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  • dropbox slow on ubuntu 14.04

    - by Donbeo
    My dropbox syncing is incredibly slow... I am using dropbox from the ubuntu repository on an almost fresh ubuntu installation. I would like to avoid to install the package from the dropbox website for the reasons explained here Dropbox Upgrade Is someone having the same problem? How can I solve? EDIT : This is an example of what I get. donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 22 secs left) Uploading 17 files (123.3 KB/sec, 22 secs left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 3 mins left) Uploading 17 files (13.2 KB/sec, 3 mins left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining, 5 mins left) Uploading 17 files (8.2 KB/sec, 5 mins left) donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining) Uploading 17 files... donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ dropbox status Syncing (17 files remaining) Uploading 17 files... donbeo@donbeo-HP-EliteBook-Folio-9470m:~$ EDIT: I have run sudo dropbox update so I am probably using the last version of dropbox

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  • Parallelism in .NET – Part 11, Divide and Conquer via Parallel.Invoke

    - by Reed
    Many algorithms are easily written to work via recursion.  For example, most data-oriented tasks where a tree of data must be processed are much more easily handled by starting at the root, and recursively “walking” the tree.  Some algorithms work this way on flat data structures, such as arrays, as well.  This is a form of divide and conquer: an algorithm design which is based around breaking up a set of work recursively, “dividing” the total work in each recursive step, and “conquering” the work when the remaining work is small enough to be solved easily. Recursive algorithms, especially ones based on a form of divide and conquer, are often a very good candidate for parallelization. This is apparent from a common sense standpoint.  Since we’re dividing up the total work in the algorithm, we have an obvious, built-in partitioning scheme.  Once partitioned, the data can be worked upon independently, so there is good, clean isolation of data. Implementing this type of algorithm is fairly simple.  The Parallel class in .NET 4 includes a method suited for this type of operation: Parallel.Invoke.  This method works by taking any number of delegates defined as an Action, and operating them all in parallel.  The method returns when every delegate has completed: Parallel.Invoke( () => { Console.WriteLine("Action 1 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); }, () => { Console.WriteLine("Action 2 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); }, () => { Console.WriteLine("Action 3 executing in thread {0}", Thread.CurrentThread.ManagedThreadId); } ); .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Running this simple example demonstrates the ease of using this method.  For example, on my system, I get three separate thread IDs when running the above code.  By allowing any number of delegates to be executed directly, concurrently, the Parallel.Invoke method provides us an easy way to parallelize any algorithm based on divide and conquer.  We can divide our work in each step, and execute each task in parallel, recursively. For example, suppose we wanted to implement our own quicksort routine.  The quicksort algorithm can be designed based on divide and conquer.  In each iteration, we pick a pivot point, and use that to partition the total array.  We swap the elements around the pivot, then recursively sort the lists on each side of the pivot.  For example, let’s look at this simple, sequential implementation of quicksort: public static void QuickSort<T>(T[] array) where T : IComparable<T> { QuickSortInternal(array, 0, array.Length - 1); } private static void QuickSortInternal<T>(T[] array, int left, int right) where T : IComparable<T> { if (left >= right) { return; } SwapElements(array, left, (left + right) / 2); int last = left; for (int current = left + 1; current <= right; ++current) { if (array[current].CompareTo(array[left]) < 0) { ++last; SwapElements(array, last, current); } } SwapElements(array, left, last); QuickSortInternal(array, left, last - 1); QuickSortInternal(array, last + 1, right); } static void SwapElements<T>(T[] array, int i, int j) { T temp = array[i]; array[i] = array[j]; array[j] = temp; } Here, we implement the quicksort algorithm in a very common, divide and conquer approach.  Running this against the built-in Array.Sort routine shows that we get the exact same answers (although the framework’s sort routine is slightly faster).  On my system, for example, I can use framework’s sort to sort ten million random doubles in about 7.3s, and this implementation takes about 9.3s on average. Looking at this routine, though, there is a clear opportunity to parallelize.  At the end of QuickSortInternal, we recursively call into QuickSortInternal with each partition of the array after the pivot is chosen.  This can be rewritten to use Parallel.Invoke by simply changing it to: // Code above is unchanged... SwapElements(array, left, last); Parallel.Invoke( () => QuickSortInternal(array, left, last - 1), () => QuickSortInternal(array, last + 1, right) ); } This routine will now run in parallel.  When executing, we now see the CPU usage across all cores spike while it executes.  However, there is a significant problem here – by parallelizing this routine, we took it from an execution time of 9.3s to an execution time of approximately 14 seconds!  We’re using more resources as seen in the CPU usage, but the overall result is a dramatic slowdown in overall processing time. This occurs because parallelization adds overhead.  Each time we split this array, we spawn two new tasks to parallelize this algorithm!  This is far, far too many tasks for our cores to operate upon at a single time.  In effect, we’re “over-parallelizing” this routine.  This is a common problem when working with divide and conquer algorithms, and leads to an important observation: When parallelizing a recursive routine, take special care not to add more tasks than necessary to fully utilize your system. This can be done with a few different approaches, in this case.  Typically, the way to handle this is to stop parallelizing the routine at a certain point, and revert back to the serial approach.  Since the first few recursions will all still be parallelized, our “deeper” recursive tasks will be running in parallel, and can take full advantage of the machine.  This also dramatically reduces the overhead added by parallelizing, since we’re only adding overhead for the first few recursive calls.  There are two basic approaches we can take here.  The first approach would be to look at the total work size, and if it’s smaller than a specific threshold, revert to our serial implementation.  In this case, we could just check right-left, and if it’s under a threshold, call the methods directly instead of using Parallel.Invoke. The second approach is to track how “deep” in the “tree” we are currently at, and if we are below some number of levels, stop parallelizing.  This approach is a more general-purpose approach, since it works on routines which parse trees as well as routines working off of a single array, but may not work as well if a poor partitioning strategy is chosen or the tree is not balanced evenly. This can be written very easily.  If we pass a maxDepth parameter into our internal routine, we can restrict the amount of times we parallelize by changing the recursive call to: // Code above is unchanged... SwapElements(array, left, last); if (maxDepth < 1) { QuickSortInternal(array, left, last - 1, maxDepth); QuickSortInternal(array, last + 1, right, maxDepth); } else { --maxDepth; Parallel.Invoke( () => QuickSortInternal(array, left, last - 1, maxDepth), () => QuickSortInternal(array, last + 1, right, maxDepth)); } We no longer allow this to parallelize indefinitely – only to a specific depth, at which time we revert to a serial implementation.  By starting the routine with a maxDepth equal to Environment.ProcessorCount, we can restrict the total amount of parallel operations significantly, but still provide adequate work for each processing core. With this final change, my timings are much better.  On average, I get the following timings: Framework via Array.Sort: 7.3 seconds Serial Quicksort Implementation: 9.3 seconds Naive Parallel Implementation: 14 seconds Parallel Implementation Restricting Depth: 4.7 seconds Finally, we are now faster than the framework’s Array.Sort implementation.

