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  • Need to upload binary to test in-app purchase?

    - by psychotik
    Opinion seems to be split on whether an app binary is required to be uploaded to iTunes Connect before a testing an in-app purchase. I've created the app (no binary uploaded yet), created the in-app purchase, enabled by App ID for in-app purchase and marked the purchase "available for sale". I've followed the instructions in the guide as far as I can tell. However, when I try it on my device I am unable to retrieve the products - SKProductRequest returns my request product as invalid. Any suggestions what I need to do? Does the in-app purchase product need to "Developer Approved" for this to work? Any definitive answer on whether a binary needs to be uploaded? I would like to avoid that if possible but am willing to do it if required.

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  • How do I configure the binary log file for auditing in MySQL?

    - by Parth
    How to use Binary Log file for Auditing in MySQL? I want to track the change in a DB using Binary Log so that I can replicate these changes to other DB please do not give me hyperlinks for MySQL website. please direct me to find the solution EDIT I have looked for auditing options and created a script using Triggers for that, but due toi the Joomla DB structure it did'nt worked for me, hence I have to move on to Binary Log file concept now i am stucked in initiating the concept as I am not getting the concept of making the server master/slave, so can any body guide me how to actually initiate it via PHP?

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  • How to obtain the root of a tree without parsing the entire file?

    - by Matt.
    I'm making an xml parser to parse xml reports from different tools, and each tool generates different reports with different tags. For example: Arachni generates an xml report with <arachni_report></arachni_report> as tree root tag. nmap generates an xml report with <nmaprun></nmaprun> as tree root tag. I'm trying not to parse the entire file unless it's a valid report from any of the tools I want. First thing I thought to use was ElementTree, parse the entire xml file (supposing it contains valid xml), and then check based on the tree root if the report belongs to Arachni or nmap. I'm currently using cElementTree, and as far as I know getroot() is not an option here, but my goal is to make this parser to operate with recognized files only, without parsing unnecessary files. By the way, I'm Still learning about xml parsing, thanks in advance.

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  • How to create a tree with filtered nodes from drupal taxonomy.

    - by sprugman
    I'm trying to create a menu tree in drupal like this: - term 1 node 1 node 2 - sub-term 1 node 3 node 4 + sub-term 2 - sub-term 3 node 5 - sub-sub-term 1 node 6 + term 2 etc. (Sub-term 2 and term 2 are toggled closed.) Some requirements: Output this using something like JQuery Menu to get an interactive tree Filter the nodes by cck type Filter the nodes by cck field Only have terms with nodes or other active terms in them show up Mark the current node as such, and automatically open the tree to that point Do I have to write this myself, or are there a combination of modules that can do it? I've got Advanced Taxonomy Blocks, which is pretty close, but it doesn't list the nodes.

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  • How to create a SHA1 digest on a tree of objects?

    - by Torok Balint
    Let's say that I have a tree of objects of which every one have a string representation. I want to create a SHA1 digest on the whole tree. The easiest way would be to recursively go over each node of the tree. For each node I would concatenate (as simple strings) the SHA1 digests of all the children, add the string representation of the given nod to this concatenated string, and do a SHA1 on it. This would be the SHA1 digest of the given node. The question is will this digest be just as "good" as if I would have concatenated the string representation of the child nodes, and not the digests of the child nodes? Thanks

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  • Is there a Tool for see files created with binary serialization?

    - by Néstor Sánchez A.
    I've working without problems serializating object graphs to and from files. Everything was fine until today: A dictionary, created in a constructor and NEVER deleted, was lost (null referece) just after deserialization from file, for the first time in more than a year doing the same without troubles. So, is there a Software Tool to look into binary serialization content showing a human/developer-readable version (a la Reflector) of what is stored? AKA: How to analyze (easy, no binary to IL translation. That would take months) binary serialized content? Thanks!

