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  • 2012 Independent Oracle Users Group Survey: Closing the Security Gap

    - by jgelhaus
    What Security Gaps Do You Have? The latest survey report from the Independent Oracle Users Group (IOUG) uncovers trends in IT security among IOUG members and offers recommendations for securing data stored in enterprise databases. According to the report, “despite growing threats and enterprise data security risks, organizations that do implement appropriate detective, preventive, and administrative controls are seeing significant results.” Download a free copy of the 2012 IOUG Data Security Survey Report and find out what your business can do to close the security gap. 

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  • Callback Contract in WCF

    Callback contracts are a very powerful concept that is easily implemented in WCF. Using this, it is very easy to achieve event-like behavior between a service and client (duplex operations).

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  • Using CTAS & Exchange Partition Replace IAS for Copying Partition on Exadata

    - by Bandari Huang
    Usage Scenario: Copy data&index from one partition to another partition in a partitioned table. Solution: Create a partition definition Copy data from one partition to another partiton by 'Insert as select (IAS)' Create a nonpartitioned table by 'Create table as select (CTAS)' Convert a nonpartitioned table into a partition of partitoned table by exchangng their data segments. Rebuild unusable index Exchange Partition Convertion Mutual convertion between a partition (or subpartition) and a nonpartitioned table Mutual convertion between a hash-partitioned table and a partition of a composite *-hash partitioned table Mutual convertiton a [range | list]-partitioned table into a partition of a composite *-[range | list] partitioned table. Exchange Partition Usage Scenario High-speed data loading of new, incremental data into an existing partitioned table in DW environment Exchanging old data partitions out of a partitioned table, the data is purged from the partitioned table without actually being deleted and can be archived separately Exchange Partition Syntax ALTER TABLE schema.table EXCHANGE [PARTITION|SUBPARTITION] [partition|subprtition] WITH TABLE schema.table [INCLUDE|EXCLUDING] INDEX [WITH|WITHOUT] VALIDATION UPDATE [INDEXES|GLOBAL INDEXES] INCLUDING | EXCLUDING INDEXES Specify INCLUDING INDEXES if you want local index partitions or subpartitions to be exchanged with the corresponding table index (for a nonpartitioned table) or local indexes (for a hash-partitioned table). Specify EXCLUDING INDEXES if you want all index partitions or subpartitions corresponding to the partition and all the regular indexes and index partitions on the exchanged table to be marked UNUSABLE. If you omit this clause, then the default is EXCLUDING INDEXES. WITH | WITHOUT VALIDATION Specify WITH VALIDATION if you want Oracle Database to return an error if any rows in the exchanged table do not map into partitions or subpartitions being exchanged. Specify WITHOUT VALIDATION if you do not want Oracle Database to check the proper mapping of rows in the exchanged table. If you omit this clause, then the default is WITH VALIDATION.  UPADATE INDEX|GLOBAL INDEX Unless you specify UPDATE INDEXES, the database marks UNUSABLE the global indexes or all global index partitions on the table whose partition is being exchanged. Global indexes or global index partitions on the table being exchanged remain invalidated. (You cannot use UPDATE INDEXES for index-organized tables. Use UPDATE GLOBAL INDEXES instead.) Exchanging Partitions&Subpartitions Notes Both tables involved in the exchange must have the same primary key, and no validated foreign keys can be referencing either of the tables unless the referenced table is empty.  When exchanging partitioned index-organized tables: – The source and target table or partition must have their primary key set on the same columns, in the same order. – If key compression is enabled, then it must be enabled for both the source and the target, and with the same prefix length. – Both the source and target must be index organized. – Both the source and target must have overflow segments, or neither can have overflow segments. Also, both the source and target must have mapping tables, or neither can have a mapping table. – Both the source and target must have identical storage attributes for any LOB columns. 

