Search Results

Search found 32753 results on 1311 pages for 'row number'.

Page 64/1311 | < Previous Page | 60 61 62 63 64 65 66 67 68 69 70 71  | Next Page >

  • All possible combinations of length 8 in a 2d array

    - by CodeJunki
    Hi, I've been trying to solve a problem in combinations. I have a matrix 6X6 i'm trying to find all combinations of length 8 in the matrix. I have to move from neighbor to neighbor form each row,column position and i wrote a recursive program which generates the combination but the problem is it generates a lot of duplicates as well and hence is inefficient. I would like to know how could i eliminate calculating duplicates and save time. int a={{1,2,3,4,5,6}, {8,9,1,2,3,4}, {5,6,7,8,9,1}, {2,3,4,5,6,7}, {8,9,1,2,3,4}, {5,6,7,8,9,1}, } void genSeq(int row,int col,int length,int combi) { if(length==8) { printf("%d\n",combi); return; } combi = (combi * 10) + a[row][col]; if((row-1)>=0) genSeq(row-1,col,length+1,combi); if((col-1)>=0) genSeq(row,col-1,length+1,combi); if((row+1)<6) genSeq(row+1,col,length+1,combi); if((col+1)<6) genSeq(row,col+1,length+1,combi); if((row+1)<6&&(col+1)<6) genSeq(row+1,col+1,length+1,combi); if((row-1)>=0&&(col+1)<6) genSeq(row-1,col+1,length+1,combi); if((row+1)<6&&(row-1)>=0) genSeq(row+1,col-1,length+1,combi); if((row-1)>=0&&(col-1)>=0) genSeq(row-1,col-1,length+1,combi); } I was also thinking of writing a dynamic program basically recursion with memorization. Is it a better choice?? if yes than I'm not clear how to implement it in recursion. Have i really hit a dead end with approach??? Thankyou Edit Eg result 12121212,12121218,12121219,12121211,12121213. the restrictions are that you have to move to your neighbor from any point, you have to start for each position in the matrix i.e each row,col. you can move one step at a time, i.e right, left, up, down and the both diagonal positions. Check the if conditions. i.e if your in (0,0) you can move to either (1,0) or (1,1) or (0,1) i.e three neighbors. if your in (2,2) you can move to eight neighbors. so on...

    Read the article

  • [java] Returning the element number of the longest string in an array

    - by JohnRoberts
    Hoookay, so. I'm trying to get the longestS method to take the user-inputted array of strings, then return the element number of the longest string in that array. I got it to the point where I was able to return the number of chars in the longest string, but I don't believe that will work for what I need. My problem is that I keep getting incompatible type errors when trying to figure this out. I don't understand the whole data type thing with strings yet. It's confusing me how I go about return a number of the array yet the array is of strings. The main method is fine, I got stuck on the ???? part. { public static void main(String [] args) { Scanner inp = new Scanner( System.in ); String [] responseArr= new String[4]; for (int i=0; i<4; i++) { System.out.println("Enter string "+(i+1)); responseArr[i] = inp.nextLine(); } int highest=longestS(responseArr); } public static int longestS(String[] values) { int largest=0 for( int i = 1; i < values.length; i++ ) { if ( ????? ) } return largest; } }

    Read the article

  • Find the number of congruent triangles?

    - by avd
    Say I have a square from (0,0) to (z,z). Given a triangle within this square which has integer coordinates for all its vertices. Find out the number of triangles within this square which are congruent to this triangle and have integer coordinates. My algorithm is as follows-- 1) Find out the minimum bounding rectangle(MBR) for the given triangle. 2) Find out the number of congruent triangles, y within that MBR, obtained after reflection, rotation of the given triangle. y can be either 2,4 or 8. 3) Now find out how many such MBR's can be drawn within the given big square, say x; (This is similar to finding number of squares on a chess board) 4) x*y is the required answer. Am I counting some triangles more than once or I am missing something by this algorithm? It is a problem on online judge? It gives me wrong answer. I have thought a lot about it, but I am not able to figure it out.

