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  • Sorted queue with dropping out elements

    - by ffriend
    I have a list of jobs and queue of workers waiting for these jobs. All the jobs are the same, but workers are different and sorted by their ability to perform the job. That is, first person can do this job best of all, second does it just a little bit worse and so on. Job is always assigned to the person with the highest skills from those who are free at that moment. When person is assigned a job, he drops out of the queue for some time. But when he is done, he gets back to his position. So, for example, at some moment in time worker queue looks like: [x, x, .83, x, .7, .63, .55, .54, .48, ...] where x's stand for missing workers and numbers show skill level of left workers. When there's a new job, it is assigned to 3rd worker as the one with highest skill of available workers. So next moment queue looks like: [x, x, x, x, .7, .63, .55, .54, .48, ...] Let's say, that at this moment worker #2 finishes his job and gets back to the list: [x, .91, x, x, .7, .63, .55, .54, .48, ...] I hope the process is completely clear now. My question is what algorithm and data structure to use to implement quick search and deletion of worker and insertion back to his position. For the moment the best approach I can see is to use Fibonacci heap that have amortized O(log n) for deleting minimal element (assigning job and deleting worker from queue) and O(1) for inserting him back, which is pretty good. But is there even better algorithm / data structure that possibly take into account the fact that elements are already sorted and only drop of the queue from time to time?

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  • If statement doesn't work? do download without filed name and email

    - by user1833871
    I've created some if / else statements to get a download when a user hit click jf he fields name and email but doesn"t work for my site http://my-easy-woodworking-projects.com because it is do download without field name and email contact.php is <?php $field_name = $_POST['cf_name']; $field_email = $_POST['cf_email']; $field_message = $_POST['cf_message']; $mail_to = '[email protected]'; $subject = 'Message from a site visitor '.$field_name; $body_message = 'From: '.$field_name."\n"; $body_message .= 'E-mail: '.$field_email."\n"; $body_message .= 'Message: '.$field_message; $headers = 'From: '.$field_email."\r\n"; $headers .= 'Reply-To: '.$field_email."\r\n"; $mail_status = mail($mail_to, $subject, $body_message, $headers); if ($mail_status) { echo <script>\n" echo "var str = \"download\"; \n"" echo "document.write(str.link("http://www.myshedplans.com/12BY8SHED.pdf"));\n" echo "</script>\n" } echo else { echo <script language="javascript" type="text/javascript"> echo // Print a message echo alert('Message failed. Please, send an email to [email protected]'); echo // Redirect to some page of the site. You can also specify full URL, e.g. http://template-help.com window.location = 'contact_page.html'; echo </script> }?>

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  • Showing the URL of the view in the address bar, instead of the one of the action

    - by aditya
    @RequestMapping(value = "updatePatient", method = RequestMethod.POST) public ModelAndView postUpdatePatientById( @ModelAttribute("patient") PatientForm patientForm, HttpSession session) { Long id = (Long) session.getAttribute("refId"); if (id != 0 || id != null) { Patient patient1 = HospitalPatientHelper .getPatientFrom_PatientForm(patientForm); patientService.updatePatient(patient1, id); PatientService patientService) { Patient patient = patientService.getPatientById(id); ModelAndView mv; PatientForm patientForm = HospitalPatientHelper .getPatientForm_FromPatient(patient); List<Weight> weights = patientService.viewLast10RecordedWeight(patient); WeightTable weightTable = new WeightTable(); List<WeightSummaryTable> summaryWeights = weightTable.summary(weights, patient.getHeight()); mv = new ModelAndView("patient1/patientDetail"); mv.addObject("patient", patientForm); mv.addObject("summaries", summaryWeights); mv.addObject("lastWeight", summaryWeights.get(0).getWeight()); mv.addObject("bmi", summaryWeights.get(0).getBmi()); return mv; } else { return new ModelAndView("patient1/patientDetail"); } } the page shown sucessfully, but the url dosn't change, means the url is not showing the address www.url.com/patient1/patientDetail.htm and i want that the returning view address should also be shown in the url too. please help me

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  • Optimization of SQL query regarding pair comparisons

