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  • Redirect to hash URL

    - by r1987
    I'm building a site with a hashchange on wordpress, all working good. It just loads a single.php template file into a div. The problem is that i can still access my single url (http://www.mydomain.com/my-single-post). Since its not having any head and style tags with it, i don't want people to go over there. Also google has picked up the direct links, because I use the href attribute to load content into the div. So my question is: If someone clicks a link lets say in a forum, http://www.mydomain.com/my-single-post , is it possible to redirect him instantly to http://www.mydomain.com/#my-single-post ? I have researched that it has something to do with .htaccess, but I also have Pages, where i don't want the hash infront of the page-name.

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  • tag cloud filter help please

    - by rod
    Hi All, I have a div that contains many spans and each of those spans contains a single href. Basically it's a tag cloud. What I'd like to do is have a textbox that filters the tag cloud on KeyUp event. Any ideas or is this possible? Thanks, rodchar

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  • how to validate

    - by kumar
    I have this Calender Control I am using..user can select any date from the calender.. I need to validate the dates like Saturday and Sundays and 1/1 and 1/25.. if they select these days I need to show them Popup message not valid date? can anybody help me out.. thanks

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  • call .js file after ajax load

    - by asovgir
    I am trying to apply a .js file to a page I loaded via ajax (since ajax automatically strips the content of all the javascript). var url; var textUrl = 'local/file.js'; $('a').click(function() { url = $(this).attr('href'); $('.secondaryDiv').load(url, function() { $.getScript(textUrl, function(data, textStatus, jqxhr) { console.log(data); //data returned from getScript console.log(textStatus); //return "success" console.log(jqxhr.status); //200 }); }); return false; }); Am I approaching this the right way? I tried everything I could think of and I can't get it to work

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  • getting a slide of 'data' returned by $.ajax

    - by Thau
    With $.ajax i'm getting a page dinamicly generated via PHP code, in the HTML returned I need only one object ('lwrapper' in my code). How can I grabber 'lwrapper' from 'data' returned. this is my code $.ajax({ url: ref, //the url cache: false, success: function(data){ //code to get the slide of data //slide = $("lwrapper",data) //not working $('wrapper').html(slide); } });

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  • how to use javascript to download a file on Chrome without Chrome auto renaming file to "download"? [duplicate]

    - by user3688566
    This question already has an answer here: Is there any way to specify a suggested filename when using data: URI? 11 answers I use javascript to generate a file and download. It seems that depending on the version of chrome, the download file names can be auto renamed to 'download'. is there a way to avoid it? this is my code: var link = document.createElement("a"); link.setAttribute("href", 'data:application/octet-stream,' + 'file content here'); link.setAttribute("download", 'file1.txt'); link.click(); This is not a duplicated question because i am using the latest chrome and the previously suggested hyperlink is exactly what i am using. I think chrome v34 works fine. but once my chrome autoupdated to v35, it went back to 'download' file name.

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  • mcsCustomscrollbar append new content not working

    - by Dariel Pratama
    i have this script in my website. $(document).ready(function(){ var comment = $('textarea[name=comment_text]').val(); var vid = $('input[name=video_id]').val(); $('#add_comment').on('click', function(){ $.post('<?php echo site_url('comment/addcomments'); ?>', $('#comment-form').serialize(), function(data){ data = JSON.parse(data); if(data.userdata){ var date = new Date(data.userdata.comment_create_time * 1000); var picture = data.userdata.user_image.length > 0 ? 'fileupload/'+data.userdata.user_image:'images/no_pic.gif'; var newComment = '<div class="row">\ <div class="col-md-4">\ <img src="<?php echo base_url(); ?>'+picture+'" class="profile-pic margin-top-15" />\ </div>\ <div class="col-md-8 no-pade">\ <p id="comment-user" class="margin-top-15">'+data.userdata.user_firstname+' '+data.userdata.user_lastname+'</p>\ <p id="comment-time">'+date.getTime()+'</p>\ </div>\ <div class="clearfix"></div>\ <div class="col-md-12 margin-top-15" id="comment-text">'+data.userdata.comment_text +'</div>\ <div class="col-md-12">\ <div class="hr-grey margin-top-15"></div>\ </div>\ </div>'; $('#comment-scroll').append($(newComment)); $('#comment').modal('hide'); } }); }); }); what i expect when a comment added to the DB and the PHP page give JSON response, the new comment will be added to the last line of $('#comment-scroll'). #comment-scroll is also have custom scroll bar by mcsCustomscrollbar. the above script also hiding the modal dialog when comment saved and it's working fine which is mean data.userdata is not empty, but why the append() isnt?

