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  • checking mongo database for data

    - by user1647484
    I'm playing around with this tutorial that uses Sinatra, backbone.js, and mongodb for the database. It's my first time using mongo. As far as I understand it the app uses both local storage and a database. it has these routes for the database. For example, it has these routes get '/api/:thing' do DB.collection(params[:thing]).find.to_a.map{|t| from_bson_id(t)}.to_json end get '/api/:thing/:id' do from_bson_id(DB.collection(params[:thing]).find_one(to_bson_id(params[:id]))).to_json end post '/api/:thing' do oid = DB.collection(params[:thing]).insert(JSON.parse(request.body.read.to_s)) "{\"_id\": \"#{oid.to_s}\"}" end After turning the server off and then on, I could see in the server getting data from the database routes 127.0.0.1 - - [17/Sep/2012 08:21:58] "GET /api/todos HTTP/1.1" 200 430 0.0033 My question is, how can I check from within the mongo shell whether the data's in the database? I started the mongo shell ./bin/mongo I selected the database 'use mydb' and then looking at the docs (http://www.mongodb.org/display/DOCS/Tutorial) I tried commands such as > var cursor = db.things.find(); > while (cursor.hasNext()) printjson(cursor.next()); but they didn't return anything.

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  • A little confused about MVC and where to put a database query

    - by jax
    OK, so my Joomla app is in MVC format. I am still a little confused about where to put certain operations, in the Controller or in the Model. This function below is in the controller, it gets called when &task=remove. Should the database stuff be in the Model? It does not seem to fit there because I have two models editapp (display a single application) and allapps (display all the applications), now which one would I put the delete operation in? /** * Delete an application */ function remove() { global $mainframe; $cid = JRequest::getVar( 'cid', array(), '', 'array' ); $db =& JFactory::getDBO(); //if there are items to delete if(count($cid)){ $cids = implode( ',', $cid ); $query = "DELETE FROM #__myapp_apps WHERE id IN ( $cids )"; $db->setQuery( $query ); if (!$db->query()){ echo "<script> alert('".$db->getErrorMsg()."');window.history.go(-1); </script>\n"; } } $mainframe->redirect( 'index.php?option=' . $option . '&c=apps'); } I am also confused about how the flow works. For example, there is a display() function in the controller that gets called by default. If I pass a task, does the display() function still run or does it go directly to the function name passed by $task?

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  • Codeigniter Inputting session data from model for a simple authentication system

    - by user1616244
    Trying to put together a simple login authentication. Been at this for quite sometime, and I can't find where I'm going wrong. Pretty new to Codeigniter and OOP PHP. I know there are authentication libraries out there, but I'm not interested in using those. Model: function login($username, $password){ if ($this->db->table_exists($username)){ $this->db->where('username', $username); $this->db->where('password', $password); $query = $this->db->get($username); if($query->num_rows >= 1) { return true; $data = array( 'username' => $this->input->post('username'), 'login' => true ); $this->session->set_userdata($data); } } } Controller function __construct(){ parent::__construct(); $this->logincheck(); } public function logincheck(){ if ($this->session->userdata('login')){ redirect('/members'); } } If I just echo from the controller: $this-session-all_userdata(); I get an empty array. So the problem seems to be that the $data array in the model isn't being stored in the session.

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  • uploading database file in assets not returning a record

    - by Alexander
    I have a problem with a database file not being read I have added the database file in assets called mydb but when i run my code it says its not being located. It is calling this toast Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); This is being called because no records are being returned. This is an example form Android Application Development book. public class DatabaseActivity extends Activity { /** Called when the activity is first created. */ TextView quest, response1, response2; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); TextView quest = (TextView) findViewById(R.id.quest); try { String destPath = "/data/data/" + getPackageName() + "/databases/MyDB"; File f = new File(destPath); if (!f.exists()) { CopyDB( getBaseContext().getAssets().open("mydb"), new FileOutputStream(destPath)); } } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } DBAdapter db = new DBAdapter(this); //---get a contact--- db.open(); Cursor c = db.getContact(2); if (c.moveToFirst()) DisplayContact(c); else Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); db.close(); } public void CopyDB(InputStream inputStream, OutputStream outputStream) throws IOException { //---copy 1K bytes at a time--- byte[] buffer = new byte[1024]; int length; while ((length = inputStream.read(buffer)) > 0) { outputStream.write(buffer, 0, length); } inputStream.close(); outputStream.close(); } public void DisplayContact(Cursor c) { quest.setText(String.valueOf(c.getString(1))); //quest.setText(String.valueOf("this is a text string")); } }