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  • Menu widget - no jQuery nor Javascript required - pure CSS

    - by Renso
    Goal: Create a menu widget that does not require any javascript, extremely lightweight, very fast, soley based on CSS, compatible with FireFox and Chrome. Issues: May have some rendering issues in some versions of IE, sorry :-) Instruments: css file html with specific menu format jQuery-ui library - optional if you want to use your own images/colors Implementation Details: HTML: <div id="header">   <div id="header_Menubar">     <ul class="linkList0 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">         <li class="first more ui-state-default ui-corner-top ui-tabs-selected"><a title="Home" href="/Home">Home</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Go Home"></abbr><a title="Home" href="/Home">Home</a></li>             </ul>         </li>         <li class="more ui-state-default ui-corner-top ui-tabs-selected"><a title="Menu 2" href="/Menu2a">Menu 2</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Menu 2 a"></abbr><a title="Menu 2 a" href="/Menu2a">Menu 2 a</a></li>                 <li class="ilast ui-state-default ui-corner-top"><abbr title="Menu 2 b"></abbr><a title="Menu 2 b" href="/Menu2b">Menu 2 b</a></li>             </ul>         </li>         <li class="more red ui-state-default ui-corner-top ui-tabs-selected"><a title="Menu 3" href="/Menu3 d">Menu 3</a>             <ul class="linkList01 ui-tabs-nav ui-helper-reset ui-helper-clearfix ui-widget-header ui-corner-all">                 <li class="ifirst ui-state-default ui-corner-top"><abbr title="Menu 3 a"><a title="Menu 3 a" href="/Menu3a">Menu 3 a</a></abbr></li>                 <li class="ui-state-default ui-corner-top"><abbr title="Menu 3 b"><a title="Menu 3 b" href="/Menu3b">Menu 3 b</a></abbr></li>                 <li class="ui-state-default ui-corner-top"><abbr title="Menu 3 c"><a title="Menu 3 c" href="/Menu3c">Menu 3 c</a></abbr></li>                 <li class="ilast ui-state-default ui-corner-top"><abbr title="Menu 3 d"><a title="Menu 3 d" href="/Menu3d">Menu 3 d</a></abbr></li>             </ul>         </li>     </ul>     </div> </div> CSS: /*    =Menu     -----------------------------------------------------------------------------------------    */ #header #header_Menubar {     margin: 0;     padding: 0;     border: 0;     width: 100%;     height: 22px; } #header {     background-color: #99cccc;     background-color: #aaccee;     background-color: #5BA3E0;     background-color: #006cb1; } /* Set menu bar background color     */ #header #header_Menubar {     background-attachment: scroll;     background-position: left center;     background-repeat: repeat-x; } /*    Set main (horizontal) menu typology    */ #header .linkList0 {     padding: 0 0 1em 0;     margin-bottom: 1em;     font-family: 'Trebuchet MS', 'Lucida Grande',           Verdana, Lucida, Geneva, Helvetica,           Arial, sans-serif;     font-weight: bold;     font-size: 1.085em;     font-size: 1em; } /*    Set all ul properties    */ #header .linkList0, #header .linkList0 ul {     list-style: none;     margin: 0;     padding: 0;     list-style-position: outside; } /*    Set all li properties    */ #header .linkList0 > li {     float: left;     position: relative;     font-size: 90%;     margin: 0 0 -1px;     width: 9.7em;     padding-right: 2em;     z-index: 100;    /*IE7:    Fix for IE7 hiding drop down list behind some other page elements    */ } /*    Set all li properties    */ #header .linkList01 > li {     width: 190px; } #header .linkList0 .linkList01 li {     margin-left: 0px; } /*    Set all list background image properties    */ /*#header .linkList0 li a {     background-position: left center;     background-image: url(  '../Content/Images/VerticalButtonBarGradientFade.png' );     background-repeat: repeat-x;     background-attachment: scroll; }*/ /*    Set all A ancor properties    */ #header .linkList0 li a {     display: block;     text-decoration: none;     line-height: 22px; } /*    IE7: Fix for a bug in IE7 where the margins between list items is doubled - need to set height explicitly    */ *+html #header .linkList0 ul li {     height: auto;     margin-bottom: -.3em; } /*    Menu:    Set different borders for different nested level lists     --------------------------------------------------------------    */ #header .linkList0 > li a {     border-left: 10px solid Transparent;     border-right: none; } #header .linkList0 > li a {     border-left: 0px;     margin-left: 0px;     border-right: none; } #header .linkList0 .linkList01 > li a {     border-left: 8px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; } #header .linkList0 .linkList01 .linkList001 > li a {     border-left: 6px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; } #header .linkList0 .linkList01 .linkList001 .linkList0001 > li a {     border-left: 4px solid #336699;     border-right: none;     border: 1px solid Transparent;     -moz-border-radius: 5px 5px 5px 5px;     -moz-box-shadow: 3px 3px 4px #696969; }     /*    Link and Visited pseudo-class settings for all lists (ul)    */ #header .linkList0 a:link, #header .linkList0 a:visited {     display: block;     text-decoration: none;     padding-left: 1em; } /*    Hide all the nested/sub menu items    */ #header .linkList0 ul {     display: none;     padding: 0;     position: absolute;    /*Important: must not impede on other page elements when drop down opens up    */ } /*    Hide all detail popups    */ #header .detailPopup {     display: none; } /*    Set the typology of all sub-menu list items li    */ /*#header .linkList0 ul li {     background-color: #AACCEE;     background-position: left center;     background-image: url(  '../Content/Images/VerticalButtonBarGradientFade.png' );     background-repeat: repeat-x;     background-attachment: scroll; }*/ #header .linkList0 ul li.more {     background: Transparent url('../Content/Images/ArrowRight.gif') no-repeat right center; } /*    Header list's margin and padding for all list items    */ #header .linkList0 ul li {     margin: 0 0 0 1em;     padding: 0; } #header .linkList01 ul li {     margin: 0;     padding: 0;     width: 189px; } /*    Set margins for the third li sibling (Plan a Call) to display to the right of the parent menu     to avoid the sub-menu overlaying the menu items below    */ #header .linkList0 li.more .linkList01 li.more > ul.linkList001 {     margin: -1.7em 0 0 13.2em;    /*Important, must be careful, if tbe EM since gap increases too much bewteen nested lists the gap will make the nested-list collapse prematurely    */ } /*    Set right hand arrow for list items with sub-menus (class-more)    */ #header li.more {     background: Transparent url('../Content/Images/ArrowRight.gif') no-repeat right center;     padding-right: 48px; } /*    Menu:    Dynamic Behavior of menu items (hover, visted, etc)     -----------------------------------------------------------    */ #header .linkList0 li a:link, #header .linkList01 li a:link {     display: block; } #header .linkList0 li a:visited, #header .linkList01 li a:visited {     display: block; } #header .linkList0 > li:hover { } #header .linkList01 > li:hover a ,#header .linkList001 > li:hover a {     text-decoration: underline; } #header .linkList0 > li abbr:hover span.detailPopup {     display: block;     position: absolute;     top: 1em;     left: 17em;     border: double 1px #696969;     border-style: outset;     width: 120%;     height: auto;     padding: 5px;     font-weight: 100; } #header .linkList0 > li:hover ,#header .linkList0 .linkList01 > li:hover { } #header .linkList0 .linkList01 .linkList001 > li:hover { } #header .linkList0 .linkList01 .linkList001 .linkList0001 > li:hover { } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 li:hover > ul {     display: block; } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 .linkList01 li:hover > ul {     display: block;         background: -moz-linear-gradient(top, #1E83CC, #619FCD);     /* Chrome, Safari:*/     background: -webkit-gradient(linear,                 center top, center bottom, from(#1E83CC), to(#619FCD)); } /*    Display the hidden sub menu when hovering over the parent ul's li    */ #header .linkList0 .linkList01 .linkList001 li:hover > ul {     display: block; } /*    Set right hand arrow for list items with sub-menus (class-more) on hover    */ #header li.more:hover { } Also some CSS for global settings that will affect this menu, you of course will have some other styling, but included it here so you can see how/why some css properties were set here: /* Neutralize styling:    Elements we want to clean out entirely: */ html, body {     margin: 0;     padding: 0;     font: 62.5%/120% Verdana, Arial, Helvetica, sans-serif; } /* Neutralize styling:    Elements with a vertical margin: */ h1, h2, h3, h4, h5, h6, p, pre, blockquote, ul, ol, dl, address {     margin: 0;    /*    most browsers set some default value that is not shared by all browsers    */     padding: 0;        /*    some borowsers default padding, set to 0 for all    */ } /* Apply left margin:    Only to the few elements that need it: */ li, dd, blockquote {     margin-left: 1em; }

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  • Android Can't get two virtual joysticks to move independently and at the same time

