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  • passing info from facebook to UITabBarController

    - by EquinoX
    When my app first start, it shows up a main page showing to login to facebook and then it goes to the UITabBarController. The code that I have in my app delegate is the following: //this is the .h @interface NMeAppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; MainViewController *controller; UITabBarController *tabBar; } @property (nonatomic, retain) IBOutlet UITabBarController *tabBar; @property (nonatomic, retain) MainViewController *controller; @property (nonatomic, retain) IBOutlet UIWindow *window; @end //this is the .m of the app delegate #import "NMeAppDelegate.h" @implementation NMeAppDelegate @synthesize window; @synthesize tabBar; @synthesize controller; #pragma mark - #pragma mark Application lifecycle - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { // Override point for customization after application launch. controller = [[MainViewController alloc] init]; [window addSubview:tabBar.view]; [window addSubview:controller.view]; [window makeKeyAndVisible]; return YES; } Inside of MainViewController, I actually have a Facebook * facebook object, which basically has all of the information that I need. Every information that I need for this apps is queried in the MainViewController. The problem is that after getting this info and now I am in the UITabViewController... how do I get those information that I already queried facebook for? I have a class called UserInfo as well, which basically has everything essential I need. I need to have the info from UserInfo so that the other ViewController in the UITabBarController have access to it.... I hope my question makes sense

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  • table column accepting "0" as a member Id

    - by user682417
    I have two tables one is members table with columns member id , member first name, member last name. I have another table guest passes with columns guest pass id and member id and issue date . I have a list view that will displays guest passes details (I.e) like member name and issue date and I have two text boxes those are for entering member name and issue date . member name text box is auto complete text box that working fine.... but the problem is when I am entering the name that is not in member table at this time it will accept and displays a blank field in list view in member name column and member id is stored as "0" in guest pass table ...... I don't want to display the member name empty blank and I don t want to store "0" in guest pass table and this is the insert statement sql2 = @"INSERT INTO guestpasses(member_Id,guestPass_IssueDate)"; sql2 += " VALUES("; sql2 += "'" + tbCGuestPassesMemberId.Text + "'"; sql2 += ",'" + tbIssueDate.Text + "'"; guestpassmemberId = memberid is there any validation that need to be done can any one suggestions on this pls... and this is the auto complete text box statement sql = @"SELECT member_Id FROM members WHERE concat(member_Firstname,'',member_Lastname) ='" + tbMemberName.Text+"'"; if (dt != null) { if (dt.Rows.Count > 0) { tbCGuestPassesMemberId.Text = Convert.ToInt32(dt.Rows[0] ["member_Id"]).ToString(); } } can any one help me on this ... is there any type of validation with sql query pls help me .....

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  • Which is the best license for Open Source project?

    - by coderex
    Hi friends, I am a web developer, and i don't have enough knowledge in software licenses. I wish to publish some of my works. and i need to apply a licenses for that. My software/product is free of cost. But I have some restrictions on the distribution/Modification. Its free of cost.(but donations are acceptable ;-)) Source Code is freely available; that you can use, customize or edit/remove(but don't deviate the basic nature of the software). You don't have any permission to change the product name. There are some lib or class are and which is put into a folder caller "myname", you don't have the permission to rename "myname". You can contribute any additions modifications to my project, to the original source repository. (The contributors name/email/site link will be listed on the credit file). Don't remove the original author's name from the license. Put the license file or license code any where is in the project file or folder. You can redistribute this code as free or commercial. :) What you this, all these kinda restrictions are valid or ... ? For this, which license i want to use.

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  • Top n items in a List ( including duplicates )

    - by Krishnan
    Trying to find an efficient way to obtain the top N items in a very large list, possibly containing duplicates. I first tried sorting & slicing, which works. But this seems unnnecessary. You shouldn't need to sort a very large list if you just want the top 20 members. So I wrote a recursive routine which builds the top-n list. This also works, but is very much slower than the non-recursive one! Question: Which is my second routine (elite2) so much slower than elite, and how do I make it faster ? My code is attached below. Thanks. import scala.collection.SeqView import scala.math.min object X { def elite(s: SeqView[Int, List[Int]], k:Int):List[Int] = { s.sorted.reverse.force.slice(0,min(k,s.size)) } def elite2(s: SeqView[Int, List[Int]], k:Int, s2:List[Int]=Nil):List[Int] = { if( k == 0 || s.size == 0) s2.reverse else { val m = s.max val parts = s.force.partition(_==m) val whole = if( parts._1.size > 1) parts._1.tail:::parts._2 else parts._2 elite2( whole.view, k-1, m::s2 ) } } def main(args:Array[String]) = { val N = 1000000/3 val x = List(N to 1 by -1).flatten.map(x=>List(x,x,x)).flatten.view println(elite2(x,20)) println(elite(x,20)) } }