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  • Drupal 7 configuration error with Postgresql in Mac OS 10.6.5

    - by Sam
    I am trying to configure Drupal 7 with Postgres. At the database setup step, I get the following error. Warning: PDO::_construct(): [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) in DatabaseConnection-_construct() (line 300 of /Users/shamod/Sites/drupal/7/includes/database/database.inc). In order for Drupal to work, and to continue with the installation process, you must resolve all issues reported below. For more help with configuring your database server, see the installation handbook. If you are unsure what any of this means you should probably contact your hosting provider. Failed to connect to your database server. The server reports the following message: SQLSTATE[HY000] [2002] No such file or directory. Is the database server running? Does the database exist, and have you entered the correct database name? Have you entered the correct username and password? Have you entered the correct database hostname? NOTE: I am trying to connect to Postgresql but it fails on var/mysql/mysql.sock error. I have setup the database connection string in settings.php for Postgresql. It still does not work. Any idea?

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  • How do you bind SQL Data to a .NET DataGridView?

    - by Jordan S
    I am trying to bind a table in an SQL database to a DataGridView Control. I would like to make it so that when the user enters a new line of data in the DataGridView that a record is automatically added to the database. Is there a way to do this using LINQ to SQL? I have tried using the code below but after I add a new entry I dont think the data gets added to the DB. Please Help! BOMClassesDataContext DB = new BOMClassesDataContext(); var mfrs = from m in DB.Manufacturers select m; BindingSource bs = new BindingSource(); bs.DataSource = mfrs; dataGridView1.DataSource = bs; I tried adding DB.SubmitChanges() to the CellValueChanged eventhandler and that partially works. If I click the bottom empty row it automatically fills in the ID (identity) column of the table with a "0" instead of the next unused value. If I change that value manually to the next available then it adds the new record fine but if I leave it at 0 it does nothing. How can i fix this?

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  • Problem with SqlLite database in Qt SDK 1.0.2

    - by Risino
    Hi I have a problem with SqlLite database. Here is my code: void incomeDialog::on_add_pushButton_clicked() { int a = ui->income_lineEdit->text().toInt(); int b = ui->other_lineEdit->text().toInt(); int c = (a+b); db = QSqlDatabase::addDatabase("QSQLITE"); db.setDatabaseName("money.db"); QSqlQuery query(db); query.exec("create table Income" "(Month TEXT, Payment NUMBER, Other NUMBER, Together NUMBER)"); query.prepare("INSERT INTO Income values (?,?,?,?)"); query.addBindValue(ui->comboBox->currentText()); query.addBindValue(ui->income_lineEdit->text().toInt()); query.addBindValue(ui->other_lineEdit->text().toInt()); query.addBindValue(c); query.exec(); } I use qt sdk 1.0.2. After building shows errors: Undefined reference to 'QSqlDatabase::addDatabase(QString const&, QString const&)... all errors is similar (Undefined reference to 'QSqlDatabase:: Do you have any idea how to repair it?

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  • JDBC going to the wrong address

    - by DCSoft
    When I try and connect it my mysql database with JDBC in java, it doesn't go to my web server. Here is the code String dbtime; String dbUrl = "jdbc:mysql://184.172.176.18:3306/dcsoft_dcsoft_balloon"; String dbUser = "myuser"; String dcPass = "mypass"; String dbClass = "com.mysql.jdbc.Driver"; String query = "Select * FROM users"; try { Class.forName("com.mysql.jdbc.Driver"); Connection con = DriverManager.getConnection(dbUrl, dbUser, dcPass); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery(query); while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } //end while con.close(); } //end try catch(ClassNotFoundException e) { e.printStackTrace(); } catch(SQLException e) { e.printStackTrace(); } This code is supposed to go to my web server but it gives this error java.sql.SQLException: Access denied for user 'dcsoft_dcsoft_java'@'jamesposse.force9.co.uk' (using password: YES) jamesposse.force9.co.uk is the not the address im trying to connect to I'm trying to connect to 184.172.176.18:3306. Thanks.