    - by Cole
    @Override public boolean onTouch(View v, MotionEvent event) { // TODO Auto-generated method stub float r = 70; float centerLx = (float) (screenWidth*.3425); float centerLy = (float) (screenHeight*.4958); float centerRx = (float) (screenWidth*.6538); float centerRy = (float) (screenHeight*.4917); float dx = 0; float dy = 0; float theta; float c; int action = event.getAction(); int actionCode = action & MotionEvent.ACTION_MASK; int pid = (action & MotionEvent.ACTION_POINTER_INDEX_MASK) >> MotionEvent.ACTION_POINTER_INDEX_SHIFT; int fingerid = event.getPointerId(pid); int x = (int) event.getX(pid); int y = (int) event.getY(pid); c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); switch (actionCode) { case MotionEvent.ACTION_DOWN: case MotionEvent.ACTION_POINTER_DOWN: //if touching down on left stick, set leftstick ID to this fingerid. if(x < screenWidth/2 && c<r*.8) { lsId = fingerid; dx = x-centerLx; dy = y-centerLy; touchingLs = true; } else if(x > screenWidth/2 && c<r*.8) { rsId = fingerid; dx = x-centerRx; dy = y-centerRy; touchingRs = true; } break; case MotionEvent.ACTION_MOVE: if (touchingLs && fingerid == lsId) { dx = x - centerLx; dy = y - centerLy; }else if (touchingRs && fingerid == rsId) { dx = x - centerRx; dy = y - centerRy; } c = FloatMath.sqrt(dx*dx + dy*dy); theta = (float) Math.atan(Math.abs(dy/dx)); //if touching outside left radius and moving left stick if(c >= r && touchingLs && fingerid == lsId) { if(dx>0 && dy<0) { //top right quadrant lsX = r * FloatMath.cos(theta); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant lsX = -(r * FloatMath.cos(theta)); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0){ //bottom right quadrant lsX = r * FloatMath.cos(theta); lsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } if(c >= r && touchingRs && fingerid == rsId) { if(dx>0 && dy<0) { //top right quadrant rsX = r * FloatMath.cos(theta); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top right"); } if(dx<0 && dy<0) { //top left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = -(r * FloatMath.sin(theta)); Log.i("message", "top left"); } if(dx<0 && dy>0) { //bottom left quadrant rsX = -(r * FloatMath.cos(theta)); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom left"); } else if(dx > 0 && dy > 0) { rsX = r * FloatMath.cos(theta); rsY = r * FloatMath.sin(theta); Log.i("message", "bottom right"); } } else { if(c < r && touchingLs && fingerid == lsId) { lsX = dx; lsY = dy; } if(c < r && touchingRs && fingerid == rsId){ rsX = dx; rsY = dy; } } break; case MotionEvent.ACTION_UP: case MotionEvent.ACTION_POINTER_UP: if (fingerid == lsId) { lsId = -1; lsX = 0; lsY = 0; touchingLs = false; } else if (fingerid == rsId) { rsId = -1; rsX = 0; rsY = 0; touchingRs = false; } break; } return true; } There's a left joystick and a right joystick. Right now only one will move at a time. If someone could set me on the right track I would be incredibly grateful cause I've been having nightmares about this problem.

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  • ALSA samples capture: cannot open device

    - by Randagio
    I'm quite new to Linux (Lubuntu 12.04 for sake of precision) and ALSA programming at all. I'm trying to write a C program to capture audio from internal PC microphone for processing it. So as first step I google a bit and I found this article for capturing audio samples A tutorial on using the ALSA Audio API but when I compile it and execute it with: ./capture "default" or ./capture "hw:0,0" and all the possible variants on theme it always raises the error: cannot open device hw:0,0 (no such file or directory). So the issue is: what is the name of the mic audio device to pass as parameter to record the audio from mic ? The mic is working ok because the Sound Recorder program records sounds perfectly and I can playback them. The output of the aplay -l is the following : **** List of PLAYBACK Hardware Devices **** card 0: I82801DBICH4 [Intel 82801DB-ICH4], device 0: Intel ICH [Intel 82801DB-ICH4] Subdevices: 1/1 Subdevice #0: subdevice #0 card 0: I82801DBICH4 [Intel 82801DB-ICH4], device 4: Intel ICH - IEC958 [Intel 82801DB-ICH4 - IEC958] Subdevices: 1/1 Subdevice #0: subdevice #0 and this is the amixer output (cut) Simple mixer control 'Master',0 Capabilities: pvolume pswitch penum Playback channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Front Left: Playback 31 [100%] [0.00dB] [on] Front Right: Playback 31 [100%] [0.00dB] [on] Simple mixer control 'Master Mono',0 Capabilities: pvolume pvolume-joined pswitch pswitch-joined penum Playback channels: Mono Limits: Playback 0 - 31 Mono: Playback 4 [13%] [-40.50dB] [on] Simple mixer control 'PCM',0 Capabilities: pvolume pswitch penum Playback channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Front Left: Playback 31 [100%] [12.00dB] [on] Front Right: Playback 31 [100%] [12.00dB] [on] Simple mixer control 'CD',0 Capabilities: pvolume pswitch cswitch cswitch-exclusive penum Capture exclusive group: 0 Playback channels: Front Left - Front Right Capture channels: Front Left - Front Right Limits: Playback 0 - 31 Front Left: Playback 0 [0%] [-34.50dB] [off] Capture [off] Front Right: Playback 0 [0%] [-34.50dB] [off] Capture [off] Simple mixer control 'Mic',0 Capabilities: pvolume pvolume-joined pswitch pswitch-joined cswitch cswitch-exclusive penum Capture exclusive group: 0 Playback channels: Mono Capture channels: Front Left - Front Right Limits: Playback 0 - 31 Mono: Playback 22 [71%] [-1.50dB] [on] Front Left: Capture [on] Front Right: Capture [on] Simple mixer control 'Mic Boost (+20dB)',0 Capabilities: pswitch pswitch-joined penum Playback channels: Mono Mono: Playback [off] Simple mixer control 'Mic Select',0 Capabilities: enum Items: 'Mic1' 'Mic2' Item0: 'Mic1' Simple mixer control 'Stereo Mic',0 Capabilities: pswitch pswitch-joined penum Playback channels: Mono Mono: Playback [off] so for aplay it seems I have no recording device, but for amixer I've got the mic, a mic boost and mic stereo as well with all those gorgeous stuffs on their place !!. If so, how could my Sound Recorder record the audio without any problem at all ?!?! For sure I'm giving the wrong device name to the command line for capturing audio but I'm loosing the hope for finding the correct one ! Please help....before I tear my hair out !!!

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  • A star algorithm implementation problems