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  • Refetching a previously visited page

    - by user613665
    All, I am having a field day with page refetching. Any help or pointer will be greatly appreciated!! The behavior is a bit specific to mobile browser. Problem: I have two pages and created a shortcut link to pg#1 in the home page. Through a form submit button, user is taken from pg#1 to pg#2. All that is working fine. Now once I am on pg#2. I will leave the browser and click the shortcut later. The browser will stay on pg#2 and won't go to pg#1 even though the path in URLS is different between the two views. It is almost like Django decides that since I have already visited view#1, it doesn't need to fetch it again. This problem or behavior doesn't happen if I move the same code that handle the two views and the templates to a bare bone test project. Setup: I am using django-registration, context session. I am not using any HTML caching tag. I already have DEBUG turned on in my settings.py. Are there other ways that I can tell what the server is doing. Thanks in advance. pdxMobile Update: Here is the code snippets. def sendmsg(request): if request.method =='POST': messages.add_message(request, messages.INFO, "Hello world") return redirect ('rcvmsg') return render_to_response('sendMsg.html',RequestContext(request)) def rcvmsg(request): '''view that receives the msg.''' printMsg ='Didnt get a message' if messages: thisMsg = messages.get_messages(request) for rcvMsg in thisMsg: printMsg = rcvMsg return render_to_response('rcvMsg.html',{'print_msg':printMsg},RequestContext(request)) URL: url(r'^rcvMsg/','mydomain.mainApp.views.rcvmsg',name='rcvmsg'), (r'^sendMsg/code','mydomain.mainApp.views.sendmsg'),

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • Need help making a div appear on the bottom of the screen while the rest of the divs scroll

    - by user1896600
    It's hard to describe my specific problem without just showing you the HTML code. The HTML source can be seen easily from clicking "View Source" while seeing the page http://techdot.us/projects/jeopardy/view.php. The CSS is located here: http://techdot.us/projects/jeopardy/style/gameStyle.css. My main goal is to have the main content table rows/columns appear on the majority of the screen (everything except 69px, to be exact). So, the bottom 69px contains an informational panel that is supposed to stay on the bottom of the screen, even when the user scrolls down the page. Scrolling is supposed to, in theory, trigger the majority of the content to go down the page normally, except the bottom bar which stays static. I have achieved this effect on the website. However, there is a big problem. On smaller screens (as you can simulate by resizing the window), some of the main table gets cut off. It seems that my CSS solution is a botch, and, in effect, does not accomplish my main goal. The bottom bar should not cut off part of the table from the main content div (gameTable), but the main content div should display all of its content in a scrollable fashion. My CSS at the moment works as long as the viewer's screen is a certain pixel height. This is definitely not permanent. Thank you SO much for the help. I really appreciate it and totally understand that I'm being a total pain by just throwing down tons of CSS and HTML code to edit.

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  • How to implement a search page which shows results on the same page?

    - by Andrew
    I'm using ASP.NET MVC 2 for the first time on a project at work and am feeling like a bit of a noob. I have a page with a customer search control/partial view. The control is a textbox and a button. You enter a customer id into the textbox and hit search. The page then "refreshes" and shows the customer details on the same page. In other words, the customer details appear below the customer search control. This is so that if the customer isn't the right one, the user can search again without hitting back in the browser. Or, perhaps they mistyped the customer id and need to try again. I want the URL to look like this: /Customer/Search/1 Obviously, this follows the default route in the project. Now, if I type the URL above directly into my browser, it works fine. However, when I then use the search control on that page to search for say customer 2, the page refreshes with the correct customer details but the URL does not change! It stays as /Customer/Search/1 When I want it to be /Customer/Search/2 How can I get it to change to the correct URL? I am only using the default route in Global.asax. My Search method looks like this: <AcceptVerbs(HttpVerbs.Get)> _ Function Search(ByVal id As String) As ActionResult Dim customer As Customer = New CustomerRepository().GetById(id) Return View("SearchResult", customer) End Function