    - by InfiniteSquirrel
    Hi, I'm working on a pair comparison site where a user loads a list of films and grades from another site. My site then picks two random movies and matches them against each other, the user selects the better of the two and a new pair is loaded. This gives a complete list of movies ordered by whichever is best. The database contains three tables; fm_film_data - this contains all imported movies fm_film_data(id int(11), imdb_id varchar(10), tmdb_id varchar(10), title varchar(255), original_title varchar(255), year year(4), director text, description text, poster_url varchar(255)) fm_films - this contains all information related to a user, what movies the user has seen, what grades the user has given, as well as information about each film's wins/losses for that user. fm_films(id int(11), user_id int(11), film_id int(11), grade int(11), wins int(11), losses int(11)) fm_log - this contains records of every duel that has occurred. fm_log(id int(11), user_id int(11), winner int(11), loser int(11)) To pick a pair to show the user, I've created a mySQL query that checks the log and picks a pair at random. SELECT pair.id1, pair.id2 FROM (SELECT part1.id AS id1, part2.id AS id2 FROM fm_films AS part1, fm_films AS part2 WHERE part1.id <> part2.id AND part1.user_id = [!!USERID!!] AND part2.user_id = [!!USERID!!]) AS pair LEFT JOIN (SELECT winner AS id1, loser AS id2 FROM fm_log WHERE fm_log.user_id = [!!USERID!!] UNION SELECT loser AS id1, winner AS id2 FROM fm_log WHERE fm_log.user_id = [!!USERID!!]) AS log ON pair.id1 = log.id1 AND pair.id2 = log.id2 WHERE log.id1 IS NULL ORDER BY RAND() LIMIT 1 This query takes some time to load, about 6 seconds in our tests with two users with about 800 grades each. I'm looking for a way to optimize this but still limit all duels to appear only once. The server runs MySQL version 5.0.90-community.

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  • Two "Calendar" entries listed on iPad - can't write to calendar using EventKit

    - by Neal
    My iOS app integrates with the device's calendar. On my iPad when I view the calendar app and tap the Calendars button on the top left to choose which calendars to show I see one entry named "Calendar". In my app when I loop through available calendars per the code below "Calendar" is listed twice. One is CalDAV for the type, the other is Local. I'm unable to create calendar entries in one of them, I believe the "Local" one, not sure why. Why do I see "Calendar" listed twice when I do NOT see it listed twice in the iCal app? public static List<string> Calendars { get { var calendars = new List<string>(); var ekCalendars = EventStore.Calendars; if (ekCalendars != null && ekCalendars.Length > 0) { foreach (EKCalendar cal in ekCalendars) { if (cal.AllowsContentModifications) calendars.Add(cal.Title); } calendars.Sort(); } return calendars; } }

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  • hibernate insert to a collection causes a delete then all the items in the collection to be inserted

    - by Mark
    I have a many to may relationship CohortGroup and Employee. Any time I insert an Employee into the CohortGroup hibernate deletes the group from the resolution table and inserts all the members again, plus the new one. Why not just add the new one? The annotation in the Group: @ManyToMany(cascade = { PERSIST, MERGE, REFRESH }) @JoinTable(name="MYSITE_RES_COHORT_GROUP_STAFF", joinColumns={@JoinColumn(name="COHORT_GROUPID")}, inverseJoinColumns={@JoinColumn(name="USERID")}) public List<Employee> getMembers(){ return members; } The other side in the Employee @ManyToMany(mappedBy="members",cascade = { PERSIST, MERGE, REFRESH } ) public List<CohortGroup> getMemberGroups(){ return memberGroups; } Code snipit Employee emp = edao.findByID(cohortId); CohortGroup group = cgdao.findByID(Long.decode(groupId)); group.getMembers().add(emp); cgdao.persist(group); below is the sql reported in the log delete from swas.MYSITE_RES_COHORT_GROUP_STAFF where COHORT_GROUPID=? insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) This seams really inefficient and is causing some issues. If sevral requests are made to add an employee to the group then some get over written.

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  • Nhibernate + Gridview + TargetInvocationException

    - by Scott
    For our grid views, we're setting the data sources as a list of results from an Nhibernate query. We're using lazy loading, so the objects are actually proxied... most of the time. In some instances the list will consist of types of Student and Composition_Aop_Proxy_jklasjdkl31231, which implements the same members as the Student class. We've still got the session open, so the lazy loading would resolve fine, if GridView didn't throw an error about the different types in the gridview. Our current workaround is to clone the object, which results in fetching all of the data that can be lazily loaded, even though most of it won't be accessed.. ever. This, however, converts the proxy into an actual object and the grid view is happy. The performance implications kind of scare me as we're getting closer to rolling the code out as is. I've tried evicting the object after a save, which should ensure that everything is a proxy, but this doesn't seem like a good idea either. Does anyone have any suggestions/workarounds?

