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  • Efficient job progress update in web application

    - by Endru6
    Hi, Creating a web application (Django in my case, but I think the question is more general) that is administrating a cluster of workers doing queued jobs, there is a need to track each jobs progress. When I've done it using database UPDATE (PostgreSQL in this case), it severely hits the database performance, because each UPDATE creates a new row in a table, and in my case only vacuuming DB removes obsolete rows. Having 30 jobs running and reporting progress every 1 minute DB may require vacuuming (and it means huge slow downs on a front end side for all the employees working with the system) every 10 days. Because the progress information isn't critical, ie. it doesn't have to be persistent, how would you do the progress updates from jobs without using an overhead database implies? There are 30 worker servers, each doing 1 or 2 jobs simultaneously, 1 front end server which serves a web application to users, and 1 database server.

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  • NHibernate Native SQL multiple joins

    - by Chris
    Hi all, I"m having some problems with Nhibernate and native sql. I've got an entity with alot of collections and I am doing an SQL Fulltext search on it. So when returning 100 or so entities, I dont want all collections be lazy loaded. For this I changed my SQL query: SELECT Query.* FROM (SELECT {spr.*}, {adr.*}, {adrt.*}, {cty.*}, {com.*}, {comt.*}, spft.[Rank] AS [Rak], Row_number() OVER(ORDER BY spft.[Rank] DESC) AS rownum FROM customer spr INNER JOIN CONTAINSTABLE ( customerfulltext , computedfulltextindex , '" + parsedSearchTerm + @"' ) AS spft ON spr.customerid = spft.[Key] LEFT JOIN [Address] adr ON adr.customerid = spr.customerid INNER JOIN [AddressType] adrt ON adrt.addresstypeid = adr.addresstypeid INNER JOIN [City] cty ON cty.cityid = adr.cityid LEFT JOIN [Communication] com ON com.customerid = spr.customerid INNER JOIN [CommunicationType] comt ON comt.communicationtypeid = com.communicationtypeid) as Query ORDER BY Query.[Rank] DESC This is how I setup the query: var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .List<Customer>(); What happens now is, that the query returns customers twice (or more), I assume this is because of the joins since for each customer address, communicationItem (e.g. phone, email), a new sql row is returned. In this case I thought I could use the DistinctRootEntityResultTransformer. var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .SetResultTransformer(new DistinctRootEntityResultTransformer()) .List<Customer>(); Doing so an exception is thrown. This is because I try to list customers .List<Customer>() but the transformer returns only entities of the last join added. E.g. in the case above, the entity with alias "comt" is returned when doing .List() instead of .List(). If I would switch last join with the join alias "cty", then the transformer returns a list of cities only... Anyone knows how I can return a clean list of customers in this case?

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  • Switch role after connecting to database

    - by Chris Gow
    Is it possible to change the postgresql role a user is using when interacting with postgres after the initial connection? The database(s) will be used in a web application and I'd like to employ database level rules on tables and schemas with connection pooling. From reading the postgresql documentation it appears I can switch roles if I originally connect as a user with the superuser role, but I would prefer to initially connect as a user with minimal permissions and switch as necessary. Having to specify the user's password when switching would be fine (in fact I'd prefer it). What am I missing?

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  • Transfer Data between databases with postgres

    - by user227932
    I need to transfer some data from another Database. The old database is called paw1.moviesDB and the new database is paw1. The schema of each table are the following Awards (name of the table)(new DB) Id [PK] Serial Award Nominations (name of the table) (old DB) Id [PK] Serial nominations I want to copy the data from old DB to the new DB.

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  • A Security (encryption) Dilemma

    - by TravisPUK
    I have an internal WPF client application that accesses a database. The application is a central resource for a Support team and as such includes Remote Access/Login information for clients. At the moment this database is not available via a web interface etc, but one day is likely to. The remote access information includes the username and passwords for the client's networks so that our client's software applications can be remotely supported by us. I need to store the usernames and passwords in the database and provide the support consultants access to them so that they can login to the client's system and then provide support. Hope this is making sense. So the dilemma is that I don't want to store the usernames and passwords in cleartext on the database to ensure that if the DB was ever compromised, I am not then providing access to our client's networks to whomever gets the database. I have looked at two-way encryption of the passwords, but as they say, two-way is not much different to cleartext as if you can decrypt it, so can an attacker... eventually. The problem here is that I have setup a method to use a salt and a passcode that are stored in the application, I have used a salt that is stored in the db, but all have their weaknesses, ie if the app was reflected it exposes the salts etc. How can I secure the usernames and passwords in my database, and yet still provide the ability for my support consultants to view the information in the application so they can use it to login? This is obviously different to storing user's passwords as these are one way because I don't need to know what they are. But I do need to know what the client's remote access passwords are as we need to enter them in at the time of remoting to them. Anybody have some theories on what would be the best approach here? update The function I am trying to build is for our CRM application that will store the remote access details for the client. The CRM system provides call/issue tracking functionality and during the course of investigating the issue, the support consultant will need to remote in. They will then view the client's remote access details and make the connection