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  • Haskell. Numbers in binary numbers. words

    - by Katja
    Hi! I need to code words into binary numbers. IN: "BCD..." OUT:1011... I have written already funktion for coding characters into siple numbers IN: 'C' OUT: 3 IN: 'c' OUT: 3 lett2num :: Char -> Int lett2num x | (ord 'A' <= ord x) && (ord x <= ord 'Z') = (ord x - ord 'A') + 1 | (ord 'a' <= ord x) && (ord x <= ord 'z') = (ord x - ord 'a') +1 num2lett :: Int -> Char num2lett n | (n <= ord 'A') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) | (n <= ord 'a') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) I wrote as well function for codind simple numbers into binary. num2bin :: Int->[Int] num2bin 0 = [] num2bin n | n>=0 = n `mod` 2 : (num2bin( n `div` 2)) | otherwise = error but I donw want those binary numbers to be in a list how can I get rid of the lists? Thanks

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  • Linux binary built for 2.0 kernel wouldn't execute on 2.6.x kernel.

    - by lorin
    I was installing a binary Linux application on Ubuntu 9.10 x86_64. The app shipped with an old version of gzip (1.2.4), that was compiled for a much older kernel: $ file gzip gzip: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.0.0, stripped I wasn't able to execute this program. If I tried, this happened: $ ./gzip -bash: ./gzip: No such file or directory ldd was similarly unhappy with this binary: $ ldd gzip not a dynamic executable This isn't a showstopper for me, since my installation has a working version of gzip I can use. But I'm curious: What's the most likely source of this problem? A corrupted file? Or a binary incompatibility due to being built for a much older {kernel,libc,...}?

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  • How to store Hierarchical K-Means tree for a large number of images, using Opencv?

    - by AquaAsh
    I am trying to make a program that will find similar images from a dataset of images. The steps are 1)extract SURF descriptors for all images 2)store the descriptors 3)Apply knn on the stored descriptors 4)Match the stored descriptors to the query image descriptor using KNN Now each images SURF descriptor will be stored as Hierarchical k means tree, now do I store each tree as a separate file or is it possible to build some sort of single tree with all the images descriptors and updated as images are added to dataset. This is the paper I am basing the program on www.ijest.info/docs/IJEST10-02-03-13.pdf.

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  • How do I write raw binary data in Python?

    - by Chris B.
    I've got a Python program that stores and writes data to a file. The data is raw binary data, stored internally as str. I'm writing it out through a utf-8 codec. However, I get UnicodeDecodeError: 'charmap' codec can't decode byte 0x8d in position 25: character maps to <undefined> in the cp1252.py file. This looks to me like Python is trying to interpret the data using the default code page. But it doesn't have a default code page. That's why I'm using str, not unicode. I guess my questions are: How do I represent raw binary data in memory, in Python? When I'm writing raw binary data out through a codec, how do I encode/unencode it?

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  • How to switch iostream from binary to text mode and vice versa?

    - by Mad Fish
    I want to read both formatted text and binary data from the same iostream. How can I do that? Why? Imagine this situation: You have different resources, and resource loaders for them, that take a std::istream as a parameter. And there are a "resource source" that provides these streams. Resources can be both text and binary and I need to handle both cases with resource loaders. Or other situation: Image that you have an archive with resources of mixed types. How can I get a text stream from inside the binary archive stream?

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  • How can I convert floating point values in text to binary using Perl?

    - by YoDar
    I have text file looks like that: float a[10] = { 7.100000e+000 , 9.100000e+000 , 2.100000e+000 , 1.100000e+000 , 8.200000e+000 , 7.220000e+000 , 7.220000e+000 , 7.222000e+000 , 1.120000e+000 , 1.987600e+000 }; unsigned int col_ind[10] = { 1 , 4 , 3 , 4 , 5 , 2 , 3 , 4 , 1 , 5 }; Now, I want to convert each array (float / unsigned int) to different binary files - big endian type. Binary file for all float values and binary file for all integer values. What is the simple way to do it in Perl, consider I have over 2 millon elements in each array?

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  • How to output list of float text to binary file in Perl ?