    Read the article

  • Find out number of fraction digits in currency in iOS

    - by thejaz
    I use NSNumberFormatter to format currencies in a localized way, and it works fine. But I want to override this and give the user the option to override the number of digits after the decimal separator. How can I find out the number of digits the NSNumberFormatter will use for a certain currency? I have looked in the NSLocale object, but none of the keys tell me this. NSString * const NSLocaleIdentifier; NSString * const NSLocaleLanguageCode; NSString * const NSLocaleCountryCode; NSString * const NSLocaleScriptCode; NSString * const NSLocaleVariantCode; NSString * const NSLocaleExemplarCharacterSet; NSString * const NSLocaleCalendar; NSString * const NSLocaleCollationIdentifier; NSString * const NSLocaleUsesMetricSystem; NSString * const NSLocaleMeasurementSystem; NSString * const NSLocaleDecimalSeparator; NSString * const NSLocaleGroupingSeparator; NSString * const NSLocaleCurrencySymbol; NSString * const NSLocaleCurrencyCode; NSString * const NSLocaleCollatorIdentifier; NSString * const NSLocaleQuotationBeginDelimiterKey; NSString * const NSLocaleQuotationEndDelimiterKey; NSString * const NSLocaleAlternateQuotationBeginDelimiterKey; NSString * const NSLocaleAlternateQuotationEndDelimiterKey; How can I find out the correct number of decimals for a currency like the NSNumberFormatter seems to know?

    Read the article

  • Making a row of divs all be the same height using CSS

    - by pavel
    I have a row of divs that must all be the same height, but I have no way of knowing what that height might be ahead of time (the content comes from an external source). I initially tried placing the divs in an enclosing div and floated them left. I then set their height to be "100%", but this had no perceptible effect. By setting the height on the enclosing div to a fixed-height I could then get the floated divs to expand, but only up to the fixed height of the container. When the content in one of the divs exceeded the fixed height, it spilled over; the floated divs refused to expand. I Googled this floated-divs-of-the-same-height problem and apparently there's no way to do it using CSS. So now I am trying to use a combination of relative and absolute positioning instead of floats. This is the CSS: <style type="text/css"> div.container { background: #ccc; position: relative; min-height: 10em; } div.a { background-color: #aaa; position: absolute; top: 0px; left: 0px; bottom: 0px; width: 40%; } div.b { background-color: #bbb; position: absolute; top: 0px; left: 41%; bottom: 0px; width: 40%; } </style> This is a simplified version of the HTML: <div class="container"> <div class="a">Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Integer pretium dui sit amet felis. Integer sit amet diam. Phasellus ultrices viverra velit.</div> <div class="b">Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Integer pretium dui sit amet felis. Integer sit amet diam. Phasellus ultrices viverra velit. Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Integer pretium dui sit amet felis. Integer sit amet diam. Phasellus ultrices viverra velit.</div> </div> This works, unless you change the min-height to something like 5em (demonstranting what happens when the content exceeds the minimum height), and you can see that while the text doesn't get cutoff, the divs still refuse to expand. Now I am at a lose. Is there any way to do this using CSS?

    Read the article

  • post row where radio button is checked

    - by ognjenb
    View: <form id="numbers-form" method="post" action="/Numbers/Numbers"> <table id="numbers"> <tr> <th> prvi_br </th> <th> drugi_br </th> <th> treci_br </th> </tr> <% int rb = 1; %> <% foreach (var item in Model) { %> <tr> <td> <%= Html.Encode(item.prvi_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.prvi_br) %>'/> </td> <td> <%= Html.Encode(item.drugi_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.drugi_br) %>'/> </td> <td> <%= Html.Encode(item.treci_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.treci_br) %>'/> </td> </tr> <% rb++; %> <% } %> </table> <p> <input type="submit" value="Save" /> </p> </form> Controller action: [HttpPost] public ActionResult Numbers(int[] rb) { brojevi br = new brojevi(); for (int i = 1; i <= rb.Length; i++) //in this line I have error:Object reference not set to an instance of an object. { br.prvi_br = i; br.drugi_br = i+1; br.treci_br = i+3; } numbers.AddTobrojevi(br); numbers.SaveChanges(); return View(); } I try to post data row in wich radio button is checked but failed, what is wrong??

