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  • Website badge system

    - by linkyndy
    I am currently working on a widget-based website, built entirely on user socialization. Since a reputation system pays off for attracting users, I decided to implement one of these. Now, I would like to hear some solutions on how should this be implemented the right way (take, for example, Foursquare's badge system). Basically, I need to be able to do the following: have a badges table, where I can add, edit and delete badges; be able to enable and disable a badge; be able to introduce a new badge, but without writing new code - simply give some parameters to the add badge form regarding what should be followed in order for a user to receive a badge; be able to give badges in real time - meaning that whenever a user accomplishes whatever it needs to receive a badge, the system should know immediately to give the badge to that user; also, the system should not be overloaded with "badge listeners" - I believe interrogating each user request with every badge requirements is time consuming; These being said, I would like to hear your opinions on how to implement the right way a badge system (logic, database schema, methods etc.) Thank you very much!

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  • is there a Java GUI for dummies ?

    - by MHero
    Hello, first I want to apologize about my english, it may be not clear enough. Well, I'm new to Java programming, and I search over this web about use of Swing, AWT, 2D, etc. but I didn't get the answer I was looking for. I want to know about a book or method to learn Java GUI programming (not even sure this is a propper term). Previous answers guide me to Filthy Rich Clients by Romain Guy and also to The Swing Tutorial in Sun Web Page. and No offense, but...the first one seems too complex and the second one a bit disorganize. so I ask about a more "for dummies" method. Thanks EDIT: Thanks everyboy, you're very kind and serious. I want to clear some things that I didn't state for being my first question. I dont' want to use autogenerated code(Don't want to say why only focus on my question for consistency) Also I've read Deitel & Deitel and it's a good beginners book but it seems to me that doesn't cover layout(and other details) Finally, I tried to read netbeans generated code but it's a mess find method by method and function by function the way that the IDE does it I hope this edition helps to solve my question

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  • Boolean comparison of array of strings in Ruby

    - by Kyle Kaitan
    I've got an array in Ruby that essentially represents a square boolean matrix. Dots represent zeroes, while any other character represents ones. Example: irb(main):044:0> g => [".b", "m."] # This grid has two '1' values and two '0' values. I'd like to perform a specified logical operation (say, OR) on this array with another similar array to get a third result. For example, if h is ["q.", "r."], then something akin to g.perform_or(h) should yield a new array ["qb", "r."]. (The choice of r to represent the result of 'm' || 'r' is arbitrary and not relevant; any other non-'.' character can be there.) How might I do this? Edit: I made an error in my example. Apologies!

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  • How to set title and class in the HTML for the options of a ModelChoiceField?

    - by celopes
    I have a model class MyModel(models.Model): name = models.CharField(max_length=80, unique=True) parent = models.ForeignKey('self', null=True, blank=True) I want to render a ModelChoiceField for that model that looks like: <select name="mymodel" id="id_mymodel"> <option value="1" title="Value 1" class="">Value 1</option> <option value="2" title="Value 2" class="Value 1">Value 2</option> </select> The differences between this output and the default output for a ModelChoiceField are the title and class elements in the OPTION tag. They don't exist in ModelChoiceField's default output. For my purposes: The title element is supposed to be the Option Name. The class element is supposed to be self.parent.name. (this is my problem) So, in the HTML snippet above, Value 1 has no parent and Value 2 has a parent of Value 1. What is the best mechanism to change ModelChoiceField's default HTML output? EDIT: I understand how to create a new Widget for rendering HTML. The problem is how to render a value from the underlying model in each of the options.

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  • Drupal 6: Creating "ON/OFF News Links" functionality for a block created with View Module.