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  • codeigniter mulitple LIKE db query using associative array- but all from the same column name...?

    - by Inigo
    Hi, I'm trying to query my database using codeigniter's active record class. I have a number of blog posts stored in a table. The query is for a search function, which will pull out all the posts that have certain categories assigned to them. So the 'category' column of the table will have a list of all the categories for that post in no particular order, separated by commas, like so: Politics,History,Sociology.. etc. If a user selects, say, Politics and History, The titles of all the posts that have BOTH these categories should be returned. Right? So, the list of categories queried will be the array $cats. I thought this would work- foreach ($cats as $cat){ $this->db->like('categories',$cat); } By Producing this- $this-db-like('categories','Politics'); $this-db-like('categories','History'); (Which would produce- 'WHERE categories LIKE '%Politics%' AND categories LIKE '%History%') But it doesn't work, it seems to only produce the first statement. The problem I guess is that the column name is the same for each of the chained queries. There doesn't seem to be anything in the CI user guide about this (http://codeigniter.com/user_guide/database/active_record.html) as they seem to assume that each chained statement is going to be for a different column name. Does anyone know how I could do this? Thanks! edit- Of course it is not possible to use an associative array in one statement as it would have to contain duplicate keys- in this case every key would have to be 'categories'...

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • How can I find the common ancestor of two nodes in a binary tree?

    - by Siddhant
    The Binary Tree here is not a Binary Search Tree. Its just a Binary Tree. The structure could be taken as - struct node { int data; struct node *left; struct node *right; }; The maximum solution I could work out with a friend was something of this sort - Consider this binary tree (from http://lcm.csa.iisc.ernet.in/dsa/node87.html) : The inorder traversal yields - 8, 4, 9, 2, 5, 1, 6, 3, 7 And the postorder traversal yields - 8, 9, 4, 5, 2, 6, 7, 3, 1 So for instance, if we want to find the common ancestor of nodes 8 and 5, then we make a list of all the nodes which are between 8 and 5 in the inorder tree traversal, which in this case happens to be [4, 9, 2]. Then we check which node in this list appears last in the postorder traversal, which is 2. Hence the common ancestor for 8 and 5 is 2. The complexity for this algorithm, I believe is O(n) (O(n) for inorder/postorder traversals, the rest of the steps again being O(n) since they are nothing more than simple iterations in arrays). But there is a strong chance that this is wrong. :-) But this is a very crude approach, and I'm not sure if it breaks down for some case. Is there any other (possibly more optimal) solution to this problem?

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  • sort files by date in PHP

    - by sasori
    hi, I currently have an index.php file which allows me to output the list of files inside the same directory, the output shows the names then I used filemtime() function to show the date when the file was modified. my problem now is, how will I sort the output to show the latest modified file ?, I've been thinking for awhile how to do this. if only I am doing it with mysql interaction there will be no problem at all. please show me an example how to sort and output the list of files starting from the latest modified one. this is what i have for now if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $lastModified = date('F d Y, H:i:s',filemtime($file)); if(strlen($file)-strpos($file,".swf")== 4){ echo "<tr><td><input type=\"checkbox\" name=\"box[]\"></td><td><a href=\"$file\" target=\"_blank\">$file</a></td><td>$lastModified</td></tr>"; } } } closedir($handle); }

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  • Block Cascade Json Serealize?

    - by CrazyJoe
    I have this Class: public class User { public string id{ get; set; } public string name{ get; set; } public string password { get; set; } public string email { get; set; } public bool is_broker { get; set; } public string branch_id { get; set; } public string created_at{get; set;} public string updated_at{get; set;} public UserGroup UserGroup {get;set;} public UserAddress UserAddress { get; set; } public List<UserContact> UserContact {get; set;} public User() { UserGroup = new UserGroup(); UserAddress = new UserAddress(); UserContact = new List<UserContact>(); } } I like to Serealize Only properties , how i block serealization of UserGroup, UserAdress, asn UserContact??? This is my Serealization function: public static string Serealize<T>(T obj) { System.Runtime.Serialization.Json.DataContractJsonSerializer serializer = new System.Runtime.Serialization.Json.DataContractJsonSerializer(obj.GetType()); MemoryStream ms = new MemoryStream(); serializer.WriteObject(ms, obj); return Encoding.UTF8.GetString(ms.ToArray(), 0,(int)ms.Length); }

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  • jQuery preventing RedirectToAction from working?