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  • Interviews: Going Beyond the Technical Quiz

    - by Tony Davis
    All developers will be familiar with the basic format of a technical interview. After a bout of CV-trawling to gauge basic experience, strengths and weaknesses, the interview turns technical. The whiteboard takes center stage and the challenge is set to design a function or query, or solve what on the face of it might seem a disarmingly simple programming puzzle. Most developers will have experienced those few panic-stricken moments, when one’s mind goes as blank as the whiteboard, before un-popping the marker pen, and hopefully one’s mental functions, to work through the problem. It is a way to probe the candidate’s knowledge of basic programming structures and techniques and to challenge their critical thinking. However, these challenges or puzzles, often devised by some of the smartest brains in the development team, have a tendency to become unnecessarily ‘tricksy’. They often seem somewhat academic in nature. While the candidate straight out of IT school might breeze through the construction of a Markov chain, a candidate with bags of practical experience but less in the way of formal training could become nonplussed. Also, a whiteboard and a marker pen make up only a very small part of the toolkit that a programmer will use in everyday work. I remember vividly my first job interview, for a position as technical editor. It went well, but after the usual CV grilling and technical questions, I was only halfway there. Later, they sat me alongside a team of editors, in front of a computer loaded with MS Word and copy of SQL Server Query Analyzer, and my task was to edit a real chapter for a real SQL Server book that they planned to publish, including validating and testing all the code. It was a tough challenge but I came away with a sound knowledge of the sort of work I’d do, and its context. It makes perfect sense, yet my impression is that many organizations don’t do this. Indeed, it is only relatively recently that Red Gate started to move over to this model for developer interviews. Now, instead of, or perhaps in addition to, the whiteboard challenges, the candidate can expect to sit with their prospective team, in front of Visual Studio, loaded with all the useful tools in the developer’s kit (ReSharper and so on) and asked to, for example, analyze and improve a real piece of software. The same principles should apply when interviewing for a database positon. In addition to the usual questions challenging the candidate’s knowledge of such things as b-trees, object permissions, database recovery models, and so on, sit the candidate down with the other database developers or DBAs. Arm them with a copy of Management Studio, and a few other tools, then challenge them to discover the flaws in a stored procedure, and improve its performance. Or present them with a corrupt database and ask them to get the database back online, and discover the cause of the corruption.

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  • Inauguration Of My Laptop

    - by Pawan_Mishra
    Today I received my new laptop which is an Intel Core i5-2450M @ 2.50GHz 4 GB RAM machine . The other laptop(office provided) which I have used for past two years for programming is an Intel Core2 Duo T6570 @ 2.10GHz machine. Reason why I am talking about the laptops that I own is because of my interest in writing multi-threaded/parallel code using the new TPL API provided in the .Net 4.0 framework. I have spent significant amount of time in past one year writing code using the Parallel API of .Net...(read more)

