rearrange Array according to values order of another Array
- by Exception
I have two arrays like below
var arr = ["x", "y", "z", "a", "b", "c"];
var tgtArr = [{val:"a"}, {val:"b"}]; It does not need to be as lengthy as Array `arr`
This is what I have tried
var dest = new Array(arr.length);
for(var i = 0; i < arr.length; i++){
for(var k = 0; k < tgtArr.length; k++){
dest[i] = dest[i] || [];
if(tgtArr[k].val == arr[i]){
dest[i] = arr[i];
}
}
}
console.log(dest);
My Expected output is (for above tgtArr value)
[{}, {}, {}, {val:"a"}, {val:"b"}, {}];
if tgtArr is empty Array
[{},{},{},{},{},{}]
Here is the fiddle. Any alternative for this, it seems not a good way to me as I am iterating through the entire array everytime.