    Read the article

  • VisualSVN How to roll back the revision number ?

    - by Ita
    The company I work in has suffered a major server failure. During this failure the SVN Repository was lost. But there is still hope ! We have an old backup of the repository which I've managed to successfully restore using VisualSVN. The problem I'm facing now is that I can't update / commit pre-failure checkedout folders. The reason for this problem is that for instance: a local folder has a revision number of 2361, while the repository itself holds a revision number of 2290, which is older. Is there a way to deal with this issue ? Can I some how change the revision numbers on either the local copy or the server copy? A few points: I'm using TortoiseSVN 1.6.6. I can checkout folders from the repo and the connection is active. I've picked one of my folders and used the Relocate option on it. This helped me see that there is something wrong with the revision number I've experimented a bit with the merge option but this lead me now where special. (I'm open for suggestions ) Thank you for your time, Ita

    Read the article

  • Is there a better way to get values out of a table row?

    - by chobo2
    Hi Say I have this <table border="1" id="tbl"> <tr> <td><input type="checkbox" name="vehicle" value="Bike" /></td> <td>row 1, cell 1</td> <td>row 1, cell 2</td> </tr> <tr> <td><input type="checkbox" name="vehicle" value="Bike" /></td> <td>row 2, cell 1</td> <td>row 2, cell 2</td> </tr> </table> Now I want to get the row that is checked, then the cell values of that checked row. So I would do this var cells = $('#tbl :checked').parents('tr').children('td'); So lets assume only one checkbox can be checked(so no jqueyr foreach loop). So now say I wanted to get the 2nd table cells value I would just go var secondCell = $(cells[1]).html(); The thing with this though it makes the code so brittle. Like what if I put another table cell after after the checkbox one? <table border="1" id="tbl"> <tr> <td><input type="checkbox" name="vehicle" value="Bike" /></td> <td> I am new </td> <td>row 1, cell 1</td> <td>row 1, cell 2</td> </tr> <tr> <td><input type="checkbox" name="vehicle" value="Bike" /></td> <td> I am new </td> <td>row 2, cell 1</td> <td>row 2, cell 2</td> </tr> </table> So now I have to go through my code and change this var secondCell = $(cells[1]).html(); to this var thirdCell = $(cells[2]).html(); since now I am actually after the 3rd cell and not the 2nd cell anymore. So is there a better way? Thanks

    Read the article

  • Extracting a number from a 1-word string

    - by Kyle
    In this program I am trying to make, I have an expression (such as "I=23mm", or "H=4V") and I am trying to extract the 23 (or the 4) out of it, so that I can turn it into an integer. The problem I keep running into is that since the expression I am trying to take the numbers out of is 1 word, I cannot use split() or anything. One example I saw but wouldnt work was - I="I=2.7A" [int(s) for s in I.split() if s.isdigit()] This wouldnt work because it only takes the numbers are are delimited by spaces. If there was a number in the word int078vert, it wouldnt extract it. Also, mine doesnt have spaces to delimit. I tried one that looked like this, re.findall("\d+.\d+", "Amps= 1.4 I") but it didnt work either, because the number that is being passed is not always 2 digits. It could be something like 5, or something like 13.6. What code do I need to write so that if I pass a string, such as I="I=2.4A" or I="A=3V" So that I can extract only the number out of this string? (and do operations on it)? There are no spaces or other constant chars that I can delimit by.

    Read the article

  • Retrieve POST data without knowing exact number of fields

    - by James
    Hi all! I'm creating an online poll from scratch which will be held in a database. I'm working on getting a system set up so someone can create a new poll. I will be having the user fill out a simple HTML form with the Questions and Answers (there may be several answers). The user will be able to add multiple questions and multiple answers for each question. As the total number of questions and answers will be decided by the user, I need to create some clever PHP to cater for this - however many there are. When dealing with a static number of questions, it's simple. But I'm having trouble thinking of a way to get all the POST data into individual PHP variables so I can process them. I was thinking of using a foreach loop, anyone got any ideas? Sorry for the long winded description! If anyone needs anything clarified, I'd be happy to do so. My problem is that I can't get my head around how to deal with the POST values when I don't know exactly which element of the array will contain what. If things were static with a set number of questions and answers, I'd know $_POST[0] was Question1, etc Thank you! =)

    Read the article

  • Linq Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

    Read the article

  • Getting the first row of the mysql resource string?