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  • LINQ to SQL - database relationships won't update after submit

    - by Quantic Programming
    I have a Database with the tables Users and Uploads. The important columns are: Users -> UserID Uploads -> UploadID, UserID The primary key in the relationship is Users -> UserID and the foreign key is Uploads -> UserID. In LINQ to SQL, I do the following operations: Retrieve files var upload = new Upload(); upload.UserID = user.UserID; upload.UploadID = XXX; db.Uploads.InsertOnSubmit(upload) db.SubmitChanges(); If I do that and rerun the application (and the db object is re-built, of course) - if do something like this: foreach(var upload in user.Uploads) I get all the uploads with that user's ID. (like added in the previous example) The problem is, that my application, after adding an upload an submitting changes, doesn't update the user.Uploads collection. i.e - I don't get the newly added uploads. The user object is stored in the Session object. At first, I though that the LINQ to SQL Framework doesn't update the reference of the object, therefore I should simply "reset" the user object from a new SQL request. I mean this: Session["user"] = db.Users.Where(u => u.UserID == user.UserID).SingleOrDefault(); (Where user is the previous user) But it didn't help. Please note: After rerunning the application, user.Uploads does have the new upload! Did anyone experience this type of problem, or is it normal behavior? I am a newbie to this framework. I would gladly take any advice. Thank you!

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  • how to download data which upload to gae ,

    - by zjm1126
    this is my code : import os from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext import db #from login import htmlPrefix,get_current_user class MyModel(db.Model): blob = db.BlobProperty() class BaseRequestHandler(webapp.RequestHandler): def render_template(self, filename, template_args=None): if not template_args: template_args = {} path = os.path.join(os.path.dirname(__file__), 'templates', filename) self.response.out.write(template.render(path, template_args)) class upload(BaseRequestHandler): def get(self): self.render_template('index.html',) def post(self): file=self.request.get('file') obj = MyModel() obj.blob = db.Blob(file.encode('utf8')) obj.put() self.response.out.write('upload ok') class download(BaseRequestHandler): def get(self): #id=self.request.get('id') o = MyModel.all().get() #self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o))) self.response.out.write(o) application = webapp.WSGIApplication( [ ('/?', upload), ('/download',download), ], debug=True ) def main(): run_wsgi_app(application) if __name__ == "__main__": main() my index.html is : <form action="/" method="post"> <input type="file" name="file" /> <input type="submit" /> </form> and it show : <__main__.MyModel object at 0x02506830> but ,i don't want to see this , i want to download it , how to change my code to run, thanks

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  • In Python, how to make sure database connection will always close before leaving a code block?

    - by Cawas
    I want to prevent database connection being open as much as possible, because this code will run on an intensive used server and people here already told me database connections should always be closed as soon as possible. def do_something_that_needs_database (): dbConnection = MySQLdb.connect(host=args['database_host'], user=args['database_user'], passwd=args['database_pass'], db=args['database_tabl'], cursorclass=MySQLdb.cursors.DictCursor) dbCursor = dbConnection.cursor() dbCursor.execute('SELECT COUNT(*) total FROM table') row = dbCursor.fetchone() if row['total'] == 0: print 'error: table have no records' dbCursor.execute('UPDATE table SET field="%s"', whatever_value) return None print 'table is ok' dbCursor.execute('UPDATE table SET field="%s"', another_value) # a lot more of workflow done here dbConnection.close() # even more stuff would come below I believe that leaves a database connection open when there is no row on the table, tho I'm still really not sure how it works. Anyway, maybe that is bad design in the sense that I could open and close a DB connection after each small block of execute. And sure, I could just add a close right before the return in that case... But how could I always properly close the DB without having to worry if I have that return, or a raise, or continue, or whatever in the middle? I'm thinking in something like a code block, similar to using try, like in the following suggestion, which obviously doesn't work: def do_something_that_needs_database (): dbConnection = MySQLdb.connect(host=args['database_host'], user=args['database_user'], passwd=args['database_pass'], db=args['database_tabl'], cursorclass=MySQLdb.cursors.DictCursor) try: dbCursor = dbConnection.cursor() dbCursor.execute('SELECT COUNT(*) total FROM table') row = dbCursor.fetchone() if row['total'] == 0: print 'error: table have no records' dbCursor.execute('UPDATE table SET field="%s"', whatever_value) return None print 'table is ok' dbCursor.execute('UPDATE table SET field="%s"', another_value) # again, that same lot of line codes done here except ExitingCodeBlock: closeDb(dbConnection) # still, that "even more stuff" from before would come below I don't think there is anything similar to ExitingCodeBlock for an exception, tho I know there is the try else, but I hope Python already have a similar feature... Or maybe someone can suggest me a paradigm move and tell me this is awful and highly advise me to never do that. Maybe this is just something to not worry about and let MySQLdb handle it, or is it?

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  • Heroku only initializes some of my models.

