Introduction :
Previewing an
image is a great way
to improve the UI of your
site. Also it is always best
to check the file type, size and see a preview before submitting the whole form. There are some ways
to do this using simple JavaScript but not work
in all browsers (like FF3).
In this Article I will show you
how do this using
ASP.
NET MVC application. You also see
how this will work
in case of nested form.
Description :
Create a new
ASP.
NET MVC project and then add a file upload and
image control into your View.
<form id="form1" method="post" action="NerdDinner/ImagePreview/AjaxSubmit"> <table> <tr> <td> <input type="file" name="imageLoad1" id="imageLoad1" onchange="ChangeImage(this,'#imgThumbnail')" /> </td> </tr> <tr> <td align="center"> <img src="images/TempImage.gif" id="imgThumbnail" height="200px" width="200px"> </td> </tr> </table> </form>
Note that here NerdDinner is refers
to the virtual directory name, ImagePreview is the Controller and ImageLoad is the action name which you will see shortly
I will use the most popular jQuery form plug-in, that turns a form into an AJAX form with very little code. Therefore you must
get these from Jquery
site and then add these files into your page.
<script src="NerdDinner/Scripts/jquery-1.3.2.js" type="text/javascript"></script> <script src="NerdDinner/Scripts/jquery.form.js" type="text/javascript"></script>
Then add the javascript function.
<script type="text/javascript">function ChangeImage(fileId,imageId){ $("#form1").ajaxSubmit({success: function(responseText){ var d=new Date(); $(imageId)[0].src="NerdDinner/ImagePreview/ImageLoad?a="+d.getTime(); } });}</script>
This function simply submit the form named form1 asynchronously
to ImagePreviewController's method AjaxSubmit and after successfully receiving the response, it will set the
image src property
to the action method ImageLoad. Here I am also adding querystring, preventing the browser
to serve the cached
image.
Now I will create a new Controller named ImagePreviewController.
public class ImagePreviewController : Controller { [AcceptVerbs(HttpVerbs.Post)] public ActionResult AjaxSubmit(int? id) { Session["ContentLength"] = Request.Files[0].ContentLength; Session["ContentType"] = Request.Files[0].ContentType; byte[] b = new byte[Request.Files[0].ContentLength]; Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength); Session["ContentStream"] = b; return Content( Request.Files[0].ContentType+";"+ Request.Files[0].ContentLength ); } public ActionResult ImageLoad(int? id) { byte[] b = (byte[])Session["ContentStream"]; int length = (int)Session["ContentLength"]; string type = (string)Session["ContentType"]; Response.Buffer = true; Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = type; Response.BinaryWrite(b); Response.Flush(); Session["ContentLength"] = null; Session["ContentType"] = null; Session["ContentStream"] = null; Response.End(); return Content(""); } }
The AjaxSubmit action method will save the
image in Session and return content type and content length
in response. ImageLoad action method will return the contents of
image in response.Then clear these Sessions.
Just run your application and see the effect.
Checking Size and Content Type of File:
You may notice that AjaxSubmit action method is returning both content type and content length. You can check both properties before submitting your complete form.
$(myform).ajaxSubmit({success: function(responseText) { var contentType=responseText.substring(0,responseText.indexOf(';')); var contentLength=responseText.substring(responseText.indexOf(';')+1); // Here you can do your validation var d=new Date(); $(imageId)[0].src="http://weblogs.
asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime(); } });
Handling Nested Form Case:
The above code will work if you have only one form. But this is not the case always.You may have a form control which wraps all the controls and you do not want
to submit the whole form, just for getting a preview effect.
In this case you need
to create a dynamic form control using JavaScript, and then add file upload control
to this form and submit the form asynchronously
function ChangeImage(fileId,imageId) { var myform=document.createElement("form"); myform.action="NerdDinner/ImagePreview/AjaxSubmit"; myform.enctype="multipart/form-data"; myform.method="post"; var imageLoad=document.getElementById(fileId).cloneNode(true); myform.appendChild(imageLoad); document.body.appendChild(myform); $(myform).ajaxSubmit({success: function(responseText) { var contentType=responseText.substring(0,responseText.indexOf(';')); var contentLength=responseText.substring(responseText.indexOf(';')+1); var d=new Date(); $(imageId)[0].src="http://weblogs.
asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime(); document.body.removeChild(myform); } }); }
You also need append the child
in order
to send request and remove them after receiving response.