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  • PHP: reusing database class

    - by citricsquid
    Hi, I built a class that allows me to do: $db->query($query); and it works perfectly, although if I want to do: $db->query($query); while($row = $db->fetch_assoc()){ $db->query($anotherquery); echo $db->result(); } it "breaks" the class. I don't want to constantly have to redeclare my class (eg: $seconddb = new database()), is there a way to get around this? I want to be able to reuse $db within $db, without overwriting the "outside" db. currently I'm create an array of data (from db-fetch_assoc() then doing a foreach and then doing the db call inside that: $db->query('SELECT * FROM table'); while($row = $db->fetch_assoc()){ $arr[] = $row; } foreach($arr as $a){ $db->query(); // query and processing here } Is this the best method or am I missing the obvious? Should I consider passing a connection link ID with the database connection?

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  • couchdb: one database per account vs all in one database w. a namespace / property

    - by thruflo
    I'm modelling a document generation system in couchdb. It semi-automates the production of proposal and presentation documents from managable document fragments. Much like, say, Basecamp, it breaks down very simply into self-contained data per 'account'. Each account has multiple users, projects, documents, etc. However, nothing should be shared between accounts. I can see two ways of doing this: one couchdb database per account use a namespace / property to identify the account It seems to me that the first approach is conceptually sound and potentially has security and partitioning advantages. However, it seems to me to restrict some cross-database data querying (that I don't have a use case for now but you never know...) and to make updating views potentially require an awful lot of writes. Does anyone experienced with this kind of decision have any advice?

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  • get data from database by manually giving the server name

    - by syedsaleemss
    Im using c# .net windows application form. I have created many databases with many tables in each. I have a datagrid view and a display button. when i click on this button, the system must prompt me to enter the server name and after typing the server name, it should display all the databases related to that server in some combo box. and again if i select a database it should show all the tables present in that database into a combobox. and if i select a table, it should prompt an option to select only required columns into the datagridview. How can i do this?

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  • MySql database design for a quiz

    - by Mark
    I'm making an online quiz with php and mysql and need a bit of help deciding how to design the database for optimal insert of questions/answers and to select questions for the quiz. The table will hold 80 questions each with 4 possible options plus the correct answer. When retrieving the questions and options from the database I will randomly select 25 questions and their options. Is it better to make a single column for all questions, options, and correct answers? For example: ID | Q | OPT1 | OPT2 | OPT3 | OPT4 | ANS Or would it be better to make a column for each individual question, option, and correct answer? For example: Q1 | Q1_OPT1 | Q1_OPT2 | Q1_OPT3 | Q1_OPT5 | Q1_ANS | Q2 | Q2_OPT1 | Q2_OPT2...

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  • save to sql server database fromclient side

    - by user281693
    I have a gridview with dropdownlist in it. When the user changes the item in the dropdownlist I want to save the new item in the database. I want this to happen using javascript and ajax like effect. I know how to access the dropdownlist inside gridview using javascript and I can get the new selectd item. But how can I save it to database without server side code? I know one way of doing this is using web services. I just want to know if there is/are any other ways to do it.

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  • How to "redefine search" or correct "misspelling" from the database

    - by From.ME.to.YOU
    Hello i want to add new feature to the search in my website. i'm using PHP and MYSQL. mysql database containing a table to the items that the user will search for, for each item there is a "keyword" column that's comma separated keywords "EXAMPLE: cat,dog,horse". after the user search in my website i want to get the words that are let me say "85%" similar to his search keyword, this is for redefine search. and for misspelling i want a service or something that provide if the keyword is correct or misspelled so i get some corrections and check if those exists in the database and then give those corrections to user to change his search keyword. i'm not asking for a solution here ... but if you can direct me in a one way or another that will be great Thanks guys Cheers

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  • How do I change a MySQL table to UTF-8?

    - by alex
    I know there are many settings for a language for a table and a database. I already created the database. I believe when I created it, it was default/LATIN. I want to change everything-I mean...both the table and the database, to UTF-8. How can I do that? thanks.

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  • how to guarantee atomicity across two databases (the filesystem and your RDBMS)?

