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  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

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  • Google App Engine: TypeError problem with Models

    - by Rosarch
    I'm running Google App Engine on the dev server. Here is my models file: from google.appengine.ext import db import pickle import re re_dept_code = re.compile(r'[A-Z]{2,}') re_course_number = re.compile(r'[0-9]{4}') class DependencyArcHead(db.Model): sink = db.ReferenceProperty() tails = db.ListProperty() class DependencyArcTail(db.Model): courses = db.ListProperty() It gives this error: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3192, in _HandleRequest self._Dispatch(dispatcher, self.rfile, outfile, env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3135, in _Dispatch base_env_dict=env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 516, in Dispatch base_env_dict=base_env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2394, in Dispatch self._module_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2304, in ExecuteCGI reset_modules = exec_script(handler_path, cgi_path, hook) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2200, in ExecuteOrImportScript exec module_code in script_module.__dict__ File "main.py", line 19, in <module> from src.Models import Course, findCourse, validateCourse, dictForJSON, clearAndBuildDependencyGraph File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1279, in Decorate return func(self, *args, **kwargs) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1929, in load_module return self.FindAndLoadModule(submodule, fullname, search_path) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1279, in Decorate return func(self, *args, **kwargs) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1831, in FindAndLoadModule description) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1279, in Decorate return func(self, *args, **kwargs) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1782, in LoadModuleRestricted description) File "src\Models.py", line 14, in <module> class DependencyArcHead(db.Model): File "src\Models.py", line 17, in DependencyArcHead tails = db.ListProperty() TypeError: __init__() takes at least 2 arguments (1 given) What am I doing wrong?

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  • Showing multiple models in a single ListView

    - by Veer
    I've three models (Contacts, Notes, Reminders). I want to search all these and produce the filtered result in a single listview and depending upon the selection I've to display the corresponding view(UserControl) to its right. I want the right way of implementing the design or atleast alternatives to this method that I've tried. Now I've tried it using a IntegratedViewModel having all the properties from all the three models. public class IntegratedViewModel { ContactModel _contactModel; NoteModel _noteModel; public IntegratedViewModel(ContactModel contactModel) { _contactModel = contactModel; } // similarly for other models also public string DisplayTitle // For displaying in ListView { get; //same as set set { If(_contactModel != null) return _contactModel.Name; If(_noteModel != null) return _noteModel.Title; } } // All other properties from the three models includin the Name/Title properties for displaying them in the corresponding views(UserControl) } Now I set the itemsSource as the List<IntegratedViewModel>. I've to now bind the visibility of the views to some properties in the MainViewModel. I tried setting bool properties like IsContactViewSelected, IsNoteViewSelected using the setter of SelectedEntity property which is bound to the ListView's SelectedItem. public SelectedEntity { //get set { oldvalue = _selectedEntity; _selectedEntity = value; // now i find the Type of model selected using oldvalue.ModelType // where ModelType is a property in the IntegratedViewModel // according to the type, i set one of the above bool properties to false // and do the same for _selectedEntity but set the property to true // so that the view corresponding to the selectedEntityType is visible // and others are collapsed } } Here is the problem: For eg: let us say, I selected an item of type ContactModel, the old selection being NoteModel. I set the property IsNoteModelSelected to false according to the oldvalue, it sets the property and then Raises the propertychanged event and does not go and check the remaining if condition where i check for _selectedEntity which is used to set the IsContactModelSelected to true.

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  • Location of DB models in Zend Framework - want them centralized

    - by jeffkolez
    Maybe I've been staring at the problem too long and it's much simpler than I think, but I'm stuck right now. I have three websites that are going to share database models. I've structured my applications so that I have an application directory for each site and a public directory for each site. The DB models live in a directory in the library along with Zend Framework and my third party libraries. I use the Autoloader class and when I try to instantiate one of my DB classes, it fails. The library directory is in my include path, but for whatever reason it refuses to instantiate my classes. It will work if I have my models in my application directory, but that's not the point. They're supposed to be shared classes in a Library. $model = new Model_Login(); $model->hello_world(); This fails when its in the library. The class is just a test: class Model_Login { public function hello_world() { echo "hello world"; } } Everything works until I try to instantiate one of my models. I've even tried renaming the class to something else (Db_Login), but that doesn't work either. Any ideas? Thanks in advance.

