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  • Naming suggestions for a function returning parent prototype

    - by hevalbaranov
    I'm having a naming trouble with a function which returns parent prototype of specified object. It's being used like this: # Pseudo Code MyClass { super(MyClass,this).constructor.call(.... The problem is that I want to use a word which is as superior as "super", but "super" is reserved even it's undefined. Now I'm using "parent", but the window object has a property named parent. I hate Javascript. What should I name this function? Names have to start with lowercase and have to be short.

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  • undefined local variable or method `user', using CarrierWave for profile images

    - by Amar H-V
    I've been following Ryan Bates' Railscasts tutorial on CarrierWave, which you can find here Everything works fine, except for when I go to view my profile, it gives me this error: undefined local variable or method `user' I don't know why it is telling me this, as I am using Devise for my authentication, and that is the name of my model. Below are some of the files which may be useful: https://gist.github.com/amarh21/7439421 I am using Rails 4.0.1 and ruby 2.0.0

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  • text from a file turned into a variable?

    - by b3y4z1d
    If I made a program that stores strings on a text file using the "list"-function(#include ), and then I want to copy all of the text from that file and call it something(so I can tell the program to type in all of the text I copied somewhere by using that one variable to refer to the text), do I use a string,double,int or what do I declare that chunk of text as? I'm making the program using c++ in a simple console application.

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  • getting names subgroups

    - by Abruzzo Forte e Gentile
    Hi All I am working with the new version of boost 1.42 and I want to use regex with named sub groups. Below an example. std::string line("match this here FIELD=VALUE in the middle"); boost::regex rgx("FIELD=(?\\w+)", boost::regex::perl ); boost::smatch thisMatch; boost::regex_searh( line, thisMatch, rgx ); Do you know how to get the content of the match ? The traditional way is std::string result( mtch["VAL"].first, mtch["VAL"].second ); but i don't want to use this way. I want to use the name of the subgroups as usual in Perl and in regex in general. I tried this, but it didn't work. std::string result( mtch["VAL"].first, mtch["VAL"].second ); Do you know how to get the value using the name of the subgroup? Thanks AFG

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  • Xcode: view references for a variable?

    - by David.Chu.ca
    I am new to Xcode. I am not sure if there is a way to view a variable's references just like "Find all references" in Visual Studio by right click on a var? For example, in my .h file, I would like to know or view all the references for property isSet: @interface MyInterface { ... BOOL isSet; // view all references to this var? ... }

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  • Regular Expression with Names and Emails

    - by Nina
    I am having a problem with regular expressions at the moment. What I'm trying to do is that for each line through the iteration, it checks for this type of pattern: Lastname, Firstname If it finds the name, then it will take the first letter of the first name, and the first six letters of the lastname and form it as an email. I have the following: $checklast = "[A-z],"; $checkfirst = "[A-z]"; if (ereg($checklast, $parts[1])||ereg($checkfirst, $parts[2])){ $first = preg_replace($checkfirst, $checkfirst{1,1}, $parts[2]); print "<a href='mailto:[email protected];'> $parts[$i] </a>"; } This one obviously broke the code. But I was initially attempting to find only the first letter of the firstname and then after that the first six letters of the lastname followed by the @email.com This didn't work out too well. I'm not sure what to do at this point. Any help is much appreciated.

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  • Get application names with specific permission

    - by rolling.stones
    I want list of all applications installed on the device which use a specific permission like INTERNET. i am using this code , but not able to retrieve results , please help . private ArrayList<String> getInstalledApps(Context context) { ArrayList<String> results = new ArrayList<String>(); PackageManager packageManager = context.getPackageManager(); List<PackageInfo> applist = packageManager.getInstalledPackages(0); Iterator<PackageInfo> it = applist.iterator(); while (it.hasNext()) { PackageInfo pk = (PackageInfo) it.next(); if (PackageManager.PERMISSION_GRANTED == packageManager.checkPermission(Manifest.permission.INTERNET, pk.packageName)) results.add("" + pk.applicationInfo.loadLabel(packageManager)); } for (int i = 0; i <= results.size(); i++) { Log.v("app using internet = ", results.toString()); } return results; } Thanks in advance. Any help accepted :)

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  • Variables variable and inheritance

    - by Xack
    I made code like this: class Object { function __get($name){ if(isset($this->{$name})){ return $this->{$name}; } else { return null; } } function __set($name, $value){ $this->{$name} = $value; } } If I extend this class (I don't want to repeat this code every time), it says "Undefined variable". Is there any way to do it?

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  • Creating "GDP in 1960" variable from GDP variables for different years

    - by Tom Smith
    Hi all, I'm pretty new to stata... I have a set of observations of the form "Country GDP Year". I want to create a new variable GDP1960, which gives the GDP in 1960 of each country for each year: USA $100m 1960 USA $100m 1960 $100m USA $200m 1965 --> USA $200m 1965 $100m Canada $60m 1960 Canada $60m 1960 $60m What's the right syntax to make this happen? (I assume egen is involved in some mysterious way)

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  • How to get path from a variable

    - by yoshco
    Following http://stackoverflow.com/questions/659647/how-to-get-folder-path-from-file-path-with-cmd I want to strip the path (without the filename) from a variable. following the logic of the methods discussed above I would like to use batch bellow, which doesn't work. any takers? possible? set cpp="C:\temp\lib.dll" echo %cpp% "C:\temp\lib.dll" echo %~dpcpp "C:\temp\" > doesn't work

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  • passing variable from vbscript to batch file

    - by sushant
    i am using vbscript to call a batch file. my script looks like: dim shell set shell=createobject("wscript.shell") shell.run "a.bat" set shell=nothing my batch file is simple and looks like: D: cd D:\d winzip32.exe -min -a D:\a i want to pass a variable from a script to the batch file. lets say the destination folder. how do i do that? any help is very much appreciated.

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  • Why is my platform variable defined as 'BNB'?

    - by Scott Langham
    Hi, Something, maybe the windows sdk or visual studio installer, has defined the Platform environment variable and given it the value BNB. What does BNB mean, and why is Platform set to BNB? Thanks. I've seen this, but it doesn't answer my question: http://social.msdn.microsoft.com/Forums/en-US/msbuild/thread/1d229d75-aa89-42bf-809b-ef98f42072bb

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  • Python script names in tasklist

    - by Richard
    I am wondering, is there a way to change the name of a script so that it is not called "python.exe" in the tasklist. The reason I am asking is that I am trying to make a batch file that run's a python script. I want the batch file to check to see if the script is already running. if the script is already running then the batch file will do nothing. Thanks

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  • Dynamic where clause in LINQ - with column names available at runtime

    - by sandesh247
    Disclaimer: I've solved the problem using Expressions from System.Linq.Expressions, but I'm still looking for a better/easier way. Consider the following situation : var query = from c in db.Customers where (c.ContactFirstName.Contains("BlackListed") || c.ContactLastName.Contains("BlackListed") || c.Address.Contains("BlackListed")) select c; The columns/attributes that need to be checked against the blacklisted term are only available to me at runtime. How do I generate this dynamic where clause? An additional complication is that the Queryable collection (db.Customers above) is typed to a Queryable of the base class of 'Customer' (say 'Person'), and therefore writing c.Address as above is not an option.

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