    - by artmania
    Hi friends, I'm a drupal newbie who needs some advice... I have a news list block at homepage, created with View Module. It is listing all added news' title and link. Everything is cool so far. Now I need to add an ON/OFF option at admin side for homepage news block. When the setting is ON, it will work as it is. When it is OFF, only the titles will be listed with no linking to news detail page. So, now where should I add this ON/OFF option? I have only add/edit/delete pages for each news, there is no common news page to add such option. Should I create an admin page with such ON/OFF option in? Also I think I need to create a db table to keep this ON/OFF status. and controlling this value at homepage block, if it is 1 or 0, and displaying links according to db value :/ it looks too long way Create db table Create an page with ON/OFF option in add php codes to update db for admin's choice get the db value in homepage block to display links, etc. is there any shorter, better way to do what I need? Appreciate helps so much!!! Thanks a lot!!

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  • How do you create a generic method in a class?

    - by Seth Spearman
    Hello, I am really trying to follow the DRY principle. I have a sub that looks like this? Private Sub DoSupplyModel OutputLine("ITEM SUMMARIES") Dim ItemSumms As New SupplyModel.ItemSummaries(_currentSupplyModel, _excelRows) ItemSumms.FillRows() OutputLine("") OutputLine("NUMBERED INVENTORIES") Dim numInvs As New SupplyModel.NumberedInventories(_currentSupplyModel, _excelRows) numInvs.FillRows() OutputLine("") End Sub I would like to collapse these into a single method using generics. For the record, ItemSummaries and NumberedInventories are both derived from the same base class DataBuilderBase. I can't figure out the syntax that will allow me to do ItemSumms.FillRows and numInvs.FillRows in the method. FillRows is declared as Public Overridable Sub FillRows in the base class. Thanks in advance. EDIT Here is my end result Private Sub DoSupplyModels() DoSupplyModelType("ITEM SUMMARIES",New DataBlocks(_currentSupplyModel,_excelRows) DoSupplyModelType("DATA BLOCKS",New DataBlocks(_currentSupplyModel,_excelRows) End Sub Private Sub DoSupplyModelType(ByVal outputDescription As String, ByVal type As DataBuilderBase) OutputLine(outputDescription) type.FillRows() OutputLine("") End Sub But to answer my own question...I could have done this... Private Sub DoSupplyModels() DoSupplyModelType(Of Projections)("ITEM SUMMARIES") DoSupplyModelType(Of DataBlocks)("DATA BLOCKS") End Sub Private Sub DoSupplyModelType(Of T as DataBuilderBase)(ByVal outputDescription As String, ByVal type As T) OutputLine(outputDescription) dim type as New T(_currentSupplyModel,_excelRows) type.FillRows() OutputLine("") End Sub Is that right? Does the New T() work? Seth

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  • Setting Icon for wpf application (VS 08)

    - by baron
    Hi everyone, Before going much further i'll mention I have tried solutions in following: http://stackoverflow.com/questions/320677/how-do-i-set-the-icon-for-my-application-in-visual-studio-2008 http://stackoverflow.com/questions/198848/set-application-icon-from-resources-in-vs-05 I am trying to set an icon for my application. AFAIK, I need potentially 3 images? 1 image is the actual image in explorer when clicking on the .exe (thumbnail for the exe) 1 image (tiny) in the top left corner (16 x 16? Not entirely sure) 1 image in the start menu dock, to the left of the app (maybe 32x32? again not sure) So thats fine. Now I have selected an Icon. How do I use it in one of above situations? I have tried adding it in resources, nothing seems to happen. Following that first SO solution, "First go to Resource View (from menu: View -- Other Window -- Resource View). Then in Resource View navigate through resources, if any. If there is already a resource of Icon type, added by Visual Studio, then open and edit it. Otherwise right-click and select Add Resource, and then add a new icon." The resource view is empty, and I cannot right click in this view. If I right click on the solution properties resources I can add the icon image, but it doesn't show in either of the locations listed above. (or anywhere that I can see) What am I doing wrong?

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  • How can I pass an array resulting from a Perl method by reference?