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  • Overly accessible and incredibly resource hungry relationships between business objects. How can I f

    - by Mike
    Hi, Firstly, This might seem like a long question. I don't think it is... The code is just an overview of what im currently doing. It doesn't feel right, so I am looking for constructive criticism and warnings for pitfalls and suggestions of what I can do. I have a database with business objects. I need to access properties of parent objects. I need to maintain some sort of state through business objects. If you look at the classes, I don't think that the access modifiers are right. I don't think its structured very well. Most of the relationships are modelled with public properties. SubAccount.Account.User.ID <-- all of those are public.. Is there a better way to model a relationship between classes than this so its not so "public"? The other part of this question is about resources: If I was to make a User.GetUserList() function that returns a List, and I had 9000 users, when I call the GetUsers method, it will make 9000 User objects and inside that it will make 9000 new AccountCollection objects. What can I do to make this project not so resource hungry? Please find the code below and rip it to shreds. public class User { public string ID {get;set;} public string FirstName {get; set;} public string LastName {get; set;} public string PhoneNo {get; set;} public AccountCollection accounts {get; set;} public User { accounts = new AccountCollection(this); } public static List<Users> GetUsers() { return Data.GetUsers(); } } public AccountCollection : IEnumerable<Account> { private User user; public AccountCollection(User user) { this.user = user; } public IEnumerable<Account> GetEnumerator() { return Data.GetAccounts(user); } } public class Account { public User User {get; set;} //This is public so that the subaccount can access its Account's User's ID public int ID; public string Name; public Account(User user) { this.user = user; } } public SubAccountCollection : IEnumerable<SubAccount> { public Account account {get; set;} public SubAccountCollection(Account account) { this.account = account; } public IEnumerable<SubAccount> GetEnumerator() { return Data.GetSubAccounts(account); } } public class SubAccount { public Account account {get; set;} //this is public so that my Data class can access the account, to get the account's user's ID. public SubAccount(Account account) { this.account = account; } public Report GenerateReport() { Data.GetReport(this); } } public static class Data { public static List<Account> GetSubAccounts(Account account) { using (var dc = new databaseDataContext()) { List<SubAccount> query = (from a in dc.Accounts where a.UserID == account.User.ID //this is getting the account's user's ID select new SubAccount(account) { ID = a.ID, Name = a.Name, }).ToList(); } } public static List<Account> GetAccounts(User user) { using (var dc = new databaseDataContext()) { List<Account> query = (from a in dc.Accounts where a.UserID == User.ID //this is getting the user's ID select new Account(user) { ID = a.ID, Name = a.Name, }).ToList(); } } public static Report GetReport(SubAccount subAccount) { Report report = new Report(); //database access code here //need to get the user id of the subaccount's account for data querying. //i've got the subaccount, but how should i get the user id. //i would imagine something like this: int accountID = subAccount.Account.User.ID; //but this would require the subaccount's Account property to be public. //i do not want this to be accessible from my other project (UI). //reading up on internal seems to do the trick, but within my code it still feels //public. I could restrict the property to read, and only private set. return report; } public static List<User> GetUsers() { using (var dc = new databaseDataContext()) { var query = (from u in dc.Users select new User { ID = u.ID, FirstName = u.FirstName, LastName = u.LastName, PhoneNo = u.PhoneNo }).ToList(); return query; } } }

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  • Pros and Cons on where to place business logic: app level or DB

    - by Juri
    Hi, I always again encounter discussions about where to place the business logic: inside a business layer in the application code or down in the DB in terms of stored procedures. Personally I'd tend to the 1st approach, but I'd like to hear some opinions from your part first, without influencing you with my personal views. I know there doesn't exist a one-size-fits-all solution and it often depends on many factors, but we can discuss about that. Btw, we are in the context of web applications and our current approach is to have UI layer which accepts UI input and does a first, client-side validation Business layer with a number of service-classes which contains the business logic including validation for user input (server-side) Data Access Layer which calls stored procedures from the DB for doing persistency/read operations Many people however tend to move the business layer stuff (especially regarding the validation) down to the DB in terms of stored procedures. What do you think about it? I'd like to discuss.

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  • What are good ways to guarantee business continuity with a SaaS product?

    - by tommyvdz
    For my Bachelor Thesis I am researching how SaaS providers can arrange some sort of business continuity guarantee. You probably know the Source Code Escrow arrangements for 'shrink-wrapped' software. They give customers access to the source code and all applicable documentation whenever the software supplier gets into (financial) trouble. This clearly does not work for SaaS, because customers have no use for just the source code, and customers probably can not afford not being able to login to their CRM system for a couple weeks because the SaaS provider went bankrupt. I am currently researching different methods to solve this problem. Do you know good and practical solutions to solve this continuity problem? Or companies that already offer a good solution? Thanks!