    - by bryan226
    I’m having some trouble implementing the A* algorithm in a 2D tile based game. The problem is basically that the algorithm gets stuck when something gets in its direct way (e.g. walls) Note that it only allows Horizontal and Vertical movement. Here's a picture as it works fine across the map without something in its direct way: (Green tile = destination, Blue = In closed list, Green = in open list) This is what happens if I try to walk 'around' a wall: I calculate costs with the F = G + H formula: G = 1 Cost per Step H = 10 Cost per Step //Count how many tiles are between current-tile & destination-tile The functions: short c_astar::GuessH(short Startx,short Starty,short Destinationx,short Destinationy) { hgeVector Start, Destination; Start.x = Startx; Start.y = Starty; Destination.x = Destinationx; Destination.y = Destinationy; short a = 0; short b = 0; if(Start.x > Destination.x) a = Start.x - Destination.x; else a = Destination.x - Start.x; if(Start.y > Destination.y) b = Start.y - Destination.y; else b = Destination.y - Start.y; return (a+b)*10; } short c_astar::GuessG(short Startx,short Starty,short Currentx,short Currenty) { hgeVector Start, Destination; Start.x = Startx; Start.y = Starty; Destination.x = Currentx; Destination.y = Currenty; short a = 0; short b = 0; if(Start.x > Destination.x) a = Start.x - Destination.x; else a = Destination.x - Start.x; if(Start.y > Destination.y) b = Start.y - Destination.y; else b = Destination.y - Start.y; return (a+b); } At the end of the loop I check which tile is the cheapest to go according to its F value: Then some quick checks are done for each tile (UP,DOWN,LEFT,RIGHT): //...CX are holding the F value of the TILE specified // Info: C0 = Center (Current) // C1 = UP // C2 = DOWN // C3 = LEFT // C4 = RIGHT //Quick checks if(((C1 < C2) && (C1 < C3) && (C1 < C4))) { Current.y -= 1; bSimilar = false; if(DEBUG) hge->System_Log("C1 < ALL"); } //.. same for C2,C3 & C4 If there are multiple tiles with the same F value: It’s actually a switch for DOWNLEFT,UPRIGHT.. etc. Here’s one of it: case UPRIGHT: { //UP Temporary = Current; Temporary.y -= 1; bTileStatus[0] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[0]) { //Proceed normal we are OK & walkable Tilex.Tile = map.at(Temporary.y).at(Temporary.x); //Search in lists if(SearchInClosedList(Tilex.Tile.ID,C0)) bFoundInClosedList[0] = true; if(SearchInOpenList(Tilex.Tile.ID,C0)) bFoundInOpenList[0] = true; //RIGHT Temporary = Current; Temporary.x += 1; bTileStatus[1] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[1]) { //Proceed normal we are OK & walkable Tilex.Tile = map.at(Temporary.y).at(Temporary.x); //Search in lists if(SearchInClosedList(Tilex.Tile.ID,C0)) bFoundInClosedList[1] = true; if(SearchInOpenList(Tilex.Tile.ID,C0)) bFoundInOpenList[1] = true; //************************************************* // Purpose: ClosedList behavior //************************************************* if(bFoundInClosedList[0] && !bFoundInClosedList[1]) { //UP found in ClosedList. Go RIGHT return RIGHT; } if(!bFoundInClosedList[0] && bFoundInClosedList[1]) { //RIGHT found in ClosedList. Go UP return UP; } if(bFoundInClosedList[0] && bFoundInClosedList[1]) { //Both found in ClosedList. Random value switch(hge->Random_Int(8,9)) { case 8: return UP; break; case 9: return RIGHT; break; } } //************************************************* // Purpose: OpenList behavior //************************************************* if(bFoundInOpenList[0] && !bFoundInOpenList[1]) { //UP found in OpenList. Go RIGHT return RIGHT; } if(!bFoundInOpenList[0] && bFoundInOpenList[1]) { //RIGHT found in OpenList. Go UP return UP; } if(bFoundInOpenList[0] && bFoundInOpenList[1]) { //Both found in OpenList. Random value switch(hge->Random_Int(8,9)) { case 8: return UP; break; case 9: return RIGHT; break; } } } else if(!bTileStatus[1]) { //RIGHT is not walkable OR out of range //Choose UP return UP; } } else if(!bTileStatus[0]) { //UP is not walkable OR out of range //Fast check RIGHT Temporary = Current; Temporary.x += 1; bTileStatus[1] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[1]) { return RIGHT; } else return FAILED; //Failed, no valid path found! } } break; A log for the second picture: (Cut down to ten passes, because it’s just repeating itself) ----------------------------------------------------- PASS: 1 | C1: 211 | C2: 191 | C3: 211 | C4: 191 DOWN + RIGHT SIMILAR Going DOWN ----------------------------------------------------- PASS: 2 | C1: 200 | C2: 182 | C3: 202 | C4: 182 DOWN + RIGHT SIMILAR Going DOWN ----------------------------------------------------- PASS: 3 | C1: 191 | C2: 193 | C3: 193 | C4: 173 C4 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 4 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going UP Tile(12.000000,5.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 5 | C1: 191 | C2: 173 | C3: 191 | C4: 999 C2 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 6 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going UP Tile(12.000000,5.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 7 | C1: 191 | C2: 173 | C3: 191 | C4: 999 C2 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 8 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going LEFT ----------------------------------------------------- PASS: 9 | C1: 191 | C2: 193 | C3: 193 | C4: 173 C4 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 10 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going LEFT ----------------------------------------------------- Its always going after the cheapest F value, which seems to be wrong. If someone could point me to the right direction I'd be thankful. Regards, bryan226

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  • Collision Error

    - by Manji
    I am having trouble with collision detection part of the game. I am using touch events to fire the gun as you will see in the video. Note, the android icon is a temporary graphic for the bullets When ever the user touches (represented by clicks in the video)the bullet appears and kills random sprites. As you can see it never touches the sprites it kills or kill the sprites it does touch. My Question is How do I fix it, so that the sprite dies when the bullet hits it? Collision Code snippet: //Handles Collision private void CheckCollisions(){ synchronized(mSurfaceHolder){ for (int i = sprites.size() - 1; i >= 0; i--){ Sprite sprite = sprites.get(i); if(sprite.isCollision(bullet)){ sprites.remove(sprite); mScore++; if(sprites.size() == 0){ mLevel = mLevel +1; currentLevel++; initLevel(); } break; } } } } Sprite Class Code Snippet: //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public boolean isCollision(Beam other) { // TODO Auto-generated method stub if(this.left>other.right || other.left<other.right)return false; if(this.bottom>other.top || other.bottom<other.top)return false; return true; } EDIT 1: Sprite Class: public class Sprite { // direction = 0 up, 1 left, 2 down, 3 right, // animation = 3 back, 1 left, 0 front, 2 right int[] DIRECTION_TO_ANIMATION_MAP = { 3, 1, 0, 2 }; private static final int BMP_ROWS = 4; private static final int BMP_COLUMNS = 3; private static final int MAX_SPEED = 5; private HitmanView gameView; private Bitmap bmp; private int x; private int y; private int xSpeed; private int ySpeed; private int currentFrame = 0; private int width; private int height; //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public Sprite(HitmanView gameView, Bitmap bmp) { this.width = bmp.getWidth() / BMP_COLUMNS; this.height = bmp.getHeight() / BMP_ROWS; this.gameView = gameView; this.bmp = bmp; Random rnd = new Random(); x = rnd.nextInt(gameView.getWidth() - width); y = rnd.nextInt(gameView.getHeight() - height); xSpeed = rnd.nextInt(MAX_SPEED * 2) - MAX_SPEED; ySpeed = rnd.nextInt(MAX_SPEED * 2) - MAX_SPEED; } private void update() { if (x >= gameView.getWidth() - width - xSpeed || x + xSpeed <= 0) { xSpeed = -xSpeed; } x = x + xSpeed; if (y >= gameView.getHeight() - height - ySpeed || y + ySpeed <= 0) { ySpeed = -ySpeed; } y = y + ySpeed; currentFrame = ++currentFrame % BMP_COLUMNS; } public void onDraw(Canvas canvas) { update(); int srcX = currentFrame * width; int srcY = getAnimationRow() * height; Rect src = new Rect(srcX, srcY, srcX + width, srcY + height); Rect dst = new Rect(x, y, x + width, y + height); canvas.drawBitmap(bmp, src, dst, null); } private int getAnimationRow() { double dirDouble = (Math.atan2(xSpeed, ySpeed) / (Math.PI / 2) + 2); int direction = (int) Math.round(dirDouble) % BMP_ROWS; return DIRECTION_TO_ANIMATION_MAP[direction]; } public boolean isCollision(float x2, float y2){ return x2 > x && x2 < x + width && y2 > y && y2 < y + height; } public boolean isCollision(Beam other) { // TODO Auto-generated method stub if(this.left>other.right || other.left<other.right)return false; if(this.bottom>other.top || other.bottom<other.top)return false; return true; } } Bullet Class: public class Bullet { int mX; int mY; private Bitmap mBitmap; //bounding box left<right and top>bottom int left ; int right ; int top ; int bottom ; public Bullet (Bitmap mBitmap){ this.mBitmap = mBitmap; } public void draw(Canvas canvas, int mX, int mY) { this.mX = mX; this.mY = mY; canvas.drawBitmap(mBitmap, mX, mY, null); } }

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  • Non persistent keyboard shortcuts in Unity

    - by nblumoe
    I did change the keyboard shortcuts for window navigation in Unity to use hjkl (vim movement). I did reassign the shortcuts via GUI in System Settings Keyboard Shortcuts. Here are two examples of the assigned shortcuts: Move window one workspace to the left = Shift+Ctrl+Alt+H Switch to workspace left = Ctrl+Alt+H Occasionally, when restarting the maching, these shortcuts are being reset to theit default values: Move window one workspace to the left = Shift+Ctrl+Alt+Left Switch to workspace left = Ctrl+Alt+Left How can I make these changes permanent? Can someone help me, narrowing down the problem?

