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  • Leapfrog Crammer won't mount as a USB flash drive

    - by William
    I can't seem to get the Leapfrog Crammer study and sound system to show up as a flash drive under ubuntu so I can transfer stuff to it. I don't want to install the leapfrog bloatware, can someone help me with this? Additional Information: When I plug my crammer into my computer it shows a 1 MB file system with a link to download the crammer software. I want to know how to access the rest of the crammer's file system so I can transfer music to it. The crammer does not show any other partitions in natulius. According to an article on the internet, the crammed is divided into three partitions: One with a link to install the crammer software, one with all content(music, flash cards, etc.) and one for firmware. I want to know how to access the one with the content so I can add music to the player. Can anyone help me with this? Thanks in advance.

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  • transfer Thunderbird (17) Profile on Win7 to Ubuntu 12.04

    - by William Curran
    I want to transfer Thunderbird Profile on Win7 to thunderbird (17) Ubuntu 12.04. I already copied the profile folder from Windows to Ubuntu and modified progile.ini on the ubuntu machine to include [Profile] Name=Bill IsRelative=1 Path=(the name of the transfered profile folder) I think the problem is that the Win. TB profile content (files and folder structure) look VERY different that the that of the unbuntu TB profile's that was created on installation. The Ubuntu install is new where as the Win TB has undergone many updates. Seems the system for profile storage has changed drastically. I tried to start TB in safe mode but could't get the path correct to start TB in the terminal with the -safe-mode switch. What can I do? Bill

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  • Should I install ia32-libs or lib32stdc++ or can I just use --force-all for 32-bit printer driver

    - by William
    I got a Brother printer MFC class. The brother website only provides 32-bit drivers but I installed 64-bit Ubuntu. It says I need to install "ia32-libs" or "lib32stdc++" to install the 32-bit drivers onto 64-bit Ubuntu. Elsewhere I've read that I don't need to install these packages, I can just use --force-all when installing, but I don't know of the accuracy of this information. My questions: 1) do I HAVE to install "ia32-libs" or "lib32stdc++" or can I use --force-all to make 32-bit drivers install on 64-bit ubuntu? 2) if I do have to install "ia32-libs" or "lib32stdc++", which should I install? Which is better, which is recommended by ubuntu experts?

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  • How to install ubuntu 12.04

    - by William A. Jordan
    I've had ubuntu on my pc for about 5 years,after the new 12.04 version and a day and a half trying to get it to just boot up. I will take it off my pc and rely on windows. I have 5 pc's which I built and am not an amateur, After installing it numerous times and even to run it from your webpage (to no avail). Granted I do have nvidia drivers on it, but after I went to their webpage and downloaded and installed the linux driver it,it still would not boot, by the way I took 2 different pc's apart and used what I thought were compatible (I shouldn't have to do this) parts. I have it on a seperate hd which I will remove and format. Have a nice day and so long (2 much trouble).

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  • App not showing up in Google Play search on app name [on hold]

    - by William Jockusch
    About 30 hours ago, I released an app on Google Play. I am concerned that if you search on the exact app name, it does not show up in the results, even if you click "show more". https://play.google.com/store/search?q=free+graphing+calculator&c=apps It does show up if you put the name in quotes. But that's awfully low discoverability. https://play.google.com/store/search?q=%22free%20graphing%20calculator%22&c=apps Possibly relevant information: I had an earlier version with a different bundle ID. It was up for just an hour or so, and probably never actually visible to users. How can I fix this?

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  • Xubuntu and other Debian based distros slow

    - by William V
    I have a Compaq Presario SR1950NX desktop computer with the AMD64 3800+ processor and 1GB ram and it seems that Ubunutu, Xubuntu and Lubuntu are all laggy. Things seem to be slow such as clicking on menus and opening programs and the UI renders in peices. When using the browser the system slows down considerably. I ran the TOP command and I do notice that xorg hits 30 to 40 percent cpu when running the browsers. I have tried these distros on a spare P4 machine and it is even worse. As long as I don't have a several things open at one time I can manage to get around although sluggishly. I also notice that I can't get debian based distros to install in 64bit (crtc6 failure) only in 32bit. Can anyone tell me what is it that I might be doing wrong? I have an integrated Nvidia card and have tried several of the recommended drivers which sometimes result in no boot screen upon reboot. Thanks

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  • How do I get a server-side count on an LDAP query from Sun Java System Directory Server?

