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  • Windows server 2008 R2 IIS7 file permissions

    - by StealthRT
    Hey all i am trying to figure out why i can not access a index.php file from within the wwwroot/mollify/backend directory. It keeps coming up with this: Server Error 403 - Forbidden: Access is denied. You do not have permission to view this directory or page using the credentials that you supplied. I've given all the permissions (Full control) to the wwwroot directory i could think of (IUSR, Guest, GUESTS, IIS_IUSRS, Users, Administrators, NETWORK, NETWORK SERVICE, SYSTEM, CREATOR OWNER & Everyone). I also added index.php to the "Default Document" under my website settings in IIS 7 manager. What else am i missing? Thanks! David

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  • Biztalk Flat File Schema - how to accept a LF or CRLF as the line delimiter

    - by FullOfQuestions
    Hi, Our client sends us a flat file as input, which we then take and convert to an XML file before sending to the destination system. The flat file consists of multiple lines, each line is delimited by LF or CRLF. How do I create a Flat File Schema so that Biztalk can interpret each line of data regardless of whether the line was delimited by LF (0x0A) or CRLF (0x0D 0x0A)? Thank you in advance, M

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  • Python: Why can't I use `super` on a class?

    - by cool-RR
    Why can't I use super to get a method of a class's superclass? Example: Python 3.1.3 >>> class A(object): ... def my_method(self): pass >>> class B(A): ... def my_method(self): pass >>> super(B).my_method Traceback (most recent call last): File "<pyshell#2>", line 1, in <module> super(B).my_method AttributeError: 'super' object has no attribute 'my_method' (Of course this is a trivial case where I could just do A.my_method, but I needed this for a case of diamond-inheritance.) According to super's documentation, it seems like what I want should be possible. This is super's documentation: (Emphasis mine) super() - same as super(__class__, <first argument>) super(type) - unbound super object super(type, obj) - bound super object; requires isinstance(obj, type) super(type, type2) - bound super object; requires issubclass(type2, type) [non-relevant examples redacted]

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  • .bat file overriding answer

    - by John Peters
    When I made this batch file, when typing y and n for the first time it works fine, but as soon as I choose n, every single time I try inputting something, it opens up the 7000 songs wpl list then closes it and replaces it with Rick Astley... HELP! @echo off :Ask echo Would you like to listen to the best songs out of the 7000 I have?(Y/N) set INPUT= set /P INPUT=Type input: %=% If /I "%INPUT%"=="y" goto yes If /I "%INPUT%"=="n" goto lolno echo Incorrect input & goto Ask :yes start c:/Users/MyName/Music/Playlists/"The Best of the 7000 songs that I have.wpl" :lolno start c:/Users/MyName/Music/Downloads/Music/"Various Artists"/"The Number One 80's Album Disc 2"/"06 Never Gonna Give You Up.mp3"

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  • What to use as a file server with a web interface and user management on MAMP

    - by Timo
    I want to set up file/photo sharing for a largish group of friends and family. Flickr, Picasa etc. are not optimal solutions because setting up accounts, sharing albums and navigating privacy settings is going to be overwhelming for some of the people. I just want to be able to give people a URL, a username, and password and have it be easy peasy. I want something very simple and easy to use (for the user) like MyTunesRSS. I've looked at a complete "social" solution like Elgg but that feels like using a cadillac to kill a fly. I only need: User management Simple upload / download of files Plug-into-MAMP ease of setup is a bonus Search / metadata / tags / commenting not necessary but also earns bonus points Free / cheap licence What would you recommend?

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  • How to get the file name for <input type="file" in jsp

    - by deepthinker121
    I want to read the file path from html input type="file" (the entry selected in the file dialog by the user) <script> function OpenFileDialog(form) { var a = document.getElementById("inputfile").click(); SampleForm.filePath.value = //set the path here document.SampleForm.submit(); } </script> <form name="SampleForm" action="TestServlet" method="get"> <input type="file" style="display:none;" id="inputfile"/> <a href="javascript:OpenFileDialog(this.form);">Open here</a> <input type="hidden" name="filePath" value=""/> </form> I want the path of the selected file to be read in my Servlet class How do I get the file path? Can I read it from var a? Or is there any way to directly access the file path from the input type="file" from my servlet?