    - by arareko
    Some XML::LibXML methods return arrays instead of references to arrays. Instead of doing this: $self->process_items($xml->findnodes('items/item')); I want to do something like: $self->process_items(\$xml->findnodes('items/item')); So that in process_items() I can dereference the original array instead of creating a copy: sub process_items { my ($self, $items) = @_; foreach my $item (@$items) { # do something... } } I can always store the results of findnodes() into an array and then pass the array reference to my own method, but let's say I want to try a reduced version of my code. Is that the correct syntax for passing the method results or should I use something different? Thanks! EDIT: Now suppose I want to change process_items() to process_item() so I can do stuff on a single element of the referenced array inside a loop. Something like: $self->process_item($_) for ([ $xml->findnodes('items/item') ]); This doesn't work as process_item() is executed only once because a single value is passed to the for loop (the reference to the array from findnodes()). What's the proper way of using $_ in this case?

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  • fastest public web app framework for quick DB apps?

    - by Steve Eisner
    I'd like to pick up a new tech for my toolbox - something for rapid prototyping of web apps. Brief requirements: public access (not hosted on my machine) - like Google's appengine, etc no tricky configuration necessary to build a simple web app host DB access (small storage provided) including some kind of SQLish query language easy front end HTML templating ability to access as a JSON service C# or Java,PHP or Python - or a fun new language to learn is OK free! An example app, very simple: render an AJAXy editable (add/delete/edit/drag) list of rich-data list items via some template language, so I can quickly mock up a UI for a client. ie. I can do most of the work client-side, but need convenient back end to handle the permanent storage. (In fact I suppose it doesn't even need HTML templating if I can directly access a DB via AJAX calls.) I realize this is a bit vague but am wondering if anyone has recommendations. A Rails host might be best for this (but probably not free) or maybe App Engine, or some other choice I'm not aware of? I've been doing everything with heavyweight servers (ASP.NET etc) for so long that I'm just not up on the latest... Thanks - I'll follow up on comments if this isn't clear enough :)

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  • java.awt.Desktop.open doesn’t work with PDF files?

    - by Jason S
    It looks like I cannot use Desktop.open() on PDF files regardless of location. Here's a small test program: package com.example.bugs; import java.awt.Desktop; import java.io.File; import java.io.IOException; public class DesktopOpenBug { static public void main(String[] args) { try { Desktop desktop = null; // Before more Desktop API is used, first check // whether the API is supported by this particular // virtual machine (VM) on this particular host. if (Desktop.isDesktopSupported()) { desktop = Desktop.getDesktop(); for (String path : args) { File file = new File(path); System.out.println("Opening "+file); desktop.open(file); } } } catch (IOException e) { e.printStackTrace(); } } } If I run DesktopOpenBug with arguments c:\tmp\zz1.txt c:\tmp\zz.xml c:\tmp\ss.pdf (3 files I happen to have lying around) I get this result: (the .txt and .xml files open up fine) Opening c:\tmp\zz1.txt Opening c:\tmp\zz.xml Opening c:\tmp\ss.pdf java.io.IOException: Failed to open file:/c:/tmp/ss.pdf. Error message: The parameter is incorrect. at sun.awt.windows.WDesktopPeer.ShellExecute(Unknown Source) at sun.awt.windows.WDesktopPeer.open(Unknown Source) at java.awt.Desktop.open(Unknown Source) at com.example.bugs.DesktopOpenBug.main(DesktopOpenBug.java:21) What the heck is going on? I'm running WinXP, I can type "c:\tmp\ss.pdf" at the command prompt and it opens up just fine. edit: if this is an example of Sun Java bug #6764271 please help by voting for it. What a pain. :(

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  • Repeater not working fine when passed a dataprovider (array) having a single element