    - by cubetwo1729
    I wish to count the number of objects returned from a query (but I do not need the actual objects themselves) from Sun Java System Directory Server 5.2. E.g., if I want to find all people with surname Smith, I would want something like ldapsearch -LLL -H ldaps://example.com -b "ou=people,dc=example,dc=com" "sn=Smith" but with some sort of count. Is this possible without returning all of the results?

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  • Sorting an array in PHP based on different values

    - by Jimbo
    I have an array whose elements are name, reversed_name, first_initial and second_initial. A typical row is "Aaron Smith", "Smith, Aaron", "a", "s". Each row in the array has a first_initial or second_initial value of "a". I need to display the rows alphabetically but based on the "a" part, so that either the name or reversed_name will be displayed. An example output would be: Aaron Smith Abbot, Paul Adrian Jones Anita Thompson Atherton, Susan I really have no idea how to sort the array this way so any help will be much appreciated!

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  • Javascript Regex to convert dot notation to bracket notation

    - by Tauren
    Consider this javascript: var joe = { name: "Joe Smith", location: { city: "Los Angeles", state: "California" } } var string = "{name} is currently in {location.city}, {location.state}"; var out = string.replace(/{([\w\.]+)}/g, function(wholematch,firstmatch) { return typeof values[firstmatch] !== 'undefined' ? values[firstmatch] : wholematch; }); This will output the following: Joe Smith is currently in {location.city}, {location.state} But I want to output the following: Joe Smith is currently in Los Angeles, California I'm looking for a good way to convert multiple levels of dot notation found between braces in the string into multiple parameters to be used with bracket notation, like this: values[first][second][third][etc] Essentially, for this example, I'm trying to figure out what regex string and function I would need to end up with the equivalent of: out = values[name] + " is currently in " + values["location"]["city"] + values["location"]["state"];

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  • Capture ASP output for monitoring

    - by scourge.zero
    How do I Capture ASP.NET output and then store it as temp memory so that I can use them in an application to do comparison. example. there's this site which has ASP output. Sorry I do not have server access, what I can do is view the output. The site by the way is a monitor for all users logged in and in which ever channel. output e.g. Channel 1 Username logged in (0 / 1) Username 1 1 John Smith 1 George B 0 Channel 2 Username logged in (0 / 1) Username 1 1 John Smith 0 George B 0 what I wanted to do is to capture this output and then show them this way. Username Channel 1 Channel 2 Total Username 1 1 1 2 John Smith 1 0 1 George B 0 0 0 I dont knw where to start.

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  • mySQL - Separate Lastname,Firstname and CompanyName entries from a single column

    - by Decalmo
    I've got a column in a database which contains company names, and customer names all in one field... what I'd like to do is keep the CompanyName column completely intact, but wherever there is a comma in the CompanyName I'd like to take that information and populate it into a FirstName and LastName field. So that basically... Before: CompanyName: Big Company Inc Smith, John Sue, Maggie After: CompanyName: Big Company Inc Smith, John Sue, Maggie LastName: Smith Sue FirstName: John Maggie This one is pretty dang tricky for me... Any help is greatly appreciated!

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  • Create a Font using strings pulled from a string table.

    - by Matthew Smith
    I am writing a tool to create an otf or ttc with only characters defined in our localized string table, so we can cut down memory usage. I already have the information for the Japanese characters we are using but I am unable to find an example of creating a new font based around these characters. Does anyone know of a good example or even the interface I can access to do this? I am working in C# with .NET 3.5. I am looking into Volt and TTOasm from Microsoft, but I am not sure if they will do exactly what I need. Any information is appreciated. Thanks, Matt Smith

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  • In OpenRasta is it possible to Pattern match multiple key/value pairs?

