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  • Why index_merge is not used here using MySQL?

    - by user198729
    Setup: mysql> create table t(a integer unsigned,b integer unsigned); mysql> insert into t(a,b) values (1,2),(1,3),(2,4); mysql> create index i_t_a on t(a); mysql> create index i_t_b on t(b); mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 3 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Is there something I'm missing? Update mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 1863 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Version: mysql> select version(); +----------------------+ | version() | +----------------------+ | 5.1.36-community-log | +----------------------+

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  • How are deleted and renamed/moved files handled when merging a feature branch with trunk and reinteg

    - by Michael Repucci
    I've got a big-ish project that needs a lot of work on a new feature, so I planned on using a branch to do this work. I haven't had to do this before, and I just wanted to get assurance from an experienced Subversion user that things "should" work smoothly. What I'm especially concerned with is how well Subversion handles deleted, renamed/moved files between a branch and the trunk. That is, if multiple files are deleted or renamed/moved in the branch, but those files continue to be used and receive changes in the trunk, will merges with the trunk still proceed without a hitch (reworking the branch, of course, as necessary)? Also, when I then reintegrate the branch with the trunk, if the files differ greatly in name (or existence) between the trunk and branch, will the reintegration be difficult? Will the files deleted (moved) in the branch now be deleted (moved) in the trunk, or will files linger and conflicts emerge? The SVN book didn't clear up these questions for me, so your experience would be greatly appreciated. Thank you!

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  • Simplifying and reducing the cost of an anti-join query

    - by Savitha
    Hi, Could you please help me in simplifying and reducing the cost of the below query? I tried making it a co-related subquery with NOT EXISTS but it didn't give me any output. Please note that the table in both main and inner query is the same 'table_1". SELECT * FROM Table_1 A WHERE A.Col1 = 'abcd' AND (A.Col2, A.Col3) NOT IN (SELECT Col2, Col3 FROM Table_1 B WHERE (B.Col4 IN (1,2,3) And B.Col5 In ('x','y')) OR (B.Col4 = 1 AND B.Col5 = 'z' AND B.Col6 = 'f') )) Thanks in advance, Savitha

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  • How can I match a partial data set with a full one in a spreadsheet?

    - by askvictor
    I have a spreadsheet (in Google Docs, but can be any spreadsheet) with a list of users (one per row), including a username (and other columns). Lets say there are 'n' rows. I have another spreadsheet with less than 'n' rows. One column has a username, another column has some other piece of data (lets say car rego number). I want to move the car rego number to the corresponding user in the first spreadsheet. How might I do this?

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  • PHP: Filling in the 'gaps' in an array

    - by aboved
    Hey gurus, I've got a php array (obtained through checkbox values in a form - as you know checkboxes only show up in the _POST variable when they are not set). Array ( [2] => 0,2 [3] => 0,3 ) I need a way to 'fill in' the gaps between the range 0-5. So above would look like (filling the empty spaces with '-1'. I tried array_merge() with an array filled with '-1' but that didn't work. Array ( [0] => -1 [2] => 0,2 [3] => 0,3 [4] => -1 [5] => -1 ) I think I may have gone down the wrong road with the problem I am trying to solve, but I have put too much time into this solution to back out - a feeling I am sure most of you are familiar with(!) Cheers!

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  • How to reference other documents in a couchDB view (joining like functionality)

    - by Surfrdan
    We have a CouchDB representation of an XML database which we use to power a javascript based frontend for manipulating the XML documents. The basic structure is a simple 3 level hierachy. i.e. A - B - C A: Parent doucument (type A) B: any number of child documents of parent type A C: any number of child documents of parent type B We represent these 3 document types in CouchDB with a 'type' attribute: e.g. { "_id":"llgc-id:433", "_rev":"1-3760f3e01d7752a7508b047e0d094301", "type":"A", "label":"Top Level A document", "logicalMap":{ "issues":{ "1":{ "URL":"http://hdl.handle.net/10107/434-0", "FILE":"llgc-id:434" }, "2":{ "URL":"http://hdl.handle.net/10107/467-0", "FILE":"llgc-id:467" etc... } } } } { "_id":"llgc-id:433", "_rev":"1-3760f3e01d7752a7508b047e0d094301", "type":"B", "label":"a B document", } What I want to do is produce a view which returns documents just like the A type but includes the label attribute from the B document within the logicalMap list e.g. { "_id":"llgc-id:433", "_rev":"1-3760f3e01d7752a7508b047e0d094301", "type":"A", "label":"Top Level A document", "logicalMap":{ "issues":{ "1":{ "URL":"http://hdl.handle.net/10107/434-0", "FILE":"llgc-id:434", "LABEL":"a B document" }, "2":{ "URL":"http://hdl.handle.net/10107/467-0", "FILE":"llgc-id:467", "LABEL":"another B document" etc... } } } } I'm struggling to get my head around the best way to perform this. It looks like it should be fairly simple though!

