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  • Permission based access control

    - by jellysaini
    I am trying to implement permission based access control in ASP.NET. To implement this I have created some database tables that hold all the information about which roles are assigned what permissions and which roles are assigned to what user. I am checking the permissions in the business access layer. Right now I have created a method which checks the permissions of the user. If the user has permissions then okay otherwise it redirects to another page. I want to know if the following things are possible? class User { [PremissionCheck(UserID,ObjectName,OperationName)] public DataTable GetUser() { //coding for user } } I have seen it in MVC3. Can I Create it in ASP.NET? If yes then how can I implement it?

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  • [ask][php] find dynamic filename exist

    - by r4ccoon
    hi. i am writing a cache module in php. it tries to write a cache with a $string+timestamp as a filename. i dont have problem with writing the cache. the problem is i do a foreach loop to get the cache that i want. this is the logic that i use for getting the cache foreach ($filenames as $filename){ if(strstr($filename,$cachename)){//if found if(check_timestamp($filename,time())) display_cace($filename); break; } } but when it tries to get and read the cache, it slows the server down. imagine that i have 10000 cache file in a folder, and i need to check for every file in that cache folder. so how do you think the best way of doing this. here i explain again, because even me still dont understand my written question.. :D i write cache file with this format filename_timestamp.. e.g cache_function_random_news_191982899010 in a folder ./cache/ when i want to get the cache, i only pass "cache_function_random_news_" and check recursively on that folder. if i find something with that needle on a file name, display it, and break. but checking recursively on a 10000 files in a folder is not a good thing yeah? please give me your opinion ok, that would clarify more. thanks.

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  • Generated PersonController expects Authority to contain word ROLE

    - by Chip L
    I'm brand new to acegi and relatively new to Grails. I just followed the tutorial to set up a new role and a new user. Every time I saved the user (with a role checked), it saved the user information fine, but not the role associated with the user. I finally dug into the controller code that was generated, and noticed this: private void addRoles(person) { for (String key in params.keySet()) { if (key.contains('ROLE') && 'on' == params.get(key)) { Authority.findByAuthority(key).addToPeople(person) } } } So to be sure I was interpreting it correctly, I added the word ROLE to my authorties, and it worked like a charm. Am I missing something obvious, is this a bug, or.......? The examples showed simple role names like "user" or "manager".

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  • how to check if entity already exists in database before inserting in doctrine?

    - by fayer
    whenever i insert a entity that already exists in database (i have a unique constraint on email) i get an error message on the screen. so i want to check if it already exists, if not i insert it. at the moment it looks like this: $q = Doctrine_Query::create() ->from('User u') ->where('u.email = ?', $email); $object = $q->fetchOne(); if( ! is_object($object)) { $user = new User(); $user-email = $email; $user->save(); } i wonder, if there an easier way to do this? thanks

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  • NetBeans/C++ - how to choose the "main file" other than when creating a project?

    - by Petike
    Hello, when I am creating a C++ project in NetBeans, there is a toggle button "Create main file" - I just enter a name for it and that's all. The problem is that I cannot put that file in a "different" folder than right in the main project folder. And I am "used" to put all the source files in a "src" folder (and its subfolders), but at the "project creation time" I "cannot" put the main file there. So I tried "not" to create the main file at project creation, but after that create manually the "src" file and then create a "cpp" file in that folder (this is "allowed" in NetBeans). But NetBeans could not find "which" is the main file. So how can I choose the main file other than when creating a project (if it is possible)?

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  • Google app engine-php: script handler

    - by Eve
    I try to create php web app using GAE. In the GAE tutorial, "A script handler executes a PHP script to handle the request that matches the URL pattern. The mapping defines a URL pattern to match, and the script to be executed" Now I want to map the url with the file having same name in the folder, e.g. if the url is /hello.* , it will map the file name hello.php in the folder. And if it is /hello1.*, hello1.php in the folder will be responded to the server. I thought this should be done directly by mapping the name of the url with the name in the folder. But if I left empty for the handler in the app.yaml, I got an error. So I want to know how to set up the handler in app.yaml?

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  • How to make dll referenced by ActiveX component accessible?

    - by sherpa
    I have an ActiveX component developed in C#. I'm referencing a dll which comes with other native dlls and it is loading them on the fly expecting them to be in the same folder (probably using Assembly.GetExecutingAssembly().Location but not sure, I don't have control over them). There is also one ini file which is also expected to be in the same folder. When I run the application as Windows form app, everything is fine, of course. But the trouble comes when I run it within Internet Explorer as the base directory is at the location of iexplore.exe. Obviously neither the dlls or the ini file can be found and many temporary working files outputted by the dlls are located in Internet Explorer folder. The workaround is to copy all ddls and ini file into the ie folder but that is not something I'd be happy about. What is the proper solution to this? Can I somehow set the base path for the ActiveX component?