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  • ZF2 namespace and file system

    - by user1918648
    I have standard Application module in ZF2. It's configured by default, I didn't change anything. I just added some stuff: module/ Application/ src/ Application/ Entity/ Product/ **Product.php** Controller/ **IndexController.php** Product.php namespace Application\Entity; class Product { } IndexController.php namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } } and I get following error: Fatal error: Class 'Application\Entity\Product' not found in \module\Application\src\Application\Controller\IndexController.php on line 20 I use the same namespace, but it doesn't see it. Why? P.S: If I will change Product.php to be the following: namespace Application\Entity\Product; class Product { } then in the IndexController.php the following code will be working: namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } }

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  • Calling a register method from 2 or more controllers best practice

    - by PussInBoots
    I don't want to repeat myself. That is, I don't want the same code in two different controllers. I always start from a default mvc5 web app project. That project has a Register ActionMethod in an AccountController: // // GET: /Account/Register [AllowAnonymous] public ActionResult Register() { return View(); } // // POST: /Account/Register [HttpPost] [AllowAnonymous] [ValidateAntiForgeryToken] public async Task<ActionResult> Register(RegisterViewModel model) { if (ModelState.IsValid) { var user = new ApplicationUser() { UserName = model.UserName }; var result = await UserManager.CreateAsync(user, model.Password); if (result.Succeeded) { await SignInAsync(user, isPersistent: false); return RedirectToAction("Index", "Home"); } else { AddErrors(result); } } // If we got this far, something failed, redisplay form return View(model); } Say I have a CampaignController and I want to register a user when he/she is on that page, fills out his/her username and pass and clicks the send form/submit button. What is the best thing to do in the ActionMethod of that form/controller? Yes, I want to have the registerform in two or more places. What is the best way to accomplish this in mvc 5?

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  • MVC and binding to List of Checkboxes

    - by Josh
    Here is my problem. I have a list of models that are displayed to the user. On the left is a checkbox for each model to indicate that the user wants to choose this model (in this case, we're building products a user can add to their shopping cart). The model has no concept of being chosen...it strictly has information about the product in question. I've talked with a few other developers after having gone through and the best I could come up with is getting the formcollection and string parsing the key values to determine whether the checkbox is checked or not. This doesn't seem ideal. I was thinking there would be something more strongly bound, but I can't figure out a way to do it. I tried creating another model that had a boolean property to represent being checked and a property of the model and passing a list of that model type to the view and creating a ActionResult on the controller that accepts a list of the new model / checked property, but it comes back null. Am I just thinking too much like web forms and should just continue on with parsing checkbox values? Here's what I've done for wrapping the models inside a collection: public class SelectableCollection[T] : IList[T] {} public class SelectableTrack{ public bool IsChecked{get;set;} public bool CurrentTrack{get;set;} } For the view, I inherit from ViewPage[SelectableCollection[SelectableTrack]] For the controller, I have this as the ActionResult: [HttpPost] public ActionResult SelectTracks(SelectableCollection sc) { return new EmptyResult(); } But when I break inside the ActionResult, the collection is null. Any reason why it isn't coming through?

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  • Sorting CouchDB Views By Value

    - by Lee Theobald
    Hi all, I'm testing out CouchDB to see how it could handle logging some search results. What I'd like to do is produce a view where I can produce the top queries from the results. At the moment I have something like this: Example document portion { "query": "+dangerous +dogs", "hits": "123" } Map function (Not exactly what I need/want but it's good enough for testing) function(doc) { if (doc.query) { var split = doc.query.split(" "); for (var i in split) { emit(split[i], 1); } } } Reduce Function function (key, values, rereduce) { return sum(values); } Now this will get me results in a format where a query term is the key and the count for that term on the right, which is great. But I'd like it ordered by the value, not the key. From the sounds of it, this is not yet possible with CouchDB. So does anyone have any ideas of how I can get a view where I have an ordered version of the query terms & their related counts? I'm very new to CouchDB and I just can't think of how I'd write the functions needed.