    - by Scott Littlewood
    Is it possible in OpenRasta to have a Uri pattern that allows for an array of values of the same key to be submitted and mapped to a handler method accepting an array of the query parameters. Example: Return all the contacts named Dave Smith from a collection. HTTP GET /contacts?filterBy=first&filterValue=Dave&filterBy=last&filterValue=Smith With a configuration of: What syntax would be best for the Uri string pattern matching? (Suggestions welcome) ResourceSpace.Has.ResourcesOfType<List<ContactResource>>() .AtUri("/contacts") .And.AtUri("/contacts?filterBy[]={filterBy}[]&filterValue[]={fv}[]") // Option 1 .And.AtUri("/contacts?filterBy={filterBy}[]&fv={fv}[]") // Option 2 Would map to a Handler method of: public object Get(params Filter[] filters) { /* create a Linq Expression based on the filters using dynamic linq query the repository using the Linq */ return Query.All<Contact>().Where(c => c.First == "Dave" && c.Last == "Smith").ToResource() } where Filter is defined by public class Filter { public string FilterBy { get; set; } public string FilterValue { get; set; } }

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  • Adding value to an Input field on click

    - by Wazdesign
    I have this structure on form, <input type="test" value="" id="username" /> <span class="input-value">John Smith</span> <a href="#" class="fill-input">Fill Input</a> when user click on the Fill Input , the data from span which has class input-value will be added to value, after clicking a tag the code should be look like this, <input type="test" value="john Smith" id="username" /> <span class="input-value">John Smith</span> <a href="#" class="fill-input">Fill Input</a> there are many forms element/input on the single page.

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  • Multiple key/value pairs in HTTP POST where key is the same name

    - by randombits
    I'm working on an API that accepts data from remote clients, some of which where the key in an HTTP POST almost functions as an array. In english what this means is say I have a resource on my server called "class". A class in this sense, is the type a student sits in and a teacher educates in. When the user submits an HTTP POST to create a new class for their application, a lot of the key value pairs look like: student_name: Bob Smith student_name: Jane Smith student_name: Chris Smith What's the best way to handle this on both the client side (let's say the client is cURL or ActiveResource, whatever..) and what's a decent way of handling this on the server-side if my server is a Ruby on Rails app? Need a way to allow for multiple keys with the same name and without any namespace clashing or loss of data.

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  • MySQL - display rows of names and addresses grouped by name, where name occures more than once

    - by Stoob
    I have two tables, "name" and "address". I would like to list the last_name and joined address.street_address of all last_name in table "name" that occur more than once in table "name". The two tables are joined on the column "name_id". The desired output would appear like so: 213 | smith | 123 bluebird | 14 | smith | 456 first ave | 718 | smith | 12 san antonia st. | 244 | jones | 78 third ave # 45 | 98 | jones | 18177 toronto place | Note that if the last_name "abernathy" appears only once in table "name", then "abernathy" should not be included in the result. This is what I came up with so far: SELECT name.name_id, name.last_name, address.street_address, count(*) FROM `name` JOIN `address` ON name.name_id = address.name_id GROUP BY `last_name` HAVING count(*) > 1 However, this produces only one row per last name. I'd like all the last names listed. I know I am missing something simple. Any help is appreciated, thanks!

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  • Adding valut to Input field on click

    - by Wazdesign
    I have this structure on form, <input type="test" value="" id="username" /> <span class="input-value">John Smith</span> <a href="#" class="fill-input">Fill Input</a> when user click on the Fill Input , the data from span which has class input-value will be added to value, after clicking a tag the code should be look like this, <input type="test" value="john Smith" id="username" /> <span class="input-value">John Smith</span> <a href="#" class="fill-input">Fill Input</a> there are many forms element/input on the single page. thanks!

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  • Track/Display Array Index As Part Of Cout (C++)

    - by John Smith
    Hi, I have a command line C++ program that lets you enter basic information about a person (ID number, name, age, etc.) and I want to output to a console in the following manner: ------------------------------------------------------------------- Index ID # First Name Last Name Age ------------------------------------------------------------------- 0 1234 John Smith 25 The person objects are stored in an array of Persons and I've overload the ostream (<<) operator to print out all of the fields like you see. The dashed lines and header come from a displayHdg() function. Anyhow, I have not been able to figure out how to get the proper index value for the array. Ideally, I'd like to generate the indices for each line, but all my attempts have failed. The array is looped through and each object printed in the main() function, and the ostream is overloaded in a person class, so I tried to use global variables as well as static variables, and all of those produce incorrect numbering (i.e. show 0, 1 the first time (for 2 objects), then change to 1, 2 on the next display). Any ideas?