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  • SQL to get rows (not groups) that match an aggregate

    - by xulochavez
    Given table USER (name, city, age), what's the best way to get the user details of oldest user per city? I have seen the following example SQL used in Oracle which I think it works select name, city, age from USER, (select city as maxCity, max(age) as maxAge from USER group by city) where city=maxCity and age=maxAge So in essence: use a nested query to select the grouping key and aggregate for it, then use it as another table in the main query and join with the grouping key and the aggregate value for each key. Is this the standard SQL way of doing it? Is it any quicker than using a temporary table, or is in fact using a temporary table interanlly anyway?

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  • How to select Distinct records from SQL without a primary key

    - by Satheesh
    I need to show a Notification on user login if there is any unread messages.So if multiple users send(5 messages each) while the user is in offline these messages should be shown on login.Means have to show the last messages from each user. I use joining to find records. In this scenario Message from User is not a primary key. This is my query SELECT UserMessageConversations.MessageFrom, UserMessageConversations.MessageFromUserName,UserMessages.MessageTo, UserMessageConversations.IsGroupChat, UserMessageConversations.IsLocationChat, UserMessageConversations.Message, UserMessages.UserGroupID,UserMessages.LocationID FROM UserMessageConversations LEFT OUTER JOIN UserMessages ON UserMessageConversations.UserMessageID = UserMessages.UserMessageID ![enter image description here][1]Where UserMessageConversations.MessageTo=743 AND UserMessageConversations.ReadFlag=0 This is the output obtained from above query. MessageFrom -582 appears twice. I need only one record of this User. How is it possible

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  • How do I create a dynamic method in PHP?

    - by sandelius
    I'm trying to extend my ActiveRecord class with some dynamic methods. I would like to be able to run this from my controller $user = User::find_by_username(param); $user = User::find_by_email(param); I've read a little about overloading and think that's the key. I'v got a static $_attributes in my AR class and I get the table name by pluralizing my model (User = users) in this case. How do I do this? All models extends the ActiveRecord class.

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  • bundles in symfony 1.4?

    - by fayer
    whenever i add a feature i want to have all files (php, css, js, img etc) in one folder. i know that this bundle feature will come with symfony 2.0 but i wonder if i can have all files in one folder/plugin in symfony 1.4 cause it seems that you have to have the js/css/img in web/ folder? thanks

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  • rails active record - Advanced find

    - by par
    I have the following model setup - a User is interested in projects in many project Categories. Each Project has many categories. Like so: class User has_many :projects has_and_belongs_to_many :project_categories class Project belongs_to :user has_and_belongs_to_many :project_categories class ProjectCategory has_and_belongs_to_many :projects has_and_belongs_to_many :users Now, I'd like to do a find for projects with any of the catogories that a certain user are interested in, i.e. if a user is interested in project categories A,B,C then I'd like to find projects which are part of one or more of those project categories. Anyone?

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  • which images load the android device at the time of installation?

    - by VSC
    I am placing 20 images in hdpi folder, 20 images in mdpi folder and 20 images in ldpi folder, all are same images but different resolutions . I am placing my app in android market. One user install my app in his normal android device through market, My question is total 60 images download the device or only 20 images(mdpi) download the device at the time of install the app.Thanks for reading my question.

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  • reading files provided via $_GET

    - by Max
    I have a php script which takes a relative pathname via $_GET, reads that file and creates a thumbnail of it. I dont want the user to be able to read any file from the server. Only files from a certain directory should be allowed, otherwiese the script should exit(). Here is my folder structure: files/ <-- all files from this folder are public my_stuff/ <-- this is the folder of my script that reads the files My script is accessed via mydomain.com/my_stuff/script.php?pathname=files/some.jpg. What should not be allowed e. g.: mydomain.com/my_stuff/script.php?pathname=files/../db_login.php So, here is the relevant part of the script in my_stuff folder: ... $pathname = $_GET['pathname']; $pathname = realpath('../' . $_GET['pathname']); if(strpos($pathname, '/files/') === false) exit('Error'); ... I am not really sure about that approach, doesnt seem too safe for me. Anyone with a better idea?

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  • nested has_many

    - by Nick Vanderbilt
    I am using Rails 2.3.5. Class User < ActiveRecord::Base has_many :phones end class Phone < ActiveRecord::Base has_many :frequency_bands end I want to get all the frequency_bands for a user. I know I can write a method def freq_bands for User but I would like to know if it is possible to have has_many freq_bands for a User. In this way I can chain the call. What I would like to have is class User < ActiveRecor::Base has_many :frequence_bands, :through => phones end I think it is possible to have nested has_many using this plugin http://github.com/ianwhite/nested_has_many_through However if possible I would like to avoid using another plugin and rely solely on rails.