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  • interface abstract in php real world scenario

    - by jason
    The goal is to learn whether to use abstract or interface or both... I'm designing a program which allows a user to de-duplicate all images but in the process rather then I just build classes I'd like to build a set of libraries that will allow me to re-use the code for other possible future purposes. In doing so I would like to learn interface vs abstract and was hoping someone could give me input into using either. Here is what the current program will do: recursive scan directory for all files determine file type is image type compare md5 checksum against all other files found and only keep the ones which are not duplicates Store total duplicates found at the end and display size taken up Copy files that are not duplicates into folder by date example Year, Month folder with filename is file creation date. While I could just create a bunch of classes I'd like to start learning more on interfaces and abstraction in php. So if I take the scan directory class as the first example I have several methods... ScanForFiles($path) FindMD5Checksum() FindAllImageTypes() getFileList() The scanForFiles could be public to allow anyone to access it and it stores in an object the entire directory list of files found and many details about them. example extension, size, filename, path, etc... The FindMD5Checksum runs against the fileList object created from scanForFiles and adds the md5 if needed. The FindAllImageTypes runs against the fileList object as well and adds if they are image types. The findmd5checksum and findallimagetypes are optionally run methods because the user might not intend to run these all the time or at all. The getFileList returns the fileList object itself. While I have a working copy I've revamped it a few times trying to figure out whether I need to go with an interface or abstract or both. I'd like to know how an expert OO developer would design it and why?

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  • How to enforce jsf to create new instance of bean instead of throwing NullPointerException?

    - by Roman
    I'm almost sure that I do something wrong and thus the question's title is a bit incorrect. I have a form with several fields for creating a new User-objects (fields like login, password, birthday etc). And I have 2 buttons - Cancel and Create. I didn't finish Create yet :) , but when I press Cancel I see NullPointerException. Here is simplified code: <f:view> <h:form> <h:panelGroup layout="block"> <h:inputText id="add_login" value="#{userSupport.user.login}"/> <h:inputSecret id="add_password" value="#{userSupport.user.password}"/> <h:inputText id="add_name" value="#{userSupport.user.name}"/> <h:inputText id="add_surname" value="#{userSupport.user.surname}"/> <h:commandButton value="Cancel" action="cancel"/> </h:panelGroup> </h:form> </f:view> UserSupport class has field user with getter and setter and some other methods. It's a Spring bean with Session scope. When I press cancel, I see NPE because jsf tries to save values from inputs in user-object, but user-object is null. What is the correct way of doing this?

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  • Paged UIScrollView with UIImageViews only showing first UIImageVIew

    - by Jonathan Brown
    I am working on a paged UIScrollView, but it only wants to show the first UIImageView within it. I add each UIImageView at an offset of the width of the scroll view, so that should create each page. When run, it says the scroll view is the right number of pages, but the images don't show. Any help would be much appreciated! int numSlides = NUM_TUTORIAL_SLIDES; NSString *fileName; UIImageView *slideImageView; CGRect slideFrame; for (int i = 1; i <= numSlides; i++) { slideFrame.origin.x = self.tutorialScrollView.frame.size.width * (i-1); slideFrame.origin.y = 0; slideFrame.size = self.tutorialScrollView.frame.size; slideImageView = [[UIImageView alloc] initWithFrame:slideFrame]; if([[AppManager sharedManager] is4inchScreen]) { fileName = [NSString stringWithFormat:@"Slide%[email protected]", i]; } else { fileName = [NSString stringWithFormat:@"Slide%[email protected]", i]; } slideImageView.image = [UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:fileName ofType:nil]]; [self.tutorialScrollView addSubview:slideImageView]; [slideImageView release]; } self.tutorialScrollView.contentSize = CGSizeMake(self.tutorialScrollView.frame.size.width * numSlides, self.tutorialScrollView.frame.size.height); self.tutorialScrollView.delegate = self;

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  • PHP delete script, return to 'viewsubjects.php?classroom_id=NO VALUE'

    - by Derek
    Hi, As the title states... I am deleting a 'subject' from a 'classroom' I view classrooms, then can click on a classroom to view the subject for that classroom. So the link where I am viewing subjects looks like: viewsubjects.php?classroom=23 When the user selects the delete button (in a row) to remove a subject from a class, I simply want the user to be redirected back to the list of subjects for the classroom (exactly where they were before!!) So I though this is simply a case of calling up the classroom ID within my delete script. Here is what I have: EDIT: corrected spelling mistake in code (this was not the problem) $subject_id = $_GET['subject_id']; $classroom_id = $_GET['classroom_id']; $sql = "DELETE FROM subjects WHERE subject_id=".$subject_id; $result = mysql_query($sql, $connection) or die("MySQL Error: ".mysql_error()); header("Location: viewsubjects.php?classroom_id=".$classroom_id); exit(); The subject is being removed from the DB, but when I am redirected back the URI is displaying with an empty classroom ID like: viewsubjects.php?classroom_id= Is there a way to carry the classroom ID through successfully through the delete script so it can be displayed after, allowing the user to be redirected back to the page? Thanks for any help!