    - by YoDar
    Hi, I have text file looks like that: float a[10] = { 7.100000e+000 , 9.100000e+000 , 2.100000e+000 , 1.100000e+000 , 8.200000e+000 , 7.220000e+000 , 7.220000e+000 , 7.222000e+000 , 1.120000e+000 , 1.987600e+000 }; unsigned int col_ind[10] = { 1 , 4 , 3 , 4 , 5 , 2 , 3 , 4 , 1 , 5 }; Now, I want to convert each array (float / unsigned int) to different binary files - big endian type. Binary file for all float values and binary file for all integer values. What is the simple way to do it in Perl, consider I have over 2 millon elements in each array? Thanks, Yodar.

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  • Workarounds for supporting MVVM in the Silverlight TreeView Control

    - by cibrax
    MVVM (Model-View-ViewModel) is the pattern that you will typically choose for building testable user interfaces either in WPF or Silverlight. This pattern basically relies on the data binding support in those two technologies for mapping an existing model class (the view model) to the different parts of the UI or view. Unfortunately, MVVM was not threated as first citizen for some of controls released out of the box in the Silverlight runtime or the Silverlight toolkit. That means that using data binding for implementing MVVM is not always something trivial and usually requires some customization in the existing controls. In ran into different problems myself trying to fully support data binding in controls like the tree view or the context menu or things like drag & drop.  For that reason, I decided to write this post to show how the tree view control or the tree view items can be customized to support data binding in many of its properties. In first place, you will typically use a tree view for showing hierarchical data so the view model somehow must reflect that hierarchy. An easy way to implement hierarchy in a model is to use a base item element like this one, public abstract class TreeItemModel { public abstract IEnumerable<TreeItemModel> Children; } You can later derive your concrete model classes from that base class. For example, public class CustomerModel { public string FullName { get; set; } public string Address { get; set; } public IEnumerable<OrderModel> Orders { get; set; } }   public class CustomerTreeItemModel : TreeItemModel { public CustomerTreeItemModel(CustomerModel customer) { }   public override IEnumerable<TreeItemModel> Children { get { // Return orders } } } The Children property in the CustomerTreeItem model implementation can return for instance an ObservableCollection<TreeItemModel> with the orders, so the tree view will automatically subscribe to all the changes in the collection. You can bind this model to the tree view control in the UI by using a Hierarchical data template. <e:TreeView x:Name="TreeView" ItemsSource="{Binding Customers}"> <e:TreeView.ItemTemplate> <sdk:HierarchicalDataTemplate ItemsSource="{Binding Children}"> <!-- TEMPLATE --> </sdk:HierarchicalDataTemplate> </e:TreeView.ItemTemplate> </e:TreeView> An interesting behavior with the Children property and the Hierarchical data template is that the Children property is only invoked before the expansion, so you can use lazy load at this point (The tree view control will not expand the whole tree in the first expansion). The problem with using MVVM in this control is that you can not bind properties in model with specific properties of the TreeView item such as IsSelected or IsExpanded. Here is where you need to customize the existing tree view control to support data binding in tree items. public class CustomTreeView : TreeView { public CustomTreeView() { }   protected override DependencyObject GetContainerForItemOverride() { CustomTreeViewItem tvi = new CustomTreeViewItem(); Binding expandedBinding = new Binding("IsExpanded"); expandedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsExpandedProperty, expandedBinding); Binding selectedBinding = new Binding("IsSelected"); selectedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsSelectedProperty, selectedBinding); return tvi; } }   public class CustomTreeViewItem : TreeViewItem { public CustomTreeViewItem() { }   protected override DependencyObject GetContainerForItemOverride() { CustomTreeViewItem tvi = new CustomTreeViewItem(); Binding expandedBinding = new Binding("IsExpanded"); expandedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsExpandedProperty, expandedBinding); Binding selectedBinding = new Binding("IsSelected"); selectedBinding.Mode = BindingMode.TwoWay; tvi.SetBinding(CustomTreeViewItem.IsSelectedProperty, selectedBinding); return tvi; } } You basically need to derive the TreeView and TreeViewItem controls to manually add a binding for the properties you need. In the example above, I am adding a binding for the “IsExpanded” and “IsSelected” properties in the items. The model for the tree items now needs to be extended to support those properties as well, public abstract class TreeItemModel : INotifyPropertyChanged { bool isExpanded = false; bool isSelected = false;   public abstract IEnumerable<TreeItemModel> Children { get; }   public bool IsExpanded { get { return isExpanded; } set { isExpanded = value; if (PropertyChanged != null) PropertyChanged(this, new PropertyChangedEventArgs("IsExpanded")); } }   public bool IsSelected { get { return isSelected; } set { isSelected = value; if (PropertyChanged != null) PropertyChanged(this, new PropertyChangedEventArgs("IsSelected")); } }   public event PropertyChangedEventHandler PropertyChanged; } However, as soon as you use this custom tree view control, you lose all the automatic styles from the built-in toolkit themes because they are tied to the control type (TreeView in this case).  The only ugly workaround I found so far for this problem is to copy the styles from the Toolkit source code and reuse them in the application.