    - by JayX
    So I ran heroku db:push And it returned Sending schema Schema: 100% |==========================================| Time: 00:00:08 Sending indexes schema_migrat: 100% |==========================================| Time: 00:00:00 projects: 100% |==========================================| Time: 00:00:00 tasks: 100% |==========================================| Time: 00:00:00 users: 100% |==========================================| Time: 00:00:00 Sending data 8 tables, 70,551 records groups: 100% |==========================================| Time: 00:00:00 schema_migrat: 100% |==========================================| Time: 00:00:00 projects: 100% |==========================================| Time: 00:00:00 tasks: 100% |==========================================| Time: 00:00:02 authenticatio: 100% |==========================================| Time: 00:00:00 articles: 100% |==========================================| Time: 00:08:27 users: 100% |==========================================| Time: 00:00:00 topics: 100% |==========================================| Time: 00:01:22 Resetting sequences And when I went to heroku console This worked >> Task => Task(id: integer, topic: string, content: string, This worked >> User => User(id: integer, name: string, email: string, But the rest only returned something like >> Project NameError: uninitialized constant Project /home/heroku_rack/lib/console.rb:150 /home/heroku_rack/lib/console.rb:150:in `call' /home/heroku_rack/lib/console.rb:28:in `call' >> Authentication NameError: uninitialized constant Authentication /home/heroku_rack/lib/console.rb:150 /home/heroku_rack/lib/console.rb:150:in `call' update 1: And when I typed >> ActiveRecord::Base.connection.tables it returned => ["projects", "groups", "tasks", "topics", "articles", "schema_migrations", "authentications", "users"] Using heroku's SQL console plugin I got SQL> show tables +-------------------+ | table_name | +-------------------+ | authentications | | topics | | groups | | projects | | schema_migrations | | tasks | | articles | | users | +-------------------+ So I think they are existing in heroku's database already. There is probably something wrong with rack db:migrate update 2: I ran rack db:migrate locally in both production and development modes and nothing wrong happened. But when I ran it on heroku it only returned: $ heroku rake db:migrate (in /disk1/home/slugs/389817_1c16250_4bf2-f9c9517b-bdbd-49d9-8e5a-a87111d3558e/mnt) $ Also, I am using sqlite3 update 3: so I opened up heroku console and typed in the following command class Authentication < ActiveRecord::Base;end Amazingly I was able to call Authentication class, but once I exited, nothing was changed.

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  • Linq to Entities Joins

    - by Bob Avallone
    I have a question about joins when using Linq to Entities. According to the documentation the use on the join without a qualifier performs like a left outer join. However when I execute the code below, I get a count returned of zero. But if I comment out the three join lines I get a count of 1. That would indicate that the join are acting as inner join. I have two questions. One which is right inner or outer as the default? Second how do I do the other one i.e. inner or outer? The key words on inner and outer do not work. var nprs = (from n in db.FMCSA_NPR join u in db.FMCSA_USER on n.CREATED_BY equals u.ID join t in db.LKUP_NPR_TYPE on n.NPR_TYPE_ID equals t.ID join s in db.LKUP_AUDIT_STATUS on n.NPR_STATUS_ID equals s.ID where n.ROLE_ID == pRoleId && n.OWNER_ID == pOwnerId && n.NPR_STATUS_ID == pNPRStatusId && n.ACTIVE == pActive select n).ToList(); if (nprs.Count() == 0) return null;

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  • nextgen gallery order issue

    - by mro
    Hi, wonder if anyone can help. I think what I'm after won't be solved by any exsiting code in nextgen plugin (in wordpress) due to the custom way I'm using it hence I come to stackoverflow for some opnions. Bascially - I am only really using the admin of nextgen to work with the gallerys etc. The actual meat of the functionality I'm querying the nextgen DB's direct from my code, I would have loved to use the inbuilt gallerys in nextgen, but my spec specifics were so custom I couldn't. My issue is, I need to pull the images from the DB's in the order it is in the admin (ie if a user pulls the sort order around in the drag and drop area). I have noticed however this doesn't affect the image id order in the DB, and wouldn't expect it to - that would be some complex shifting around just to reorder everytime surely. So obviously when I query the DB the order it's looking at is when it was created, by image id, with my filtering on top. I'm wondering though if there is a way I can query that sort order that's determined in the admin somehow, then at least I could sort the array somehow in the code ? does next gen store it's user custom sort order somewhere ? Hope this makes sense :) any thoughts appreciated. Thanks

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  • Computer Science taxonomy