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  • undefined method `code' for nil:NilClass message with rails and a legacy database

    - by Jude Osborn
    I'm setting up a very simple rails 3 application to view data in a legacy MySQL database. The legacy database is mostly rails ORM compatible, except that foreign key fields are pluralized. For example, my "orders" table has a foreign key field to the "companies" table called "companies_id" (rather than "company_id"). So naturally I'm having to use the ":foreign_key" attribute of "belongs_to" to set the field name manually. I haven't used rails in a few years, but I'm pretty sure I'm doing everything right, yet I get the following error when trying to access "order.currency.code": undefined method `code' for nil:NilClass This is a very simple application so far. The only thing I've done is generate the application and a bunch of scaffolds for each of the legacy database tables. Then I've gone into some of the models to make adjustments to accommodate the above mentioned difference in database naming conventions, and added some fields to the views. That's it. No funny business. So my database tables look like this (relevant fields only): orders ------ id description invoice_number currencies_id currencies ---------- id code description My Order model looks like this: class Order < ActiveRecord::Base belongs_to :currency, :foreign_key=>'currencies_id' end My Currency model looks like this: class Currency < ActiveRecord::Base has_many :orders end The relevant view snippet looks like this: <% @orders.each do |order| %> <tr> <td><%= order.description %></td> <td><%= order.invoice_number %></td> <td><%= order.currency.code %></td> </tr> <% end %> I'm completely out of ideas. Any suggestions?

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  • Can't return data to parent activity

    - by user23
    I'm trying to return data (the position of the item picked from the grid) to parent activity, but my code fails. The debbuger shows how 'data' gets right the key and data in the "data.putExtra("POS_ICON", position)" at child activity, but after in onActivityResult() at parent activity the debbuger shows 'data' with no key nor data returned...it's like if data loses its content. I've followed other posts and tutorials but no way. Please help. Parent activity: public void selIcono(View v){ Intent intent = new Intent (this, SelIconoActivity.class); startActivityForResult(intent,PICK_ICON_REQUEST); } protected void onActivityResult(int requestCode, int resultCode, Intent data) { //here's the problem: no data is returned!! if (requestCode == PICK_ICON_REQUEST) { if (resultCode == RESULT_OK) { // An icon was picked. putIcon(data.getIntExtra("POS_ICON", -1)); } } } Child activity: public class SelIconoActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_sel_icono); GridView gridview = (GridView)findViewById(R.id.gr_iconos); gridview.setAdapter(new ImageAdapter (this)); gridview.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View v, int position, long id) { Intent data = new Intent(); data.putExtra("POS_ICON", position); setResult(Activity.RESULT_OK, data); finish(); } }); } }

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  • Gmail Sync on Android phone

    - by sunocky
    Android has the Gmail push features, which means the new message arrives in the mailbox without checking or refreshing the mailbox. As I understand, the sync processes are like these: 1) User turns on the sync 2) There will be a alert msg and the sync flag in the Gmail DB of this device will be True 3) When a new email reach the Gmail Server, it will check if the device sync value, if it's True then send the email OK, here, I don't quite understand how exactly does it work, For a WiFi and cell signal connection, does the phone has a TCP socket open keep listening to the Gmail Server, or when a new email arrives the Server send a SMS alert to the phone, and then it will open the data channel to fetch the email? Are the two ways of connections have different approaches? And second question is which method is the priority one? Say when you are in the middle of receiving data(emails), and suddenly the phone connect to a wireless network, will the data socket be closed and then reopened for the WiFi one? What's the behavior for the case when carrier's data channel and WiFi flips? I have also downloaded the source code, anyone knows which part should I be looking into in order to solves my questions? I found a folder called "email" inside the folder "package", should I be looking at its code? I know I asked quite some questions here, I'd appreciate if you know the answer for any of them, thanks very much!