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  • How to set sprite source coordinates?

    - by ChaosDev
    I am creating own sprite drawer with DX11 on C++. Works fine but I dont know how to apply source rectangle to texture coordinates of rendering surface(for animation sprite sheets) //source = (0,0,32,64); //RECT D3DXVECTOR2 t0 = D3DXVECTOR2( 1.0f, 0.0f); D3DXVECTOR2 t1 = D3DXVECTOR2( 1.0f, 1.0f); D3DXVECTOR2 t2 = D3DXVECTOR2( 0.0f, 1.0f); D3DXVECTOR2 t3 = D3DXVECTOR2( 0.0f, 1.0f); D3DXVECTOR2 t4 = D3DXVECTOR2( 0.0f, 0.0f); D3DXVECTOR2 t5 = D3DXVECTOR2( 1.0f, 0.0f); VertexPositionColorTexture vertices[] = { { D3DXVECTOR3( dest.left+dest.right, dest.top, z),D3DXVECTOR4(1,1,1,1), t0}, { D3DXVECTOR3( dest.left+dest.right, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t1}, { D3DXVECTOR3( dest.left, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t2}, { D3DXVECTOR3( dest.left, dest.top+dest.bottom, z),D3DXVECTOR4(1,1,1,1), t3}, { D3DXVECTOR3( dest.left , dest.top, z),D3DXVECTOR4(1,1,1,1), t4}, { D3DXVECTOR3( dest.left+dest.right, dest.top, z),D3DXVECTOR4(1,1,1,1), t5}, };

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  • This program runs but not correctly; the numbers aren't right.

    - by user320950
    this program runs but not correctly numbers arent right, i read numbers from a file and then when i am using them in the program they are not right.:brief decription of what i am trying to do can someone tell me if something doesnt look right. this is what i have to do: write a program that determines the grade dispersal for 100 students You are to read the exam scores into three arrays, one array for each exam. You must then calculate how many students scored A’s (90 or above), B’s (80 or above), C’s (70 or above), D’s (60 or above), and F’s (less than 60). Do this for each exam and write the distribution to the screen. // basic file operations #include <iostream> #include <fstream> using namespace std; int read_file_in_array(double exam[100][3]); double calculate_total(double exam1[], double exam2[], double exam3[]); // function that calcualates grades to see how many 90,80,70,60 //void display_totals(); double exam[100][3]; int main() { double go,go2,go3; double exam[100][3],exam1[100],exam2[100],exam3[100]; go=read_file_in_array(exam); go2=calculate_total(exam1,exam2,exam3); //go3=display_totals(); cout << go,go2,go3; return 0; } /* int display_totals() { int grade_total; grade_total=calculate_total(exam1,exam2,exam3); return 0; } */ double calculate_total(double exam1[],double exam2[],double exam3[]) { int calc_tot,above90=0, above80=0, above70=0, above60=0,i,j, fail=0; double exam[100][3]; calc_tot=read_file_in_array(exam); for(i=0;i<100;i++) { for (j=0; j<3; j++) { exam1[i]=exam[100][0]; exam2[i]=exam[100][1]; exam3[i]=exam[100][2]; if(exam[i][j] <=90 && exam[i][j] >=100) { above90++; { if(exam[i][j] <=80 && exam[i][j] >=89) { above80++; { if(exam[i][j] <=70 && exam[i][j] >=79) { above70++; { if(exam[i][j] <=60 && exam[i][j] >=69) { above60++; { if(exam[i][j] >=59) { fail++; } } } } } } } } } } } return 0; } int read_file_in_array(double exam[100][3]) { ifstream infile; int exam1[100]; int exam2[100]; int exam3[100]; infile.open("grades.txt");// file containing numbers in 3 columns if(infile.fail()) // checks to see if file opended { cout << "error" << endl; } int num, i=0,j=0; while(!infile.eof()) // reads file to end of line { for(i=0;i<100;i++) // array numbers less than 100 { for(j=0;j<3;j++) // while reading get 1st array or element infile >> exam[i][j]; infile >> exam[i][j]; infile >> exam[i][j]; cout << exam[i][j] << endl; { if (! (infile >> exam[i][j]) ) cout << exam[i][j] << endl; } exam[i][j]=exam1[i]; exam[i][j]=exam2[i]; exam[i][j]=exam3[i]; } infile.close(); } return 0; }

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  • Mysql - Help me change this single complex query to use temporary tables

    - by sandeepan-nath
    About the system: - There are tutors who create classes and packs - A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is the concerned query Can anybody help me suggest an approach using temporary tables. We have indexed all the relevant fields and it looks like this is the least time possible with this approach:- SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" OR tt.tag LIKE "%Dictatorship%" OR ttt.tag LIKE "%Dictatorship%" )) AS key_1_total_matches , SUM(DISTINCT( t.tag LIKE "%democracy%" OR tt.tag LIKE "%democracy%" OR ttt.tag LIKE "%democracy%" )) AS key_2_total_matches , COUNT(DISTINCT( od.id_od )) AS tutor_popularity, CASE WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'classes_published' , CASE WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'packs_published', td . *, u . * FROM tutor_details AS td JOIN users AS u ON u.id_user = td.id_user LEFT JOIN learning_packs_tag_relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN learning_packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN learning_packs_categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN learning_packs_categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN learning_pack_content AS lpct ON ( lp.id_lp = lpct.id_lp ) LEFT JOIN webclasses_tag_relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN webclasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN learning_packs_categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN learning_packs_categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN order_details AS od ON td.id_tutor = od.id_author LEFT JOIN orders AS o ON od.id_order = o.id_order LEFT JOIN tutors_tag_relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor LEFT JOIN tags AS t ON t.id_tag = ttagrels.id_tag LEFT JOIN tags AS tt ON tt.id_tag = lptagrels.id_tag LEFT JOIN tags AS ttt ON ttt.id_tag = wtagrels.id_tag WHERE ( u.country = 'IE' OR u.country IN ( 'INT' ) ) AND CASE WHEN ( ( tt.id_tag = lptagrels.id_tag ) AND ( lp.id_lp > 0 ) ) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( ( ttt.id_tag = wtagrels.id_tag ) AND ( wc.id_wc > 0 ) ) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( od.id_od > 0 ) THEN od.id_author = td.id_tutor AND o.order_status = 'paid' AND CASE WHEN ( od.id_wc > 0 ) THEN od.can_attend_class = 1 ELSE 1 END ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%" OR tt.tag LIKE "%Dictatorship%" OR tt.tag LIKE "%democracy%" OR ttt.tag LIKE "%Dictatorship%" OR ttt.tag LIKE "%democracy%" ) GROUP BY td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 ORDER BY tutor_popularity DESC, u.surname ASC, u.name ASC LIMIT 0, 20 The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query rises alarmingly for heavier data and for the current data I have it is like 10 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. Somebody suggested in my previous question to do the following:- create a temporary table and insert here all relevant data that might end up in the final result set run several updates on this table, joining the required tables one at a time instead of all of them at the same time finally perform a query on this temporary table to extract the end result All this was done in a stored procedure, the end result has passed unit tests, and is blazing fast. I have never worked with temporary tables till now. Only if I could get some hints, kind of schematic representations so that I can start with... Is there something faulty with the query? What can be the reason behind 10+ seconds of execution time? How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. The explain query output:- Please see this screenshot - http://www.test.examvillage.com/Explain_query_improved.jpg

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  • CSS: move a "float:right" element to top (to align with the first element of the list)