    - by baltusaj
    I am using a Repeater in an Accordian which does not appear to see a single element in userArray. If I add another entry to userArray then the Repeater works fine. Thoughts?? private function currUsersServiceHandler(event:ResultEvent):void{ if (event.result.currentUsers != null) { if (event.result.currentUsers.user is ArrayCollection) // if more than one elements are present { usersArray = event.result.currentUsers.user; } else if (event.result.currentUsers is ObjectProxy) { //FIXIT usersArray populate by following line has some issue usersArray = new ArrayCollection(ArrayUtil.toArray(event.result.currentUsers)); } } } <mx:HTTPService id="currUsersService" url="currUsers.xml" result="currUsersServiceHandler(event)"/> <mx:Accordion includeIn="UserList" x="10" y="10" width="554" height="242" > <mx:Repeater id="rep" dataProvider="{usersArray}"> <mx:Canvas width="100%" height="100%" label="{rep.currentItem.firstName}" > <mx:HBox> <s:Label text="{rep.currentItem.firstName}"/> <s:Label text="{rep.currentItem.lastName}"/> <mx:/HBox> </mx:Canvas> </mx:Repeater> </mx:Accordian> Edit: There is another thing I have just noticed i.e. that the accordian does show a single tab (when Array has a single element) but it's not labeled with the first name which I am setting. If I enter another user, two tabs appear and both are labeled with names I am setting. The first tab appears labeled too then.

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  • Supersized, show a div depending on the slide

    - by Dlacrem
    EDIT: So, I want to take a different approach to try and clarify what I'm looking for, I've been reading as much as I could these last hours and I feel I have a better grasp of how the system works, but I still don't know how to accomplish my goal. Reference links: -SUPERSIZED API So, I have the following script: <script type="text/javascript"> $(document.body).ready(function () { if (vars.current_slide == 5){**-I want it to display a div if the slider is the number 5-** } }); </script> My questions are these: 1) What do I add in the - - area to display a div that only shows up when the slider is at the 5th slide? 2) Am I doing the rest right or am I missing something? I created that code so it could be terribly wrong lol, hopefuly I got something right :P That's all, hope this clarifies it. Thank you all for the help! I'm really excited to start creating my own scripts :D Alright, so I've uploaded the site with the code you posted and it still doesn't seem to work, I also tried reducing the code to the conditional and the result only but that didn't work either, mind checking it out? Click Here Thanks for giving it a thought!

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  • jQuery only firing last class in multiple-class click

    - by user1134644
    I have a set of links like so: <a href="#internalLink1" class="classA">This has Class A</a> <a href="#internalLink2" class="classB">This has Class B</a> <a href="#internalLink3" class="classA classB">This has Class A and Class B</a> And here's the corresponding jQuery: $('.classA').click(function(){ // do class A stuff }); $('.classB').click(function(){ // do class B stuff }); Currently, when I click on the first link with Class A, it does the Class A stuff like it's supposed to. Similarly, when I click on the second link with Class B, it does the Class B stuff like it's supposed to. No worries there. My issue is, when I click on the third link with BOTH classes, it only fires the function for whichever class comes last (in this case, class B. If I put class A at the end instead, it performs class A's function). I want it to fire both. What am I doing wrong? Thanks in advance. EDIT: To those posting fiddles, nearly all of them work, so as many have said, it's most likely not my code, but the way it displays in my file. For a little more clarification, I was teaching myself some jQuery and decided to try making a (very) simple "Choose Your Own Adventure" type game. Here's a jsfiddle containing the opening of my bare-bones-please-don't-laugh game. Click on "Hide in the bushes", then "Examine the victim", then "Take any valuables and leave, he's dead already" <-- THIS is where the issue is. It's supposed to add 98 gold ("hawks") to your inventory, AND tell you that your alignment has shifted 1 point towards Chaotic. At the moment, it only does the chaotic alert, and no gold gets added to your inventory. The other option (refresh the fiddle to restart) that adds money to your inventory, but DOES NOT make you chaotic, works just fine (if you select "Search him for identification" instead of "take the money and run") Sorry this is so long!