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  • right click values for Gridview column

    - by peter
    I have grid named 'GridView1' and displaying columns like this <asp:GridView ID="GridView1" OnRowCommand="ScheduleGridView_RowCommand" runat="server" AutoGenerateColumns="False" Height="60px" Style="text-align: center" Width="869px" EnableViewState="False"> <Columns> <asp:BoundField HeaderText="Topic" DataField="Topic" /> <asp:BoundField DataField="Moderator" HeaderText="Moderator" /> <asp:BoundField DataField="Expert" HeaderText="Expert" /> <asp:BoundField DataField="StartTime" HeaderText="Start" > <HeaderStyle Width="175px" /> </asp:BoundField> <asp:BoundField DataField="EndTime" HeaderText="End" > <HeaderStyle Width="175px" /> </asp:BoundField> <asp:TemplateField HeaderText="Join" ShowHeader="False"> <ItemTemplate> <asp:Button ID="JoinBT" runat="server" CommandArgument="<%# Container.DataItemIndex %>" CommandName="Join" Text="Join" Width="52px" /> </ItemTemplate> <HeaderStyle Height="15px" /> </asp:TemplateField> </Columns> </asp:GridView> Here what is my requirement is whenever we right click on each row in gridview ,it should display three option join meeting(if we click it will go to meeting.aspx),,view details(will go to detail.aspx),,Subscribe(subscribe.aspx) just like when we click right any where we can see view,sortby,refresh like that..Do we need to implement javascript here

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  • Handle edittexts onKeyListener ?

    - by hungson175
    Hi everyone, I am creating login screen with 2 editTexts: etUsername and etPassword. On the etUsername, user should input the username and press Enter to go to the edit text etPassword, then he inputs the password, press Enter to login. Here are my current codes: etUsername.setOnKeyListener(new OnKeyListener() { @Override public boolean onKey(View v, int keyCode, KeyEvent event) { if ((keyCode == KeyEvent.KEYCODE_ENTER)) { etPassword.requestFocus(); return true; } else return false; } }); etPassword.setOnKeyListener(new OnKeyListener() { @Override public boolean onKey(View v, int keyCode, KeyEvent event) { if ((keyCode == KeyEvent.KEYCODE_ENTER)) { loginToServer(); return true; } else return false; } }); But when I input the username, and then press Enter – the program tries to log in to the server. In the debug mode, I saw that when I pressed Enter once (on the etUsername) then first: etUsername.onKey() is called and then etPassword.onKey() is also called ! Can anyone please tell me, how to implement what I want ? Thank you very much, Son

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  • Creation of AsyncTask taking too much time Android

    - by user2842342
    I am making a network call in an AsyncTask, but the problem i am facing is the amount of time it is taking to start the doInBackground method. Here is a part of my code: button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.d("Temp:",System.currentTimeMillis()+""); new Move().execute(); /*some other logic } } And my AsyncTask is: private class Move extends AsyncTask<Void, Void, Void> { @Override protected Void doInBackground(Void... temp) { Log.d("start:",System.currentTimeMillis()+""); gson.fromJson(Web.Request.get(some_URL),Void.class); Log.d("end:",System.currentTimeMillis()+""); return null; } } These are the logs i got: 32658-998/com.example.game D/temp:? 1408923006159 32658-998/com.example.game D/start:? 1408923035163 32658-998/com.example.game D/end:? 1408923035199 So actually it took almost 29 secs to reach the first line in doInBackground method, where as it took just 36 ms to finish the network call. I tried it many times, the time taken is almost in the same order. Is it possible to start the AsyncTask immediately? Or is there any other way to solve this problem.(other than a running a simple thread?) Thank you :)

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  • OOP + MVC advice on Member Controller

