Why can't I create a templated sublcass of System::Collections::Generic::IEnumerable<T>?
- by fiirhok
I want to create a generic IEnumerable implementation, to make it easier to wrap some native C++ classes. When I try to create the implementation using a template parameter as the parameter to IEnumerable, I get an error.
Here's a simple version of what I came up with that demonstrates my problem:
ref class A {};
template<class B>
ref class Test : public System::Collections::Generic::IEnumerable<B^> // error C3225...
{};
void test()
{
Test<A> ^a = gcnew Test<A>();
}
On the indicated line, I get this error:
error C3225: generic type argument for 'T' cannot be 'B ^', it must be a value type or a handle to a reference type
If I use a different parent class, I don't see the problem:
template<class P>
ref class Parent {};
ref class A {};
template<class B>
ref class Test : public Parent<B^> // no problem here
{};
void test()
{
Test<A> ^a = gcnew Test<A>();
}
I can work around it by adding another template parameter to the implementation type:
ref class A {};
template<class B, class Enumerable>
ref class Test : public Enumerable
{};
void test()
{
using namespace System::Collections::Generic;
Test<A, IEnumerable<A^>> ^a = gcnew Test<A, IEnumerable<A^>>();
}
But this seems messy to me. Also, I'd just like to understand what's going on here - why doesn't the first way work?