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  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

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  • Using unions to simplify casts

    - by Steven Lu
    I realize that what I am trying to do isn't safe. But I am just doing some testing and image processing so my focus here is on speed. Right now this code gives me the corresponding bytes for a 32-bit pixel value type. struct Pixel { unsigned char b,g,r,a; }; I wanted to check if I have a pixel that is under a certain value (e.g. r, g, b <= 0x10). I figured I wanted to just conditional-test the bit-and of the bits of the pixel with 0x00E0E0E0 (I could have wrong endianness here) to get the dark pixels. Rather than using this ugly mess (*((uint32_t*)&pixel)) to get the 32-bit unsigned int value, i figured there should be a way for me to set it up so I can just use pixel.i, while keeping the ability to reference the green byte using pixel.g. Can I do this? This won't work: struct Pixel { unsigned char b,g,r,a; }; union Pixel_u { Pixel p; uint32_t bits; }; I would need to edit my existing code to say pixel.p.g to get the green color byte. Same happens if I do this: union Pixel { unsigned char c[4]; uint32_t bits; }; This would work too but I still need to change everything to index into c, which is a bit ugly but I can make it work with a macro if i really needed to.

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  • find a duplicate series in SQL

    - by SomeMiscGuy
    I have a table with 3 columns containing a variable number of records based off of the first column which is a foreign key. I am trying to determine if I can detect when there is a duplicate across multiple rows for an entire series declare @finddupseries table ( portid int, asset_id int, allocation float ) ; INSERT INTO @finddupseries SELECT 250, 6, 0.05 UNION ALL SELECT 250, 66, 0.8 UNION ALL SELECT 250, 2, 0.105 UNION ALL SELECT 250, 4, 0.0225 UNION ALL SELECT 250, 5, 0.0225 UNION ALL SELECT 251, 13, 0.6 UNION ALL SELECT 251, 2, 0.3 UNION ALL SELECT 251, 5, 0.1 UNION ALL SELECT 252, 13, 0.8 UNION ALL SELECT 252, 2, 0.15 UNION ALL SELECT 252, 5, 0.05 UNION ALL SELECT 253, 13, 0.4 UNION ALL SELECT 253, 2, 0.45 UNION ALL SELECT 253, 5, 0.15 UNION ALL SELECT 254, 6, 0.05 UNION ALL SELECT 254, 66, 0.8 UNION ALL SELECT 254, 2, 0.105 UNION ALL SELECT 254, 4, 0.0225 UNION ALL SELECT 254, 5, 0.0225 select * from @finddupseries The records for portid 250 and 254 match. Is there any way I can write a query to detect this? edit: yes, the entire series must match. Also, if there was a way to determine which one it DID match would be helpful as the actual table has around 10k records. thanks!

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  • PHP | Online Notepad

    - by user2947423
    I recently made a Chat application in Visual Basic using PHP. I used this code: <?php $msg = $_GET['w']; $logfile= 'Chats.php'; $fp = fopen($logfile, "a"); fwrite($fp, $msg); fclose($fp); ?> I'm now trying to make a Online Notepad. What i want to do is in Visual Basic create a unique ID. That unique ID, has to be his filename. I'm not very good with PHP so what i want to know is: I want the unique ID to be the filename of the "Note". Like: $logfile= '{uniqueID.php}'; Whenever the user opens the program, it'll open his uniqueID.php file and he can edit that in my program. Long Story Short (TL;DR) Program generates uniqueID uniqueID is going to be a new file; {uniqueID}.php On next open it will check if {uniqueID}.php of him/her exists else it will make a new one. I know this isn't really secure but it's to learn something for myself.