    - by DaveDev
    I'm trying to redirect the user if they login successfully but the code I have on my page seems to be preventing the redirection from working. If I remove the jQuery below the redirection works. Can somebody tell me tell me if there's something I'm doing wrong? Thanks I have the following Action: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Login(User user) { var myErrors = new Dictionary<string, string>(); try { if (ModelState.IsValid) { if (userRepository.ValidUser(user)) { return RedirectToAction("Index", "Group", new {page = (int?)null}); } else { return Json("Username or password seems to be incorrect"); } } else { foreach (KeyValuePair<string, ModelState> keyValuePair in ViewData.ModelState) { if (keyValuePair.Value.Errors.Count > 0) { List<string> errors = new List<string>(); myErrors.Add(keyValuePair.Key, keyValuePair.Value.Errors[0].ErrorMessage); } } return Json(myErrors); } } catch (Exception) { return Json("Invalid"); } } and the following code on my page: <script language="javascript" type="text/javascript"> $(document).ready(function() { $("#SaveSuccess").hide(); $("#btnLogin").click(function() { $("form").submit(function(event) { var formData = $(this).serialize(); $.post($(this).attr("action"), formData, function(res) { ShowErrors(res); if (res == true) { $("#SaveSuccess").text("Saved"); } else { $("#divError").html(res); } $("#SaveSuccess").fadeIn(100); }, "json"); return false; }); }); }); </script>

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  • Batch insert mode with hibernate and oracle: seems to be dropping back to slow mode silently

    - by Chris
    I'm trying to get a batch insert working with Hibernate into Oracle, according to what i've read here: http://docs.jboss.org/hibernate/core/3.3/reference/en/html/batch.html , but with my benchmarking it doesn't seem any faster than before. Can anyone suggest a way to prove whether hibernate is using batch mode or not? I hear that there are numerous reasons why it may silently drop into normal mode (eg associations and generated ids) so is there some way to find out why it has gone non-batch? My hibernate.cfg.xml contains this line which i believe is all i need to enable batch mode: <property name="jdbc.batch_size">50</property> My insert code looks like this: List<LogEntry> entries = ..a list of 100 LogEntry data classes... Session sess = sessionFactory.getCurrentSession(); for(LogEntry e : entries) { sess.save(e); } sess.flush(); sess.clear(); My 'logentry' class has no associations, the only interesting field is the id: @Entity @Table(name="log_entries") public class LogEntry { @Id @GeneratedValue public Long id; ..other fields - strings and ints... However, since it is oracle, i believe the @GeneratedValue will use the sequence generator. And i believe that only the 'identity' generator will stop bulk inserts. So if anyone can explain why it isn't running in batch mode, or how i can find out for sure if it is or isn't in batch mode, or find out why hibernate is silently dropping back to slow mode, i'd be most grateful. Thanks

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  • jquery tabbed interface breaks when using images

    - by Steve
    hello all, using jquery to create a tabbed interface. coding is quite typical: html: <div id="tabbed-interface"> <ul> <li><a href="#option1">Option1</a></li> <li><a href="#option2">Option2</a></li> <li><a href="#option3">Option3</a></li> </ul> </div> jquery: $(document).ready(function(){ $('#tabbed-interface li:first').addClass('active'); $('#tabbed-interface div').not(':first').hide(); $('#tabbed-interface>ul>li>a').click(function(event){ $('#tabbed-interface>ul>li').removeClass('active'); $(event.target).parent().addClass('active'); $('#tabbed-interface>div').fadeOut().filter(this.hash).fadeIn(250); return false;});}); css: ul li {background: #232323; list-style: none; border: 1px solid #616161; } ul li.active {background: none; list-style: none; border: 1px solid: #616161; border-bottom: 1px solid #121212; z-index: 1; } as you can see, all this does is add the class 'active' to the li that is clicked, and this corresponds to whether a background is shown or not. this works perfectly with text, but i am required to use non standard fonts. when i try to side step the issue using transparent .png images, it is unreliable. For instance, changing the HTML to: <div id="tabbed-interface"> <ul> <li><a href="#option1"><img src="option1.png" /></a></li>