    - by dan727
    Hi, I am trying to follow good practices as much as possible while I'm learning using OOP in an MVC structure, so i'm turning to you guys for a bit of advice on something which is bothering me a little here. I am writing a site where I will have a number of different forms for members to fill in (mainly data about themselves), so i've decided to set up a Member controller where all of the forms relating to the member are represented as individual methods. This includes login/logout methods, as well as editing profile data etc. In addition to these methods, i also have a method to generate the member's control panel widget, which is a constant on every page on the site while the member is logged in. The only thing is, all of the other methods in this controller all have the same dependencies and form templates, so it would be great to generate all this in the constructor, but as the control_panel method does not have the same dependencies etc, I cannot use the constructor for this purpose, and instead I have to redeclare the dependencies and same template snippets in each method. This obviously isn't ideal and doesn't follow DRY principle, but I'm wondering what I should do with the control_panel method, as it is related to the member and that's why I put it in that controller in the first place. Am I just over-complicating things here and does it make sense to just move the control_panel method into a simple helper class? Here are the basic methods of the controller: class Member_Controller extends Website_Controller { public function __construct() { parent::__construct(); if (request::is_ajax()) { $this->auto_render = FALSE; // disable auto render } } public static function control_panel() { //load control panel view $panel = new View('user/control_panel'); return $panel; } public function login() { } public function register() { } public function profile() { } public function household() { } public function edit_profile() { } public function logout() { } }

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  • My iPhone app runs fine in simulator but quit in device (iPod touch 3.1.2) test, I got the following

    - by Mickey Shine
    I was running myapp on an iPod touch and I noticed it missed some libraries. Is that the reason? [Session started at 2010-03-19 15:57:04 +0800.] GNU gdb 6.3.50-20050815 (Apple version gdb-1128) (Fri Dec 18 10:08:53 UTC 2009) Copyright 2004 Free Software Foundation, Inc. GDB is free software, covered by the GNU General Public License, and you are welcome to change it and/or distribute copies of it under certain conditions. Type "show copying" to see the conditions. There is absolutely no warranty for GDB. Type "show warranty" for details. This GDB was configured as "--host=i386-apple-darwin --target=arm-apple-darwin".tty /dev/ttys007 Loading program into debugger… Program loaded. target remote-mobile /tmp/.XcodeGDBRemote-237-78 Switching to remote-macosx protocol mem 0x1000 0x3fffffff cache mem 0x40000000 0xffffffff none mem 0x00000000 0x0fff none run Running… [Switching to thread 11779] [Switching to thread 11779] sharedlibrary apply-load-rules all (gdb) continue warning: Unable to read symbols for "/Library/MobileSubstrate/MobileSubstrate.dylib" (file not found). 2010-03-19 15:57:18.892 myapp[2338:207] MS:Notice: Installing: com.yourcompany.myapp [myapp] (478.52) 2010-03-19 15:57:19.145 myapp[2338:207] MS:Notice: Loading: /Library/MobileSubstrate/DynamicLibraries/Backgrounder.dylib warning: Unable to read symbols for "/Library/MobileSubstrate/DynamicLibraries/Backgrounder.dylib" (file not found). warning: Unable to read symbols for "/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS3.1.2.sdk/usr/lib/libsubstrate.dylib" (file not found). MS:Warning: message not found [myappAppDelegate applicationWillResignActive:] MS:Warning: message not found [myappAppDelegate applicationDidBecomeActive:] 2010-03-19 15:57:19.550 myapp[2338:207] in FirstViewController 2010-03-19 15:57:20.344 myapp[2338:207] in load table view 2010-03-19 15:57:20.478 myapp[2338:207] in loading splash view 2010-03-19 15:57:22.793 myapp[2338:207] in set interface Program received signal: “0”. warning: check_safe_call: could not restore current frame

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  • MVC2 AJAX - determining UpdateTargetId based on the returned data

    - by DanielJW
    The scenario: I'm creating a login form for an MVC2 application. How i'm doing it: The form submits to an MVC2 action which validates the username/password. If it fails validation the action returns the form (a partial view) for the user to try again. If it passes validation the action returns the page the user was visiting before they logged in (a view). What i want to happen: 1 - when the form is submitted and the user validates successfully, The returned result should replace the current page (like what happens if you don't set an UpdateTargetId). 2 - When the form is submitted and the user fails validation, the returned result should replace the form (like what happens if you set the UpdateTargetID to the form's containing element). The problem: I can make both of those things work, but not at the same time. I can either have it always replace the current page, or always just replace the contents of the UpdateTargetId element. But I need it to be able to do either depending on whether the user successfully validated or not. What I need The ideal solution would be to be able to examine the result of the ajax request and determine whether to use the UpdateTargetId (replacing just the form) or not (replacing the whole page). I expect it would involve some work with jquery (assuming it's possible) but i'm not really that great with jquery yet to figure out how to do it myself. If it can't be done this way I'm also open to other methods/solutions for making it work in a similar fashion. Thanks in advance ..

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