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  • JAR file: Could not find main class

    - by ApertureT3CH
    Okay, I have a strange problem. I wanted to run one of my programs as a .jar file, but when I open it by double-clicking it, I get an error message like "Could not find main class, program is shutting down". I'm pretty sure I did everything right, the jar should work afaik. I also tried other programs, it's the same with every single one. (I'm creating the .jar's through BlueJ) There is no problem when I run them through a .bat . And here comes the strangest thing of all: The .jar's have worked some time ago (one or two months I guess), and I don't remember doing anything different. It's the same BlueJ-Version. Okay, maybe Java updated and something got messed up... I googled, but I couldn't find a solution. (some people seem to have a similar problem, and it seems to be only them who can't run their .jar's; they uploaded them and other people say the .jar's run fine.) What could be the problem? How can I solve it? I'd really appreciate some help here. Thank you :) ApertureT3CH EDIT: okay guys, you're making me unsure here. Imma check the manifest again, at this unholy time ( 1:34 am ) :P EDIT2: This is my MANIFEST.MF Manifest-Version: 1.0 Class-Path: Main-Class: LocalChatClientGUI [empty line] [empty line] The Main class is correct. EDIT3: Thanks to hgrey: There is nothing wrong with the jar. I can run it from a bat file, which actually should not be different from double-clicking the jar, right? Yet I get the error when clicking it, and it works fine through the bat. EDIT4: I finally solved the problem. I re-installed the JRE and now it works, although I can't see any version differences. Thanks to everyone!

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • innerText/textContent vs. retrieving each text node

    - by J-P
    I've heard that using el.innerText||el.textContent can yield unreliable results, and that's why I've always insisted on using the following function in the past: function getText(node) { if (node.nodeType === 3) { return node.data; } var txt = ''; if (node = node.firstChild) do { txt += getText(node); } while (node = node.nextSibling); return txt; } This function goes through all nodes within an element and gathers the text of all text nodes, and text within descendants: E.g. <div id="x">foo <em>foo...</em> foo</div> Result: getText(document.getElementById('x')); // => "foo foo... foo" I'm quite sure there are issues with using innerText and textContent, but I've not been able to find a definitive list anywhere and I am starting to wonder if it's just hearsay. Can anyone offer any information about the possibly lacking reliability of textContent/innerText? EDIT: Found this great answer by Kangax -- http://stackoverflow.com/questions/1359469/innertext-works-in-ie-but-not-in-firefox/1359822#1359822

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  • How to document an existing small web site (web application), inside and out?

    - by Ricket
    We have a "web application" which has been developed over the past 7 months. The problem is, it was not really documented. The requirements consisted of a small bulleted list from the initial meeting 7 months ago (it's more of a "goals" statement than software requirements). It has collected a number of features which stemmed from small verbal or chat discussions. The developer is leaving very soon. He wrote the entire thing himself and he knows all of the quirks and underlying rules to each page, but nobody else really knows much more than the user interface side of it; which of course is the easy part, as it's made to be intuitive to the user. But if someone needs to repair or add a feature to it, the entire thing is a black box. The code has some minimal comments, and of course the good thing about web applications is that the address bar points you in the right direction towards fixing a problem or upgrading a page. But how should the developer go about documenting this web application? He is a bit lost as far as where to begin. As developers, how do you completely document your web applications for other developers, maintainers, and administrative-level users? What approach do you use, where do you start, do you have a template? An idea of magnitude: it uses PHP, MySQL and jQuery. It has about 20-30 main (frontend) files, along with about 15 included files and a couple folders of some assets. So overall it's a pretty small application. It interfaces with 7 MySQL tables, each one well-named, so I think the database end is pretty self-explanatory. There is a config.inc.php file with definitions of consts like the MySQL user details, some from/to emails, and URLs which PHP uses to insert into emails and pages (relative and absolute paths, basiecally). There is some AJAX via jQuery. Please comment if there is any other information that would help you help me and I will be glad to edit it in.

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  • How can I call a function in a parent movieclip from an externally-loaded child?