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  • Fast path cache generation for a connected node graph

    - by Sukasa
    I'm trying to get a faster pathfinding mechanism in place in a game I'm working on for a connected node graph. The nodes are classed into two types, "Networks" and "Routers." In this picture, the blue circles represent routers and the grey rectangles networks. Each network keeps a list of which routers it is connected to, and vice-versa. Routers cannot connect directly to other routers, and networks cannot connect directly to other networks. Networks list which routers they're connected to Routers do the same I need to get an algorithm that will map out a path, measured in the number of networks crossed, for each possible source and destination network excluding paths where the source and destination are the same network. I have one right now, however it is unusably slow, taking about two seconds to map the paths, which becomes incredibly noticeable for all connected players. The current algorithm is a depth-first brute-force search (It was thrown together in about an hour to just get the path caching working) which returns an array of networks in the order they are traversed, which explains why it's so slow. Are there any algorithms that are more efficient? As a side note, while these example graphs have four networks, the in-practice graphs have 55 networks and about 20 routers in use. Paths which are not possible also can occur, and as well at any time the network/router graph topography can change, requiring the path cache to be rebuilt. What approach/algorithm would likely provide the best results for this type of a graph?

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  • Designing a chain of states

    - by devoured elysium
    I want to model a kind of FSM(Finite State Machine). I have a sequence of states (let's say, from StateA to StateZ). This sequence is called a Chain and is implemented internally as a List. I will add states by the order I want them to run. My purpose is to be able to make a sequence of actions in my computer (for example, mouse clicks). (I know this has been done a zillion times). So a state is defined as a: boolean Precondition() <- Checks to see if for this state, some condition is true. For example, if I want to click in the Record button of a program, in this method I would check if the program's process is running or not. If it is, go to the next state in the chain list, otherwise, go to what was defined as the fail state (generally is the first state of them all). IState GetNextState() <- Returns the next state to evaluate. If Precondition() was sucessful, it should yield the next state in the chain otherwise it should yield the fail state. Run() Simply checks the Precondition() and sets the internal data so GetNextState() works as expected. So, a naive approach to this would be something like this: Chain chain = new Chain(); //chain.AddState(new State(Precondition, FailState, NextState) <- Method structure chain.AddState(new State(new WinampIsOpenCondition(), null, new <problem here, I want to referr to a state that still wasn't defined!>); The big problem is that I want to make a reference to a State that at this point still wasn't defined. I could circumvent the problem by using strings when refrering to states and using an internal hashtable, but isn't there a clearer alternative? I could just pass only the pre-condition and failure states in the constructor, having the chain just before execution put in each state the correct next state in a public property but that seems kind of awkward.

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  • How do I convert a simple ruby flashcard program into a ROR app?

    - by Mark Wilbur
    What I'm trying to do is make a basic flashcard app on rails. At this point, all I'm looking for is the functionality to iterate through a list of flashcards, quiz the user and let the user know if they were right or not. In ruby, it didn't take me long to write: class Card attr_accessor :answer, :question def initialize(answer = "", question="") @answer = answer @question = question end def quiz puts "What does #@question mean?" answer = gets.chomp if answer == @answer puts "Right" return true else puts "Wrong" return answer end end end class Cardlist attr_accessor :Cards def initialize(Cards = []) @Cards = Cards end def quiz Cards.each do |w| w.quiz end end end The problem I'm having with rails is figuring out where to put the logic to loop through all the cards in the list. I've made models specifying that Card belongs_to cardlist and that Cardlist has_many cards. I know application logic should go in the controller, but if I were to make a "quiz" action for my Cardlist controller, how would I make it iterate through all the cards? After each "quiz" page generated, I'd need to get an answer back from the user, respond (maybe flash) whether it was right or not and then continue onto the next question. Would any of that logic have to go into the view in order to make sure it's sending back the user inputted answers to the controller?

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  • How to pick a specific object from a Linq Query using Distinct?

