row['rapport'] ) / 5 ; $moyenne_ge = round( $moyenne_ge, 2); $xml .= '<GSP>'; $xml .= '<nom>'.$row["nom"].'</nom>'; $xml .= '<nombre-votes>'.$row["nb_votes"].'</nombre-votes>'; $xml .= '<services>'.$moyenne_services.'</services>'; $xml .= '<qualite>'.$row["qualite"].'</qualite>'; $xml .= '<prix>'.$row["rapport"].'</prix>'; $xml .= '<label-transparence>'.$row["transparence"].'</label-transparence>'; $xml .= '<moyenne-generale>'.$moyenne_ge.'</moyenne-generale>'; $xml .= '<serveurs-dedies>'.$row["offreDedie"].'</serveurs-dedies>'; $xml .= '</GSP>'; } $xml .= '</GamerCertified>'; echo $xml; Thanks

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  • Does anybody have practice in programming PCMEF - architectures?

    - by Erkki
    PCMEF is an architecture style presented in the book Practical Software Engineering by Maciaszek and Liong. The layers are: P: Presentation C: Controller M: Mediator E: Entity F: Foundation. It is some kind of enchancement compared with MVC - architecture. I recommend it to interactice, data and communicating - oriented purposes. I have programmed it using Visual Prolog. Foundation in my applications is the data model (domains) for the application. PCMEF is like a simulated computer: Presentation is the display, Controller the user interface and event handling, Mediator the internal logic and data highway. Entity is the database or external interfaces and F defines the knowledge. This is a really nice small architecture. Does any other have experiance of it?

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  • How do I make a recursive list that checks company rankings?

    - by Sera
    I have a set of companies in rank order. I want my rule to check if the companies in a specified list are in rank order, and for the rule to recur until all companies in the list have been checked. I currently have the following: isOrder([]). isOrder([COM1,COM2|T]) :- rank(COM1,D), rank(COM2,E), D<E, print("in order"), isOrder([COM2|T]). However, this does not seem to work. Sometimes, the recursion goes on forever without ending, and sometimes the recursion doesn't work at all. This is when I vary the code to try and get the correct answer. Can anybody help me? I have just started Prolog and my understanding of it is severely limited. Any help would be greatly appreciated.

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  • argv Memory Allocation

    - by Joshua Green
    I was wondering if someone could tell me what I am doing wrong that I get this Unhandled Exception error message: 0xC0000005: Access violation reading location 0x0000000c. with a green pointer pointing at my first Prolog code (fid_t): Here is my header file: class UserTaskProlog { public: UserTaskProlog( ArRobot* r ); ~UserTaskProlog( ); protected: int cycles; char* argv[ 1 ]; term_t tf; term_t tx; term_t goal_term; functor_t goal_functor; ArRobot* robot; void logTask( ); }; And here is my main code: UserTaskProlog::UserTaskProlog( ArRobot* r ) : robot( r ), robotTaskFunc( this, &UserTaskProlog::logTask ) { cycles = 0; argv[ 0 ] = "libpl.dll"; argv[ 1 ] = NULL; PL_initialise( 1, argv ); PlCall( "consult( 'myPrologFile.pl' )" ); robot->addSensorInterpTask( "UserTaskProlog", 50, &robotTaskFunc ); } UserTaskProlog::~UserTaskProlog( ) { robot->remSensorInterpTask( &robotTaskFunc ); } void UserTaskProlog::logTask( ) { cycles++; fid_t fid = PL_open_foreign_frame( ); tf = PL_new_term_ref( ); PL_put_integer( tf, 5 ); tx = PL_new_term_ref( ); goal_term = PL_new_term_ref( ); goal_functor = PL_new_functor( PL_new_atom( "factorial" ), 2 ); PL_cons_functor( goal_term, goal_functor, tf, tx ); int fact; if ( PL_call( goal_term, NULL ) ) { PL_get_integer( tx, &fact ); cout << fact << endl; } PL_discard_foreign_frame( fid ); } int main( int argc, char** argv ) { ArRobot robot; ArArgumentParser argParser( &argc, argv ); UserTaskProlog talk( &robot ); } Thank you,

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  • Is my heuristic algorithm correct? (Sudoku solver)

    - by Aposperite
    First of -yes this IS a homework- but it's primarily a theoretical question rather than a practical one, I am simply asking a confirmation if I am thinking correctly or any hints if I am not. I have been asked to compile a simple Sudoku solver (on Prolog but that is not so important right now) with the only limitation being that it must utilize a heuristic function using Best-First Algorithm. The only heuristic function I have been able to come up with is explained below: 1. Select an empty cell. 1a. If there are no empty cells and there is a solution return solution. Else return No. 2. Find all possible values it can hold. %% It can't take values currently assigned to cells on the same line/column/box. 3. Set to all those values a heuristic number starting from 1. 4. Pick the value whose heuristic number is the lowest && you haven't checked yet. 4a. If there are no more values return no. 5. If a solution is not found: GoTo 1. Else Return Solution. // I am sorry for errors in this "pseudo code." If you want any clarification let me know. So am I doing this right or is there any other way around and mine is false? Thanks in advance.

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