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  • Download file popup in IE not working it works well in Fire Fox

    - by Yogesh
    Hi window.location.href, using hidden Iframe and setting its source dynamically, setting return false; for onclick Nothing is working for IE. Basically, my dwr response generates a log file (foo.log) @business layer and it sends file name as response to dwr rpc request. Now I know the file name and its location I just want to download that file.(It works in FF not in IE).

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  • How to Read Java File Structure using Java?

    - by Iso
    Hi, I'm trying to read a java file and display in console the package, class and method name. something like this: File: Test.java package tspec.test; public class Test { public void addTest () {} public void deleteTest () {} } Output: package name: tspec.test class name: Test method name: addTest deleteTest Thanks in advance :)

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  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

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  • Windows redirect traffic to different DNS name not fixed IP address (hosts file equivalent)

    - by Arik Raffael Funke
    Using the Windows hosts file, one can redirect traffic for a domain to a specific IP address, e.g. domainA.com -- 127.0.0.1 I am looking for a SIMPLE way to do the same, but for a target domain name not for a target IP address (as this is dynamic), I.e. domainA.com -- domainB.com Addition: After the getting some initial answers I think I need to concretise my question. Situation: I have an application which looks up the IP of the target domain via DNS and then connects via HTTP to the IP address. I do not have control over any proxy settings. Option 1 Basically I am looking for a way to: intercept DNS requests for a domainA.com launch a DNS request for a domainB.com serve the IP of domainB.com in response to the request for domainA.com Without running an entire DNS server. Option 2 If a DNS server is the only way, in the alternative I would also be happy with an solution to how to define a non-standard DNS-server for a single application. Any ideas for wrapper applications, etc?

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  • How to repair a broken .EXE file association

    - by Pointy
    After (hopefully) scrubbing viruses out of a Windows 7 installation (after deciding not to simply run over the laptop repeatedly with my car), I've got everything almost back to normal. The only lingering issue I have is that for my non-admin users, the ".exe" file extension doesn't work. That is, clicking on the various desktop application links results in a "How do you want to open this?" dialog. I've been through the alleged registry fixing from "winhelponline" and that had absolutely no effect. I've tried running "assoc" for the affected users, but it reports the .exe association to be "exefile" even though it persistently does not work. Right-clicking on a desktop icon and then choosing "start" does successfully open an application, but that's clearly a terrible situation. For my admin user, things seem to work fine. What do I need to do to get things working?

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  • How do I create a list or set object in a class in Python?

    - by Az
    For my project, the role of the Lecturer (defined as a class) is to offer projects to students. Project itself is also a class. I have some global dictionaries, keyed by the unique numeric id's for lecturers and projects that map to objects. Thus for the "lecturers" dictionary (currently): lecturer[id] = Lecturer(lec_name, lec_id, max_students) I'm currently reading in a white-space delimited text file that has been generated from a database. I have no direct access to the database so I haven't much say on how the file is formatted. Here's a fictionalised snippet that shows how the text file is structured. Please pardon the cheesiness. 0001 001 "Miyamoto, S." "Even Newer Super Mario Bros" 0002 001 "Miyamoto, S." "Legend of Zelda: Skies of Hyrule" 0003 002 "Molyneux, P." "Project Milo" 0004 002 "Molyneux, P." "Fable III" 0005 003 "Blow, J." "Ponytail" The structure of each line is basically proj_id, lec_id, lec_name, proj_name. Now, I'm currently reading the relevant data into the relevant objects. Thus, proj_id is stored in class Project whereas lec_name is a class Lecturer object, et al. The Lecturer and Project classes are not currently related. However, as I read in each line from the text file, for that line, I wish to read in the project offered by the lecturer into the Lecturer class; I'm already reading the proj_id into the Project class. I'd like to create an object in Lecturer called offered_proj which should be a set or list of the projects offered by that lecturer. Thus whenever, for a line, I read in a new project under the same lec_id, offered_proj will be updated with that project. If I wanted to get display a list of projects offered by a lecturer I'd ideally just want to use print lecturers[lec_id].offered_proj. My Python isn't great and I'd appreciate it if someone could show me a way to do that. I'm not sure if it's better as a set or a list, as well. Update After the advice from Alex Martelli and Oddthinking I went back and made some changes and tried to print the results. Here's the code snippet: for line in csv_file: proj_id = int(line[0]) lec_id = int(line[1]) lec_name = line[2] proj_name = line[3] projects[proj_id] = Project(proj_id, proj_name) lecturers[lec_id] = Lecturer(lec_id, lec_name) if lec_id in lecturers.keys(): lecturers[lec_id].offered_proj.add(proj_id) print lec_id, lecturers[lec_id].offered_proj The print lecturers[lec_id].offered_proj line prints the following output: 001 set([0001]) 001 set([0002]) 002 set([0003]) 002 set([0004]) 003 set([0005]) It basically feels like the set is being over-written or somesuch. So if I try to print for a specific lecturer print lec_id, lecturers[001].offered_proj all I get is the last the proj_id that has been read in.