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  • Git branch unknown to local clone

    - by Rimian
    I have a git repository with two branches. If I clone my repo I can only see the master branch. I have both branches up to date. The problem is I don't fully understand merging and branching. Darn it! My example can be seen here: http://github.com/rimian/rimian/network Can anyone tell me how to get this back to normal?

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  • array_merge vs array_value for resetting array index

    - by Jamex
    I have 1 array that I want to re-index. I have found that both array_values and array_merge functions can do the job (and I don't need 2 arrays for the array_merge function to work). Which is faster for a very large array? I would benchmark this, but I don't know how and don't have the large array yet. Before re-index: Array ( [0] => AB [4] => EA [6] => FA [9] => DA [10] => AF ) After re-index: Array ( [0] => AB [1] => EA [2] => FA [3] => DA [4] => AF )

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  • How to display two ObservableCollections as a single list in WPF?

    - by nareshbhatia
    I have two ObservableCollections, say ObservableCollection<Cat> and ObservableCollections<Dog>. Cat and Dog both derive from class Pet. I want to display a list of all Pets. How do I do this? I prefer not want create a new ObservableCollection<Pet> by adding items from the two source lists because this list will become stale as more Cats and Dogs are added to the source lists. I can think of two approaches: 1) Create a "Decorator" ObservableCollection that keeps the two source collections as members and iterates over them every time. 2) Create an ObservableCollection<Pet> that does have the combined elements of the two source collections, but is also dependent on the source collections. Thus if a Cat is added to the Cat collection, this collection is notified and it adds the new Cat to itself. Is there a standard way to solve this issue? I don't want to reinvent the wheel!

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  • Rails advanced queries with join and sum calculation

    - by Dustin Brewer
    I have two models: companies and expenses. Companies have many expenses and expenses belong to companies. My expense model has an 'amount' column. I was wondering if there is a way to perform a find based on a date range and the amount column of the expenses. Something like top 3 companies by total expense amounts over a 7 day period. I've tried for the better part of the day to get this to work, I've attempted joins, chaining named scopes, raw sql, etc. and I'm not having any luck. Thanks for the help.

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  • MYSQL - SELECT ALL FROM TABLE if...

    - by hornetbzz
    Hello I have a (nice) mysql table built like this : Fields Datas id (pk) 1 2 3 4 5 6 master_id 1000 1000 1000 2000 2000 2000 ... master_name home home home shop shop shop ... type_data value common client value common client ... param_a foo_a 1 0 bar_a 0 1 ... param_b foo_b 1 0 bar_b 1 0 ... param_c foo_c 0 1 bar_c 0 1 ... ... ... ... ... ... ... ... ... All these datas are embed in a single table. Each datas are dispatched on 3 "columns" set (1 for the values, 1 for identifying if these are common values and one for identifying client values). It's not the best I got but many other scripts depends on this structure. I'd need sthg like this: SELECT parameters name (eg param_a, param_b..) and their values (eg foo_a, foo_b..) WHEN master_id=? AND type_data=(common or client) (eg for values=1 on the 2nd column) . in order to get the parameters hash like param_a => foo_a param_b => foo_b param_c => foo_c ... I could not succeed in self joining on the same table till now but I guess it should be feasible. (I'd like to avoid to do several queries) Thx in advance

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  • Oracle Procedure to join two tables with latest status

    - by Sony
    Please help me make an oracle stored procedure ; I have two tables tblLead: lead_id Name 1 x 2 y 3 z tblTransaction: Tran_id lead_id date status 1 1 04/20/2010 call Later 2 1 05/05/2010 confirmed I want a result like lead_id Name status 1 x confirmed 2 y not available ! 3 z not available !