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  • How to select only the first rows for each unique value of a column

    - by nuit9
    Let's say I have a table of customer addresses: CName | AddressLine ------------------------------- John Smith | 123 Nowheresville Jane Doe | 456 Evergreen Terrace John Smith | 999 Somewhereelse Joe Bloggs | 1 Second Ave In the table, one customer like John Smith can have multiple addresses. I need the select query for this table to return only first row found where there are duplicates in 'CName'. For this table it should return all rows except the 3rd (or 1st - any of those two addresses are okay but only one can be returned). Is there a keyword I can add to the SELECT query to filter based on whether the server has already seen the column value before?

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  • scrollTo (jQuery) won't work in firefox

    - by William
    For some reason, firefox seems to ignore my scrollTo function even though it works in chrome and safari. Here's an example link: http://blog.rainbird.me/post/2358248459/blowholes-are-awesome Chrome and Safari will automatically scroll to the top of the image (with an offset of 20 pixels) It doesn't work in firefox. I'm baffled! code: $(document).ready(function() { $(".photoShell img").lazyload({ placeholder: "http://william.rainbird.me/boston-polaroid/white.gif", threshold: 200 }); window.viewport = { height: function() { return $(window).height(); }, width: function() { return $(window).width(); }, scrollTop: function() { return $(window).scrollTop(); }, scrollLeft: function() { return $(window).scrollLeft(); } }; $(".photoShell img").hide(); $(".photoShell .caption").hide(); $(".photoShell img").load(function() { var maxWidth = viewport.width() - 40; // Max width for the image if(maxWidth > 960){ maxWidth = 960; } var maxHeight = viewport.height() - 50; // Max height for the image var ratio = 0; // Used for aspect ratio var width = $(this).width(); // Current image width var height = $(this).height(); // Current image height // Check if the current width is larger than the max if(width > maxWidth){ ratio = maxWidth / width; // get ratio for scaling image $(this).css("width", maxWidth); // Set new width $(this).css("height", height * ratio); // Scale height based on ratio height = height * ratio; // Reset height to match scaled image width = width * ratio; // Reset width to match scaled image } // Check if current height is larger than max if(height > maxHeight){ ratio = maxHeight / height; // get ratio for scaling image $(this).css("height", maxHeight); // Set new height $(this).css("width", width * ratio); // Scale width based on ratio width = width * ratio; // Reset width to match scaled image } $(this).parents('div.photoShell').css("width", $(this).width() + 22); $(this).parents('div.photoShell').addClass('loaded'); $(this).next(".caption").show(); var scrollNum = $(this).parents('div.photoShell').offset().top; $.scrollTo(scrollNum - 20, {duration: 700, axis:"y"}); $(this).fadeIn("slow"); }).each(function() { // trigger the load event in case the image has been cached by the browser if(this.complete) $(this).trigger('load'); });

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  • Limit user in sql plus to a single record in a table.

    - by BFK
    I have one employee table...this table has 5 coloumns (empname, empgsm, empsal, empaddr, empdep)...it has 10 records. i've created 10 users equivelent to the empnames coloumn in the table. When a user logs in with his empname aka username & password, he will be able to see only his record from the table. eg.Smith is an employee, a user called smith was created. when this user is in session, and types "Select * from Employee_table" he only gets the record that belongs to him, where empname is smith. how do i do this using privileges? thanks in advance

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  • ArchBeat Link-o-Rama for 2012-06-29

