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  • Script working with mysql and php into a textarea and back

    - by Tribalcomm
    I am trying to write a custom script that will keep a list of strings in a textarea. Each line of the textarea will be a row from a table. The problem I have is how to work the script to allow for adding, updating, or deleting rows based on a submit. So, for instance, I currently have 3 rows in the database: john sue mark I want to be able to delete sue and add richard and it will delete the row with sue and insert a row for richard. My code so far is as follows: To query the db and list it in the textarea: $basearray = mysql_query("SELECT name FROM mytable ORDER BY name"); <textarea name="names" cols=6 rows=12>'); <?php foreach($basearray as $base){ echo $base->name."\n"; } ?> </textarea> After the submit, I have: <?php $namelist = $_REQUEST[names]; $newarray = explode("\n", $namelist); foreach($newarray as $name) { if (!in_array($name, $basearray)) { mysql_query(DELETE FROM mytable WHERE word='$name'"); } elseif (in_array($name, $basearray)) { ; } else { mysql_query("INSERT INTO mytable (name) VALUES ("$name")"); } } ?> Please tell me what I am doing wrong. I am not getting any functions to work when I edit the contents of the textarea. Thanks!

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  • Error querying database in PHP, MySQL

    - by user296516
    Hi guys, I have this code in PHP. It connects to the DB fine, but pops an error, when tryinto to insert the info. $dbc = mysqli_connect('localhost', 'root', 'marina', 'aliendatabase') or die('Error connecting to MySQL server.'); $query = "INSERT INTO aliens_abduction (name, email) VALUSE ('John', '[email protected]')"; $result = mysqli_query($dbc, $query) or die('Error querying database.'); mysqli_close($dbc); Here's a screenshot: http://img532.imageshack.us/img532/2930/63306356.jpg Thanks, R

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  • select similar values from mysql database

    - by mathew
    Hi I have several data s in MySQL database. In my table there is a column called rank. what I want is when some one enter a rank say 25 then the result should display names on similar(+ or -) ranks LIMIT to 10 from table. example mathew - 25 john - 26 joe - 25 stewart - 27 kelly - 24 brandon -23 magy - 22 .......etc. Thanks Mathew

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  • mysql real escape string error

    - by user547995
    Code mysql_query("INSERT INTO Account(User, Pw, email) VALUES('mysql_real_escape_string($_POST[user])', '$pw','mysql_real_escape_string($_POST[email]) ) ") or die(mysql_error()); Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''mysql_real_escape_string(123) )' at line 1 Please help

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  • Flex - Increase timeout on a PHP service function call

    - by Travesty3
    I'm using Flash Builder 4 Beta 2. I have it connecting to a PHP service. The way I set this up was using the wizard, so I didn't actually write the code to connect to it. The service looks like this: package services.flash { import mx.rpc.AsyncToken; import com.adobe.fiber.core.model_internal; import mx.rpc.AbstractOperation; import valueObjects.CustomDatatype8; import valueObjects.NewUsageData; import mx.collections.ItemResponder; import mx.rpc.remoting.RemoteObject; import mx.rpc.remoting.Operation; import com.adobe.fiber.services.wrapper.RemoteObjectServiceWrapper; import com.adobe.fiber.valueobjects.AvailablePropertyIterator; import com.adobe.serializers.utility.TypeUtility; [ExcludeClass] internal class _Super_FLASH extends RemoteObjectServiceWrapper { // Constructor public function _Super_FLASH() { // initialize service control _serviceControl = new RemoteObject(); var operations:Object = new Object(); var operation:Operation; operation = new Operation(null, "sendCommand"); operation.resultType = Object; operations["sendCommand"] = operation; ... } } One of the functions that I'm calling fetches users from a MySQL database. There are about 30,000 users right now. The service seems to timeout when fetching more than around 22,000 rows, I get the "Channel Disconnected before an acknowledgement was received" error. If I call the PHP script from a browser, it fetches them all with no problems at all, however. I have tried increasing the timeout in the PHP script (which didn't work), but obviously this isn't the problem since the browser is able to pull them up with no problems. Is there a way to increase the timeout of the PHP service in Flash Builder? I'm a bit of a noob when it comes to Flash, so please be descriptive. Thanks in advance!

