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• Need help on how to begin learning website development

  - by Golfy

  OK for the past 10 days I have been trying to figure out where to begin learning website development a dynamic one, So far everyone told me you should start with computer science and I am like What the @#$% how am I suppose to learn computer science without going to school and get a degree but I don't want a degree I just want to learn how to devlope websites. So now I am here and confused about how to put together a website. I get HTML and CSS but still have some problems designing the site now on the other had I am having trouble trying to figure out how php and database mysql is used to put together a website. I have seen videos from lynda.com and still have no Idea after I have watched the video the basic one, one that teach you the Variables, Loops, Strings ext... ok than what happens, how do you build the website with it, that is the question I am real not understand the answer to. Any help will be appreciated.

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• Returned JSON is seemingly mixed up when using jQuery Ajax

  - by Niall Paterson

  I've a php script that has the following line: echo json_encode(array('success'=>'true','userid'=>$userid, 'data' => $array)); It returns the following: { "success": "true", "userid": "1", "data": [ { "id": "1", "name": "Trigger", "image": "", "subtitle": "", "description": "", "range1": null, "range2": null, "range3": null }, { "id": "2", "name": "DWS", "image": "", "subtitle": "", "description": "", "range1": null, "range2": null, "range3": null } ] } But when I call a jQuery ajax as below: $.ajax({ type: 'POST', url: 'url', crossDomain: true, data: {name: name}, success: function(success, userid, data) { if (success = true) { document.write(userid); document.write(success); } } }); The userid is 'success'. The actual success one works, its true. Is this malformed data being returned? Or is it simply my code? Thanks in advance, Niall

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• how to have defined connection within function for pdo communication with DB

  - by Scarface

  hey guys I just started trying to convert my query structure to PDO and I have come across a weird problem. When I call a pdo query connection within a function and the connection is included outside the function, the connection becomes undefined. Anyone know what I am doing wrong here? I was just playing with it, my example is below. include("includes/connection.php"); function query(){ $user='user'; $id='100'; $sql = 'SELECT * FROM users'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($user, $id)); // now iterate over the result as if we obtained // the $stmt in a call to PDO::query() while($r = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "$r[username] $r[id] \n"; } } query();

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• Action "foo/foobar" does not exist error in Symfony

  - by morpheous

  I am saving pictures under my web folder in the folder: web/media/photo In the template that displays the photo, I have the following snippet: <?php echo link_to(image_tag('media/photo/filename.jpg', '@some_url); ?> When I display the view, although the photo is displayed correctly and the link works, I get the following error in my php_errors.log file: Action "media/photo" does not exist. Why is symfony trying to parse the path to the image as a url? Does anyone know how to fix this?

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• Extending mysqli and using multiple classes

  - by Mikk

  Hi, I'm new to PHP oop stuff. I'm trying to create class database and call other classes from it. Am I doing it the right way? class database: class database extends mysqli { private $classes = array(); public function __construct() { parent::__construct('localhost', 'root', 'password', 'database'); if (mysqli_connect_error()) { $this->error(mysqli_connect_errno(), mysqli_connect_error()); } } public function __call($class, $args) { if (!isset($this->classes[$class])) { $class = 'db_'.$class; $this->classes[$class] = new $class(); } return $this->classes[$class]; } private function error($eNo, $eMsg) { die ('MySQL error: ('.$eNo.': '.$eMsg); } } class db_users: class db_users extends database { public function test() { echo 'foo'; } } and how I'm using it $db = new database(); $db->users()->test(); Is it the right way or should it be done another way? Thank you.

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• Remove trailing slash from comment form

  - by Sergio Vargott

  and i really need a code to remove the ending slash when a user put their link. for example i need them to put their url to grab their avatar, but in some cases they put their url ending with a slash (.com/) how can i remove that slash automatically? because when they put their url like that the avatar doesn't show i need them to end like this (.com) in order to show their avatar. I was looking for a remove trailing slash php code, but any solution will be appreciated. i tried to use this code but didn't work $string = rtrim($string, '/');

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• adding up value of array and getting the average

