Android return to the original position of the view after MotionEvent
- by Kurty
My application currently changes to another random int (View) when I let go of it (ACTION_UP) but the view stays in the same spot where I dropped it. I want it to return to the original location (the middle of the screen) when I drop it so I can repeat the process.
// OnTouch and MotionEvent
OnTouchListener dragt = new OnTouchListener() {
public boolean onTouch(View v, MotionEvent me) {
FrameLayout.LayoutParams par = (FrameLayout.LayoutParams) v.getLayoutParams();
switch (v.getId()) {
case R.id.randomView:
}
switch(me.getAction()) {
case MotionEvent.ACTION_MOVE:
par.gravity = 0;
par.setMargins((int)me.getRawX() - (v.getWidth())/2, (int)me.getRawY() - (v.getHeight())/2, 0, 0);
v.setLayoutParams(par);
break;
case MotionEvent.ACTION_UP:
// tallies score.
score++;
textScore.setText(String.valueOf(score));
// this generates the new view but the location is still the same
color.setImageResource(mImageIds[rgenerator.nextInt(mImageIds.length)]);
break;
}
return true;
}
};