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  • SQL join to grab data from same table via intermediate table

    - by Sergio
    Hi Could someone help me with building the following query. I have a table called Sites, and one called Site_H. The two are joined by a foreign key relationship on page_id. So the Sites table contains pages, and the Site_H table shows which pages any given page is a child of by having another foreign key relation back to the site table with a column called ParentOf. So, a page can be have another page as a parent. Other data is stored in the Site_H table such as position etc, hence why it is separated out. I would like a query that returns the details of a page along with the details of its parent page. I just cant quite think about how to structure the SQL. Thanks

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  • Get records using left outer join

    - by Devendra Gohil
    I have two tables as given below Table A Table B Table C ============= ============== ========= Id Name Id AId CId Id Name 1 A 1 1 1 1 x 2 B 2 1 1 2 y 3 C 3 2 1 3 z 4 D 4 2 3 4 w 5 E 5 3 2 5 v Now I want all the records of Table A with matching Id column CId from Table B where CId = 1. So the output should be like below : Id Name CId 1 A 1 2 B 1 3 C 1 4 D Null 5 E Null Can anyone help me please?

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  • Help with grasping (INNER?) JOIN

    - by Greenie
    I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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  • c# linq to sql join problem

    - by b0x0rz
    i am trying to do using (UserManagementDataContext context = new UserManagementDataContext()) { var users = from u in context.Users where u.UserEMailAdresses.EMailAddress == "[email protected]" select u; return users.Count(); } however, when i get to: using (UserManagementDataContext context = new UserManagementDataContext()) { var users = from u in context.Users where u.UserEMailAdresses. i do not get offered the EMailAddress name, but rather some neutral default-looking list of options in intelisense. what am i doing wrong? table Users ID bigint NameTitle nvarchar(64) NameFirst nvarchar(64) NameMiddle nvarchar(64) NameLast nvarchar(64) NameSuffix nvarchar(64) Status bigint IsActive bit table UserEMailAddresses ID bigint UserID bigint EMailAddress nvarchar(256) IsPrimary bit IsActive bit obviously, 1 user can have many addresses and so Users.ID and UserEMailAddresses.UserID have a relationship between them: 1 to MANY.

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  • Mysql advanced SELECT, or multiple SELECTS? Movies keywords

    - by Supyxy
    I have a mysql database with movies as follows: MOVIES(id,title) KEYWORDS_TABLE(id,key_id) [id is referenced to movies.id, key_id is refernced to keywords.id] KEYWORDS(id,keyword) //this doesn't matter on my example.. Basically i have movies with their titles and plot keywords for each one, i want to select all movies that have the same keywords with with a given movie id. I tried something like: SELECT key_id FROM keywords_table WHERE id=9 doing that in php and storing all the IDs in an array $key_id.. then i build another select that looks like: SELECT movies.title FROM movies,keywords_table WHERE keywords_table.key_id=$key_id[1] OR keywords_table.key_id=$key_id[2] OR ......... OR keywords_table.key_id=$key_id[n] This kinda works but it takes too much time as we talk about a database with thousands of thousands of records. So, any suggestions?? thanks!

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  • Combining JSON Arrays

    - by George
    I have 3 json arrays, each with information listed in the same format: Array: ID: NAME: DATA: ID: NAME: DATA: etc... My goal is to combine all 3 arrays into one array, and sort and display by NAME by passing the 3 arrays into a function. The function I've tried is: JSCRIPT Call: // to save time I'm just passing the name of the array, I've tried passing // the full array name as json[0]['DATA'][array_1][0]['NAME'] as well. combineNames(['array_1','array_2']); FUNCTION: function combineNames(names) { var allNames = [] for (i=0;i<names.length;i++) { for (j=0;j<json[0]['DATA'][names[i]].length;j++) { allNames.push(json[0]['DATA'][names[i]][j]['NAME']); } } return allNames.sort(); } The above gives me the error that NAME is null or undefined. I've also tried using the array.concat function which works when I hard code it: var names = []; var allNames = []; var names = names.concat(json[0]['DATA']['array_1'],json[0]['DATA']['array_2']); for (i=0;i<names.length;i++) { allNames.push(names[i]['NAME']); } return allNames.sort(); But I can't figure out how to pass in the arrays into the function (and if possible I would like to just pass in the array name part instead of the whole json[0]['DATA']['array_name'] like I was trying to do in the first function...