    - by mrNepal
    Here is my problem. I need more than one row from the database, and i need the first row for certain task and then go through all the list again to create a record set. $query = "SELECT * FROM mytable"; $result = mysql_query($query); $firstrow = //extract first row from database //add display some field from it while($row = mysql_fetch_assoc($result)) { //display all of them } Now, how to extract just the first row?

    Read the article

  • Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

    Read the article

  • Finding an odd perfect number

    - by Coin Bird
    I wrote these two methods to determine if a number is perfect. My prof wants me to combine them to find out if there is an odd perfect number. I know there isn't one(that is known), but I need to actually write the code to prove that. The issue is with my main method. I tested the two test methods. I tried debugging and it gets stuck on the number 5, though I can't figure out why. Here is my code: public class Lab6 { public static void main (String[]args) { int testNum = 3; while (testNum != sum_of_divisors(testNum) && testNum%2 != 0) testNum++; } public static int sum_of_divisors(int numDiv) { int count = 1; int totalDivisors = 0; while (count < numDiv) if (numDiv%count == 0) { totalDivisors = totalDivisors + count; count++; } else count++; return totalDivisors; } public static boolean is_perfect(int numPerfect) { int count = 1; int totalPerfect = 0; while (totalPerfect < numPerfect) { totalPerfect = totalPerfect + count; count++; } if (numPerfect == totalPerfect) return true; else return false; } }

    Read the article

  • how to record mic input and pipe the output to another program

    - by acrs
    Hi everyone Im trying to follow a tutorial on generating truly random bits How To Generate Truly Random Bits This is the command from the tutorial but it does not work rec -c 1 -d /dev/dsp -r 8000 -t wav -s w - | ./noise-filter >bits I know i can record my mic input using rec -c 1 no.wav this is the command i tried using rec -c 1 -r 8000 -t wav -s noise.wav | ./noise-filter >bits but i get root@xxc:~/cc# rec -c 1 -r 8000 -t wav -s noise.wav - | ./noise-filter >bits rec WARN formats: can't set sample rate 8000; using 48000 rec FAIL sox: Input files must have the same sample-rate I have complied noise-filter noise-filter I think the tutorial is using an older version of SOX and REC I'm using sox: SoX v14.3.2 on Ubuntu 12.04 server Can someone please help me ?

    Read the article

  • Identifying the version of ATI Catalyst drivers

    - by Snark
    I have bought a new video card based on the ATI Radeon HD 5670 chipset. I couldn't make it work with the latest ATI Catalyst drivers found on their website, only the drivers found on the CD delivered with the card worked. How can I know the version of Catalyst that is installed on my PC (running Windows 7 64-bits)? The ATI Catalyst Control Center returns the following information: Driver Packaging Version 8.673-091110a-092263C Provider ATI Technologies Inc. 2D Driver Version 8.01.01.973 2D Driver File Path /REGISTRY/MACHINE/SYSTEM/ControlSet001/Control/CLASS/{4D36E968-E325-11CE-BFC1-08002BE10318}/0000 Direct3D Version 8.14.10.0708 OpenGL Version 6.14.10.9120 Catalyst™ Control Center Version 2009.1110.2225.40230 I do not recognize anything pointing to a "marketing version". The website says the current version of Catalyst is 10.2.

    Read the article

  • Why is my /dev/random so slow when using dd?