    - by Holli
    I have a list with two or more objects of class Agent. Name = "A" Priority = 0 ResultCount = 100 ; Name = "B" Priority = 1 ResultCount = 100 ; Both objects have the same ResultCount. In that case I only need one object and not two or more. I did this with a Linq Query with Distinct and an custom made Comparer. IEnumerable<Agent> distinctResultsAgents = (from agt in distinctUrlsAgents select agt).Distinct(comparerResultsCount); With this query I get only one object from the list but I never know which one. But I don't want just any object, I want object "B" because the Priority is higher then object "A". How can I do that? My custom Comparer is very simple and has a method like this: public bool Equals(Agent x, Agent y) { if (x == null || y == null) return false; if (x.ResultCount == y.ResultCount) return true; return false; }

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  • Most watched videos this week

    - by Jan Hancic
    I have a youtube like web-page where users upload&watch videos. I would like to add a "most watched videos this week" list of videos to my page. But this list should not contain just the videos that ware uploaded in the previous week, but all videos. I'm currently recording views in a column, so I have no information on when a video was watched. So now I'm searching for a solution to how to record this data. The first is the most obvious (and the correct one, as far as I know): have a separate table in which you insert a new line every time you want to record a new view (storing the ID of the video and the timestamp). I'm worried that I would quickly get huge amounts of data in this table, and queries using this table would be extremely slow (we get about 3 million views a month). The second solution isn't as flexible but is more easy on the database. I would add 7 columns to the "videos" table (one for each day of the week): views_monday, views_tuesday , views_wednesday, ... And increment the value in the correct column based on the day it is. And I would reset the current day's column to 0 at midnight. I could then easily get the most watched videos of the week by summing this 7 columns. What do you think, should I bother with the first solution or will the second one suffice for my case? If you have a better solution please share! Oh, I'm using MySQL.

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  • PageableListView Not rendering my data as required

    - by Robin
    i am working on wicket, where i am supposed to show my data's under <tr> <td>Name</td> <td>Single Player Score</td> <td>Double Player Score</td> <td>Total Score</td> </tr> <tr wicket:id="data"> <td wicket:id="name"></td> <td wicket:id="singlePlayerScore"></td> <td wicket:id="doublePlayerScore"></td> <td wicket:id="totalScore"></td> </tr> My Player model class is as: Player class with attributes singlePlayerScore, doublePlayerScore(), name with getter and setter and also a list data obtained from database. Data from SQLQuery is as; name score gamemode A 200 singlePlayerMode A 100 doublePLayerMode B 400 singlePlayerMode B 300 doublePLayerMode dataList == player.getScoreList(); My PageableListView is as: final PageableListView listView = new PageableListView("data",dataList,10){ @Override protected void populateItem(Item item){ player = (Player)item.getModelObject(); item.add(Label("name",player.getName())); item.add(Label("singlePlayerScore",player.getName())); item.add(Label("doublePlayerScore",player.getName())); item.add(Label("totalScore",String.valueOf(player.getSinglePlayerScore()+player.getDoublePlayerScore()))); } } My Problem is as: What view i get is as: Name single Player Score Double Player Score Total Score A 0 100 100 A 200 0 200 B 0 300 300 B 400 0 400 How do i achieve below view on my webpage? Name single Player Score Double Player Score Total Score A 200 100 300 B 400 300 700 Please help me as to why is this happening? I guess my list has size four that's one reason why as to it is rendering the view? So what can i do to get as require rendering view?

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  • ListView - Index and Position Behavior upon restart()

    - by tunneling
    I am using a ListView with an ArrayAdapter that holds objects. When I select an item, I am capturing the position and index of the selected item. If I scroll down prior to selection, the position and index represent the location of the item in the list. Selecting that items takes me to another activity. When I use the back button to return to the list, it seems that the ListView get's a new position and index for the visible items. As a result, I can't figure out how to reference the selected item during the restart() of the ListView Activity. I have tried to caputure position and index, but as I've said, they change upon returning to the Activity. Is my understanding of the ListView "redraw" correct? Does it renumber my items based on what's visible? -When in the life cycle is getView() called? Is there a way to force an update to the ListView so that my caputured index still points to the same object? Thanks, Jason

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  • Why do I get null objects in a many-to-many bag?