    - by Bob Rhubart
    Backward-compatible vs. forward-compatible: a tale of two clouds | William Vambenepe "There is the Cloud that provides value by requiring as few changes as possible. And there is the Cloud that provides value by raising the abstraction and operation level," says William Vambenepe. "The backward-compatible Cloud versus the forward-compatible Cloud." Vambenepe was a panelist on the recent ArchBeat podcast Public, Private, and Hybrid Clouds. Andrejus Baranovskis's Blog: ADF 11g PS5 Application with Customized BPM Worklist Task Flow (MDS Seeded Customization) Oracle ACE Director Andrejus Baranovskis investigates "how you can customize a standard BPM Task Flow through MDS Seeded customization." Oracle OpenWorld 2012 Music Festival If, after a day spent in sessions at Oracle Openworld, you want nothing more than to head back to your hotel for a quiet evening spent responding to email, please ignore the rest of this message. Because every night from Sept 30 to Oct 4 the streets of San Francisco will pulsate with music from a vast array of bands representing more musical styles than a single human brain an comprehend. It's the first ever Oracle Music Festival, baby, 7:00pm to 1:00am every night. Are those emails that important...? Resource Kit: Oracle Exadata - includes demos, videos, product datasheets, and technical white papers. This free resource kit includes several customer case study videos, two 3D product demos, several product datasheets, and three technical architecture white papers. Registration is required for the who don't already have a free Oracle.com membership account. Some execs contemplate making 'Bring Your Own Device' mandatory | ZDNet "Companies and agencies are recognizing that individual employees are doing a better job of handling and managing their devices than their harried and overworked IT departments – who need to focus on bigger priorities, such as analytics and cloud," says ZDNet SOA blogger Joe McKendrick. Podcast Show Notes: Public, Private, and Hybrid Clouds All three parts of this discussion are now available. Featuring a panel of leading Oracle cloud computing experts, including Dr. James Baty, Mark T. Nelson, Ajay Srivastava, and William Vambenepe, the discussion covers an overview of the various flavors of cloud computing, the importance of standards, Why cloud computing is a paradigm shift—and why it isn't, and advice on what architects need to know to take advantage of the cloud. And for those who prefer reading to listening, a complete transcript is also available. Amazon AMIs and Oracle VM templates (Cloud Migrations) Cloud migration expert Tom Laszewski shares an objective comparison of these two resources. IOUC : Blogs : Read the latest news on the global user group community - June 2012! The June 2012 edition of "Are You a Member Yet?"—the quarterly newsletter about Oracle user group communities around the world. Webcast: Introducing Identity Management 11g R2 - July 19 Date: Thursday, July 19, 2012 Time: 10am PT / 1pm ET Please join Oracle and customer executives for the launch of Oracle Identity Management 11g R2, the breakthrough technology that dramatically expands the reach of identity management to cloud and mobile environments. Thought for the Day "The most important single aspect of software development is to be clear about what you are trying to build." — Bjarne Stroustrup Source: SoftwareQuotes.com

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  • Null reading in stream images? Unable to start activity ComponentInfo