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  • More Fun With Math

    - by PointsToShare
    More Fun with Math   The runaway student – three different ways of solving one problem Here is a problem I read in a Russian site: A student is running away. He is moving at 1 mph. Pursuing him are a lion, a tiger and his math teacher. The lion is 40 miles behind and moving at 6 mph. The tiger is 28 miles behind and moving at 4 mph. His math teacher is 30 miles behind and moving at 5 mph. Who will catch him first? Analysis Obviously we have a set of three problems. They are all basically the same, but the details are different. The problems are of the same class. Here is a little excursion into computer science. One of the things we strive to do is to create solutions for classes of problems rather than individual problems. In your daily routine, you call it re-usability. Not all classes of problems have such solutions. If a class has a general (re-usable) solution, it is called computable. Otherwise it is unsolvable. Within unsolvable classes, we may still solve individual (some but not all) problems, albeit with different approaches to each. Luckily the vast majority of our daily problems are computable, and the 3 problems of our runaway student belong to a computable class. So, let’s solve for the catch-up time by the math teacher, after all she is the most frightening. She might even make the poor runaway solve this very problem – perish the thought! Method 1 – numerical analysis. At 30 miles and 5 mph, it’ll take her 6 hours to come to where the student was to begin with. But by then the student has advanced by 6 miles. 6 miles require 6/5 hours, but by then the student advanced by another 6/5 of a mile as well. And so on and so forth. So what are we to do? One way is to write code and iterate it until we have solved it. But this is an infinite process so we’ll end up with an infinite loop. So what to do? We’ll use the principles of numerical analysis. Any calculator – your computer included – has a limited number of digits. A double floating point number is good for about 14 digits. Nothing can be computed at a greater accuracy than that. This means that we will not iterate ad infinidum, but rather to the point where 2 consecutive iterations yield the same result. When we do financial computations, we don’t even have to go that far. We stop at the 10th of a penny.  It behooves us here to stop at a 10th of a second (100 milliseconds) and this will how we will avoid an infinite loop. Interestingly this alludes to the Zeno paradoxes of motion – in particular “Achilles and the Tortoise”. Zeno says exactly the same. To catch the tortoise, Achilles must always first come to where the tortoise was, but the tortoise keeps moving – hence Achilles will never catch the tortoise and our math teacher (or lion, or tiger) will never catch the student, or the policeman the thief. Here is my resolution to the paradox. The distance and time in each step are smaller and smaller, so the student will be caught. The only thing that is infinite is the iterative solution. The race is a convergent geometric process so the steps are diminishing, but each step in the solution takes the same amount of effort and time so with an infinite number of steps, we’ll spend an eternity solving it.  This BTW is an original thought that I have never seen before. But I digress. Let’s simply write the code to solve the problem. To make sure that it runs everywhere, I’ll do it in JavaScript. function LongCatchUpTime(D, PV, FV) // D is Distance; PV is Pursuers Velocity; FV is Fugitive’ Velocity {     var t = 0;     var T = 0;     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     t = d / pv;     while (t > 0.000001) //a 10th of a second is 1/36,000 of an hour, I used 1/100,000     {         T = T + t;         d = t * fv;         t = d / pv;     }     return T;     } By and large, the higher the Pursuer’s velocity relative to the fugitive, the faster the calculation. Solving this with the 10th of a second limit yields: 7.499999232000001 Method 2 – Geometric Series. Each step in the iteration above is smaller than the next. As you saw, we stopped iterating when the last step was small enough, small enough not to really matter.  When we have a sequence of numbers in which the ratio of each number to its predecessor is fixed we call the sequence geometric. When we are looking at the sum of sequence, we call the sequence of sums series.  Now let’s look at our student and teacher. The teacher runs 5 times faster than the student, so with each iteration the distance between them shrinks to a fifth of what it was before. This is a fixed ratio so we deal with a geometric series.  We normally designate this ratio as q and when q is less than 1 (0 < q < 1) the sum of  + … +  is  – 1) / (q – 1). When q is less than 1, it is easier to use ) / (1 - q). Now, the steps are 6 hours then 6/5 hours then 6/5*5 and so on, so q = 1/5. And the whole series is multiplied by 6. Also because q is less than 1 , 1/  diminishes to 0. So the sum is just  / (1 - q). or 1/ (1 – 1/5) = 1 / (4/5) = 5/4. This times 6 yields 7.5 hours. We can now continue with some algebra and take it back to a simpler formula. This is arduous and I am not going to do it here. Instead let’s do some simpler algebra. Method 3 – Simple Algebra. If the time to capture the fugitive is T and the fugitive travels at 1 mph, then by the time the pursuer catches him he travelled additional T miles. Time is distance divided by speed, so…. (D + T)/V = T  thus D + T = VT  and D = VT – T = (V – 1)T  and T = D/(V – 1) This “strangely” coincides with the solution we just got from the geometric sequence. This is simpler ad faster. Here is the corresponding code. function ShortCatchUpTime(D, PV, FV) {     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     return d / (pv - fv); } The code above, for both the iterative solution and the algebraic solution are actually for a larger class of problems.  In our original problem the student’s velocity (speed) is 1 mph. In the code it may be anything as long as it is less than the pursuer’s velocity. As long as PV > FV, the pursuer will catch up. Here is the really general formula: T = D / (PV – FV) Finally, let’s run the program for each of the pursuers.  It could not be worse. I know he’d rather be eaten alive than suffering through yet another math lesson. See the code run? Select  “Catch Up Time” in www.mgsltns.com/games.htm The host is running on Unix, so the link is case sensitive. That’s All Folks