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  • File and Printer Sharing Port issue in Windows 7 64 bit

    - by Mohit
    So, This is totally weird and I could not find any way to fix it. In simple words after the diagnosis this what is happening. On a windows 7 64 bit box, Whenever I am trying to access a server using file share. It is trying to connect to port 80 http on the place of 445. I observed that using WireShark. Telnet to 445 works. Any clue how to fix this. Scanned the machine using Malware bytes, Symantec and MS live essentials . I dont want to recreate the whole machine again. Please help me here. Regards Mohit Thakral

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  • Which should be created first ER Diagram OR Class Diagram?

    - by isthatacode
    The very first step i created a DFD. Then i moved on to create a Class Diagram. And while doing that i felt that i should create the ER diagram first. As there were many details which could not be captured in a Class diagram. So, my question should i create ERD first OR Class Diagrams ? your valuable inputs are appreciated guys!!! thanks for reading

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  • Who owns a php exec tar extracted file?

    - by Ken
    As far as file permissions are concerned, when you use a php script to unzip a tar file, who is the "owner" user of the files created? I'm wondering if its my ftp user because I uploaded the script file? Or does apache own the file? I know their are flags to be set to preserve the original permissions which I don't want (files where created and archived by someone else). I want my user to be the creater/owner of the files.

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  • Accessing constructor from abstract base class with reflection

    - by craesh
    Hi! I'm playing around with Java's Reflection. I have an abstract class Base with a constructor. abstract class Base { public Base( String foo ) { // do some magic } } I have some further classes extending Base. They don't contain much logic. I want to instantiate them with Base's constructor, without having to write some proxy contructors in those derived classes. And of course, I want to instantiate those derived classes with Reflection. Say: Class cls = SomeDerivedClass.class; Constructor constr; constr = cls.getConstructor( new Class[] { String.class } ); // will return null Class clsBase = Base.class; constr = clsBase.getConstructor( new Class[] { String.class } ); // ok Base obj = (Base) constr.newInstance( new Object[] { "foo" } ); // will throw InstantiationException because it belongs to an abstract class Any ideas, how I can instantiate a derived class with Base's constructor? Or must I declare those dumb proxy constructors?

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  • OS X Snow Leopard, change file permissions on copy

    - by Francesco K
    I work with OS X, Snow Leopard and need to allow users to make copies of files (templates) located in a read-only repository for subsequent editing. The repository is located on a separate physical drive mounted to the OS X boot volume. As this is a shared computer in a school environment, all users access the machine via a single login ("user_local"). Whether using POSIX permissions or ACLs, the use case requires the file permissions to change from "read" to "read write" as they get copied to the "user_local" home directory. Googling around has not yielded anything that would indicate that this is possible via the Snow Leopard permission system. Question 1: Is this in fact possible via the permission system? If so, how? Question 2: If not possible, how would one go about solving this problem? I imagine this to be a fairly common use case so there must be a workable solution for it out there. Thanks.