    - by Patrick
    hi, I've a sequence of elements and the last one has css "float:left". I would like to display it at the same height of the first element and not on the bottom of the list. (I cannot change the html code, so it is the last in the list). At the same time, I would like to keep it on the right. How can I make it wich CSS ? thanks Code: <div class="field field-type-text field-field-year"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Year:&nbsp;</div> 2009 </div> </div> </div> <div class="field field-type-text field-field-where"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Where:&nbsp;</div> Musée Rath, Geneva </div> </div> </div> <div class="field field-type-text field-field-when"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> When:&nbsp;</div> 25.8 – 27.9.2009 </div> </div> </div> <div class="field field-type-text field-field-editor"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Editor:&nbsp;</div> Blabla Blabla </div> </div> </div> <div class="field field-type-text field-field-material"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Material/techniques:&nbsp;</div> contemporary art installations </div> </div> </div> <div class="field field-type-text field-field-dimension"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Dimension:&nbsp;</div> 2 floors in a neoclassical building </div> </div> </div> <div class="field field-type-text field-field-artists"> <div class="field-items"> <div class="field-item odd"> <div class="field-label-inline-first"> Artists:&nbsp;</div> Blablablabla balbalbalbalba </div> </div> </div> .field-field-year, .field-field-where, .field-field-when, .field-field-editor, .field-field-material, .field-field-dimension { width:300px; } .field-field-artists { width:400px; float:right; clear:right; top-margin: -200px; }

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  • Right-aligning button in a grid with possibly no content - stretch grid to always fill the page

    - by Peter Perhác
    Hello people, I am losing my patience with this. I am working on a Windows Phone 7 application and I can't figure out what layout manager to use to achieve the following: Basically, when I use a Grid as the layout root, I can't make the grid to stretch to the size of the phone application page. When the main content area is full, all is well and the button sits where I want it to sit. However, in case the page content is very short, the grid is only as wide as to accommodate its content and then the button (which I am desperate to keep near the right edge of the screen) moves away from the right edge. If I replace the grid and use a vertically oriented stack panel for the layout root, the button sits where I want it but then the content area is capable of growing beyond the bottom edge. So, when I place a listbox full of items into the main content area, it doesn't adjust its height to be completely in view, but the majority of items in that listbox are just rendered below the bottom edge of the display area. I have tried using a third-party DockPanel layout manager and then docked the button in it's top section and set the button's HorizontalAlignment="Right" but the result was the same as with the grid, it also shrinks in size when there isn't enough content in the content area (or when title is short). How do I do this then? ==EDIT== I tried WPCoder's XAML, only I replaced the dummy text box with what I would have in a real page (stackpanel) and placed a listbox into the ContentPanel grid. I noticed that what I had before and what WPCoder is suggesting is very similar. Here's my current XAML and the page still doesn't grow to fit the width of the page and I get identical results to what I had before: <phone:PhoneApplicationPage x:Name="categoriesPage" x:Class="CatalogueBrowser.CategoriesPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:phone="clr-namespace:Microsoft.Phone.Controls;assembly=Microsoft.Phone" xmlns:shell="clr-namespace:Microsoft.Phone.Shell;assembly=Microsoft.Phone" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" FontFamily="{StaticResource PhoneFontFamilyNormal}" FontSize="{StaticResource PhoneFontSizeNormal}" Foreground="{StaticResource PhoneForegroundBrush}" SupportedOrientations="PortraitOrLandscape" Orientation="Portrait" mc:Ignorable="d" d:DesignWidth="480" d:DesignHeight="768" xmlns:ctrls="clr-namespace:Microsoft.Phone.Controls;assembly=Microsoft.Phone.Controls.Toolkit" shell:SystemTray.IsVisible="True"> <Grid x:Name="LayoutRoot" Background="Transparent"> <Grid.RowDefinitions> <RowDefinition Height="Auto"/> <RowDefinition Height="*"/> </Grid.RowDefinitions> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> <ColumnDefinition Width="Auto" /> </Grid.ColumnDefinitions> <StackPanel Orientation="Horizontal" VerticalAlignment="Center" > <TextBlock Text="Browsing:" Margin="10,10" Style="{StaticResource PhoneTextTitle3Style}" /> <TextBlock x:Name="ListTitle" Text="{Binding DisplayName}" Margin="0,10" Style="{StaticResource PhoneTextTitle3Style}" /> </StackPanel> <Button Grid.Column="1" x:Name="btnRefineSearch" Content="Refine Search" Style="{StaticResource buttonBarStyle}" FontSize="14" /> </Grid> <Grid x:Name="ContentPanel" Grid.Row="1"> <ListBox x:Name="CategoryList" ItemsSource="{Binding Categories}" Style="{StaticResource CatalogueList}" SelectionChanged="CategoryList_SelectionChanged"/> </Grid> </Grid> </phone:PhoneApplicationPage> This is what the page with the above XAML markup looks like in the emulator:

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  • Sorting an XML file through XSL

    - by jbugeja
    I have an XML file that I want to sort by an attribute. The file is structured as shown below: <wb xmlns:cf="http://www.macromedia.com/2004/cfform"> <a:form name="chart"> <a:input FIELDNUMBER="09" INDEX="2" LEFT="200" /> <a:input FIELDNUMBER="08" INDEX="3" LEFT="200" /> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="02" INDEX="4" LEFT="200" /> <a:select1 FIELDNUMBER="01" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="04" INDEX="7" LEFT="200" /> <a:select1 FIELDNUMBER="03" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> </a:fieldset> </a:fieldset> </a:form> </wb> I would like to sort the above XML all throughout by @fieldnumber, but at the same I want to keep the same structure of the XML. I have managed to sort other XML file but they did not have such nesting levels. Is this possible with XSL alone and if so how can this be done? The output should be as follows: <wb xmlns:cf="http://www.macromedia.com/2004/cfform"> <a:form name="chart"> <a:input FIELDNUMBER="08" INDEX="3" LEFT="200" /> <a:input FIELDNUMBER="09" INDEX="2" LEFT="200" /> <a:fieldset FIELD="a" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="01" /> <a:input FIELDNUMBER="02" INDEX="4" LEFT="200" /> </a:fieldset> <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" /> <a:input FIELDNUMBER="04" INDEX="7" LEFT="200" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> </a:fieldset> </a:fieldset> </a:form> </wb> As another example, should the FIELDNUMBER 04 be changed to a value greater than 7 such as 10 (let's assume 10 in this example) then the output of the fieldset with FIELD value b becomes: <a:fieldset FIELD="b" FIELDNAME="FieldSet1"> <a:select1 FIELDNUMBER="03" /> <a:fieldset FIELD="c" FIELDNAME="FieldSet1"> <a:input FIELDNUMBER="05" INDEX="6" LEFT="200" /> <a:input FIELDNUMBER="06" INDEX="8" LEFT="200" /> </a:fieldset> <a:input FIELDNUMBER="10" INDEX="7" LEFT="200" /> </a:fieldset>

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  • multi divs centered

    - by user1319385
    I have 2 divs with 3 divs inside them, all 2 wrapped around one big div. I try and center it and its not working. Here is my code: <div stye="margin-left:auto; margin-right:auto; width: 1210px;"> <div id="left" style=" float:left; width: 606px; height: 506px;"> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> <div id="left" style="float:left; width: 604px; height: 506px;"> <div style="top:0px; float:right; width:300px; border: 2px solid #FF0; border-left:0px; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> </div>

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  • How do I remove msysgit's right click menu options?

    - by DevelopingChris
    This isn't the best programming question but lets face it, the server fault guys aren't well versed in git, so I think its more towards this audience. Do I have to write a script to uninstall them? How do I get them to go away, I want to switch to tortoise git, or portablegit in my shell, but I'm left with these annoying menu options.

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  • How do I remove the time from printpreview dialog?