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  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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  • Access error in Windows 7

    - by Sathish
    I am working on a windows appliciation in which i create a folder at runtime and save some xml files in the folder.... Every thing works fine in Windows XP but when i run this in Widows 7 / Vista i get the error saying Access to the path is denied.. i am creating the folder in C:\Programfiles\MyApplication\ Please help me in resolving this

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  • Why doesn't this require_once statement find the file? (PHP)

    - by ggfan
    I not sure what's going on..maybe I missed something simple. In my connectvars.php file, I connect to the database using the variables in my config.php folder. Here's the hierarchy: admin(folder) config.php includes(folder) connectvars.php I want to get information from config.php to use in connectvars.php, so I use: require_once("../admin/config.php"); But everytime I do this I get Warning: require_once(../admin/config.php) [function.require-once]: failed to open stream: No such file or directory in /home/a8879415/public_html/includes/connectvars.php on line 2 BUT when I type: require_once("admin/config.php");, it works. I thought I had to go up a level, then go down to admin, then get config.php. So how come I just need to go into the admin folder then get config.php?

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  • Why can't I view a directory in Linux?

    - by Thread7
    I am setting up a Linux web server running apache. I uploaded and untared my web sites files. The files in the main directory are all visible when I am SSH'd into the system. However, I am blocked from all subdirectories. If I write: # cd images Then I get the error: -bash: cd: images: Permission denied I am signed in as ec2-user. I untarred the stuff as ec2-user and I doubt there was any permissions in the tar file since I created the archive on a Windows system. The weird thing is that I am the owner of this directory. Here is a snippet of the command: ls -l drw-rw-r-- 19 ec2-user ec2-user 4096 May 4 04:09 images When I do "sudo su" and then type the command cd images everything is fine. Why do I get "Permission denied" as ec2-user if I am the owner and have rw permission?

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  • How to get suggestions in NetBeans for included files

    - by Flexx
    i have a problem to get suggestions for classes which are included in included files. E.g. content of file 'Header.php' is: //File 'Header.php': include('User.php'); //Class file When I now include the Header.php in my file 'Example.php', i do not get any suggestions: //File 'Example.php': include('Header.php'); User:: After typing User:: I exspect Methods and Vars of class User as suggestions, but there arent any. If I would include 'User.php' directly in my 'Example.php' it works, but that doesn't help me. How to solve this problem?

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  • Why does this basic class not work?

    - by kalaba2003
    I could not understand why my class does no t work. Returns nothing. Is there any mistake? class User { public $first_name; public $last_name; public function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return "No name!"; } } public function assign () { $this->first_name = "Name"; $this->last_name = "Surname"; } } $user = new User(); $user->assign(); $user->full_name(); ?>

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  • generate 10 UUID records and save it it database in rails

    - by user662503
    I need to create certain number of UUId records (based on the selection of a drop down) and save them in the database. Now I am generating only one unique id. Can this be done in the model in this way? Or do I need to write a helper file for that? def generate_unique_token=(value) self.secret = Base64.encode64(UUIDTools::UUID.random_create)[0..8] end My controller: def create @secretcode = Secretcode.new(params[:secretcode]) @user = User.new(params[:user]) @secretcode.user_id = @user @secretcode.generate_unique_token = params[:secretcode][:secret] if @secretcode.valid? @secretcode.save redirect_to secretcodes_path else render 'new' end end My view page <%= form_for(@secretcode) do |f| %> <%= f.select(:secret, options_for_select([['1',1], ['10',10], ['20',20],['50',50]['100',100]])) %> <%= render 'layouts/error' %> <%=f.label :secret%> <%= f.hidden_field :user %> <%=f.submit :generate %> <% end %>

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  • Rails 2.3: using another models named_scope inside another named_scope

    - by mustafi
    Hi Let's say I have two models like so: class Comment < ActiveRecord::Base belongs_to :user named_scope :about_x :conditions => "comments.text like '%x%')" end class User < ActiveRecord::Base has_many :comments end How can I add a named_scope to the user model like so class User < ActiveRecord::Base has_many :comments named_scope :comments_about_x, :includes => :comments, :comments_named_scope => :about_x end Which allows me to do all_user_comments_about_x = User.comments_about_x The reasoning is I often need to use the comment models about_x named scope logic but I don't want to have "comments.text like '%x%')" scattered around my code. I hope this make sense :) Thank you

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  • nested has_many

    - by dorelal
    I am using Rails 2.3.5. Class User < ActiveRecord::Base has_many :phones end class Phone < ActiveRecord::Base has_many :frequency_bands end I want to get all the frequency_bands for a user. I know I can write a method def freq_bands for User but I would like to know if it is possible to have has_many freq_bands for a User. In this way I can chain the call. What I would like to have is class User < ActiveRecor::Base has_many :frequence_bands, :through => phones end I think it is possible to have nested has_many using this plugin http://github.com/ianwhite/nested_has_many_through However if possible I would like to avoid using another plugin and rely solely on rails.

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