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  • cant get ajax response (JSON) to call 'success' function?

    - by Haroldo
    for some reason the success function isnt being called? javscript: $.ajax({ type: 'POST', url: 'http://localhost/hf_latest_desktop/st_pages/user_area/acc_buttons/pass_change/pass_change_ajax.php', data: data, dataType: 'json', success: function(e){ console.log(e); if(e.status == 'success'){ alert('your password has been changed!'); } if(e.status == 'error1'){ alert('please fill in all inputs!'); } if(e.status == 'error2'){ alert('password incorrect!'); } if(e.status == 'error3'){ alert('change failed!'); } } }); php file ajax is calling to: <?php session_start(); session_cache_limiter('nocache'); header('Expires: ' . gmdate('r', 0)); header('Content-type: application/json'); $status = 'error1'; //for sake of example ?> {'status':'<?php echo $status; ?>'}

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  • fadeIn on page load

    - by Brad
    I want to fade in a background of an entry within a div - this is to show the user what the most recent entry is on page load. I want it to do it on page load, without having to click or hover or anything, just when the page loads. I have this: $(document).ready(function() { $('#box').fadeIn(5000, function() { // Animation complete }); }); Is it something like pageLoad? Any help is appreciated.

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  • Python - Submit Information on a Website to Extract Data from Resulting Page

    - by bloodstorm17
    So I am trying to figure out how to post on a website that uses a drop down menu which is holding the values like this (based on the page source): <td valign="top" align="right"><span class="emphasis">Select Item Option : </span></td> <td align="left"> <span class="notranslate"> <select name="ItemOption1"> <option value="">Select Item Option</option> <option value="321_cba">Item Option 1</option> <option value="123_abcd">Item Option 2</option> ... Now there are two of these drop down menus on top of each other. I want to be able to select an item from drop down menu 1 and drop down menu 2 and then submit the page. Now based on the code it submits the information using the following code: <td colspan="2" align="center"> <input type="submit" value="View Result" onclick="return check()"> </td> </tr> </table> <input type="hidden" name="ItemOption1" value=""> <input type="hidden" name="ItemOption2" value=""> I have no idea how to select the items in the drop down menu and then submit the page and capture the information on the resulting page into a text file. Can someone please help me with this?

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  • Slide Effect happening too many times

    - by Abs
    Hello all, I call this functions on onmouseover and onmouseout for several divs. //Takes effect on divs with id, 62,63,64,65... function slide_it(id){ $('#options_'+id).slideToggle('slow'); } The problem is that if I move my mouse over and then mouse out, then again, mouse over and then mouse out. If I do this several times, the slide effect happens the same number of times I moved my mouse over and out of the div, as expected. But I can't figure out how I can do this once? I can set a variable, but I have several divs that this function is used by and I can't think of a simple way of doing this rather than storing things into an array, but this is messy! I really appreciate any help on this that is simple to implement! Thanks all for any help

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  • serializeArray doesn't include submit-button value