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  • What is the business case for a dependency injection (DI) framework?

    - by kalkie
    At my company we want to start using a dependency injection (DI) framework for managing our dependencies. I have some difficulty with explaining the business value of such a framework. Currently I have come up with these reasons. Less source code, delete all the builder patterns in the code. Increase in flexibility. Easier to switch dependencies. Better separation of concern. The framework is responsible for creating instances instead of our code. Has anybody else had to persuade management? How did you do that? What reasons did you use?

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  • working on lists in python

    - by owca
    I'm trying to make a small modification to django lfs project, that will allow me to deactivate products with no stocks. Unfortunatelly I'm just beginning to learn python, so I have big trouble with its syntax. That's what I'm trying to do. I'm using method 'has_variants' which returns true if product has any. Then I'm building a list from variants for this product. Next for every product in this list (I've called it 'set') I check it's stock and set bool variable 'inactive' to true if product has no stocks and to false if there are any. Finally if 'inactive' is false I'm setting self.active to 0. Code fails in line with: set[] = s How to correct it ? def deactivate(self): """If there are no stocks, deactivate the product. Used in last step of checkout. """ if self.has_variants(): for s in self.variants.filter(active=True): set[] = s for var in set: if var.get_stock_amount() == 0: inactive = True else: inactive = False else: if self.get_stock_amount() == 0: inactive = True if inactive: self.active = False return 0 error log : Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 362, in execute_manager utility.execute() File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 213, in execute translation.activate('en-us') File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 73, in activate return real_activate(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 180, in _fetch app = import_module(appname) File "/home/purplecow/rails/purpledev/site-packages/django/utils/importlib.py" , line 35, in import_module __import__(name) File "/home/purplecow/rails/purpledev/lfs/caching/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/caching/listeners.py", line 10, in < module> from lfs.cart.models import Cart File "/home/purplecow/rails/purpledev/lfs/cart/models.py", line 8, in <module> from lfs.catalog.models import Product File "/home/purplecow/rails/purpledev/lfs/catalog/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/catalog/listeners.py", line 5, in <m odule> from lfs.catalog.models import PropertyGroup File "/home/purplecow/rails/purpledev/lfs/catalog/models.py", line 589 set[] = s ^ SyntaxError: invalid syntax

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  • List display names from django models

    - by Ed
    I have an object: POP_CULTURE_TYPES = ( ('SG','Song'), ('MV', 'Movie'), ('GM', 'Game'), ('TV', 'TV'), ) class Pop_Culture(models.Model): name = models.CharField(max_length=30, unique=True) type = models.CharField(max_length=2, choices = POP_CULTURE_TYPES, blank=True, null=True) Then I have a function: def choice_list(request, modelname, field_name): mdlnm = get.model('mdb', modelname.lower()) mdlnm = mdlnm.objects.values_list(field_name, flat=True).distinct().order_by(field_name) return render_to_response("choice_list.html", { 'model' : modelname, 'field' : field_name, 'field_list' : mdlnm }) This gives me a distinct list of all the "type" entries in the database in the "field_list" variable passed in render_to_response. But I don't want a list that shows: SG MV I want a list that shows: Song Movie I can do this on an individual object basis if I was in the template object.get_type_display But how do I get a list of all of the unique "type" entries in the database as their full names for output into a template? I hope this question was clearly described. . .

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  • Designing Web Service Using Ruby on Rails - Mapping ActiveRecord Models

    - by michaeldelorenzo
    I've put together a RoR application and would now like to publish a RESTful web service for interacting with my application. I'm not sure where to go exactly, I don't want to simply expose my ActiveRecord models since there is some data on each model that isn't needed or shouldn't be exposed via an API like this. I also don't want to create a SOAP solution. My application is built using Rails 2.3.5 and I hope to move to Rails 3.0 soon after its released. I'm basically looking for a way to map my ActiveRecord models to "models" that would be exposed via the web service. Is ActiveResource the correct thing to use? What about ActionWebService?

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  • Zend Framework Modules can't find/load Models..