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  • mysql query - blog posts and comments with limit

    - by Lemon
    Hi, I have 2 tables: comments and posts and I'd like to display a list of 15 posts and maximum 2 most recent comments under each blog post the database scheme looks like this posts_table: post_id, post_txt, post_timestamp comments_table: post_id, comment_txt, comment_timestamp how the mysql query should look like to select 15 posts and related comments (max 2 most recent ones per post) ??? thanks, Leo

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  • Better PHP,MySql,HTML and JavaScript IDE

    - by War Coder
    Hello guys, I am currently using the below IDE's. They serve their purposes but am wondering if there are better ones out there that i can switch to. phpDesigner v6.2.5 (For PHP) Navicat 8.0.29 (For MySql) Dreamweaver CS3 (For HTML & CSS) Spket IDE (For JavaScript) Thats my collection of production tools. Wondering if there is anyone of them i can switch to a better one. Thanks

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  • Exporting to CSV from MySQL via PHP in FireFox

    - by typoknig
    Hi all, I am pulling some info from a database with the following code: <input type="button" value="Export to Excel" onClick="window.navigate('breakfast_service.php?action=export')"> Here is the code for that action. <?php if ($_GET['action'] == 'export') { // Get the registration data $user = 'root'; $pass = 'billiards'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link) { die('Could not connect to database!' . mysql_error()); } mysql_select_db('breakfast', $link); $query = "SELECT * FROM registration"; $result = mysql_query($query); mysql_close($link); // format into CSV $contents = "id, school_id, first_name, last_name, email, attending, created_on\n"; $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++) { $row = mysql_fetch_array($result); $id = $row['id']; $school_id = $row['school_id']; $fname = $row['first_name']; $lname = $row['last_name']; $email = $row['email']; $attending = ($row['attending'] == 0) ? 'No' : 'Yes'; $date = $row['created_on']; $contents = $contents . "$id, $school_id, $fname, $lname, $email, $attending, $date\n"; } // return as excel file $filename = "export.csv"; header('Content-type: application/ms-excel'); header('Content-Disposition: attachment; filename='.$filename); echo $contents; } ?> This combination of code works excellent in IE, but fails to do create/download a file in Firefox or Chrome. Why?

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  • Select random row from MySQL (with probability)

    - by James Simpson
    I have a MySQL table that has a row called cur_odds which is a percent number with the percent probability that that row will get selected. How do I make a query that will actually select the rows in approximately that frequency when you run through 100 queries for example? I tried the following, but a row that has a probability of 0.35 ends up getting selected around 60-70% of the time. SELECT * FROM table ORDER BY RAND()*cur_odds DESC

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  • PHP & MySQL Pagination

    - by Francesc
    Hi. I have a MySQL query SELECT * FROM 'redirect' WHERE 'user_id'= \''.$_SESSION['user_id'].' \' ORDER BY 'timestamp'` I want to paginate 10 results per page. How Can I do it?

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  • Advice on how to complete specific MySQL JOIN

    - by Tim
    Hello, I have a mysql table jobs. This is the basic structure of jobs. id booked_user_id assigned_user_id I then also have another table, meta. Meta has the structure: id user_id first_name last_name How can I join these tables so that both booked_user_id and assigned_user_id can access meta.first_name? Thanks for your advice Tim