  - by sea_1987

  I have an array that looks similar to this, [4] => Common_Model Object ( [id] => 4 [name] => [date_created] => [last_updated] => [user_id_updated] => [_table] => [_aliases] => Array ( [id] => 4 [name] => [date_created] => [date_updated] => [user_id_updated] => [rating] => 3 [recipe_id] => 5 ) [_nonDBAliases] => Array ( ) [_default] => Array ( ) [_related] => Array ( ) [_enums] => [_alsoDelete] => Array ( ) [_readOnly] => Array ( [0] => date_updated ) [_valArgs] => Array ( ) [_valArgsHash] => Array ( [default] => Array ( ) ) [_valAliases] => Array ( ) [_extraData] => Array ( ) [_inputs] => Array ( ) [_tableName] => jm_ratings [_tablePrefix] => [_niceDateUpdated] => 1st Jan 70 [_niceDateCreated] => 1st Jan 70 [_fetchAdminData] => [_mCache] => [_assets] => Array ( ) ) [3] => Common_Model Object ( [id] => 3 [name] => [date_created] => [last_updated] => [user_id_updated] => [_table] => [_aliases] => Array ( [id] => 3 [name] => [date_created] => [date_updated] => [user_id_updated] => [rating] => 1 [recipe_id] => 5 ) [_nonDBAliases] => Array ( ) [_default] => Array ( ) [_related] => Array ( ) [_enums] => [_alsoDelete] => Array ( ) [_readOnly] => Array ( [0] => date_updated ) [_valArgs] => Array ( ) [_valArgsHash] => Array ( [default] => Array ( ) ) [_valAliases] => Array ( ) [_extraData] => Array ( ) [_inputs] => Array ( ) [_tableName] => jm_ratings [_tablePrefix] => [_niceDateUpdated] => 1st Jan 70 [_niceDateCreated] => 1st Jan 70 [_fetchAdminData] => [_mCache] => [_assets] => Array ( ) ) [2] => Common_Model Object ( [id] => 2 [name] => [date_created] => [last_updated] => [user_id_updated] => [_table] => [_aliases] => Array ( [id] => 2 [name] => [date_created] => [date_updated] => [user_id_updated] => [rating] => 1 [recipe_id] => 5 ) [_nonDBAliases] => Array ( ) [_default] => Array ( ) [_related] => Array ( ) [_enums] => [_alsoDelete] => Array ( ) [_readOnly] => Array ( [0] => date_updated ) [_valArgs] => Array ( ) [_valArgsHash] => Array ( [default] => Array ( ) ) [_valAliases] => Array ( ) [_extraData] => Array ( ) [_inputs] => Array ( ) [_tableName] => jm_ratings [_tablePrefix] => [_niceDateUpdated] => 1st Jan 70 [_niceDateCreated] => 1st Jan 70 [_fetchAdminData] => [_mCache] => [_assets] => Array ( ) ) I wanting to add up the [rating] and get the mean average. But I dont know how do this with PHP, my attempt looks like this, <?php foreach ($rt as $rating) { $total = $rating->rating + $rating->rating } $total / count($rt); ?>

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• Magento Product Details Image Size

  - by Jason

  Magento 1.4 Default Product Details image size is 265x265. All of our product images will be probably 2x taller than wide, and even if we pad them to make them square 265 will be too small to see detail in the image, so we'd like to make the image taller. I found the media.phtml file How would we go about modifying this file/Magento so that the product details page image is 265W x 530H. This looks like the code that displays the image. <p class="product-image"> <?php $_img = '<img src="'.$this->helper('catalog/image')->init($_product, 'image')->resize(265).'" alt="'.$this->htmlEscape($this->getImageLabel()).'" title="'.$this->htmlEscape($this->getImageLabel()).'" />'; echo $_helper->productAttribute($_product, $_img, 'image'); ?> </p> Thanks

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• problem during data modification

  - by nectar

  here my code - if($pin == '105') { $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level($newid); } function update_level() { //for 1st level $newid = $_SESSION['newid']; //getting senior's level 1 and to increase by 1 $sqlgetlevel = "SELECT superId,level1 FROM tbltree WHERE userID='$newid'"; echo "<br>test:".$sqlgetlevel; $result = mysql_query($sqlgetlevel,$link)or die(mysql_error()); //line 340 $row = mysql_fetch_array($result, MYSQL_ASSOC); $level1 = $row["level1"]; $level1 = $level1 + 1; //update increased level $sqlupdate = "UPDATE tbltree SET level1='$level1' WHERE userId='$newid';"; mysql_query($sqlupdate,$link)or die(mysql_error()); //change superId for new level $superid = $row["superId"]; } ERROR - test:SELECT superId,level1 FROM tbltree WHERE userID='29277640' Warning: mysql_query() expects parameter 2 to be resource, null given in C:\xampp\htdocs\303\levelupdate.php on line 340

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• Web app - Biometric system connection