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  • Can can I reference extended methods/params without having to cast from the base class object return

    - by Greg
    Hi, Is there away to not have a "cast" the top.First().Value() return to "Node", but rather have it automatically assume this (as opposed to NodeBase), so I then see extended attributes for the class I define in Node? That is is there a way to say: top.Nodes.First().Value.Path; as opposed to now having to go: ((Node)top.Nodes.First().Value).Path) thanks [TestMethod()] public void CreateNoteTest() { var top = new Topology(); Node node = top.CreateNode("a"); node.Path = "testpath"; Assert.AreEqual("testpath", ((Node)top.Nodes.First().Value).Path); // *** HERE *** } class Topology : TopologyBase<string, Node, Relationship> { } class Node : NodeBase<string> { public string Path { get; set; } } public class NodeBase<T> { public T Key { get; set; } public NodeBase() { } public NodeBase(T key) { Key = key; } } public class TopologyBase<TKey, TNode, TRelationship> where TNode : NodeBase<TKey>, new() where TRelationship : RelationshipBase<TKey>, new() { // Properties public Dictionary<TKey, NodeBase<TKey>> Nodes { get; private set; } public List<RelationshipBase<TKey>> Relationships { get; private set; } }

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  • VSFTPD uploaded file permissions

    - by Katafalkas
    Let me first say that there are loads of topics regarding this, and I am sure i have seen them all by now. Still non of the solutions seem to help. I installed vsftpd. created a user ftp-data. Now I need that files uploaded by user ftp-data would have 755 permissions. Solving this should be as easy as adding: local_umask=002 file_open_mode=0755 but that did not help, then I have tried a number of variations of this, still did not help. The I added: chmod_enable=YES still did not help. At the moment I think that I am missing something very simple and obvious, just cant find it. Maybe someone could help me to find what I am missing. This is my config file: anonymous_enable=NO local_enable=YES write_enable=YES local_umask=002 anon_upload_enable=NO anon_mkdir_write_enable=NO dirmessage_enable=NO xferlog_enable=YES connect_from_port_20=YES xferlog_file=/var/log/xferlog listen=YES local_root=/var/www/ftp-gallery pam_service_name=vsftpd userlist_enable=YES tcp_wrappers=YES

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  • downloaded zip file returns zero has 0 bytes as size

    - by Yaw Reuben
    I have written a Java web application that allows a user to download files from a server. These files are quite large and so are zipped together before download. It works like this: 1. The user gets a list of files that match his/her criteria 2. If the user likes a file and wants to download he/she selects it by checking a checkbox 3. The user then clicks "download" 4. The files are then zipped and stored on a server 5. The user this then presented with a page which contains a link to the downloadable zip file 6. However on downloading the zip file the file that is downloaded is 0 bytes in size I have checked the remote server and the zip file is being created properly, all that is left is to serve the file the user somehow, can you see where I might be going wrong, or suggest a better way to serve the zip file. The code that creates the link is: <% String zipFileURL = (String) request.getAttribute("zipFileURL"); %> <p><a href="<% out.print(zipFileURL); %> ">Zip File Link</a></p> The code that creates the zipFileURL variable is: public static String zipFiles(ArrayList<String> fileList, String contextRootPath) { //time-stamping Date date = new Date(); Timestamp timeStamp = new Timestamp(date.getTime()); Iterator fileListIterator = fileList.iterator(); String zipFileURL = ""; try { String ZIP_LOC = contextRootPath + "WEB-INF" + SEP + "TempZipFiles" + SEP; BufferedInputStream origin = null; zipFileURL = ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"; FileOutputStream dest = new FileOutputStream(ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"); ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream( dest)); // out.setMethod(ZipOutputStream.DEFLATED); byte data[] = new byte[BUFFER]; while(fileListIterator.hasNext()) { String fileName = (String) fileListIterator.next(); System.out.println("Adding: " + fileName); FileInputStream fi = new FileInputStream(fileName); origin = new BufferedInputStream(fi, BUFFER); ZipEntry entry = new ZipEntry(fileName); out.putNextEntry(entry); int count; while ((count = origin.read(data, 0, BUFFER)) != -1) { out.write(data, 0, count); } origin.close(); } out.close(); } catch (Exception e) { e.printStackTrace(); } return zipFileURL; }

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  • What am I not getting about this abstract class implementation?