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  • PHP: Join two separate mysql queries into the same json data object

    - by Dan
    I'm trying to mesh the below mysql query results into a single json object, but not quite sure how to do it properly. //return data $sql_result = mysql_query($sql,$connection) or die ("Fail."); $arr = array(); while($obj = mysql_fetch_object($sql_result)) { $arr[] = $obj; } echo json_encode($arr); //return json //plus the selected options $sql_result2 = mysql_query($sql2,$connection) or die ("Fail."); $arr2 = array(); while($obj2 = mysql_fetch_object($sql_result2)) { $arr2[] = $obj2; } echo json_encode($arr2); //return json Here's the current result: [{"po_number":"test","start_date":"1261116000","end_date":"1262239200","description":"test","taa_required":"0","account_overdue":"1","jobs_id":null,"job_number":null,"companies_id":"4","companies_name":"Primacore Inc."}][{"types_id":"37"},{"types_id":"4"}] Notice how the last section [{"types_id":"37"},{"types_id":"4"}] is placed into a separate chunk under root. I'm wanting it to be nested inside the first branch under a name like, "types". I think my question has more to do with Php array manipulation, but I'm not the best with that. Thank you for any guidance.

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  • What is a SQL statement that can tally up the counts even including the Zeros? (all in 1 statement)

    - by Jian Lin
    A SQL statement can give a list of the most popular gifts that are sent in a Social application, all the way to the ones that are sent 1, or 2 times, but it won't include the Zeros. I think the same goes for getting the list of the most popular Classes that students are registering for, when the registration process for all students is 10 days and now it is the 3rd day. Again, we get the count but the Zeros are not there. Is there a simple SQL statement that can show the whole list, including the zeros?

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  • rails include with options

    - by holden
    Is it possible to limit an AR :include to say only pull in one record... Item.find(:all, :include => [ :external_ratings, :photos => LIMIT 1 ]) I have a list of items and each item has between 5 and 15 photos. I want to load a photo id into memory, but i don't need all of them, I just want to preview the first one. Is there a way to do this?

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  • LINQ Join for Orderby only

    - by RandomBen
    I am trying to run this code: ItemTaxonomy iTaxonomy = from itemTaxonomy in connection.ItemTaxonomy where itemTaxonomy.Item.ID == itemView.ID orderby itemTaxonomy.Taxonomy.Name select itemTaxonomy; When I compiled it I get the error: Cannot implicitly convert type 'System.Linq.IOrderedQueryable<Website.Models.ItemTaxonomy>' to 'Website.Models.ItemTaxonomy'. An explicit conversion exists (are you missing a cast?) I believe the issue is with orderby itemTaxonomy.Taxonomy.Name but I am just trying to order by the name of Taxonomy items instead of their IDs. Is there a way to do that?

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  • Oracle (Old?) Joins

    - by Grasper
    I have been porting oracle selects, and I have been running across a lot of queries like so: SELECT e.last_name, d.department_name FROM employees e, departments d WHERE e.department_id(+) = d.department_id; ...and: SELECT last_name, d.department_id FROM employees e, departments d WHERE e.department_id = d.department_id(+); Are there any guides/tutorials for converting all of the variants of the (+) syntax? What is that syntax even called (so I can scour google)? When was this standard phased out? Any info is appreciated.

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  • Two entities with @ManyToOne should join the same table

    - by Ivan Yatskevich
    I have the following entities Student @Entity public class Student implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Teacher @Entity public class Teacher implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Task @Entity public class Task implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "student_id") }) private Student author; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "teacher_id") }) private Teacher curator; //getters and setters } Consider that author and curator are already stored in DB and both are in the attached state. I'm trying to persist my Task: Task task = new Task(); task.setAuthor(author); task.setCurator(curator); entityManager.persist(task); Hibernate executes the following SQL: insert into student_task (teacher_id, id) values (?, ?) which, of course, leads to null value in column "student_id" violates not-null constraint Can anyone explain this issue and possible ways to resolve it?

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  • SQL SELECT Join?

    - by SurfingCat
    Hello, i got a MySql DB. There is a table with products and orders. Structure: Products: product_id, name, manufacturers_id Orders: orders_id, product_id, quantitiy Now I want to get all orders (show only products where product id=1). I tried: SELECT orders.orders_id, orders.product_od FROM products, orders WHERE products.manufacturers_id = 1 GROUP BY orders_id ORDER BY orders_id But this doesnt work

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