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  • Display arbitrary size 2d image in opengl

    - by Martin Beckett
    I need to display 2d images in opengl using textures. The image dimensions are not necessarily powers of 2. I thought of creating a larger texture and restricting the display to the part I was using but the image data will be shared with openCV so I don't want to copy data a pixel at a time into a larger texture. EDIT - it turns out that even the simplest Intel on board graphics under Windows supports none-power-of-2 textures.

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  • http error code 12019 in Ajax call

    - by Bas Hendriks
    Hi, When executing a ajax call i received a http error code 12019. This call works most of the time, but in rare occasions i get this errorcall. I found that this error code is described as "The requested operation cannot be carried out because the handle supplied is not in the correct state." (@msdn). Can anybody tell me what this means? Thanx, Bas Hendriks

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  • How do you display a binary search tree?

    - by fakeit
    I'm being asked to display a binary search tree in sorted order. The nodes of the tree contain strings. I'm not exactly sure what the best way is to attack this problem. Should I be traversing the tree and displaying as I go? Should I flatten the tree into an array and then use a sorting algorithm before I display? I'm not looking for the actual code, just a guide where to go next.

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  • CollectionViewSource & Selective Column Display

    - by Berryl
    By selective column display i mean the following: a control shows a listing of widgets (WidgetVm.DisplayName), with the default display name being in English (WidgetVm.EnglishName), but with the option to show the widget in French (WidgetVm.FrenchName). There also sorting and filtering available, which is why CollectionViewSource seems ideal. I know you can have multiple views over the same source but I haven't figured out how to do this yet. Is that the right approach to solving this? How? Cheers, Berryl

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  • Swift : missing argument label 'xxx' in call

    - by henry4343
    func say(name:String, msg:String) { println("\(name) say \(msg)") } say("Henry","Hi,Swift") <---- error because missing argument label 'msg' in call I need to use say("Henry",msg:"Hi,Swift") Why ? If I put more than two var in func so that I need to write var name instead of first var when I call this func It's really trouble, and I don't see any explain in iBook Swift tutorial. Can someone give me a help ... Thanks

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  • alternative ways to display a list

    - by joshua
    Hi everyone, I know on how to display a list by using loop. For example, choice(a):-write('This is the top 15 countries list:'),nl, loop(X). loop(X):-country(X),write(X),nl,fail. Unfortunately,I don't know on how to display list by using list.anyone can guide me?

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  • servlet--call jsp file

    - by megala
    I created servlet program it contained the following coding. ======coding public class GreetingServiceImpl extends RemoteServiceServlet implements GreetingService { public String greetServer(String input) { Cal c=new Cal(); c.call(input); return "success"; } } =========My constraints is i want to call index.jsp from this servlet how to achieve this.

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  • Android - display specific contacts information

    - by Donal Rafferty
    In my application when a user clicks on a button I want to open the contacts application and display a particular contacts information. At the minute I have this: Intent intent = new Intent(Intent.ACTION_VIEW, People.CONTENT_URI); startActivity(intent); This displays the contact application with all the contacts displayed. But how do I get it to display just one contact according to the contacts name or number?

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  • How do I call a static bool method in main.m

    - by AaronG
    This is Objective-C, in Xcode for the iPhone. I have a method in main.m: int main(int argc, char *argv[]) { NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; //I want to call the method here// int retVal = UIApplicationMain(argc, argv, nil, nil); [pool release]; return retVal; } static BOOL do_it_all () { //code here// } How do I call the do_it_all method from main.m?

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  • How do I display children in succession, as3

    - by VideoDnd
    How do I display children in succession? By succession I mean 1,2,3,4, etc. Perhapse incrementing with a loop or using a timer is what I'm after. Add, remove, appear, or disappear children, could all work. I want a simple way to display 1 child every second until I reach 10. METHODS TRYED addChild and removeChild visible !visible for loop

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  • jQuery UI Autocomplete plug-in pass in optional data for ajax call

    - by dev.e.loper
    I'm using jQuery UI Autocomplete plug-in. I'm giving it an URL to make an ajax call and retrieve data. I want to pass optional data parameters but not as part of URL. In the code they make a getJSON call and pass in 'request' parameter(which is an optional data parameter), however I don't see a way to get at this request parameter. this.source = function( request, response ) { $.getJSON( url, request, response ); };

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  • How to display specific data from a file

    - by user1067332
    My program is supposed to ask the user for firstname, lastname, and phone number till the users stops. Then when to display it asks for the first name and does a search in the text file to find all info with the same first name and display lastname and phones of the matches. import java.util.*; import java.io.*; import java.util.Scanner; public class WritePhoneList { public static void main(String[] args)throws IOException { BufferedWriter output = new BufferedWriter(new FileWriter(new File( "PhoneFile.txt"), true)); String name, lname, age; int pos,choice; try { do { Scanner input = new Scanner(System.in); System.out.print("Enter First name, last name, and phone number "); name = input.nextLine(); output.write(name); output.newLine(); System.out.print("Would you like to add another? yes(1)/no(2)"); choice = input.nextInt(); }while(choice == 1); output.close(); } catch(Exception e) { System.out.println("Message: " + e); } } } Here is the display code, when i search for a name, it finds a match but displays the last name and phone number of the same name 3 times, I want it to display all of the possible matches with the first name. import java.util.*; import java.io.*; import java.util.Scanner; public class DisplaySelectedNumbers { public static void main(String[] args)throws IOException { String name; String strLine; try { FileInputStream fstream = new FileInputStream("PhoneFile.txt"); // Get the object of DataInputStream DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); Scanner input = new Scanner(System.in); System.out.print("Enter a first name"); name = input.nextLine(); strLine= br.readLine(); String[] line = strLine.split(" "); String part1 = line[0]; String part2 = line[1]; String part3 = line[2]; //Read File Line By Line while ((strLine= br.readLine()) != null) { if(name.equals(part1)) { // Print the content on the console System.out.print("\n" + part2 + " " + part3); } } }catch (Exception e) {//Catch exception if any System.out.println("Error: " + e.getMessage()); } } }

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  • Ajax cross domain call

    - by jAndy
    Hi Folks, I know about ajax cross-domain policy. So I can't just call "http://www.google.com" over a ajax HTTP request and display the results somewhere on my site. I tried it with dataType "jsonp", that actually would work, but I get a syntax error (obviously because the received data is not json formated) Is there any other possiblity to receive/display data from a foreign domain ? iFrames follow the same policy? Kind Regards --Andy

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