  - by DMin

  Hi, I will be developing an application for a club where they will have visitors use biometric systems(finger print) or magnetic cards to mark their attendance. This application is planned as a web app, made using PHP/MySQL/Javascript. It does a lot of other things as well. What I wanted to find out is how is the interface between Biometric/Megnetic Card systems to a web app done? I've never worked on this and am hoping if someone who has experience with this can throw some light on this as to how this could be accomplished. Any pointers will be appreciated. (I'm afraid there's got to be some form of application installed on a pc that would interface with the hardware and probably makes calls to the web app. But, if there was a way to connect it to the web app directly, then the app would be easy to deploy to any location with minimal installation.) Thanks! :)

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• CDATA xml parsing extra greater than problem

  - by Ruchir Shah

  Hi, I am creating an xml using php and parsing that xml in iphone application code. In description field there is some html tags and text. I am using following line to convert this html tags in to xml tag using CDATA. $response .= '<desc><![CDATA['.trim($feed['fulltext']).']]></desc>'; Now, here my $feed['fulltext'] value is like this <span class="ABC">...text...</span> In xml I am getting following response, <desc><![CDATA[><span class"ABC">...text...</span>]]></desc> You can see here, I am getting an extra greater-than symbol just before the value of $feed['fulltext'] starts. (like this: ...text...) Any solution or suggestion for this? Thanks in advance. Cheers.

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• Why is the value not passed to my controller page in codeigniter?

  - by udaya

  I am selecting state from country and city from state. This is my country select box: <td width=""><select name="country" onChange="getState(this.value)" class="text_box_width_190"> <option value="0">Select Country</option> <? foreach($country as $row) { ?> <option value="<?=$row['dCountry_id']?>"><?=$row['dCountryName']?></option> <? } ?> </select></td> This is my state select box: <select name="state" id="state" class="text_box_width_190" > <option value="0">Select State</option> </select> This is my city select box: <td width=""><div id="citydiv"><select name="city" class="text_box_width_190"> <option>Select City</option> </select></div></td> This is my script: <script type ="text/javascript"> function getXMLHTTP() { //fuction to return the xml http object var xmlhttp=false; try{ xmlhttp=new XMLHttpRequest(); } catch(e) { try{ xmlhttp= new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ try{ xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch(e1){ xmlhttp=false; } } } return xmlhttp; } function getState(countryId) { var strURL="http://localhost/ssit/system/application/views/findState.php?country="+countryId; var req = getXMLHTTP(); if (req) { req.onreadystatechange = function() { if (req.readyState == 4) { // only if "OK" if (req.status == 200) { document.getElementById('statediv').innerHTML=req.responseText; } else { alert("There was a problem while using XMLHTTP:\n" + req.statusText); } } } req.open("GET", strURL, true); req.send(null); } } function getCity(countryId,stateId) { var strURL="http://localhost/ssit/system/application/views/findCity.php?country="+countryId+"&state="+stateId; var req = getXMLHTTP(); if (req) { req.onreadystatechange = function() { if (req.readyState == 4) { // only if "OK" if (req.status == 200) { document.getElementById('citydiv').innerHTML=req.responseText; } else { alert("There was a problem while using XMLHTTP:\n" + req.statusText); } } } req.open("GET", strURL, true); req.send(null); } } </script> This is my find state page: <? $country=intval($_GET['country']); $link = mysql_connect('localhost', 'root', ''); //changet the configuration in required if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('ssit'); $query="Select dStateName,dState_id FROM tbl_state Where dCountry_id='1'"; $result=mysql_query($query); ?> <select name="state" onchange="getCity(<?=$country?>,this.value)"> <option value="0">Select State</option> <? while($row=mysql_fetch_array($result)) { ?> <option value=<?=$row['dState_id']?>><?=$row['dStateName']?></option> <? } ?> </select> This is my find city page: <? $countryId=intval($_GET['country']); $stateId=intval($_GET['state']); $link = mysql_connect('localhost', 'root', ''); //changet the configuration in required if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('ssit'); $query="Select dCityName,dCity_id FROM tbl_city Where dState_id='30'"; $result=mysql_query($query); ?> <select name="city"> <option>Select City</option> <? while($row=mysql_fetch_array($result)) { ?> <option value><?=$row['dCityName']?></option> <? } ?> </select> When I post a country, I can receive it but I can't receive my state and city. How to receive them?

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• mysql: select ... where id = any value. is it possible?