    - by Schnapple
    PREFACE: I'm relatively inexperienced in C++ so this very well could be a Day 1 n00b question. I'm working on something whose long term goal is to be portable across multiple operating systems. I have the following files: Utilities.h #include <string> class Utilities { public: Utilities() { }; virtual ~Utilities() { }; virtual std::string ParseString(std::string const& RawString) = 0; }; UtilitiesWin.h (for the Windows class/implementation) #include <string> #include "Utilities.h" class UtilitiesWin : public Utilities { public: UtilitiesWin() { }; virtual ~UtilitiesWin() { }; virtual std::string ParseString(std::string const& RawString); }; UtilitiesWin.cpp #include <string> #include "UtilitiesWin.h" std::string UtilitiesWin::ParseString(std::string const& RawString) { // Magic happens here! // I'll put in a line of code to make it seem valid return ""; } So then elsewhere in my code I have this #include <string> #include "Utilities.h" void SomeProgram::SomeMethod() { Utilities *u = new Utilities(); StringData = u->ParseString(StringData); // StringData defined elsewhere } The compiler (Visual Studio 2008) is dying on the instance declaration c:\somepath\somecode.cpp(3) : error C2259: 'Utilities' : cannot instantiate abstract class due to following members: 'std::string Utilities::ParseString(const std::string &)' : is abstract c:\somepath\utilities.h(9) : see declaration of 'Utilities::ParseString' So in this case what I'm wanting to do is use the abstract class (Utilities) like an interface and have it know to go to the implemented version (UtilitiesWin). Obviously I'm doing something wrong but I'm not sure what. It occurs to me as I'm writing this that there's probably a crucial connection between the UtilitiesWin implementation of the Utilities abstract class that I've missed, but I'm not sure where. I mean, the following works #include <string> #include "UtilitiesWin.h" void SomeProgram::SomeMethod() { Utilities *u = new UtilitiesWin(); StringData = u->ParseString(StringData); // StringData defined elsewhere } but it means I'd have to conditionally go through the different versions later (i.e., UtilitiesMac(), UtilitiesLinux(), etc.) What have I missed here?

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  • Using Terminal Services 'query' in batch file

    - by dboarman-FissureStudios
    I have a batch file that checks several of our servers for a user. From the command: query user %userID% /server:ServerName I want to capture the output before it goes to the screen. Is there a way to redirect the output to a variable? The basic gist of what I want to accomplish is this - we iterate through our servers: query user %userID% /server:Server1 query user %userID% /server:Server2 query user %userID% /server:Server3 query user %userID% /server:Server4 Instead of outputting a message that the user could not be found on a specific server, I would like for it to only notify me if it finds the user on a server.

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  • linux/shell: change a file's modify timestamp relatively?

    - by index
    My Canon camera produces files like IMG_1234.JPG and MVI_1234.AVI. It also timestamps those files. Unfortunately during a trip to another timezone several cameras were used, one of which did not have the correct time zone set - meta data mess.. Now I would like to correct this. Proposed algorithm: 1 read file's modify date 2 add delta, i.e. hhmmss (preferred: change timezone) 3 write new timestamp Unless someone knows a tool or a combination of tools that do the trick directly, maybe one could simplify the calculation using epoch time (seconds since ..) and whip up a shell script. Any help appreciated!

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  • Python Introspection: How to get varnames of class methods?

    - by daccle
    I want to get the names of the keyword arguments of the methods of a class. I think I understood how to get the names of the methods and how to get the variable names of a specific method, but I don't get how to combine these: class A(object): def A1(self, test1=None): self.test1 = test1 def A2(self, test2=None): self.test2 = test2 def A3(self): pass def A4(self, test4=None, test5=None): self.test4 = test4 self.test5 = test5 a = A() # to get the names of the methods: for methodname in a.__class__.__dict__.keys(): print methodname # to get the variable names of a specific method: for varname in a.A1.__func__.__code__.co_varnames: print varname # I want to have something like this: for function in class: print function.name for varname in function: print varname # desired output: A1 self test1 A2 self test2 A3 self A4 self test4 test5

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