    - by guzh
    Hi, I got two submit buttons in a form. One that deletes the post, and one to edit it. I want to display a fancybox with either the edit-form or a message saying that the user deleted the post. It's all decided by which button was pushed, with a "if(isset)"-sentence in edit.php. However I can't figure out how to get the value of the button within the serializeArray.. I tried with .click(function() instead, but that didn't send anything to the fancybox.. $("#form").bind("submit", function() { $.ajax({ type : "POST", cache : false, url : "edit.php", data : $(this).serializeArray(), success: function(data) { $.fancybox(data); } }); return false; }); The form looks like this: <form method='post' action='' id="form"> <input type='submit' value='Edit' name='edit' /> <input type='submit' value='Delete' name='delete' onClick="return slett('<?php echo $oppgave->name; ?>')"/> <input name='oppgaveID' type='hidden' value='<?php echo $oppgave->id; ?>' /> </form> I would really appreciate it if someone could help me! Thanks in advance!

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  • How Can I Create A Featured Content Area?

    - by ThatMacLad
    I'm working on a blog and I'd love to create a homepage with a featured post image area. I'd like it to switch between 2-3 of the latest posts images. I was wondering how I would go about doing this but so that I also have a form to update it rather than constantly editing my code.

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  • MySql - JSON data not showing in html

    - by Ramzie
    I'm trying to create a drop down list from a MySql. The php is successfully fetching the data from the MySql. But my problem is the data is not showing on the drop down list in my HTML page? json_mysql_data2.php header("Content-Type: application/json"); require_once("con.php"); $i=0; $jsonData = array(); foreach ($conn_db->query("SELECT customerID FROM customers WHERE furniture='33' ") as $result){ $i++; $jsonData["article".$i]=$result['customerID']; } echo json_encode($jsonData); myJS.js $(document).ready(function(){ var ddlist = document.getElementById("ddlist"); var hr = new XMLHttpRequest(); hr.open("GET", "json_mysql_data2.php", true); hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); hr.onreadystatechange = function() { if(hr.readyState == 4 && hr.status == 200) { var d = JSON.parse(hr.responseText); for(var o in d){ if(d[o].title){ ddlist.innerHTML += '</option><option value='+d[o].title+'</option>'; } } } } hr.send("null"); ddlist.innerHTML = "Loading Customer ID...."; }); html <script src="myJS.js" type="text/javascript"></script> </head> <body> <div class="dlist"> Customer ID: <select id='EmpLst' name="dwlist" onchange='document.getElementById("val1").value = this.value;'><option value="">SELECT STUDENT ID</option> <div id="ddlist"></div> </select> </div>

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  • Does submit() function has a callback?

    - by ecu
    Hi, I have this code: setMyCookie('name','value_1'); $('.myform').submit(); setMyCookie('name','value_2'); Problem: Webkit browsers seem to update 'MyCookie' with 'value_2' before the form gets submited, or in the exact moment it is being submited, so wrong cookie value is sent with it. I want to change cookie value to 'value_2' immediately after the form is submited so the cookie is ready for another request. The following code works fine, but I don't think using timeout() is the best solution. Maybe there is another way to solve this problem? setMyCookie('name','value_1'); $('.myform').submit(); setTimeout(function(){setMyCookie('name',value_2);},100); Thanks.

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  • how to get img src value

    - by MKN
    I have some contents inside div tag... within that div tag content I have to search for img src tag value based on that value i have to highlight some images and to show some div content for example if img src value contains "http://google.com/test/test.img" have to highlight and to show img is highlighted div content if img src value contains some specific path "news/images/test1.jpg" have to highlight and to show img is highlighted div content if img src value contains some specific path "news/articles/images/test1.gif" no need to highlight and to show img is not highlighted div content.

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  • JQuery Tabs - HTML not displayed in any other tab except default tab

    - by user346347
    I'm pretty new to jquery, but I have a tab structure working and make a $.getJSON call to retrieve the JSON results from the backend. Now, I have 3 tabs: Tab1, Tab2 and Tab3. All the three tabs have the same divs but different content. The content shows up just fine in the first tab which is shown by default, but on clicking the 2nd tab, I make the same $.getJSON call and retrieve the JSON just fine, the same HTML is being constructed on the fly and set in the DIV within the tab but it is not being displayed... Any pointers??

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