  - by Syom

  look at this table please table |id| |name| |order| i must get the rows, where name = something and order = somevalue so i write select `id` from `table` where `name` = 'something' and `order` = 'somevalue' but depend on php logic, sometimes i need to get all rows, where name = somethimg, independently of order value. i don't want to change the query structure, because in practise there are many number of fields, and possible count of queries will became very big. so i want to save the structure of query, and when i need to select just by name, i want to write something like this select `id` from `table` where `name` = 'something' and `order` = any value is it possible? maybe the question is incomprehensible, at least i tried;) sorry for bad english thanks

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• Umbrella websites with Microsites & Blogs - recommendations

  - by pingu

  Hi guys, I'm in the process of scoping a solution for an events organisation. Their main website features information about them and blog entries etc, but they hold major events which require microsites (domain.com/event). The microsites all have a different look-and-feel, different nav structure, and custom content-managed components. The one thing that's common across everything is the blog - it will have a category for each event under which users can post. How would you guys implement this? The solution needs to be PHP, and my initial thought was CodeIgniter but if possible I'd like to avoid building the blog functionality - so I guess I could integrate it with EE or Wordpress. If anyone has any other suggestions they would be most appreciated.

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• Dynamically created image doesn't show when <img>'s src is refreshed to point to it

  - by Obay

  Hello, I have a javascript function generateGraph() { ... jQuery.get('chart.php?month='+month+'&year='+year); document.getElementById('graph').src = 'charts/'+month+'_'+year+'.png'; ... } which is called onChange. It basically creates, if not exists, or refreshes if already exists, a PNG image (using the first line above) and supposedly displays the generated image (using the second line above). The first line works, but the second one doesn't. Meaning, the image is generated, but the second line can't display the image, unless the page is reloaded, or if the image being referred to already existed before the page was loaded (meaning the 1st line just "refreshed" the image) Any ideas as to why this is and how to fix it? Thanks much for your help in advance!

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• Ajax Fancy Capture in CakPHP

  - by Constantin.FF

  I have found a nice ajax capture which i would like to use in a CakePHP framework website. The plugin can be found here: http://www.webdesignbeach.com/beachbar/ajax-fancy-captcha-jquery-plugin What I have tried: in the controller: public function index($slug = null, $capture = false) { if($capture AND $capture =="get_capture"){ $rand = rand(0,4); $_SESSION['captcha'] = $rand; echo $rand; die; } if (!empty($this->data) && $_POST['captcha'] == $_SESSION['captcha']) { .... save the post } } in the view: $selectURL = " $(function() { $('.ajax-fc-container').captcha({ borderColor: 'silver', captchaDir: 'http://localhost/img/capture', url: 'http://localhost/contacts/index/contacts/get_capture', formId: 'MessageIndexForm', }); });"; $this->Html->scriptBlock($selectURL, array('inline' => false)); also I have tried with url: 'http://localhost/js/capture.php' which is the original file coming with the plugin but still not working.

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• Screen Scraping

  - by Sambo

  Hi I'm trying to implement a screen scraping scenario on my website and have the following set so far. What I'm ultimately trying to do is replace all links in the $results variable that have "ResultsDetails.aspx?" to "results-scrape-details/" then output again. Can anyone point me in the right direction? <?php $url = "http://mysite:90/Testing/label/stuff/ResultsIndex.aspx"; $raw = file_get_contents($url); $newlines = array("\t","\n","\r","\x20\x20","\0","\x0B"); $content = str_replace($newlines, "", html_entity_decode($raw)); $start = strpos($content,"<div id='pageBack'"); $end = strpos($content,'</body>',$start) + 6; $results = substr($content,$start,$end-$start); $pattern = 'ResultsDetails.aspx?'; $replacement = 'results-scrape-details/'; preg_replace($pattern, $replacement, $results); echo $results;

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• When to alter a function vs when to just write a new one...?

  - by Andrew Heath

  /is n00b Through the gift of knowledge and expertise encoded here, I am doing my best to avoid n00b mistakes as I learn the basics of programming. I use functions when I (think I) can in PHP, and keep them somewhat sorted in different includes. The n00b problem I'm running into now is situations where perhaps 4/5th of an existing function is relevant to a new need. Maybe there are a slightly different set of inputs, or an additional calculation or two in the series, or output needs a different format/structure... but the core of the function is still applicable. Is there a good rule of thumb regarding when one should bolt-on crap to an original function and when one should (literally) copy & paste most of it into a new function and tweak to fit the situation? On the one hand I feel bad duping code, on the other I feel bad cluttering up an existing function with stuff not always needed...

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• How do I echo out something different when reached last row?