    - by Albo Best
    Here is my code: Imports System.Data.OleDb Imports System.Drawing.Printing Namespace Print Public Class Form1 Inherits System.Windows.Forms.Form Dim PrintC As PrinterClass Dim conn As OleDb.OleDbConnection Dim connectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=..\\db1.mdb" Dim sql As String = String.Empty Dim ds As DataSet Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load FillDataGrid() '//create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) End Sub Private Sub FillDataGrid() Try Dim dt As New DataTable Dim ds As New DataSet ds.Tables.Add(dt) Dim da As New OleDbDataAdapter con.Open() da = New OleDbDataAdapter("SELECT * from klient ", con) da.Fill(dt) con.Close() dataGrid.DataSource = dt.DefaultView Dim dTable As DataTable For Each dTable In ds.Tables Dim dgStyle As DataGridTableStyle = New DataGridTableStyle dgStyle.MappingName = dTable.TableName dataGrid.TableStyles.Add(dgStyle) Next ' DataGrid settings dataGrid.CaptionText = "TE GJITHE KLIENTET" dataGrid.HeaderFont = New Font("Verdana", 12) dataGrid.TableStyles(0).GridColumnStyles(0).Width = 60 dataGrid.TableStyles(0).GridColumnStyles(1).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(2).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(3).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(4).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(5).HeaderText = "" dataGrid.TableStyles(0).GridColumnStyles(5).Width = -1 Catch ex As Exception MessageBox.Show(ex.Message) End Try End Sub Private Sub btnPrint_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPrint.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) PrintDocument1.Print() End Sub Private Sub btnPreview_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPreview.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) ''preview Dim ps As New PaperSize("A4", 840, 1150) ps.PaperName = PaperKind.A4 PrintDocument1.DefaultPageSettings.PaperSize = ps PrintPreviewDialog1.WindowState = FormWindowState.Normal PrintPreviewDialog1.StartPosition = FormStartPosition.CenterScreen PrintPreviewDialog1.ClientSize = New Size(600, 600) PrintPreviewDialog1.ShowDialog() End Sub Private Sub PrintDocument1_PrintPage(ByVal sender As System.Object, ByVal e As System.Drawing.Printing.PrintPageEventArgs) Handles PrintDocument1.PrintPage 'print grid Dim morepages As Boolean = PrintC.Print(e.Graphics) If (morepages) Then e.HasMorePages = True End If End Sub End Class End Namespace This is how data looks in DataGrid (that's perfect)... and here is how it looks when I click PrintPreview. (I don't want the time to appear there, the "12:00:00" part. in database the date is stored as Short Date (10-Dec-12) Can somebody suggest a way around that? Imports System Imports System.Windows.Forms Imports System.Drawing Imports System.Drawing.Printing Imports System.Collections Imports System.Data Namespace Print Public Class PrinterClass '//clone of Datagrid Dim PrintGrid As Grid '//printdocument for initial printer settings Private PrintDoc As PrintDocument '//defines whether the grid is ordered right to left Private bRightToLeft As Boolean '//Current Top Private CurrentY As Single = 0 '//Current Left Private CurrentX As Single = 0 '//CurrentRow to print Private CurrentRow As Integer = 0 '//Page Counter Public PageCounter As Integer = 0 '/// <summary> '/// Constructor Class '/// </summary> '/// <param name="pdocument"></param> '/// <param name="dgrid"></param> Public Sub New(ByVal pdocument As PrintDocument, ByVal dgrid As DataGrid) 'MyBase.new() PrintGrid = New Grid(dgrid) PrintDoc = pdocument '//The grid columns are right to left bRightToLeft = dgrid.RightToLeft = RightToLeft.Yes '//init CurrentX and CurrentY CurrentY = pdocument.DefaultPageSettings.Margins.Top CurrentX = pdocument.DefaultPageSettings.Margins.Left End Sub Public Function Print(ByVal g As Graphics, ByRef currentX As Single, ByRef currentY As Single) As Boolean '//use predefined area currentX = currentX currentY = currentY PrintHeaders(g) Dim Morepages As Boolean = PrintDataGrid(g) currentY = currentY currentX = currentX Return Morepages End Function Public Function Print(ByVal g As Graphics) As Boolean CurrentX = PrintDoc.DefaultPageSettings.Margins.Left CurrentY = PrintDoc.DefaultPageSettings.Margins.Top PrintHeaders(g) Return PrintDataGrid(g) End Function '/// <summary> '/// Print the Grid Headers '/// </summary> '/// <param name="g"></param> Private Sub PrintHeaders(ByVal g As Graphics) Dim sf As StringFormat = New StringFormat '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = 0 To PrintGrid.Columns - 1 '//set header alignment Select Case (CType(PrintGrid.Headers.GetValue(i), Header).Alignment) Case HorizontalAlignment.Left 'left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX -= PrintGrid.Headers(i).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX += PrintGrid.Headers(i).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY = CurrentY + CType(PrintGrid.Headers.GetValue(0), Header).Height End Sub Private Function PrintDataGrid(ByVal g As Graphics) As Boolean Dim sf As StringFormat = New StringFormat PageCounter = PageCounter + 1 '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = CurrentRow To PrintGrid.Rows - 1 Dim j As Integer For j = 0 To PrintGrid.Columns - 1 '//set cell alignment Select Case (PrintGrid.Cell(i, j).Alignment) '//left Case HorizontalAlignment.Left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center '//right Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX -= PrintGrid.Cell(i, j).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text '//Draw text by alignment g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX += PrintGrid.Cell(i, j).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY += PrintGrid.Cell(i, 0).Height CurrentRow += 1 '//if we are beyond the page margin (bottom) then we need another page, '//return true If (CurrentY > PrintDoc.DefaultPageSettings.PaperSize.Height - PrintDoc.DefaultPageSettings.Margins.Bottom) Then Return True End If Next Return False End Function End Class End Namespace

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  • How to create a status bar icon on the right side? (Android)

    - by yuku
    Notification and NotificationManager are used to create icons to be placed on the top-left position of the screen. A Notification also need to have an entry on the status bar pull-down. However, icons on the right side such as the battery, signal strength, wireless indicators do not need any entry on the status bar. How do I make such icons without any entry in the status bar pull-down?

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  • What is the right way to scale a Flex application up to fullscreen?

    - by Impirator
    Fullscreen mode and I have been battling for a while in this Flex application, and I'm coming up short on Google results to end my woes. I have no problem going into fullscreen mode by doing a Application.application.stage.displayState = StageDisplayState.FULL_SCREEN;, but the rest of the content just sits there in the top, left corner at it's original size. All right, says I, I'll just do a stage.scaleMode = StageScaleMode.SHOW_ALL and make it figure out how to pull this off. And it looks like it does. Except that when you mouse over the individual checkboxes and buttons and various components, they all fidget slightly. Just a slight jump up or down as they resize...on mouse over. Well, this is frustrating, but bearable. I can always just invoke invalidateSize() explicitly for all of them. But for the comboboxes. The ones at the bottom have their menus go off the bottom of the screen, and when I pop out of fullscreen mode, their drop downs cut off half way. I have no idea how to fix that. Can someone step in here, and put me out of my misery? What is the right way to scale a Flex application up to fullscreen? var button:Button = button_fullscreen; try { if(stage.displayState == StageDisplayState.FULL_SCREEN) { Application.application.stage.displayState = StageDisplayState.NORMAL; button.label = "View Fullscreen Mode"; stage.scaleMode = StageScaleMode.NO_SCALE; } else { Application.application.stage.displayState = StageDisplayState.FULL_SCREEN; button.label = "Exit Fullscreen Mode"; stage.scaleMode = StageScaleMode.SHOW_ALL; } invalidateSizes(); // Calls invalidateSize() explicitly on several components. } catch(error:SecurityError) { Alert.show("The security settings of your computer prevent this from being displayed in fullscreen.","Error: "+error.name+" #"+error.errorID); } catch(error:Error) { Alert.show(error.message,error.name+" #"+error.errorID); }

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  • mySQL Efficiency Issue - How to find the right balance of normalization...?

    - by Foo
    I'm fairly new to working with relational databases, but have read a few books and know the basics of good design. I'm facing a design decision, and I'm not sure how to continue. Here's a very over simplified version of what I'm building: People can rate photos 1-5, and I need to display the average votes on the picture while keeping track of the individual votes. For example, 12 people voted 1, 7 people voted 2, etc. etc. The normalization freak of me initially designed the table structure like this: Table pictures id* | picture | userID | Table ratings id* | pictureID | userID | rating With all the foreign key constraints and everything set as they shoudl be. Every time someone rates a picture, I just insert a new record into ratings and be done with it. To find the average rating of a picture, I'd just run something like this: SELECT AVG(rating) FROM ratings WHERE pictureID = '5' GROUP by pictureID Having it setup this way lets me run my fancy statistics to. I can easily find who rated a certain picture a 3, and what not. Now I'm thinking if there's a crapload of ratings (which is very possible in what I'm really designing), finding the average will became very expensive and painful. Using a non-normalized version would seem to be more efficient. e.g.: Table picture id | picture | userID | ratingOne | ratingTwo | ratingThree | ratingFour | ratingFive To calculate the average, I'd just have to select a single row. It seems so much more efficient, but so much more uglier. Can someone point me in the right direction of what to do? My initial research shows that I have to "find the right balance", but how do I go about finding that balance? Any articles or additional reading information would be appreciated as well. Thanks.