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  • MySQL Query Error

    - by Nano HE
    I am debug my php forum. Before the error,I modified the DB table name from cdb_sessions to imc_forum_sessions successfully. I tried my best to debug with NetBeans but can't find the reason. Could you please have a look at my post below. Thank you. // It will run to else during debug if($sid) { if($discuz_uid) { $query = $db->query("SELECT s.sid, s.styleid, s.groupid='6' AS ipbanned, s.pageviews AS spageviews, s.lastolupdate, s.seccode, $membertablefields FROM {$tablepre}sessions s, {$tablepre}members m WHERE m.uid=s.uid AND s.sid='$sid' AND CONCAT_WS('.',s.ip1,s.ip2,s.ip3,s.ip4)='$onlineip' AND m.uid='$discuz_uid' AND m.password='$discuz_pw' AND m.secques='$discuz_secques'"); } else { $query = $db->query("SELECT sid, uid AS sessionuid, groupid, groupid='6' AS ipbanned, pageviews AS spageviews, styleid, lastolupdate, seccode FROM {$tablepre}sessions WHERE sid='$sid' AND CONCAT_WS('.',ip1,ip2,ip3,ip4)='$onlineip'"); } } MySQL data table exported as below CREATE TABLE IF NOT EXISTS `imc_forum_sessions` ( `sid` char(6) NOT NULL DEFAULT '', `ip1` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip2` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip3` tinyint(3) unsigned NOT NULL DEFAULT '0', `ip4` tinyint(3) unsigned NOT NULL DEFAULT '0', `uid` mediumint(8) unsigned NOT NULL DEFAULT '0', `username` char(15) NOT NULL DEFAULT '', `groupid` smallint(6) unsigned NOT NULL DEFAULT '0', `styleid` smallint(6) unsigned NOT NULL DEFAULT '0', `invisible` tinyint(1) NOT NULL DEFAULT '0', `action` tinyint(1) unsigned NOT NULL DEFAULT '0', `lastactivity` int(10) unsigned NOT NULL DEFAULT '0', `lastolupdate` int(10) unsigned NOT NULL DEFAULT '0', `pageviews` smallint(6) unsigned NOT NULL DEFAULT '0', `seccode` mediumint(6) unsigned NOT NULL DEFAULT '0', `fid` smallint(6) unsigned NOT NULL DEFAULT '0', `tid` mediumint(8) unsigned NOT NULL DEFAULT '0', `bloguid` mediumint(8) unsigned NOT NULL DEFAULT '0', UNIQUE KEY `sid` (`sid`), KEY `uid` (`uid`), KEY `bloguid` (`bloguid`) ) ENGINE=MEMORY DEFAULT CHARSET=utf8 MAX_ROWS=5000; -- -- Dumping data for table `imc_forum_sessions` -- INSERT INTO `imc_forum_sessions` (`sid`, `ip1`, `ip2`, `ip3`, `ip4`, `uid`, `username`, `groupid`, `styleid`, `invisible`, `action`, `lastactivity`, `lastolupdate`, `pageviews`, `seccode`, `fid`, `tid`, `bloguid`) VALUES ('NYC4r7', 127, 0, 0, 1, 0, '', 6, 5, 0, 3, 1271372018, 0, 0, 939015, 51, 303, 0); And the IE error showed, Time: 2010-4-16 7:12am Script: /forum/index.php SQL: SELECT sid, uid AS sessionuid, groupid, groupid='6' AS ipbanned, pageviews AS spageviews, styleid, lastolupdate, seccode FROM [Table]sessions WHERE sid='NYC4r7' AND CONCAT_WS('.',ip1,ip2,ip3,ip4)='127.0.0.1' Error: Table 'dbbbs.[Table]sessions' doesn't exist Errno.: 1146 Similar error report has beed dispatched to administrator before.

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  • Dealing with PHP server and MySQL server in different time zones

    - by Kyle Noland
    For those of us who use standard shared hosting packages, such as GoDaddy or Network Solutions, how do you handle datetime conversions when your hosting server (PHP) and MySQL server are in different time zones? Also, does anybody have some best practice advice for determining what time zone a visitor to your site is in and manipulating a datetime variable appropriately?

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  • Running PHP scripts as the owner of the PHP file: security issues

    - by thomasrutter
    I'm using suexec to ensure that PHP scripts (and other CGI/FastCGI apps) are run as the account holder associated with the relevant virtual host. This allows for securing each users' scripts from reading/writing by other users. However, it occurs to me that this opens up a different security hole. Previously, the web server ran as an unprivileged user, with read-only access to user's files (unless the user changed the file permissions for some reason). Now, the web user can also write to user's files. So while I've prevented different users taking advantage of each other's scripts, I've made it so that in the event that some application has a remote code injection vulnerability, it now has not only read access but also write access to all that user's scripts and website. How can I deal with this? One idea I've had is to create a second user account for each user account in the system, so that each user has their own user account, and all their scripts are run under another user account. But that seems cumbersome.

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  • Security issues of running PHP scripts as the owner of the PHP file with suexec

    - by thomasrutter
    I'm using suexec to ensure that PHP scripts (and other CGI/FastCGI apps) are run as the account holder associated with the relevant virtual host. This allows for securing each users' scripts from reading/writing by other users. However, it occurs to me that this opens up a different security hole. Previously, the web server ran as an unprivileged user, with read-only access to user's files (unless the user changed the file permissions for some reason). Now, the web server can also write to user's files. So while I've prevented different users taking advantage of each other's scripts, I've made it so that in the event that some application has a remote code injection vulnerability, it now has not only read access but also write access to all that user's scripts and website. How can I deal with this? One idea I've had is to create a second user account for each user account in the system, so that each user has their own user account, and all their scripts are run under another user account. But that seems cumbersome.