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  • Interesting links week #10

    - by erwin21
    Below a list of interesting links that I found this week: Interaction: The Ultimate 20 Usability Tips for Your Website Frontend: Adobe Releases Flash-to-HTML5 Converter, Codenamed Wallaby Development: 10 Tips for Decreasing Web Page Load Times Ten Things Every WordPress Plugin Developer Should Know Progressive enhancement tutorial with ASP.NET MVC 3 and jQuery Marketing: 5 Tips for SEO & User-Friendly Copy Other: Interested in more interesting links follow me at twitter http://twitter.com/erwingriekspoor

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  • How To Build An Enterprise Application - Introduction

    - by Tuan Nguyen
    An enterprise application is a software which fulfills 4 core quality attributes: Reliability Flexibility Reusability Maintainability Reliability is the ability of a system or component to perform its required functions under stated conditions for a specific period of time. Because there are no ways more than testing to make sure a system is reliability, we can exchange the term reliability with the term testability. Flexibility is the ability of changing a system's core features without violating unrelated features or components. Although flexibility can helps us to achieve interoperability easily but the opposite is not true. For example, a program might run on multiple platforms, contains logic for many scenarios but that wouldn't mean it was flexibility if it forces us rewrite code in all components when we just want to change some aspects of a feature it had. Reusability is the ability of sharing one or more system's components for another system. We should just open a component's reusability in the context in which it is used. For example, we write classes that implement UI logic and deliver them to only classes which implementing UI. Maintainability is the ability of adding or removing features to a system after it was released. Maintainability consists of many factors such as readability, analyzability, extensibility therein extensibility is critical. Maintainability requires us to write code that is longer and complexer than normal but it doesn't mean we introduce unneccessarily complex code. We always try to make our code clear and transparent to everyone. An application enterprise is built on an enterprise design which consists of two parts: low-level design and high-level design. At low-level design, it focuses on building loose-coupled classes or components. Particularly, it recommends: Each class or component undertakes only single responsibility (design based on unit test) Classes or components implement and work through interfaces (design based on contract) Dependency relationship between classes and components could be injected at run-time (design based on dependency) At high-level design, it focuses on architecting system into tiers and layers. Particularly, it recommends: Divide system into subsystems for deployment. Each subsytem is called a tier. Typical, an enterprise application would have 3 tiers as illustrated in the following figure: Arrange classes and components to logical containers called layers. Typical, an enterprise application would have 5 layers as illustrated in the following figure

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  • PowerShell Script to Enumerate SharePoint 2010 or 2013 Permissions and Active Directory Group Membership