    - by Bakhtiyor
    I am developing web application where users have collection of tags. I need to create a suggestion list for users based on the similarity of their tags. For example, when a user logs in to the system, system gets his tags and search these tags in the DB of users and showing users who have similar tags. For instance if User 1 has following tags [Linux, Apache, MySQL, PHP] and User 2 has [Windows, IIS, PHP, MySQL] it says that User 2 matchs User 1 with a weight of 50%, because he has 2 similar tags(PHP and MySQL). But imagine the situation where User 1 has [ASP, IIS, MS Access] and User 2 has [PHP, Apache, MySQL]. In this situation my system doesn't suggest User 2 as a "friend" to User 1 or vice versa. But we now that these two users has similarity on the the field of work, both works on Web Technology (or Web Programming, etc). So, that is why I need kind of taxonomy of computer science (right now, but probably I would need taxonomy of other fields also, like medicine, physics, mathematics, etc.) where these concepts are categorized and so that when I search for similarity of ASP and PHP, for example, it can say that they have similarity and belong into one group(or category). I hope I described my problem clearly, but if something wrong explained would be happy for your corrections. Thanks

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  • SQLITE crash when no data present in table

    - by johnblack45
    Hey, Im having a problem with my app that causes it to crash when no data is present in the table when using a table view. I have tested my code and it works fine as long as there is data present but i need it to work when there is no data present. -(void)initialiseTableData { NSMutableArray *array = [[NSMutableArray alloc]init]; sqlite3 *db = [iCaddyAppDelegate getNewDBConnection]; sqlite3_stmt *statement; const char *sql = "select courseId, courseName, totalPar, totalyardage, holePars, holeYardages, holeStrokeIndexs from Course"; if(sqlite3_prepare_v2(db, sql, -1, &statement, NULL)!= SQLITE_OK) { NSAssert1(0,@"Error preparing statement",sqlite3_errmsg(db)); sqlite3_close(db); } else { while (sqlite3_step(statement) == SQLITE_ROW) { Course *temp = [[Course alloc]init]; temp.courseId = sqlite3_column_int(statement,0); temp.courseName = [NSString stringWithFormat:@"%s",(char*)sqlite3_column_text(statement,1)]; temp.totalPar =sqlite3_column_int(statement,2); temp.totalYardage =sqlite3_column_int(statement,3); NSString tempHolePars = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,4)]; NSString tempHoleYardages = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,5)]; NSString tempHoleStrokeIndexes = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,6)]; NSArray *temp1 = [tempHolePars componentsSeparatedByString:@":"]; NSArray *temp2 = [tempHoleYardages componentsSeparatedByString:@":"]; NSArray *temp3 = [tempHoleStrokeIndexes componentsSeparatedByString:@":"]; for(int i = 0; i<=17; i++) { NSString *temp1String = [temp1 objectAtIndex:i]; [temp.holePars insertObject:temp1String atIndex:i]; NSString *temp2String = [temp2 objectAtIndex:i]; [temp.holeYardages insertObject:temp2String atIndex:i]; NSString *temp3String = [temp3 objectAtIndex:i]; [temp.holeStrokeIndexes insertObject:temp3String atIndex:i]; } [array addObject:temp]; } self.list = array; [self.table reloadData]; } }

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  • Worth website that a web developer must surf daily?

    - by I Like PHP
    Hello All, this may be not a right place to ask this question, but i can get best answer only from here, so i m posting here. i m a web developer and working with technology PHP,MySQL, JavaScript,jQuery,AJAX, CSS, HTML, JSON i daily surf few websites regarding web development , i know there are a lot of website with very good knowledge but we are not aware of that so i think we have to share with each other.i m mentioning some useful links that we must surf daily for gaining knowledge and do better/fast development. please you also suggest some good links which you surf regularly and best in their field. i surf belows links regularly - [Stack Overflow][1] // No doubt, it is best - [Delicious][2]// best social bookmarking website - [Smashing Magazine][3] // Best site to improve knowledege for a web developer - [Net tuts][4] // Best tutorail wesbsite with full explanation - [Official PHP site ][5] // i think nothing to mention about it( just superb) - [Javascript Debugger][6] // U can filter your javascript/jquery code here - [jQuery Official site][7] // best to learn jQuery i m waiting for you great response. i also need any good and trusted website on mysql, i think mysql officail website is very confusing, i had to search a lot to find a single thing, if u have any good regarding mysql then share please. Thanks alwayz.

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  • PHP Fix Warning: Cannot modify header information - headers already sent...