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  • Create a Cumulative Sum Column in MySQL

    - by Kirk
    I have a table that looks like this: id count 1 100 2 50 3 10 I want to add a new column called cumulative_sum, so the table would look like this: id count cumulative_sum 1 100 100 2 50 150 3 10 160 Is there a MySQL update statement that can do this easily? What's the best way to accomplish this?

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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  • Count Records Returned MySQL Doctrine

    - by 01010011
    Hi, How do I check the number of records returned from a search of my MySQL database with a statement like this: $searchKey = 'Something to search for'; $searchResults = Doctrine::getTable('TableName')->createQuery('t')- >where('columnName LIKE ?','%'.$searchKey.'%')->execute();

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  • sending email in php unable to use HTML tags

    - by JPro
    I am trying to send an email through the result sets generated in MySQL in PHP This is the code. <?php $txtMsg = '<table><th>Name</th>'; $txtMsg = ''; mysql_connect("localhost", "root", "pop") or die(mysql_error()); mysql_select_db("jpd") or die(mysql_error()); $oustanding = mysql_query("select Name from results") or die(mysql_error()); $num=mysql_num_rows($oustanding); while($row1 = mysql_fetch_array( $oustanding )) { ?> <tr> <td><h3><?php echo $row1['Name']; ?></h3></td> </tr> <?php $txtMsg .= "<tr><td>".$row1['Name']."</td></tr>"; } ini_set ( "SMTP", "xy.domain.com" ); $mail_to= '[email protected]'; $mail_from='[email protected]'; $mail_sub='OutStanding Results'; $mail_mesg=$txtMsg; //Check for success/failure of delivery if(mail($mail_to,$mail_sub,$mail_mesg,"From: $mail_from")) echo "<br><br>Email Successfully Sent!"; else echo "<br><br>Error Sending Email!"; } ?> The problem is , I want the results to be displayed in table format. But instead of processing the html tags, they are getting printed as well. How to get the email with table format? Thanks.

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  • mysql query for getting all messages that belong to user's contacts

    - by aharon
    So I have a database that is setup sort of like this (simplified, and in terms of the tables, all are InnoDBs): Users: contains based user authentication information (uid, username, encrypted password, et cetera) Contacts: contains two rows per relationship that exists between users as (uid1, uid2), (uid2, uid1) to allow for a good 1:1 relationship (must be mutual) between users Messages: has messages that consist of a blob, owner-id, message-id (auto_increment) So my question is, what's the best MySQL query to get all messages that belong to all the contacts of a specific user? Is there an efficient way to do this?

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  • Saving commands for later re-use in MySQL?

    - by Zombies
    What would be the equivalant in MySQL for: Saving a command for later reuse. eg: alias command1='select count(*) from sometable;' Where then I simply type command 1 to get the count for SomeTable. Saving just a string, or rather part of a command. eg: select * from sometable where $complex_where_logic$ order by attr1 desc; WHere $complex_where_logic$ is something I wish to save and not have to keep writing out

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  • Php/Mysql Simple survey

    - by creativz
    I want to make a little php poll. The script should ask the users a question they can only answer by numbers from 0-999. After pressing the submit button the data should be stored into mysql. So I just want to know how much users choosed the same number (in percent). It's a simple poll but I don't want any output to be shown.

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  • PHP & MySQL deleting multiple rows script problem.

    - by oReiLLy
    I'm trying to delete two tables rows from two different tables at once when a user clicks the delete button, but for some reason I cant get the table rows to delete can some one help me figure out what is wrong with my script? Thanks Here is the MySQL tables. CREATE TABLE cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, file VARCHAR(255) NOT NULL, case VARCHAR(255) NOT NULL, name VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, cases_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL script. if(isset($_POST['delete_case'])) { $cases_ids = array(); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT cases.*, users_cases.* FROM cases INNER JOIN users_cases ON users_cases.cases_id = cases.id WHERE users_cases.user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $cases_ids[] = $row["cases_id"]; } } foreach($_POST['delete_id'] as $di) { if(in_array($di, $cases_ids)) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"DELETE FROM users_cases WHERE cases_id = '$delete_id'"); $dbc2 = mysqli_query($mysqli,"DELETE FROM cases WHERE id = '$delete_id'"); } } } Here is the XHTML. <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li>

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