    - by user284503
    For some frustrating reason, I configured some Modules, which seemed to work fine, However I cannot load a Modules Models. If I move the Models to the Default they load, but I just can't get the Framework to find them locally.. Example: My Modules Directory is: application\modules\books\models\books.php (books is my Model) class Application_Module_Books_Model_Books extends Zend_Db_Table_Abstract {} I also tried.. Books_Model_Books, Model_Books, books, Modules_.. you name it I tried it :) My controller is in the Books Module, and is an Index Controller, and it can never find the Local Model. I'm using Application.ini and it is configured this way: resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.params.displayExceptions = 1 resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" I have a BootStrap in the Modules Directory: class Admin_Bootstrap extends Zend_Application_Module_Bootstrap { } I'm on Zend Framework 1.10, and ideas.. ?

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  • Of Models / Entities and N-tier applications

    - by Jonn
    I've only discovered a month ago the folly of directly accessing entities / models from the data access layer of an n-tier app. After reading about ViewModels while studying ASP.NET MVC, I've come to understand that to make a truly extensible application the model that the UI layer interacts with must be different from the one that the Data Access layer has access to. But what about the Business layer? Should I have a different set of models for my business layer as well? For true separation of concern, should I have a specific set of models that are relevant only to my business layer so as not to mess around with any entities (possibly generated by for example, the entity framework, or EJB) in the DAL or would that be overkill?

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  • access models and forms within modules

    - by sims
    Hi Stackers, What is the best way to access my models and forms from a controller of a module? Let's explain with "pictures": /application/module/storage/controllers/IndexController.php needs to call readAction in the class called storage_Model_Files in /application/module/storage/models/Files.php I've made this app's dir structure and these forms and models with zf.sh (Zend_Tool). I've read about all sorts of ways of manually including these files. I want to lazy load them much like everything is done automatically with the default module. I can't seem to find how in the docs. Does that make sense? I have: resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" in my application.ini file. So I can access my controllers fine. Thanks for your help!

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  • Overriding fetch in multiple spine models

    - by Adam Charnock
    I need to override Spine's @fetch() method in all of my Spine models. Currently I have code duplication as follows: TastypieEndpointMixin = fromJSON: (data) -> return unless data return Spine.Model.fromJSON(data.objects) class App.models.Position extends Spine.Model @configure 'Position', 'code', 'name' @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/position/?format=json' validate: -> 'code is required' unless @code @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer class App.models.Player extends Spine.Model @configure 'Player', 'first_name', 'last_name', ... @extend Spine.Model.Ajax @extend TastypieEndpointMixin @url: '/api/v1/player/?format=json' @fetch: -> defer = $.Deferred() @one "refresh", -> defer.resolve() super return defer My question is: How can I create some form of parent class which contains @fetch()? I know this should be a simple problem to solve. I have tried many options (including extending Spine.Model and Spine.Model.Ajax), but nothing works and I cannot seem to get my head around it.

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  • Creating custom model using other models in ASP.NET MVC

    - by Soham Dasgupta
    As the title suggests I have two models Products And Orders which are actually two table in my database and I have used a LINQ to SQL class to create there models. Now I wan to create a model named "OrderDetails" which will have properties from both the model like product name and id from product and Order number from orders something like this. An then I want to create a view from this custom model and from which I want to add "CRUD" operation. What should be my approach. And in many scenarios I may have to use data from more than 4 models. Please help. I'm wondering helplessly and I have only two days experience in ASP.NET MVC.

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  • Rails 3 loading all models on startup

    - by janechii
    Hi all, I have a class method mixed in to all my models. the method gets called when the model class is evaluated. unfortunately (for me), this seems to be on-demand, whenever the model is needed in development env. how can have rails load all the models at start up? is this even advisable? class Foo < ActiveRecord::Base include Acl register_acl # i need this to be called for all models at start up end thank you!

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  • Django notification get date one accesses a link

    - by dana
    hi there, i'm making a notification system, so that a user in a virtual community to be announced when someone sends him a message, or starts following him (the follow relation is like a friend relation, but it is not necessarily reciprocal) my view function: def notification_view(request, last_checked): u = Relation.objects.filter(date_follow>Notification.objects.get(last_checked=last_checked)) v = Message.objects.filter(date>Notification.objects.get(last_checked=last_checked)) if u: notification_type = follow if notice_settings == receive_notification or notice_settings == only_follow following = u if v: notification_type = message if notice_settings == receive_notification or notice_settings == only_messages message = v return render_to_response('notification/notification.html', { 'following': following, 'message':message, }, context_instance=RequestContext(request)) the models.py: class NoticeType(models.Model): follow = models.ForeignKey(Relations, editable = False) message = models.ForeignKey(Messages) classroom_invitation = models.ForeignKey(Classroom) class Notification(models.Model): receiver = models.ForeignKey(User, editable=False) date = models.DateTimeField(auto_now=True, editable = False) notice_type = models.ForeignKey(NoticeType, editable = False, related_name = "notification_type") sent = models.BooleanField(default = True) last_checked = models.DateTimeField(auto_now=True, editable = False) class NotificationSettings(models.Model): user = models.ForeignKey(User) receive_notifications = models.BooleanField(default = True) only_follow = models.BooleanField(default = False) only_message = models.BooleanField(default = False) only_classroom = models.BooleanField(default = False) #receive_on_email = models.BooleanField(default = False) my problem is: i want last_checked to be the time when someone acceses a link (the notification link). How can i possibily save that time? how can i get it? thanks in avance!