    - by Mikey
    I am trying to semi-securely erase a bunch of hard drives. The following is working at 20-50Mb/s dd if=/dev/zero of=/dev/sda But dd if=/dev/random of=/dev/sda seems not to work. Also when I type dd if=/dev/random of=stdout It only gives me a few bytes regardless of what I pass it for bs= and count= Am I using /dev/random wrong? What other info should I look for to move this troubleshooting forward? Is there some other way to do this with a script or something like makeMyLifeEasy | dd if=stdin of=/dev/sda Or something like that...

    Read the article

  • Excel - Dynamic reference based on the row I paste into?

    - by michaelmichael
    I have a simple, oft-used formula that I paste into spreadsheets I receive. It looks like this: =IF(AND(D8="COMPLETE",E8=""),A8,"") It looks in D8 for the word "COMPLETE" and checks that E8 is blank. If both conditions are fulfilled it grabs the contents of A8. It works fine. The only problem with this is that I don't always paste it into row 8. Every spreadsheet is different. I usually end up spending a few seconds making the formula fit the current spreadsheet I'm working on by dragging the cell references to the appropriate row. Hence, my question: Is there a way to make an absolute row reference based on whatever row I paste into? For example, if I paste the above formula into a cell in row 25, the formula would automatically look like this: =IF(AND(D25="COMPLETE", E25=""), A25, "")

    Read the article

  • How to change row color based on a single cell's value?

    - by flyfisher
    I have a spreadsheet where I have cell within a row that will contain specific text via data validation. So for instance a cell could contain the text "Due in 7 Days", "Past Due", or "Closed". I want the row color to change depending on the text that appears in the cell. So if the text "Past Due" appears in the cell I want that entire row to turn red, if "Due In 7 Days" appears the row should turn yellow, and if "Closed" the row would turn gray. How can I do that?

    Read the article

  • "Row not found or changed" Problem

    - by winston schröder
    Hi there, I'm working on a SQL CE Database and get into the "Row nor found or changed" exception. The exception only occurs when I try to update. On the first Run after the insert it shows up a MemberChangeConflict which says, that my Column Created_at has in all three values (current, original, database) the same. But in a second attempt it doesn't appear anymore. The DataContext is instanciated on Startup and freed on Exit of my Local(!) Application. I use a sqlmetal generated mapping and code file. In the map I added some Associations and set the timemstamp columns UpdateCheck property to Always while all other have the setting never. The Timestamp Column is marked as isVersion="true", the Id Column as Primary Key. Since I don't dispose the datacontext I expected to be using implicit transaction. When I run the SubmitChanges Method within a TransactionScope. Can anyone tell me how I can update the timestamp within the code ? I know about the Problems one has to deal with if you dispose the datacontext. So I decided not to do this since I use a Single User Local DB Cache File. (I did already use a version where I disposed the datacontext after every usage, but this version had a real bad performance and error rate, so I decided to choose the other variant.) LibDB.Client.Vehicles tmp = null; try { tmp = e.Parameter as LibDB.Client.Vehicles; if (tmp == null) return; if (!this._dc.Vehicles.Contains(tmp)) { this._dc.Vehicles.Attach(tmp); } this.ShowChangesReport(this._dc.GetChangeSet()); using (TransactionScope ts = new TransactionScope()) { try { this._dc.SubmitChanges(); ts.Complete(); } catch (ChangeConflictException cce) { Console.WriteLine("Optimistic concurrency error."); Console.WriteLine(cce.Message); Console.ReadLine(); foreach (ObjectChangeConflict occ in this._dc.ChangeConflicts) { MetaTable metatable = this._dc.Mapping.GetTable(occ.Object.GetType()); LibDB.Client.Vehicles entityInConflict = (LibDB.Client.Vehicles)occ.Object; Console.WriteLine("Table name: {0}", metatable.TableName); Console.Write("Vin: "); Console.WriteLine(entityInConflict.Vin); foreach (MemberChangeConflict mcc in occ.MemberConflicts) { object currVal = mcc.CurrentValue; object origVal = mcc.OriginalValue; object databaseVal = mcc.DatabaseValue; MemberInfo mi = mcc.Member; Console.WriteLine("Member: {0}", mi.Name); Console.WriteLine("current value: {0}", currVal); Console.WriteLine("original value: {0}", origVal); Console.WriteLine("database value: {0}", databaseVal); } throw cce; } } catch (Exception ex) { this.ShowChangeConflicts(this._dc.ChangeConflicts); Console.WriteLine(ex.Message); } } this.ShowChangesReport(this._dc.GetChangeSet());