    - by Storm Kiernan
    Warning: Cannot modify header information - headers already sent by (output started at /home/blocexco/public_html/homepage.php:73) in /home/blocexco/public_html/classes/mysql/mysql.security.php on line 99 This error is repeated a second time for mysql.security.php on line 100. homepage:73 <div class="login"> <?php require_once 'login.php'; ?> </div> mysql.security.php: 99-100 setcookie('username', "", time() - (60 * 60 * 24 * 365)); setcookie('password', "", time() - (60 * 60 * 24 * 365)); I know this isn't a "BOM" issue as I've read about. There is output before and after my calls to header() and setcookie() functions - this is necessary since the homepage includes a php file which then injects the right login or logout form. I've heard about using ob_start() at the beginning of content, but that's not a very specific instruction...I tried placing it at the beginning of homepage.php (just before the html tag) and that didn't fix anything. I'm new to PHP (a few days in, and new to web-app dev in general). To be honest, it blows my mind that I can't just change which page I am on, via php without bending over backwards...

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  • Create ImageButton programatically depending on local database records

    - by user2507920
    As i described in title, i have a local db in sqlite. I want to create ImageButton parametrically. How many times is local database loop executing? Please see code below : RelativeLayout outerRelativeLayout = (RelativeLayout)findViewById(R.id.relativeLayout2_making_dynamically); db.open(); Cursor c = db.getAllLocal_Job_Data(); if(c!=null){ if(c.moveToFirst()){ do { RelativeLayout innerRelativeLayout = new RelativeLayout(CalendarActivity.this); innerRelativeLayout.setGravity(Gravity.CENTER); ImageButton imgBtn = new ImageButton(CalendarActivity.this); imgBtn.setBackgroundResource(R.drawable.color_001); RelativeLayout.LayoutParams imageViewParams = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); imgBtn.setLayoutParams(imageViewParams); // Adding the textView to the inner RelativeLayout as a child innerRelativeLayout.addView(imgBtn, new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); outerRelativeLayout.addView(innerRelativeLayout, new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); } while (c.moveToNext()); } } db.close(); But when i run the project, i can see only one button created there. I think there are many buttons but here image button is creating on last created image button. I think i should use android:layout_toRightOf with previous created button but i cant find how to place it here. I have tried some ideas but it did not change any thing. So please anybody has any idea to solve my problem then please share it with me.

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  • WCF operationcontract with List type unavailable in (Silverlight) client

    - by Dave
    This is the first time I have tried returning a List of data to a Silverlight client, so I'm having trouble getting the client to recognize this operationcontract. All others are fine. I have a method on the server called ReadOwFileData that needs to return a List. ReadOwFileDataCompletedEventArgs shows up in the Object Browser in the client, but not ReadOwFileDataAsync. What I want is similar to the tutorial here. The Dictionary collection type on the client is set to System.Collections.Generic.List. I tried deleting and recreating the service reference. Web.Config on the server is using basicHttpBinding. Here is the operationcontract on the server: [OperationContract] public List<OwFileData> ReadOwFileData(string OrderID) { DataClasses1DataContext db = new DataClasses1DataContext(); var dFileData = (from p in db.OwFileDatas where p.OrderID == OrderID select p).ToList(); List<OwFileData> x = new List<OwFileData>(dFileData); return x; } Incidently, this works fine: [OperationContract] public Customer GetShippingAndContactInfo(string login, string ordernum) { DataClasses1DataContext db = new DataClasses1DataContext(); Customer dInfo = (from p in db.Customers where p.Login == login select p).Single(); return dInfo; } I would like to read this data in the client and place it into an object I created called ObservableCollection. But that obviously can't happen until the client can see the method on the server. I do not know if this is an acceptable start, but this is what is on the client so far. The ReadOwFileDataAsync object is null: void populatefilesReceivedDataSource(string OrderID) { ArtUpload.ServiceReference1.UploadServiceClient client = new ArtUpload.ServiceReference1.UploadServiceClient(); var myList = client.ReadOwFileDataAsync(OrderID); // can I just itterate thru the list instead of 'binding' }

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  • Project Naming Convention Feedback Please