    - by Brian T. Jackett
    Originally posted on: http://geekswithblogs.net/bjackett/archive/2013/07/01/powershell-script-to-enumerate-sharepoint-2010-or-2013-permissions-and.aspx   In this post I will present a script to enumerate SharePoint 2010 or 2013 permissions across the entire farm down to the site (SPWeb) level.  As a bonus this script also recursively expands the membership of any Active Directory (AD) group including nested groups which you wouldn’t be able to find through the SharePoint UI.   History     Back in 2009 (over 4 years ago now) I published one my most read blog posts about enumerating SharePoint 2007 permissions.  I finally got around to updating that script to remove deprecated APIs, supporting the SharePoint 2010 commandlets, and fixing a few bugs.  There are 2 things that script did that I had to remove due to major architectural or procedural changes in the script. Indenting the XML output Ability to search for a specific user    I plan to add back the ability to search for a specific user but wanted to get this version published first.  As for indenting the XML that could be added but would take some effort.  If there is user demand for it (let me know in the comments or email me using the contact button at top of blog) I’ll move it up in priorities.    As a side note you may also notice that I’m not using the Active Directory commandlets.  This was a conscious decision since not all environments have them available.  Instead I’m relying on the older [ADSI] type accelerator and APIs.  It does add a significant amount of code to the script but it is necessary for compatibility.  Hopefully in a few years if I need to update again I can remove that legacy code.   Solution    Below is the script to enumerate SharePoint 2010 and 2013 permissions down to site level.  You can also download it from my SkyDrive account or my posting on the TechNet Script Center Repository. SkyDrive TechNet Script Center Repository http://gallery.technet.microsoft.com/scriptcenter/Enumerate-SharePoint-2010-35976bdb   001 002 003 004 005 006 007 008 009 010 011 012 013 014 015 016 017 018 019 020 021 022 023 024 025 026 027 028 029 030 031 032 033 034 035 036 037 038 039 040 041 042 043 044 045 046 047 048 049 050 051 052 053 054 055 056 057 058 059 060 061 062 063 064 065 066 067 068 069 070 071 072 073 074 075 076 077 078 079 080 081 082 083 084 085 086 087 088 089 090 091 092 093 094 095 096 097 098 099 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 ########################################################### #DisplaySPWebApp8.ps1 # #Author: Brian T. Jackett #Last Modified Date: 2013-07-01 # #Traverse the entire web app site by site to display # hierarchy and users with permissions to site. ########################################################### function Expand-ADGroupMembership {     Param     (         [Parameter(Mandatory=$true,                    Position=0)]         [string]         $ADGroupName,         [Parameter(Position=1)]         [string]         $RoleBinding     )     Process     {         $roleBindingText = ""         if(-not [string]::IsNullOrEmpty($RoleBinding))         {             $roleBindingText = " RoleBindings=`"$roleBindings`""         }         Write-Output "<ADGroup Name=`"$($ADGroupName)`"$roleBindingText>"         $domain = $ADGroupName.substring(0, $ADGroupName.IndexOf("\") + 1)         $groupName = $ADGroupName.Remove(0, $ADGroupName.IndexOf("\") + 1)                                     #BEGIN - CODE ADAPTED FROM SCRIPT CENTER SAMPLE CODE REPOSITORY         #http://www.microsoft.com/technet/scriptcenter/scripts/powershell/search/users/srch106.mspx         #GET AD GROUP FROM DIRECTORY SERVICES SEARCH         $strFilter = "(&(objectCategory=Group)(name="+($groupName)+"))"         $objDomain = New-Object System.DirectoryServices.DirectoryEntry         $objSearcher = New-Object System.DirectoryServices.DirectorySearcher         $objSearcher.SearchRoot = $objDomain         $objSearcher.Filter = $strFilter         # specify properties to be returned         $colProplist = ("name","member","objectclass")         foreach ($i in $colPropList)         {             $catcher = $objSearcher.PropertiesToLoad.Add($i)         }         $colResults = $objSearcher.FindAll()         #END - CODE ADAPTED FROM SCRIPT CENTER SAMPLE CODE REPOSITORY         foreach ($objResult in $colResults)         {             if($objResult.Properties["Member"] -ne $null)             {                 foreach ($member in $objResult.Properties["Member"])                 {                     $indMember = [adsi] "LDAP://$member"                     $fullMemberName = $domain + ($indMember.Name)                                         #if($indMember["objectclass"]                         # if child AD group continue down chain                         if(($indMember | Select-Object -ExpandProperty objectclass) -contains "group")                         {                             Expand-ADGroupMembership -ADGroupName $fullMemberName                         }                         elseif(($indMember | Select-Object -ExpandProperty objectclass) -contains "user")                         {                             Write-Output "<ADUser>$fullMemberName</ADUser>"                         }                 }             }         }                 Write-Output "</ADGroup>"     } } #end Expand-ADGroupMembership # main portion of script if((Get-PSSnapin -Name microsoft.sharepoint.powershell) -eq $null) {     Add-PSSnapin Microsoft.SharePoint.PowerShell } $farm = Get-SPFarm Write-Output "<Farm Guid=`"$($farm.Id)`">" $webApps = Get-SPWebApplication foreach($webApp in $webApps) {     Write-Output "<WebApplication URL=`"$($webApp.URL)`" Name=`"$($webApp.Name)`">"     foreach($site in $webApp.Sites)     {         Write-Output "<SiteCollection URL=`"$($site.URL)`">"                 foreach($web in $site.AllWebs)         {             Write-Output "<Site URL=`"$($web.URL)`">"             # if site inherits permissions from parent then stop processing             if($web.HasUniqueRoleAssignments -eq $false)             {                 Write-Output "<!-- Inherits role assignments from parent -->"             }             # else site has unique permissions             else             {                 foreach($assignment in $web.RoleAssignments)                 {                     if(-not [string]::IsNullOrEmpty($assignment.Member.Xml))                     {                         $roleBindings = ($assignment.RoleDefinitionBindings | Select-Object -ExpandProperty name) -join ","                         # check if assignment is SharePoint Group                         if($assignment.Member.XML.StartsWith('<Group') -eq "True")                         {                             Write-Output "<SPGroup Name=`"$($assignment.Member.Name)`" RoleBindings=`"$roleBindings`">"                             foreach($SPGroupMember in $assignment.Member.Users)                             {                                 # if SharePoint group member is an AD Group                                 if($SPGroupMember.IsDomainGroup)                                 {                                     Expand-ADGroupMembership -ADGroupName $SPGroupMember.Name                                 }                                 # else SharePoint group member is an AD User                                 else                                 {                                     # remove claim portion of user login                                     #Write-Output "<ADUser>$($SPGroupMember.UserLogin.Remove(0,$SPGroupMember.UserLogin.IndexOf("|") + 1))</ADUser>"                                     Write-Output "<ADUser>$($SPGroupMember.UserLogin)</ADUser>"                                 }                             }                             Write-Output "</SPGroup>"                         }                         # else an indivdually listed AD group or user                         else                         {                             if($assignment.Member.IsDomainGroup)                             {                                 Expand-ADGroupMembership -ADGroupName $assignment.Member.Name -RoleBinding $roleBindings                             }                             else                             {                                 # remove claim portion of user login                                 #Write-Output "<ADUser>$($assignment.Member.UserLogin.Remove(0,$assignment.Member.UserLogin.IndexOf("|") + 1))</ADUser>"                                                                 Write-Output "<ADUser RoleBindings=`"$roleBindings`">$($assignment.Member.UserLogin)</ADUser>"                             }                         }                     }                 }             }             Write-Output "</Site>"             $web.Dispose()         }         Write-Output "</SiteCollection>"         $site.Dispose()     }     Write-Output "</WebApplication>" } Write-Output "</Farm>"      The output from the script can be sent to an XML which you can then explore using the [XML] type accelerator.  This lets you explore the XML structure however you see fit.  See the screenshot below for an example.      If you do view the XML output through a text editor (Notepad++ for me) notice the format.  Below we see a SharePoint site that has a SharePoint group Demo Members with Edit permissions assigned.  Demo Members has an AD group corp\developers as a member.  corp\developers has a child AD group called corp\DevelopersSub with 1 AD user in that sub group.  As you can see the script recursively expands the AD hierarchy.   Conclusion    It took me 4 years to finally update this script but I‘m happy to get this published.  I was able to fix a number of errors and smooth out some rough edges.  I plan to develop this into a more full fledged tool over the next year with more features and flexibility (copy permissions, search for individual user or group, optional enumerate lists / items, etc.).  If you have any feedback, feature requests, or issues running it please let me know.  Enjoy the script!         -Frog Out