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  • The Data Scientist

    - by BuckWoody
    A new term - well, perhaps not that new - has come up and I’m actually very excited about it. The term is Data Scientist, and since it’s new, it’s fairly undefined. I’ll explain what I think it means, and why I’m excited about it. In general, I’ve found the term deals at its most basic with analyzing data. Of course, we all do that, and the term itself in that definition is redundant. There is no science that I know of that does not work with analyzing lots of data. But the term seems to refer to more than the common practices of looking at data visually, putting it in a spreadsheet or report, or even using simple coding to examine data sets. The term Data Scientist (as far as I can make out this early in it’s use) is someone who has a strong understanding of data sources, relevance (statistical and otherwise) and processing methods as well as front-end displays of large sets of complicated data. Some - but not all - Business Intelligence professionals have these skills. In other cases, senior developers, database architects or others fill these needs, but in my experience, many lack the strong mathematical skills needed to make these choices properly. I’ve divided the knowledge base for someone that would wear this title into three large segments. It remains to be seen if a given Data Scientist would be responsible for knowing all these areas or would specialize. There are pretty high requirements on the math side, specifically in graduate-degree level statistics, but in my experience a company will only have a few of these folks, so they are expected to know quite a bit in each of these areas. Persistence The first area is finding, cleaning and storing the data. In some cases, no cleaning is done prior to storage - it’s just identified and the cleansing is done in a later step. This area is where the professional would be able to tell if a particular data set should be stored in a Relational Database Management System (RDBMS), across a set of key/value pair storage (NoSQL) or in a file system like HDFS (part of the Hadoop landscape) or other methods. Or do you examine the stream of data without storing it in another system at all? This is an important decision - it’s a foundation choice that deals not only with a lot of expense of purchasing systems or even using Cloud Computing (PaaS, SaaS or IaaS) to source it, but also the skillsets and other resources needed to care and feed the system for a long time. The Data Scientist sets something into motion that will probably outlast his or her career at a company or organization. Often these choices are made by senior developers, database administrators or architects in a company. But sometimes each of these has a certain bias towards making a decision one way or another. The Data Scientist would examine these choices in light of the data itself, starting perhaps even before the business requirements are created. The business may not even be aware of all the strategic and tactical data sources that they have access to. Processing Once the decision is made to store the data, the next set of decisions are based around how to process the data. An RDBMS scales well to a certain level, and provides a high degree of ACID compliance as well as offering a well-known set-based language to work with this data. In other cases, scale should be spread among multiple nodes (as in the case of Hadoop landscapes or NoSQL offerings) or even across a Cloud provider like Windows Azure Table Storage. In fact, in many cases - most of the ones I’m dealing with lately - the data should be split among multiple types of processing environments. This is a newer idea. Many data professionals simply pick a methodology (RDBMS with Star Schemas, NoSQL, etc.) and put all data there, regardless of its shape, processing needs and so on. A Data Scientist is familiar not only with the various processing methods, but how they work, so that they can choose the right one for a given need. This is a huge time commitment, hence the need for a dedicated title like this one. Presentation This is where the need for a Data Scientist is most often already being filled, sometimes with more or less success. The latest Business Intelligence systems are quite good at allowing you to create amazing graphics - but it’s the data behind the graphics that are the most important component of truly effective displays. This is where the mathematics requirement of the Data Scientist title is the most unforgiving. In fact, someone without a good foundation in statistics is not a good candidate for creating reports. Even a basic level of statistics can be dangerous. Anyone who works in analyzing data will tell you that there are multiple errors possible when data just seems right - and basic statistics bears out that you’re on the right track - that are only solvable when you understanding why the statistical formula works the way it does. And there are lots of ways of presenting data. Sometimes all you need is a “yes” or “no” answer that can only come after heavy analysis work. In that case, a simple e-mail might be all the reporting you need. In others, complex relationships and multiple components require a deep understanding of the various graphical methods of presenting data. Knowing which kind of chart, color, graphic or shape conveys a particular datum best is essential knowledge for the Data Scientist. Why I’m excited I love this area of study. I like math, stats, and computing technologies, but it goes beyond that. I love what data can do - how it can help an organization. I’ve been fortunate enough in my professional career these past two decades to work with lots of folks who perform this role at companies from aerospace to medical firms, from manufacturing to retail. Interestingly, the size of the company really isn’t germane here. I worked with one very small bio-tech (cryogenics) company that worked deeply with analysis of complex interrelated data. So  watch this space. No, I’m not leaving Azure or distributed computing or Microsoft. In fact, I think I’m perfectly situated to investigate this role further. We have a huge set of tools, from RDBMS to Hadoop to allow me to explore. And I’m happy to share what I learn along the way.