    - by Sam Striano
    I am creating a ASP.NET MVC 3 application using Entity Framework 4. I am using the Repository/Service Pattern and was looking for feedback. I currently have the following: MVC Application (GTG.dll) GTG GTG.Controllers GTG.ViewModels Business POCO's (GTG.Business.dll) This contains all business objects (Customer, Order, Invoice, etc...) EF Model/Repositories (GTG.Data.dll) GTG.Business (GTG.Context.tt) I used the Entity POCO Generator Templates. GTG.Data.Repositories Service Layer (GTG.Data.Services.dll) GTG.Data.Services - Contains all of the service objects, one per aggregate root. The following is a little sample code: Controller Namespace Controllers Public Class HomeController Inherits System.Web.Mvc.Controller Function Index() As ActionResult Return View(New Models.HomeViewModel) End Function End Class End Namespace Model Namespace Models Public Class HomeViewModel Private _Service As CustomerService Public Property Customers As List(Of Customer) Public Sub New() _Service = New CustomerService _Customers = _Service.GetCustomersByBusinessName("Striano") End Sub End Class End Namespace Service Public Class CustomerService Private _Repository As ICustomerRepository Public Sub New() _Repository = New CustomerRepository End Sub Function GetCustomerByID(ByVal ID As Integer) As Customer Return _Repository.GetByID(ID) End Function Function GetCustomersByBusinessName(ByVal Name As String) As List(Of Customer) Return _Repository.Query(Function(x) x.CompanyName.StartsWith(Name)).ToList End Function End Class Repository Namespace Data.Repositories Public Class CustomerRepository Implements ICustomerRepository Public Sub Add(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Add End Sub Public Sub Delete(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Delete End Sub Public Function GetByID(ByVal ID As Integer) As Business.Customer Implements IRepository(Of Business.Customer).GetByID Using db As New GTGContainer Return db.Customers.FirstOrDefault(Function(x) x.ID = ID) End Using End Function Public Function Query(ByVal Predicate As System.Linq.Expressions.Expression(Of System.Func(Of Business.Customer, Boolean))) As System.Linq.IQueryable(Of Business.Customer) Implements IRepository(Of Business.Customer).Query Using db As New GTGContainer Return db.Customers.Where(Predicate) End Using End Function Public Sub Save(ByVal Entity As Business.Customer) Implements IRepository(Of Business.Customer).Save End Sub End Class End Namespace

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  • PHP - Calling function inside another class -> function

    - by Kolind
    I'm trying to do this: class database { function editProvider($post) { $sql = "UPDATE tbl SET "; foreach($post as $key => $val): if($key != "providerId") { $val = formValidate($val); $sqlE[] = "`$key`='$val'"; } endforeach; $sqlE = implode(",", $sqlE); $where = ' WHERE `id` = \''.$post['id'].'\''; $sql = $sql . $sqlE . $where; $query = mysql_query($sql); if($query){ return true; } } // }//end class And then use this function * INSIDE of another class *: function formValidate($string){ $string = trim($string); $string = mysql_real_escape_string($string); return $string; } // .. on $val. Why doesn't this work? if I write in a field of the form, it's not escaping anything at all. How can that be? * UPDATE * handler.php: if(isset($_GET['do'])){ if($_GET['do'] == "addLogin") { $addLogin = $db->addLogin($_POST); } if($_GET['do'] == "addProvider") { $addProvider = $db->addProvider($_POST); } if($_GET['do'] == "editProfile") { $editProfile = $db->editProfile($_POST); } if($_GET['do'] == "editProvider") { $editProvider = $db->editProvider($_POST); } } //end if isset get do ** The editProvider function works fine except for this :-) **

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  • Compile Apache 2.4.3 on Centos 6.2 (64bit)