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  • Why do I get this file loading exception when trying to draw sprites with libgdx?

    - by BluFire
    I'm having trouble with the "Drawing Images" section on the libgdx tutorial. I set up the documents completely and I typed the code as follows: public class Game implements ApplicationListener { public static final String LOG = Game.class.getSimpleName(); private FPSLogger fpsLogger; private SpriteBatch batch; private Texture texture; private Sprite sprite; private TextureRegion region; //removed irrelevant code for this question... @Override public void render() { texture = new Texture(Gdx.files.internal("android.png")); region = new TextureRegion(texture, 20, 20, 50, 50); sprite = new Sprite(texture, 20, 20, 50, 50); sprite.setPosition(10, 10); sprite.setRotation(45); Gdx.gl.glClearColor(0f, 1f, 0f, 1f); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); batch.begin(); batch.draw(texture,10,10); batch.draw(region,10,10); sprite.draw(batch); batch.end(); // output the current FPS fpsLogger.log(); } } I went through the tutorial on the website but when I run the code I get errors: Exception in thread "LWJGL Application" com.badlogic.gdx.utils.GdxRuntimeException: Couldn't load file: android.png at com.badlogic.gdx.graphics.Pixmap.<init>(Pixmap.java:137) at com.badlogic.gdx.graphics.glutils.FileTextureData.prepare(FileTextureData.java:55) at com.badlogic.gdx.graphics.Texture.load(Texture.java:175) at com.badlogic.gdx.graphics.Texture.create(Texture.java:159) at com.badlogic.gdx.graphics.Texture.<init>(Texture.java:133) at com.badlogic.gdx.graphics.Texture.<init>(Texture.java:122) at com.game.Game.render(Game.java:46) at com.badlogic.gdx.backends.lwjgl.LwjglApplication.mainLoop (LwjglApplication.java:163) at com.badlogic.gdx.backends.lwjgl.LwjglApplication$1.run(LwjglApplication.java:113) Caused by: com.badlogic.gdx.utils.GdxRuntimeException: File not found: android.png (Internal) at com.badlogic.gdx.files.FileHandle.read(FileHandle.java:108) at com.badlogic.gdx.files.FileHandle.length(FileHandle.java:364) at com.badlogic.gdx.files.FileHandle.readBytes(FileHandle.java:156) at com.badlogic.gdx.graphics.Pixmap.<init>(Pixmap.java:134) ... 8 more I set the android.png in my assests folder in my android project linking it to the desktop one, I don't understand what I'm doing wrong. What is making these errors? FIX. Weird ending.this was the plus where the sprite is suppose to look like. The top right corner of the next image should look like, the bottom left is what turned out in the code. I'm think it was because of the texture region but I'm not 100%. Can somebody explain why it is really warped? I thought the changes I made in the coding will just change position/rotation, rather then a change in the image.

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  • Internet problems

    - by user288636
    I have a strange problem. When I copy/paste via ethernet everything is working fine. But when I go to youtube or downloading some files via internet, connection is freezing very often. Just stop downloading and after few minutes continue and than again stop and etc... Could it be hardware problem with network card or motherboard (network is integrated on board)? I am using Ubuntu 14.04 but it happens on live cd distribution of Mint. There is no restrictions cose when I using on same switch my other laptop with linux installed everything working fine.

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  • Policy Implementation is Damaging Organizations: Economist Intelligence Unit

    - by michael.seback
    Read new research revealing the hidden risks of inefficient policy implementation The frenetic pace of regulatory and legislative change means public and private sector organizations must continuously update internal policies - in particular, as associated with decision making and disbursements. Yet with policy management efforts alarmingly under-resourced and under-funded, the risk and cost of non-compliance - and their associated implications - are growing daily. To find out how inefficient policy management could be putting your business at risk, read your complimentary copy of the full EIU paper - Enabling Efficient Policy Implementation - today.

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  • How to ensure images all loaded before I reference in my HTML canvas [closed]

    - by mark stephens
    I want to draw some images in on a HTML canvas with context.drawImage(Im1 ,205,18,184,38); In order to make sure it loads I need to put in code like this but then I cannot draw things with it var Im1 = new Image(); Im1.src="rechnung11014page1/img/1/Im1.png"; Im1.onload = function() { context.drawImage(Im1 ,205,18,184,38); } Is there a way to load all the images and then execute a block of code using several images?

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