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  • How can I print text fields at the right coordinates?

    - by Milad
    I don't have any background in programming and this is my first shot. I wrote a Delphi program that is supposed to print on a result sheet. I work in an institute and we have to establish hundreds of result sheets every 2 months. It's really difficult to do that and different handwriting is also an important issue. I have this code: if PrintDialog.Execute() then begin with MyPrinter do begin MyPrinter.BeginDoc();//Start Printing //Prints First Name MyPrinter.Canvas.TextOut(FirstNameX,FirstNameY,EditFirstName.Text); //Prints Last Name MyPrinter.Canvas.TextOut(LastNameX,LastNameY,EditLastName.Text); //Prints Level MyPrinter.Canvas.TextOut(LevelX,LevelY,EditLevel.Text); //Prints Date MyPrinter.Canvas.TextOut(DateX,DateY,MEditDate.Text); //Prints Student Number MyPrinter.Canvas.TextOut(StdNumX,StdNumY,EditStdnumber.Text); .... MyPrinter.EndDoc();//End Printing end; end; I can't get the right coordinates to print properly. Am I missing something? How can I set the right coordinates? You know TPrinter uses pixels to get the coordinates but papers are measured in inches or centimeters. I'm really confused. I appreciate any help.

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  • How can I direct edge to get out of the diamond on the right?

    - by Didier Trosset
    I have a simple dot diagram to show how to perform tests. PerformTests; PerformTests<---+ PerformTests -> TestsPassed; | | TestsPassed [shape="diamond"]; v | TestsPassed -> Release [label="Yes"]; TestsPassed | TestsPassed -> FixErrors [label="No"]; Y| N\ | FixErrors -> PerformTests; v FixErrors Release The diagram shows square boxes for all nodes, except TestPassed that has a diamond shape. My issue is here. I'd like the edge that goes outside of the diamond for No to be getting out of the diamond at the right (east) instead of oblique down-right (south-east). What I have What I want ^ ^ / \ / \ < > < >---> \ /\ \ / v \ v I've seen such compass_pt in the dot grammar, but cannot figure out how to use it. I what I want possible, and how to do it?

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  • Naive Bayesian classification (spam filtering) - Doubt in one calculation? Which one is right? Plz c

    - by Microkernel
    Hi guys, I am implementing Naive Bayesian classifier for spam filtering. I have doubt on some calculation. Please clarify me what to do. Here is my question. In this method, you have to calculate P(S|W) - Probability that Message is spam given word W occurs in it. P(W|S) - Probability that word W occurs in a spam message. P(W|H) - Probability that word W occurs in a Ham message. So to calculate P(W|S), should I do (1) (Number of times W occuring in spam)/(total number of times W occurs in all the messages) OR (2) (Number of times word W occurs in Spam)/(Total number of words in the spam message) So, to calculate P(W|S), should I do (1) or (2)? (I thought it to be (2), but I am not sure, so plz clarify me) I am refering http://en.wikipedia.org/wiki/Bayesian_spam_filtering for the info by the way. I got to complete the implementation by this weekend :( Thanks and regards, MicroKernel :) @sth: Hmm... Shouldn't repeated occurrence of word 'W' increase a message's spam score? In the your approach it wouldn't, right?. Lets take a scenario and discuss... Lets say, we have 100 training messages, out of which 50 are spam and 50 are Ham. and say word_count of each message = 100. And lets say, in spam messages word W occurs 5 times in each message and word W occurs 1 time in Ham message. So total number of times W occuring in all the spam message = 5*50 = 250 times. And total number of times W occuring in all Ham messages = 1*50 = 50 times. Total occurance of W in all of the training messages = (250+50) = 300 times. So, in this scenario, how do u calculate P(W|S) and P(W|H) ? Naturally we should expect, P(W|S) P(W|H)??? right. Please share your thought...

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  • Conceptual data modeling: Is RDF the right tool? Other solutions?

    - by paprika
    I'm planning a system that combines various data sources and lets users do simple queries on these. A part of the system needs to act as an abstraction layer that knows all connected data sources: the user shouldn't [need to] know about the underlying data "providers". A data provider could be anything: a relational DBMS, a bug tracking system, ..., a weather station. They are hooked up to the query system through a common API that defines how to "offer" data. The type of queries a certain data provider understands is given by its "offer" (e.g. I know these entities, I can give you aggregates of type X for relationship Y, ...). My concern right now is the unification of the data: the various data providers need to agree on a common vocabulary (e.g. the name of the entity "customer" could vary across different systems). Thus, defining a high level representation of the entities and their relationships is required. So far I have the following requirements: I need to be able to define objects and their properties/attributes. Further, arbitrary relations between these objects need to be represented: a verb that defines the nature of the relation (e.g. "knows"), the multiplicity (e.g. 1:n) and the direction/navigability of the relation. It occurs to me that RDF is a viable option, but is it "the right tool" for this job? What other solutions/frameworks do exist for semantic data modeling that have a machine readable representation and why are they better suited for this task? I'm grateful for every opinion and pointer to helpful resources.

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  • Flex chart not displaying right values along x axis.

    - by Shah Al
    I don't know of any better way to ask this question. If the below code is run (i know the cData sections are not visible in the preview, something causes it to be ignored). The result does not represent the data correctly. 1. Flex ignores missing date 24 aug for DECKER. 2. It wrongly associates 42.77 to 23-Aug instead of 24-AUG. Is there a way in flex, where the x-axis is a union of all available points ? The below code is entirely from : Adobe website link I have only commented 2 data points. //{date:"23-Aug-05", close:45.74}, and //{date:"24-Aug-05", close:150.71}, <?xml version="1.0"?> [Bindable] public var SMITH:ArrayCollection = new ArrayCollection([ {date:"22-Aug-05", close:41.87}, //{date:"23-Aug-05", close:45.74}, {date:"24-Aug-05", close:42.77}, {date:"25-Aug-05", close:48.06}, ]); [Bindable] public var DECKER:ArrayCollection = new ArrayCollection([ {date:"22-Aug-05", close:157.59}, {date:"23-Aug-05", close:160.3}, //{date:"24-Aug-05", close:150.71}, {date:"25-Aug-05", close:156.88}, ]); [Bindable] public var deckerColor:Number = 0x224488; [Bindable] public var smithColor:Number = 0x884422; ]] <mx:horizontalAxisRenderers> <mx:AxisRenderer placement="bottom" axis="{h1}"/> </mx:horizontalAxisRenderers> <mx:verticalAxisRenderers> <mx:AxisRenderer placement="left" axis="{v1}"> <mx:axisStroke>{h1Stroke}</mx:axisStroke> </mx:AxisRenderer> <mx:AxisRenderer placement="left" axis="{v2}"> <mx:axisStroke>{h2Stroke}</mx:axisStroke> </mx:AxisRenderer> </mx:verticalAxisRenderers> <mx:series> <mx:ColumnSeries id="cs1" horizontalAxis="{h1}" dataProvider="{SMITH}" yField="close" displayName="SMITH" > <mx:fill> <mx:SolidColor color="{smithColor}"/> </mx:fill> <mx:verticalAxis> <mx:LinearAxis id="v1" minimum="40" maximum="50"/> </mx:verticalAxis> </mx:ColumnSeries> <mx:LineSeries id="cs2" horizontalAxis="{h1}" dataProvider="{DECKER}" yField="close" displayName="DECKER" > <mx:verticalAxis> <mx:LinearAxis id="v2" minimum="150" maximum="170"/> </mx:verticalAxis> <mx:lineStroke> <mx:Stroke color="{deckerColor}" weight="4" alpha="1" /> </mx:lineStroke> </mx:LineSeries> </mx:series> </mx:ColumnChart> <mx:Legend dataProvider="{myChart}"/>

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