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  • Small Business Server 2008 - Microsoft Windows Search or Microsoft Search Server 2020 Express

    - by Christopher Edwards
    See Also - Small (Business) Server - Microsoft Windows Search or Microsoft Search Server 2008 Express Can anyone tell me if they have Search Server Express 2010 Beta working on Small Business Server 2010, or indeed if it is supported. The only reference I can find is here, but given how scant it is I'm not sure I should trust it:- http://social.technet.microsoft.com/Forums/en/sharepoint2010setup/thread/12cf9846-b940-4441-9fc1-30016ea87e5c

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  • Django custom managers - how do I return only objects created by the logged-in user?

    - by Tom Tom
    I want to overwrite the custom objects model manager to only return objects a specific user created. Admin users should still return all objects using the objects model manager. Now I have found an approach that could work. They propose to create your own middleware looking like this: #### myproject/middleware/threadlocals.py try: from threading import local except ImportError: # Python 2.3 compatibility from django.utils._threading_local import local _thread_locals = local() def get_current_user(): return getattr(_thread_locals, 'user', None) class ThreadLocals(object): """Middleware that gets various objects from the request object and saves them in thread local storage.""" def process_request(self, request): _thread_locals.user = getattr(request, 'user', None) #### end And in the Custom manager you could call the get_current_user() method to return only objects a specific user created. class UserContactManager(models.Manager): def get_query_set(self): return super(UserContactManager, self).get_query_set().filter(creator=get_current_user()) Is this a good approach to this use-case? Will this work? Or is this like "using a sledgehammer to crack a nut" ? ;-) Just using: Contact.objects.filter(created_by= user) in each view doesn`t look very neat to me. EDIT Do not use this middleware approach !!! use the approach stated by Jack M. below After a while of testing this approach behaved pretty strange and with this approach you mix up a global-state with a current request. Use the approach presented below. It is really easy and no need to hack around with the middleware. create a custom manager in your model with a function that expects the current user or any other user as an input. #in your models.py class HourRecordManager(models.Manager): def for_user(self, user): return self.get_query_set().filter(created_by=user) class HourRecord(models.Model): #Managers objects = HourRecordManager() #in vour view you can call the manager like this and get returned only the objects from the currently logged-in user. hr_set = HourRecord.objects.for_user(request.user)

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  • Custom Django Field is deciding to work as ForiegnKey for no reason

    - by Joe Simpson
    Hi, i'm making a custom field in Django. There's a problem while trying to save it, it's supposed to save values like this 'user 5' and 'status 9' but instead in the database these fields show up as just the number. Here is the code for the field: def find_key(dic, val): return [k for k, v in dic.items() if v == val][0] class ConnectionField(models.TextField): __metaclass__ = models.SubfieldBase serialize = False description = 'Provides a connection for an object like User, Page, Group etc.' def to_python(self, value): if type(value) != unicode: return value value = value.split(" ") if value[0] == "user": return User.objects.get(pk=value[1]) else: from social.models import connections return get_object_or_404(connections[value[0]], pk=value[1]) def get_prep_value(self, value): from social.models import connections print value, "prep" if type(value) == User: return "user %s" % str(value.pk) elif type(value) in connections.values(): o= "%s %s" % (find_key(connections, type(value)), str(value.pk)) print o, "return" return o else: print "CONNECTION ERROR!" raise TypeError("Value is not connectable!") Connection is just a dictionary with the "status" text linked up to the model for a StatusUpdate. I'm saving a model like this which is causing the issue: Relationship.objects.get_or_create(type="feedback",from_user=request.user,to_user=item) Please can someone help, Many Thanks Joe *_*

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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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