    - by Jim Geurts
    I have a bag defined for a many-to-many list: <class name="Author" table="Authors"> <id name="Id" column="AuthorId"> <generator class="identity" /> </id> <property name="Name" /> <bag name="Books" table="Author_Book_Map" where="IsDeleted=0" fetch="join"> <key column="AuthorId" /> <many-to-many class="Book" column="BookId" where="IsDeleted=0" /> </bag> </class> If I return all author objects using something like the following, I will get what initially appeared to be duplicate Author records: Session.Query<Author>().List<Author>() The extra author objects are created when an author is mapped to Book objects that have IsDeleted = 1 and IsDeleted = 0. Rather than creating one Author object with an enumerable that contains only the books with IsDeleted = 0, it will create two author objects. The first author object has a Books enumerable that contains books with IsDeleted = 0. The second author object will contain an enumerable of null book objects. Similarly, if an object only has one book map, and that map points to a book with IsDeleted = 1, then an author object is returned with a Books collection having one null object. I'm thinking part of the problem stems from the map table objects linking to rows that satisfy the where condition on the bag object but do not meet the many-to-many where condition. This is happening with NHibernate version 3.0.0.4980. Is this a configuration issue or something else?

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  • How to load the SQL data into several ComboBox easily, am i doing the correctly or is there another way

    - by Dominic Deepan.d
    I have a Combobox to fill the data for City, State and PinCode these combobox is dopdown list and the user will pick it. and it loads once the form opens. Here is the CODE: /// CODE TO BRING A DATA FROM SQL INTO THE FORM DROP LIST /// To fill the sates from States Table cn = new SqlConnection(@"Data Source=Nick-PC\SQLEXPRESS;Initial Catalog=AutoDB;Integrated Security=True"); cmd= new SqlCommand("select * from TblState",cn); cn.Open(); SqlDataReader dr; try { dr = cmd.ExecuteReader(); while (dr.Read()) { SelectState.Items.Add(dr["State"].ToString()); } } catch (Exception ex) { MessageBox.Show(ex.Message); } finally { cn.Close(); } //To fill the Cities from City Table cn1 = new SqlConnection(@"Data Source=Nick-PC\SQLEXPRESS;Initial Catalog=AutoDB;Integrated Security=True"); cmd1 = new SqlCommand("SELECT * FROM TblCity", cn); cn.Open(); SqlDataReader ds; try { ds = cmd1.ExecuteReader(); while (ds.Read()) { SelectCity.Items.Add(ds["City"].ToString()); } } catch (Exception ex) { MessageBox.Show(ex.Message); } finally { cn1.Close(); } // To fill the Data in the Pincode from the City Table cn2 = new SqlConnection(@"Data Source=Nick-PC\SQLEXPRESS;Initial Catalog=AutoDB;Integrated Security=True"); cmd2 = new SqlCommand("SELECT (Pincode) FROM TblCity ", cn2); cn2.Open(); SqlDataReader dm; try { dm = cmd2.ExecuteReader(); while (dm.Read()) { SelectPinCode.Items.Add(dm["Pincode"].ToString()); } } catch (Exception ex) { MessageBox.Show(ex.Message); } finally { cn2.Close(); } its kinda Big, i am doing the same steps for all the combo-box, but is there a way i can merge it in a simple way.

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  • Why does this javascript code have an infinite loop?

    - by asdas
    optionElements is a 2d array. Each element has an array of length 2. These are an integer number and an element. I have a select list called linkbox, and i want to add all of the elements to the select list. The order I want them to go in is important, and is determined by the number each element has. It should be smallest to highest. So think of it like this: optionElements is: [ [5, <option>], [3, <option], [4, <option], [1, <option], [2, <option]] and it would add them to link box in order of those numbers. BUT that is not what happens. It is an infinite loop after the first time. I added the x constraint just to stop it from freezing my browser but you can ignore it. var b; var smallest; var samllestIndex; var x = 0; while(optionElements.length > 0 && ++x < 100) { smallestIndex = 0; smallest = optionElements[0][0]; b = 0; while( ++b < optionElements.length) { if(optionElements[b][0] > smallest) { smallestIndex = b; smallest = optionElements[b][0]; } } linkbox.appendChild(optionElements[smallestIndex][1]); optionElements.unshift(optionElements[smallestIndex]); } can someone point out to me where my problem is?

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