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  • Monkey Hunter algorithm - Interview question [closed]

    - by Estefany Velez
    Question asked in an Interview: You are a hunter in the forest. A monkey is in the trees, but you don't know where and you can't see it. You can shoot at the trees, you have unlimited ammunition. Immediately after you shoot at a tree, if the monkey was in the tree, he falls and you win. If the monkey was not in the tree, he jumps (randomly) to an adjacent tree (he has to). Find an algorithm to get the monkey in the fewest shots possible. SOLUTION: The correct answer according to me was in the comments, credit to @rtperson: You could eliminate this possibility by shooting each tree twice as you sweep left, giving you a worst case of O(2n). EDIT: ...that is, a worst case of O(2n-1). You don't need to shoot the last tree twice.

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  • How to build, sort and print a tree of a sort?

    - by Tuplanolla
    This is more of an algorithmic dilemma than a language-specific problem, but since I'm currently using Ruby I'll tag this as such. I've already spent over 20 hours on this and I would've never believed it if someone told me writing a LaTeX parser was a walk in the park in comparison. I have a loop to read hierarchies (that are prefixed with \m) from different files art.tex: \m{Art} graphical.tex: \m{Art}{Graphical} me.tex: \m{About}{Me} music.tex: \m{Art}{Music} notes.tex: \m{Art}{Music}{Sheet Music} site.tex: \m{About}{Site} something.tex: \m{Something} whatever.tex: \m{Something}{That}{Does Not}{Matter} and I need to sort them alphabetically and print them out as a tree About Me (me.tex) Site (site.tex) Art (art.tex) Graphical (graphical.tex) Music (music.tex) Sheet Music (notes.tex) Something (something.tex) That Does Not Matter (whatever.tex) in (X)HTML <ul> <li>About</li> <ul> <li><a href="me.tex">Me</a></li> <li><a href="site.tex">Site</a></li> </ul> <li><a href="art.tex">Art</a></li> <ul> <li><a href="graphical.tex">Graphical</a></li> <li><a href="music.tex">Music</a></li> <ul> <li><a href="notes.tex">Sheet Music</a></li> </ul> </ul> <li><a href="something.tex">Something</a></li> <ul> <li>That</li> <ul> <li>Doesn't</li> <ul> <li><a href="whatever.tex">Matter</a></li> </ul> </ul> </ul> </ul> using Ruby without Rails, which means that at least Array.sort and Dir.glob are available. All of my attempts were formed like this (as this part should work just fine). def fss_brace_array(ss_input)#a concise version of another function; converts {1}{2}...{n} into an array [1, 2, ..., n] or returns an empty array ss_output = ss_input[1].scan(%r{\{(.*?)\}}) rescue ss_output = [] ensure return ss_output end #define tree s_handle = File.join(:content.to_s, "*") Dir.glob("#{s_handle}.tex").each do |s_handle| File.open(s_handle, "r") do |f_handle| while s_line = f_handle.gets if s_all = s_line.match(%r{\\m\{(\{.*?\})+\}}) s_all = s_all.to_a #do something with tree, fss_brace_array(s_all) and s_handle break end end end end #do something else with tree

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  • How to encrypt and save a binary stream after serialization and read it back?