  - by Josh Brown

  I am wanting to not echo out the comma at the end of the echo after the last row. How can I do that? Here is my code: <?php header("Content-type: application/json"); echo '{"points":['; mysql_connect("localhost", "user", "password"); mysql_select_db("database"); $q = "SELECT venues.id, venues.lat, venues.lon, heat_indexes.temperature FROM venues, heat_indexes WHERE venues.id = heat_indexes.venue_id"; $res = mysql_query($q) or die(mysql_error()); while ($point = mysql_fetch_assoc($res)) { echo $point['lat'] . "," . $point['lon'] . "," . $point['temperature'] . ","; } mysql_free_result($res); echo ']}'; ?>

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• How to use soap in javascript

  - by fresher

  Hi guys, I am trying to use SOAP in javascript but i am not getting how to start it. Here is the code sample i write in PHP and it works fine. I want to write this code in Javascript. In following code i call one api from a www.example.com and for calling certain api we require to pass some parameters. $soapClient = new SoapClient("https://www.example.com/abc.aspx?WSDL"); // Prepare SoapHeader parameters $param_sh = array( ); $header = new SoapHeader('http://somesite.com/action/', 'user_credential', $param_sh); // Prepare Soap Client $soapClient->__setSoapHeaders(array($header)); // Setup the RemoteFunction parameters $param = array( "pwd" => "password", "id" => "name" ); // Call RemoteFunction () $contents = $soapClient->__call("name_of_api",array($param)); print_r($contents); Thanx in advance!!!

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• Methods to achieve first, previous, next and last navigation

  - by Koroviev

  I'm new to programming and have a question about navigation. What are the various methods that can achieve a "First", "Previous", "Next" and "Last" navigation, as seen in article or comic based sites? (Admittedly the "First" link isn't confusing as it can stay static, but what about the others?) For example, on the 50th page, the links would appropriately lead to the 49th and 51st (if it exists, if not it would not function but would automatically become active when such a page exists. In most examples of this I see urls ending with something like ".php?id=50" but am not certain how it's achieved, with a database? Any help will be very much appreciated, thanks.

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• MySQL or SQL Server

  - by user203708

  I'm creating an application that I want to run on either MySQL or SQL Server (not both at the same time) I've created two PHP classes DatabaseMySQL and DatabaseSQLSVR and I'd like my application to know which database class to use based on a constant set up at install. define(DB_TYPE, "mysql"); // or "sqlsrv" I'm trying to think of the best way to handle this. My thought is to do an "if else" wherever I instantiate the database: $db = (DB_TYPE == "mysql") ? new DatabaseMySQL : new DatabaseSQLSVR; I know there has to be a better way of doing this though. Suppose I want to add a third database type later; I'll have to go and redo all my code. Yuk!! Any help would be much appreciated. Thank

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• PDO::ATTR_EMULATE_PREPARES => false

  - by user264058

  I'm new to php and PDO ,so i read this response to a similar post- Does PDO really not use prepared statements with mysql? Yes, by default (at least with version I tested) but native mode can be turned on manually. If not, can it be forced to do so By employing PDO::ATTR_EMULATE_PREPARES setting, the name is pretty self-explanatory. $dbh-setAttribute( PDO::ATTR_EMULATE_PREPARES, false ); should you do that? That's hardest question of them all. Well, I'd say - yes, you should. If you choose PDO as your db driver, there is no point in using it in the emulation mode. by YOUR COMMON SENSE Aren't prepared statements secure from SQL injection, why change if from 'true'-false?? what is native mode??

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• How to retrieve Aggregate objects?

  - by Jebb

  In DDD, Repository takes care of saving and retrieving domain objects and also serves as collection of Aggregate Roots. My question is how do you retrieve the information for those child entities (let's say from DB) of an Aggregate where basic rule is Repository should just hold collection of Aggregate Roots (parent object) and not child objects? For example: User (parent object) Orders (child object) User domain object is stored in user table and Orders are stored in another table. Basically, retrieving a Domain Object could be like this: <?php $userRepos = new UserRepository(); $user = $userRepos->find($userId); ?> How then the child object (Orders) of User entity be retrieve to be as part of the User aggregate?

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• Can't seem to get Prototype AJAX form validation to work in conjunction with Codeigniter

  - by MattB

  Is there some kind of trick involved? Here's how I would envision it working: 1) User tries submitting the form 2) Event.observe captures this and sends an AJAX request to a special validation URL (PHP using Codeigniter) 3) If no errors were returned, continue submitting the original form 4) If errors were found, cancel form submission and display Mostly, I can't seem to get a separate AJAX validation request to work as the form continues submitting. I could use Event.stop(event), but have not found a way to re-start the process if no validation errors exist from the validation call. I'd post code, but I have about 15 examples of things I've tried and it would just clutter this question. Any ideas? :-( I didn't think form validation would be this difficult. Many thanks, - Matt

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