    - by lasmith
    I have reviewed a lot of similar questions regarding not being able to launch an activity but they don't seem to quite match my problem. I am working on a simple black jack game but its force quitting. I suspect there is a problem with loading up the card png images I have. Stepping through the debugger it crashes right while in the resetGame() function. I'm sure I am doing something dumb. My Logcat: 10-15 20:21:43.309: E/AndroidRuntime(2863): FATAL EXCEPTION: main 10-15 20:21:43.309: E/AndroidRuntime(2863): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.smith.blackjack/com.smith.blackjack.Main}: java.lang.NullPointerException 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2059) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2084) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread.access$600(ActivityThread.java:130) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1195) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.os.Handler.dispatchMessage(Handler.java:99) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.os.Looper.loop(Looper.java:137) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread.main(ActivityThread.java:4745) 10-15 20:21:43.309: E/AndroidRuntime(2863): at java.lang.reflect.Method.invokeNative(Native Method) 10-15 20:21:43.309: E/AndroidRuntime(2863): at java.lang.reflect.Method.invoke(Method.java:511) 10-15 20:21:43.309: E/AndroidRuntime(2863): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:786) 10-15 20:21:43.309: E/AndroidRuntime(2863): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553) 10-15 20:21:43.309: E/AndroidRuntime(2863): at dalvik.system.NativeStart.main(Native Method) 10-15 20:21:43.309: E/AndroidRuntime(2863): Caused by: java.lang.NullPointerException 10-15 20:21:43.309: E/AndroidRuntime(2863): at com.smith.blackjack.DeckOfCards.<init>(DeckOfCards.java:17) 10-15 20:21:43.309: E/AndroidRuntime(2863): at com.smith.blackjack.Main.resetGame(Main.java:98) 10-15 20:21:43.309: E/AndroidRuntime(2863): at com.smith.blackjack.Main.onCreate(Main.java:67) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.Activity.performCreate(Activity.java:5008) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1079) 10-15 20:21:43.309: E/AndroidRuntime(2863): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2023) 10-15 20:21:43.309: E/AndroidRuntime(2863): ... 11 more My androidmanifest: <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.smith.blackjack" android:versionCode="1" android:versionName="1.0" > <uses-sdk android:minSdkVersion="11" android:targetSdkVersion="15" /> <application android:icon="@drawable/ic_launcher" android:label="@string/app_name" android:theme="@style/AppTheme" > <activity android:name=".Main" android:label="@string/title_activity_main" > <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> Here is my Main.java package com.smith.blackjack; import android.os.Bundle; import android.app.Activity; import android.content.res.AssetManager; import android.graphics.drawable.Drawable; import java.io.IOException; import java.io.InputStream; import android.util.Log; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.ImageView; public class Main extends Activity { private ImageView dealerCard0; private ImageView dealerCard1; private ImageView dealerCard2; private ImageView dealerCard3; private ImageView playerCard0; private ImageView playerCard1; private ImageView playerCard2; private ImageView playerCard3; private ImageView imgResult; private Button btnDeal; private Button btnDraw; private Button btnHold; private DeckOfCards deckOfCards; private int[] dealerValues; private int dealerSum; private int dealerCardNumber; private int[] playerValues; private int playerSum; private int playerCardNumber; private InputStream dealerHiddenCard; private Card dealerCard; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); dealerCard0 = (ImageView) findViewById(R.id.dealerCard0); dealerCard1 = (ImageView) findViewById(R.id.dealerCard1); dealerCard2 = (ImageView) findViewById(R.id.dealerCard2); dealerCard3 = (ImageView) findViewById(R.id.dealerCard3); playerCard0 = (ImageView) findViewById(R.id.playerCard0); playerCard1 = (ImageView) findViewById(R.id.playerCard1); playerCard2 = (ImageView) findViewById(R.id.playerCard2); playerCard3 = (ImageView) findViewById(R.id.playerCard3); imgResult = (ImageView) findViewById(R.id.imgResult); btnDeal = (Button) findViewById(R.id.deal); btnDraw = (Button) findViewById(R.id.draw); btnHold = (Button) findViewById(R.id.hold); btnDeal.setOnClickListener(btnDealListener); btnDraw.setOnClickListener(btnDrawListener); btnHold.setOnClickListener(btnHoldListener); resetGame(); } private void resetGame(){ AssetManager assets = getAssets(); dealerValues = new int[4]; playerValues = new int[4]; dealerSum = 0; playerSum = 0; dealerCardNumber = 0; playerCardNumber = 0; for (int i = 0; i < 4; i++) { dealerValues[i] = 0; playerValues[i] = 0; } try { InputStream stream = assets.open("cardback.png"); // stream = assets.open("cardback.png"); Drawable cardImage = Drawable.createFromStream(stream, null); dealerCard0.setImageDrawable(cardImage); dealerCard1.setImageDrawable(cardImage); dealerCard2.setImageDrawable(cardImage); dealerCard3.setImageDrawable(cardImage); playerCard0.setImageDrawable(cardImage); playerCard1.setImageDrawable(cardImage); playerCard2.setImageDrawable(cardImage); playerCard3.setImageDrawable(cardImage); imgResult.setImageDrawable(cardImage); deckOfCards = new DeckOfCards(); deckOfCards.shuffle(); assets.close(); } catch (IOException e){ Log.e("Reset Game", "Error Loading", e); } } public OnClickListener btnDealListener = new OnClickListener() { // @Override public void onClick(View v) { try { AssetManager assets = getAssets(); InputStream stream; // first player card Card newCard; newCard = deckOfCards.dealCard(); playerValues[playerCardNumber] = newCard.faceValue; playerCardNumber++; stream = assets.open(newCard.File); Drawable cardImage = Drawable.createFromStream(stream, newCard.File); playerCard0.setImageDrawable(cardImage); assets.close(); // second player card newCard = deckOfCards.dealCard(); playerValues[playerCardNumber] = newCard.faceValue; playerCardNumber++; stream = assets.open(newCard.File); cardImage = Drawable.createFromStream(stream, newCard.File); playerCard1.setImageDrawable(cardImage); assets.close(); // first dealer card hidden newCard = deckOfCards.dealCard(); dealerCard = newCard; dealerValues[dealerCardNumber] = newCard.faceValue; dealerCardNumber++; dealerHiddenCard = assets.open(newCard.File); stream = assets.open("cardback.png"); cardImage = Drawable.createFromStream(stream, "cardback"); dealerCard0.setImageDrawable(cardImage); assets.close(); // second dealer card open newCard = deckOfCards.dealCard(); dealerValues[dealerCardNumber] = newCard.faceValue; dealerCardNumber++; stream = assets.open(newCard.File); cardImage = Drawable.createFromStream(stream, newCard.File); dealerCard1.setImageDrawable(cardImage); assets.close(); } catch (IOException e){ Log.e("Deal", "Error Loading", e); } }; }; public OnClickListener btnDrawListener = new OnClickListener() { // @Override public void onClick(View v) { try { AssetManager assets = getAssets(); InputStream stream; // get next player card Card newCard; newCard = deckOfCards.dealCard(); playerValues[playerCardNumber] = newCard.faceValue; playerCardNumber++; stream = assets.open(newCard.File); Drawable cardImage = Drawable.createFromStream(stream, newCard.File); switch (playerCardNumber){ case 3: playerCard2.setImageDrawable(cardImage); case 4: playerCard3.setImageDrawable(cardImage); } assets.close(); } catch (IOException e){ Log.e("Draw", "Error Loading", e); } }; }; public OnClickListener btnHoldListener = new OnClickListener() { // @Override public void onClick(View v) { Drawable cardImage; // evaluate player hand playerSum = evaluate(playerValues); if (playerSum > 21){ // player losses } // flip over the dealer hidden card cardImage = Drawable.createFromStream(dealerHiddenCard, dealerCard.File); Card newCard; InputStream stream; AssetManager assets = getAssets(); for (int i=2; i<4; i++){ dealerSum = evaluate(dealerValues); if (dealerSum < 16 ) { newCard = deckOfCards.dealCard(); dealerValues[dealerCardNumber] = newCard.faceValue; dealerCardNumber++; try { stream = assets.open(newCard.File); cardImage = Drawable.createFromStream(stream, newCard.File); switch (dealerCardNumber){ case 3: dealerCard2.setImageDrawable(cardImage); case 4: dealerCard3.setImageDrawable(cardImage); } assets.close(); } catch (IOException e){ Log.e("Draw", "Error Loading", e); } if (dealerSum < playerSum) { // player wins } if (dealerSum > playerSum){ // dealer wins } if (dealerSum == playerSum){ // it is a draw } } } }; }; public int evaluate (int[]values) { int sumCards = 0; for (int i = 0; i < 4; i++){ sumCards += values[i]; } if (sumCards > 21) { for (int i = 0; i < 4; i++){ if (values[i] == 11) { values[i] = 1; sumCards -= 10; continue; } } } return sumCards; } } My DeckOfCards class: package com.smith.blackjack; import java.util.Random; public class DeckOfCards { private Card [] deck; private int currentCard; private static final int NUMBER_OF_CARDS = 52; private static final Random randomNumbers = new Random(); public DeckOfCards () { deck = new Card[NUMBER_OF_CARDS]; currentCard = 0 ; for(int count = 0; count < deck.length; count++) { deck[count].faceValue = count + 1; } } public void shuffle () { currentCard = 0; for (int first = 0; first < deck.length; first ++){ int second = randomNumbers.nextInt(NUMBER_OF_CARDS); int temp = deck[first].faceValue; deck[first].faceValue=deck[second].faceValue; deck[second].faceValue = temp; } } public Card dealCard(){ Card temp = new Card(); temp.faceValue = 0; temp.File = ""; if(currentCard < deck.length) { temp.faceValue = deck[currentCard].faceValue / 4; int suit = deck[currentCard].faceValue % 4; String suitString = ""; switch (suit){ case 0: suitString = "c"; case 1: suitString = "d"; case 2: suitString = "h"; case 3: suitString = "s"; } Integer face = temp.faceValue / 4 ; String faceString = face.toString(); temp.File = faceString + suitString + ".png"; switch (temp.faceValue){ case 11: temp.faceValue = 10; case 12: temp.faceValue = 10; case 13: temp.faceValue = 10; } return temp; } else return temp; } }

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  • How do I Handle Ties When Ranking Results in MySQL?

    - by Laxmidi
    Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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