    - by Anindya Chatterjee
    I am having some problems in using CryptoStream when I want to encrypt a binary stream after binary serialization and save it to a file. I am getting the following exception System.ArgumentException : Stream was not readable. Can anybody please show me how to encrypt a binary stream and save it to a file and deserialize it back correctly? The code is as follows: class Program { public static void Main(string[] args) { var b = new B {Name = "BB"}; WriteFile<B>(@"C:\test.bin", b, true); var bb = ReadFile<B>(@"C:\test.bin", true); Console.WriteLine(b.Name == bb.Name); Console.ReadLine(); } public static T ReadFile<T>(string file, bool decrypt) { T bObj = default(T); var _binaryFormatter = new BinaryFormatter(); Stream buffer = null; using (var stream = new FileStream(file, FileMode.OpenOrCreate)) { if(decrypt) { const string strEncrypt = "*#4$%^.++q~!cfr0(_!#$@$!&#&#*&@(7cy9rn8r265&$@&*E^184t44tq2cr9o3r6329"; byte[] dv = {0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF}; CryptoStream cs; DESCryptoServiceProvider des = null; var byKey = Encoding.UTF8.GetBytes(strEncrypt.Substring(0, 8)); using (des = new DESCryptoServiceProvider()) { cs = new CryptoStream(stream, des.CreateEncryptor(byKey, dv), CryptoStreamMode.Read); } buffer = cs; } else buffer = stream; try { bObj = (T) _binaryFormatter.Deserialize(buffer); } catch(SerializationException ex) { Console.WriteLine(ex.Message); } } return bObj; } public static void WriteFile<T>(string file, T bObj, bool encrypt) { var _binaryFormatter = new BinaryFormatter(); Stream buffer; using (var stream = new FileStream(file, FileMode.Create)) { try { if(encrypt) { const string strEncrypt = "*#4$%^.++q~!cfr0(_!#$@$!&#&#*&@(7cy9rn8r265&$@&*E^184t44tq2cr9o3r6329"; byte[] dv = {0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF}; CryptoStream cs; DESCryptoServiceProvider des = null; var byKey = Encoding.UTF8.GetBytes(strEncrypt.Substring(0, 8)); using (des = new DESCryptoServiceProvider()) { cs = new CryptoStream(stream, des.CreateEncryptor(byKey, dv), CryptoStreamMode.Write); buffer = cs; } } else buffer = stream; _binaryFormatter.Serialize(buffer, bObj); buffer.Flush(); } catch(SerializationException ex) { Console.WriteLine(ex.Message); } } } } [Serializable] public class B { public string Name {get; set;} } It throws the serialization exception as follows The input stream is not a valid binary format. The starting contents (in bytes) are: 3F-17-2E-20-80-56-A3-2A-46-63-22-C4-49-56-22-B4-DA ...

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  • How can I read a binary string in C#?

    - by Sergey
    There is a php script which sends a binary string to the client application: $binary_string = pack('i',count($result_matrix)); foreach ($result_matrix as $row) { foreach ($row as $cell) { $binary_string .= pack('d',$cell); } } echo $binary_string; Silverlight application receives $binary_string via POST protocol. How can I parse this binary string? Or maybe there is a better way to send matrix from PHP to Silverlight?

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  • how to generate an N level tree using datatable?

    - by Kishore Kumar
    I have a DataTable with column ID, Name, RootID. The tree stucture is implmented using the RootId field. If the RootId is null it is considered as Root Node. How to create an Nlevel tree using the DataTale. eg. 1 Manager null, 2 Project Lead 1, 3 Test Lead 1, 4 Sr Soft Eng 2, 5 Soft eng 2, 6 HR Manager Null, 7 HR exec 6, ......

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  • How do I read a binary file in C#?

    - by tomcamara
    I have a file that exists within a text and a binary image, I need to read from 0 to 30 position the text in question, and the position on 31 would be the image in binary format. What are the steps that I have to follow to proceed with that problem? Currently, I am trying to read it using FileStream, and then I move the FileStream var to one BinaryReader as shown below: FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Read) BinaryReader br = new BinaryReader(fs) From there forward, I'm lost.

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