    - by Lock up
    i am working on a online file management project.In which we are storing references on the database(sql server) and files data on the on file system;.In which we are facing a problem of coordination between file system and database while we are uploading a file and also in case of deleting a file that first we create a reference in the data base or store files on file system;;the problem is that if create a reference in the database first and then storing a file on file system.bur while storing files on the file system any type of error occur.then reference for that file is created in the database but no file data on the file system;; please give me some solution how to deal with such situation;;i am badly in need of it;; and reason for that?

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  • Why does SQL Server consider N'????' and N'???' to be equal?

    - by Aidan Ryan
    We are testing our application for Unicode compatibility and have been selecting random characters outside the Latin character set for testing. On both Latin and Japanese-collated systems the following equality is true (U+3422): N'????' = N'???' but the following is not (U+30C1): N'????' = N'???' This was discovered when a test case using the first example (using U+3422) violated a unique index. Do we need to be more selective about the characters we use for testing? Obviously we don't know the semantic meaning of the above comparisons. Would this behavior be obvious to a native speaker?

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  • Play Framework: Error getting sequence nextval using H2 in-memory database

    - by alexhanschke
    As the title suggests, I get an error running Play 2.0.1 Tests using a FakeApplication w/ H2 in memory. I set up a basic unit test: public class ModelTest { @Test public void checkThatIndustriesExist() { running(fakeApplication(inMemoryDatabase()), new Runnable() { public void run() { Industry industry = new Industry(); industry.name = "Some name"; industry.shortname = "some-name"; industry.save(); assertThat(Industry.find.all()).hasSize(1); } }); } Which yields the following exception: [info] test.ModelTest [error] Test test.ModelTest.checkThatIndustriesExist failed: Error getting sequence nextval [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:213) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.loadMoreIds(SequenceIdGenerator.java:163) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.nextId(SequenceIdGenerator.java:118) [error] at com.avaje.ebeaninternal.server.deploy.BeanDescriptor.nextId(BeanDescriptor.java:1218) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.setIdGenValue(DefaultPersister.java:1304) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.insert(DefaultPersister.java:403) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveEnhanced(DefaultPersister.java:345) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveRecurse(DefaultPersister.java:315) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.save(DefaultPersister.java:282) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1577) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1567) [error] at com.avaje.ebean.Ebean.save(Ebean.java:538) [error] at play.db.ebean.Model.save(Model.java:76) [error] at test.ModelTest$1.run(ModelTest.java:24) [error] at play.test.Helpers.running(Helpers.java:277) [error] at test.ModelTest.checkThatIndustriesExist(ModelTest.java:21) [error] ... [error] Caused by: org.h2.jdbc.JdbcSQLException: Syntax Fehler in SQL Befehl "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; erwartet "identifier" [error] Syntax error in SQL statement "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; expected "identifier"; SQL statement: [error] select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval [42001-158] [error] at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) [error] at org.h2.message.DbException.get(DbException.java:169) [error] at org.h2.message.DbException.getSyntaxError(DbException.java:194) [error] at org.h2.command.Parser.readColumnIdentifier(Parser.java:2777) [error] at org.h2.command.Parser.readTermObjectDot(Parser.java:2336) [error] at org.h2.command.Parser.readTerm(Parser.java:2453) [error] at org.h2.command.Parser.readFactor(Parser.java:2035) [error] at org.h2.command.Parser.readSum(Parser.java:2022) [error] at org.h2.command.Parser.readConcat(Parser.java:1995) [error] at org.h2.command.Parser.readCondition(Parser.java:1860) [error] at org.h2.command.Parser.readAnd(Parser.java:1841) [error] at org.h2.command.Parser.readExpression(Parser.java:1833) [error] at org.h2.command.Parser.parseSelectSimpleSelectPart(Parser.java:1746) [error] at org.h2.command.Parser.parseSelectSimple(Parser.java:1778) [error] at org.h2.command.Parser.parseSelectSub(Parser.java:1673) [error] at org.h2.command.Parser.parseSelectUnion(Parser.java:1518) [error] at org.h2.command.Parser.parseSelect(Parser.java:1506) [error] at org.h2.command.Parser.parsePrepared(Parser.java:405) [error] at org.h2.command.Parser.parse(Parser.java:279) [error] at org.h2.command.Parser.parse(Parser.java:251) [error] at org.h2.command.Parser.prepareCommand(Parser.java:217) [error] at org.h2.engine.Session.prepareLocal(Session.java:415) [error] at org.h2.engine.Session.prepareCommand(Session.java:364) [error] at org.h2.jdbc.JdbcConnection.prepareCommand(JdbcConnection.java:1119) [error] at org.h2.jdbc.JdbcPreparedStatement.<init>(JdbcPreparedStatement.java:71) [error] at org.h2.jdbc.JdbcConnection.prepareStatement(JdbcConnection.java:267) [error] at com.jolbox.bonecp.ConnectionHandle.prepareStatement(ConnectionHandle.java:820) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:193) [error] ... 80 more My model looks like this: @Entity @Table(name = "industry") public class Industry extends Model { @Id public Long id; public String name; public String shortname; // called in the view to trigger lazy-loading public String getName() { return name; } public static Finder<Long, Industry> find = new Finder<Long, Industry>(Long.class, Industry.class); } ... and finally the relevant part from my initial evolution: create table industry ( id bigint not null, name varchar(255), shortname varchar(255), constraint pk_industry primary key (id) } create sequence industry_seq start with 1000; Everything works fine running on my PostgreSQL DB, and from my point of view the code is not any different from the Play2.0 Computer Database Sample. I am happy for any help - thanks! Regards, Alex

