I have downloaded a lot of files in one directory, but many of them are stored with URL escaped filename, containing sign percents folowed by two hexadecimal chars, like:
ls -ltr $HOME/Downloads/
-rw-r--r-- 2 user user 13171425 24 nov 10:07 Swisscom%20Mobile%20Unlimited%20Kurzanleitung-%282011-05-12%29.pdf
-rw-r--r-- 2 user user 1525794 24 nov 10:08 31010ENY-HUAWEI%20E173u-1%20HSPA%20USB%20Stick%20Quick%20Start-%28V100R001_01%2CEnglish%2CIndia-Reliance%2CC%2Ccolor%29.pdf
...
All theses names match the following form whith exactly 3 parts:
Name of the object -( Revision, and/or Date, useless ... ). Extension
In same command, I would like to obtain unde
My goal is to having one command to rename all this files to obtain:
-rw-r--r-- 2 user user 13171425 24 nov 10:07 Swisscom_Mobile_Unlimited_Kurzanleitung.pdf
-rw-r--r-- 2 user user 1525794 24 nov 10:08 31010ENY-HUAWEI_E173u-1_HSPA_USB_Stick_Quick_Start.pdf
I've successfully do the job in full bash with:
urlunescape() {
local srce="$1" done=false part1 newname ext
while ! $done ;do
part1="${srce%%%*}"
newname="$part1\\x${srce:${#part1}+1:2}${srce:${#part1}+3}"
[ "$part1" == "$srce" ] &&
done=true ||
srce="$newname"
done
newname="$(echo -e $srce)"
ext=${newname##*.}
newname="${newname%-(*}"
echo ${newname// /_}.$ext
}
for file in *;do
mv -i "$file" "$(urlunescape "$file")"
done
ls -ltr
-rw-r--r-- 2 user user 13171425 24 nov 10:07 Swisscom_Mobile_Unlimited_Kurzanleitung.pdf
-rw-r--r-- 2 user user 1525794 24 nov 10:08 31010ENY-HUAWEI_E173u-1_HSPA_USB_Stick_Quick_Start.pdf
or using sed, tr, bash ... and sed:
for file in *;do
echo -e $(
echo $file |
sed 's/%\(..\)/\\x\1/g'
) |
sed 's/-(.*\.\([^\.]*\)$/.\1/' |
tr \ \\n _\\0 |
xargs -0 mv -i "$file"
done
ls -ltr
-rw-r--r-- 2 user user 13171425 24 nov 10:07 Swisscom_Mobile_Unlimited_Kurzanleitung.pdf
-rw-r--r-- 2 user user 1525794 24 nov 10:08 31010ENY-HUAWEI_E173u-1_HSPA_USB_Stick_Quick_Start.pdf
But, I'm sure, there must exist simplier and/or shorter way to do this.