    Read the article

  • How to add next and previous buttons to my pager row

    - by eddy
    Hi folks!! How would I add next/previous buttons to this snippet, cause as you can see ,it will display as many links as it needs, so if you have a high number of pages then this might not be the best solution <c:choose> <c:when test="${pages >1}"> <div class="pagination art-hiddenfield" > <c:forEach var="i" begin="1"end="${pages}" step="1"> <c:url value="MaintenanceListVehicles.htm" var="url"> <c:param name="current" value="${i}"/> </c:url> <c:if test="${i==current}"> <a href="<c:out value="${url}"/> " class="current" > <c:out value="${i}" /></a> </c:if> <c:if test="${i!=current}"> <a href="<c:out value="${url}"/> " > <c:out value="${i}" /></a> </c:if> </c:forEach> </div> </c:when> <c:otherwise> <div align="center"> </div> </c:otherwise> </c:choose> CSS: .pagination .current { background: #26B; border: 1px solid #226EAD; color: white; } .pagination a { display: block; border: 1px solid #226EAD; color: #15B; text-decoration: none; float: left; margin-bottom: 5px; margin-right: 5px; padding: 0.3em 0.5em; } .pagination { font-size: 80%; float: right; } div { display: block; } This is what I get with my current code: And this is what I'd like to display, with ellipsis if possible Hope you can help me out.

    Read the article

  • Get Two row with multiple column in asp.net c#

    - by Gaurav Naik
    How to get data from database with two rows and multiple column with seperator will be there after the 1 row end as an example: <div class="_thum_bar"> <div class="box1"> <div class="_t1_box"><a href="#!/condom_details"><img src="images/pack/pack1.png" border="0"></a></div> <div class="_t2_box"> <h1>Dotted Condom</h1> <p>Dotted condoms for additional friction. Pure ecstasy makes this a KamaSutra all time favourite.</p> <h2><a href="#!/condom_details">Add to cart</a></h2> </div> </div> <div class="box2"> <div class="_t1_box"><a href="#!/condom_details"><img src="images/pack/pack1.png" border="0"></a></div> <div class="_t2_box"> <h1>Dotted Condom</h1> <p>Dotted condoms for additional friction. Pure ecstasy makes this a KamaSutra all time favourite.</p> <h2><a href="#!/condom_details">Add to cart</a></h2> </div> </div> <div class="box3"> <div class="_t1_box"><a href="#"><img src="images/pack/pack1.png" border="0"></a></div> <div class="_t2_box"> <h1>Dotted Condom</h1> <p>Dotted condoms for additional friction. Pure ecstasy makes this a KamaSutra all time favourite.</p> <h2><a href="#!/condom_details">Add to cart</a></h2> </div> </div> </div> <div class="_t_spacer">&nbsp;</div> <div class="_thum_bar"> <div class="box1"> <div class="_t1_box"><a href="#!/condom_details"><img src="images/pack/pack1.png" border="0"></a></div> <div class="_t2_box"> <h1>Dotted Condom</h1> <p>Dotted condoms for additional friction. Pure ecstasy makes this a KamaSutra all time favourite.</p> <h2><a href="#!/condom_details">Add to cart</a></h2> </div> </div> <div class="box2"> <div class="_t1_box"><a href="#!/condom_details"><img src="images/pack/pack1.png" border="0"></a></div> <div class="_t2_box"> <h1>Dotted Condom</h1> <p>Dotted condoms for additional friction. Pure ecstasy makes this a KamaSutra all time favourite.</p> <h2><a href="#!/condom_details">Add to cart</a></h2> </div> </div> </div> <div class="_t_spacer">&nbsp;</div>

    Read the article

  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

    Read the article

< Previous Page | 60 61 62 63 64 65 66 67 68 69 70 71  | Next Page >