    - by Doug Wolfgram
    I have a swf file that is my 'shell' program that contains many functions. This shell program loads child movies. In the root timeline of the child movie, I have the following code: function putresponse(q,r) { trace (r); _root.debug(r); } _root.debug("foo"); Debug is a function that writes some text to the screen. When I run this locally, the putresponse function gets called and the trace happens. When I run it remotely (inside the shell) the first debug happens immediately on load (as you'd expect) but then later when putresponse is called, the debug(r) is not executed. The external clip is at the same url as the shell so I don't think it is a security issue. Also, as I said, the debug("foo") works fine. This one really has me perplexed. Can anyone shed some light as to why I can't call the debug from _root when called from a function rather than on the first-level timeline? EDIT: The call to putresponse is coming form two layers deep in local (within the child MC) MCs. The actual call is: _parent._parent.putrepsonse(q,r);

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  • Processor, OS : 32bit, 64 bit

    - by Sandbox
    I am new to programming and come from a non-CS background (no formal degree). I mostly program winforms using C#. I am confused about 32 bit and 64 bit.... I mean, have heard about 32 bit OS, 32 bit processor and based on which a program can have maximum memory. How it affects the speed of a program. There are lot more questions which keep coming to mind. I tried to go through some Computer Organization and Architecture books. But, either I am too dumb to understand what is written in there or the writers assume that the reader has some CS background. Can someone explain me these things in a plain simple English or point me to something which does that. EDIT: I have read things like In 32-bit mode, they can access up to 4GB memory; in 64-bit mode, they can access much much more....I want to know WHY to all such things. BOUNTY: Answers below are really good....esp one by Martin. But, I am looking at a thorough explanation, but in plain simple English.

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  • PHP delete script, return to 'viewsubjects.php?classroom_id=NO VALUE'

    - by Derek
    Hi, As the title states... I am deleting a 'subject' from a 'classroom' I view classrooms, then can click on a classroom to view the subject for that classroom. So the link where I am viewing subjects looks like: viewsubjects.php?classroom=23 When the user selects the delete button (in a row) to remove a subject from a class, I simply want the user to be redirected back to the list of subjects for the classroom (exactly where they were before!!) So I though this is simply a case of calling up the classroom ID within my delete script. Here is what I have: EDIT: corrected spelling mistake in code (this was not the problem) $subject_id = $_GET['subject_id']; $classroom_id = $_GET['classroom_id']; $sql = "DELETE FROM subjects WHERE subject_id=".$subject_id; $result = mysql_query($sql, $connection) or die("MySQL Error: ".mysql_error()); header("Location: viewsubjects.php?classroom_id=".$classroom_id); exit(); The subject is being removed from the DB, but when I am redirected back the URI is displaying with an empty classroom ID like: viewsubjects.php?classroom_id= Is there a way to carry the classroom ID through successfully through the delete script so it can be displayed after, allowing the user to be redirected back to the page? Thanks for any help!

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  • Dependency Injection: How to pass DB around?

    - by Stephane
    Edit: This is a conceptual question first and foremost. I can make applications work without knowing this, but I'm trying to learn the concept. I've seen lots of videos with related classes and that makes sense, but when it comes to classes wrapping around other classes, I can't seem to grasp where things should be instantiated/passed around. =-=-=-=-=-=-= Question: Let's say I have a simple page that loads data from a table, manipulates the result and displays it. Simple. I'm going to use '=' for instantiating a class and '-' for passing a class in using constructor injection. It seems to me that the database has to be passed from one end of the application to the other which doesn't seem right. Here's how I would do it if I wanted to separate concerns: index =>Controller =>Model Layer =>Database =>DAO->Database I have this rule in my head that says I'm not supposed to create objects inside other objects. So what do I do with the Database? Or even the Model for that matter? I'm obviously missing something so basic about this. I would love a simplified example so that I can move forward in my code. I feel really hamstrung by this.

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