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  • Form Submitting Incorrect Information to MySQL Database

    - by ThatMacLad
    I've created a form that submits data to a MySQL database but the Date, Time, Year and Month fields constantly revert to the exact same date (1st January 1970) despite the fact that when I submit the information to the database the form displays the current date, time etc to me. I've already set it so that the time and date fields automatically display the current time and date. Could someone please help me with this. Form: <html> <head> <title>Blog | New Post</title> <link rel="stylesheet" href="css/newposts.css" type="text/css" /> </head> <body> <div class="new-form"> <div class="header"> <a href="edit.php"><img src="images/edit-home-button.png"></a> </div> <div class="form-bg"> <?php if (isset($_POST['submit'])) { $month = htmlspecialchars(strip_tags($_POST['month'])); $date = htmlspecialchars(strip_tags($_POST['date'])); $year = htmlspecialchars(strip_tags($_POST['year'])); $time = htmlspecialchars(strip_tags($_POST['time'])); $title = htmlspecialchars(strip_tags($_POST['title'])); $entry = $_POST['entry']; $timestamp = strtotime($month . " " . $date . " " . $year . " " . $time); $entry = nl2br($entry); if (!get_magic_quotes_gpc()) { $title = addslashes($title); $entry = addslashes($entry); } mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "INSERT INTO php_blog (timestamp,title,entry) VALUES ('$timestamp','$title','$entry')"; $result = mysql_query($sql) or print("Can't insert into table php_blog.<br />" . $sql . "<br />" . mysql_error()); if ($result != false) { print "<p class=\"success\">Your entry has successfully been entered into the blog. </p>"; } mysql_close(); } ?> <?php $current_month = date("F"); $current_date = date("d"); $current_year = date("Y"); $current_time = date("H:i"); ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_month; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_date; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_year; ?>" /> <input type="text" name="time" id="time" size="5"value="<?php echo $current_time; ?>" /> <input class="field2" type="text" id="title" value="Title Goes Here." name="title" size="40" /> <textarea class="textarea" cols="80" rows="20" name="entry" id="entry" class="field2"></textarea> <input class="field" type="submit" name="submit" id="submit" value="Submit"> </form> </div> </div> </div> <div class="bottom"></div> </body> </html>

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  • Unable to connect: incorrect log on parameters Crystal report

    - by Brave ali Khatri
    I am using windows 7 ,SQL Server 2000 and VS 2008 / Crystal Report XI. i am getting Below Error when click on GetReport Button. Logon failed. Details: ADO Error Code: 0x Source: Microsoft OLE DB Provider for SQL Server Description: Login failed for user 'sa'. SQL State: 42000 Native Error: Error in File C:\Users\bahadur\AppData\Local\Temp\Total_Sales_Comparision {C4649F80-D1F7-4AED-A4B1-0B8EF83996C6}.rpt: Unable to connect: incorrect log on parameters. Blockquote MY C# Code is below ConnectionInfo crConnectionInfo = new ConnectionInfo(); crConnectionInfo.ServerName = "BRAVEALI-PC"; crConnectionInfo.DatabaseName = "SCM_TEST"; crConnectionInfo.UserID = "sa"; crConnectionInfo.Password = "myDB Password"; ReportDocument report = new ReportDocument(); report.Load(@"D:\Project's\SCM Reports\Total_Sales_Comparision.rpt"); report.SetParameterValue("@invcm_date_from", Convert.ToDateTime (TextBox4.Text)); report.SetParameterValue("@invcm_date_to", Convert .ToDateTime(TextBox5.Text)); CrystalReportViewer1.ReportSource = report; //CrystalReportViewer1.RefreshReport(); Regards Brave Ali

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