    - by RiseCakoPlusplus
    I attempt to compile Apache 2.4.3 with apr-1.4.6 and apr-util-1.5.1 on Centos 6.2 (64bit). ./configure --build=x86_64-unknown-linux-gnu --host=x86_64-unknown-linux-gnu --target=x86_64-redhat-linux-gnu --program-prefix= --prefix=/usr --exec-prefix=/usr --bindir=/usr/bin --sbindir=/usr/sbin --sysconfdir=/etc --datadir=/usr/share --includedir=/usr/include --libdir=/usr/lib64 --libexecdir=/usr/libexec --localstatedir=/var --sharedstatedir=/var/lib --mandir=/usr/share/man --infodir=/usr/share/info --cache-file=../config.cache --with-libdir=lib64 --with-config-file-path=/etc --with-config-file-scan-dir=/etc/php.d --disable-debug --with-pic --disable-rpath --without-pear --with-bz2 --with-exec-dir=/usr/bin --with-freetype-dir=/usr --with-png-dir=/usr --with-xpm-dir=/usr --enable-gd-native-ttf --with-t1lib=/usr --without-gdbm --with-gettext --with-gmp --with-iconv --with-jpeg-dir=/usr --with-openssl --with-zlib --with-layout=GNU --enable-exif --enable-ftp --enable-magic-quotes --enable-sockets --with-kerberos --enable-ucd-snmp-hack --enable-shmop --enable-calendar --with-libxml-dir=/usr --enable-xml --with-system-tzdata --with-mhash --with-apxs2=/usr/sbin/apxs --libdir=/usr/lib64/php --enable-pdo=shared --with-mysql=shared,/usr --with-mysqli=shared,/usr/lib64/mysql/mysql_config --with-pdo-mysql=shared,/usr/lib64/mysql/mysql_config --without-pdo-sqlite --without-gd --disable-dom --disable-dba --without-unixODBC --disable-xmlreader --disable-xmlwriter --without-sqlite3 --disable-phar --disable-fileinfo --disable-json --without-pspell --disable-wddx --without-curl --disable-posix --disable-sysvmsg --disable-sysvshm --disable-sysvsem ./configure --with-included-apr --with-included-apr-util and when I issue make this happen: /root/httpd-2.4.3/srclib/apr/libtool: line 5989: cd: yes/lib: No such file or directory libtool: link: cannot determine absolute directory name of yes/lib' make[3]: *** [libaprutil-1.la] Error 1 make[3]: Leaving directory/root/httpd-2.4.3/srclib/apr-util' make[2]: * [all-recursive] Error 1 make[2]: Leaving directory /root/httpd-2.4.3/srclib/apr-util' make[1]: *** [all-recursive] Error 1 make[1]: Leaving directory/root/httpd-2.4.3/srclib' make: * [all-recursive] Error 1 anything I missed?

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  • Facebook / Offline Permission - Trying to perform an action on a set of offline users.

    - by blueigloo
    Hi there, We're building an app which in part of its functionality tries to capture the number of likes associated to a particular video owned by a user. Users of the app are asked for extended off-line access and we capture the key for each user: The format is like this: 2.hg2QQuYeftuHx1R84J1oGg__.XXXX.1272394800-nnnnnn Each user has their offline / infinite key stored in a table in a DB. The object_id which we're interested in is also stored in the DB. At a later stage (offline) we try to run a batch job which reads the number of likes for each user's video. (See attached code) For some reason however, after the first iteration of the loop - which yields the likes correctly, we get a failure with the oh so familiar message: "Session key is invalid or no longer valid" Any insight would be most appreciated. Thanks, B List<DVideo> videoList = db.SelectVideos(); foreach (DVideo video in videoList) { long userId = 0; ConnectSession fbSession = new ConnectSession(APPLICATION_KEY, SECRET_KEY); //session key is attached to the video object for now. fbSession.SessionKey = video.UserSessionKey; fbSession.SessionExpires = false; string fbuid =video.FBUID; long.TryParse(fbuid, out userId); if (userId > 0) { fbSession.UserId = userId; fbSession.Login(); Api fbApi = new Facebook.Rest.Api(fbSession); string xmlQueryResult = fbApi.Fql.Query("SELECT user_id FROM like WHERE object_id = " + video.FBVID); XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(new StringReader(xmlQueryResult)); int likesCount = xmlDoc.GetElementsByTagName("user_id").Count; //Write entry in VideoWallLikes if (likesCount > 0) { db.CountWallLikes(video.ID, likesCount); } fbSession.Logout(); } fbSession = null; }

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  • How do I do a table join on two fields in my second table?

    - by Cannonade
    I have two tables: Messages - Amongst other things, has a to_id and a from_id field. People - Has a corresponding person_id I am trying to figure out how to do the following in a single linq query: Give me all messages that have been sent to and from person x (idself). I had a couple of cracks at this. Not quite right MsgPeople = (from p in db.people join m in db.messages on p.person_id equals m.from_id where (m.from_id == idself || m.to_id == idself) orderby p.name descending select p).Distinct(); This almost works, except I think it misses one case: "people who have never received a message, just sent one to me" How this works in my head So what I really need is something like: join m in db.messages on (p.people_id equals m.from_id or p.people_id equals m.to_id) Gets me a subset of the people I am after It seems you can't do that. I have tried a few other options, like doing two joins: MsgPeople = (from p in db.people join m in AllMessages on p.person_id equals m.from_id join m2 in AllMessages on p.person_id equals m2.to_id where (m2.from_id == idself || m.to_id == idself) orderby p.name descending select p).Distinct(); but this gives me a subset of the results I need, I guess something to do with the order the joins are resolved. My understanding of LINQ (and perhaps even database theory) is embarrassingly superficial and I look forward to having some light shed on my problem.

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