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  • How to return string name of calling method?

    - by keruilin
    Right now my code works as such: def method_a self.method_b ==> 'method_b' end def method_b puts self.name_of_calling_method end def name_of_calling_method if /`(.*)'/.match(caller.first) return $1 else return nil end end Instead of method_b printing 'method_b', how can I print the name of the calling method - 'method_a'?

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  • Get name given by phone number on the iPhone

    - by ganti
    I'm using a TextField where the user types a phone number. When the TextField changes, it should check if this number is already in the phonebook and display the name. So far, my only way is to parse all names and number in a Dict and read it from there. Is there a simpler, more efficient and sophisticated way to do that?

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  • Access property using its name in vb.net

    - by Aleksey
    For example: Sub Test() Dim car as new MyCar car.chassis.wheel.radius = 15 Console.WriteLine(car.chassis.wheel.radius) End Sub So question is. Is it possible to access the property using its string name like Something("car.chassis.wheel.radius") = 15?

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  • AutoMapper: setup member name matching convention

    - by epitka
    I tried setting up a member name mapping convention so that the source members ending with a "Id" are mapped to destination members without Id. For example UserId - User How does one do this? I tried using SourceMemberNameTransformer without success. Also tried using RecognizePostfixes(). this.SourceMemberNameTransformer = s => { return s.Replace("Id", string.Empty); };

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  • The name/identity of the invoker of a web service

    - by Swamy g
    I have a SOAP web service which I call from two clients using axis2. Can the web service know from which of these two clients the call originated from? If so, how do I know that during runtime? Is there any API provided to lookup the name of the invoker of a particular web service by that web service. Thanks.

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  • MySQL ORDER BY rand(), name ASC

    - by Josh K
    I would like to take a database of say, 1000 users and select 20 random ones (ORDER BY rand(),LIMIT 20) then order the resulting set by the names. I came up with the following query which is not working like I hoped. SELECT * FROM users WHERE 1 ORDER BY rand(), name ASC LIMIT 20

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  • use a variable for table name in mysql sproc

    - by Kyle
    I'm trying to pass a table name into my mysql stored procedure to use this sproc to select off of different tables but it's not working... this is what I"m trying: CREATE PROCEDURE `usp_SelectFromTables`( IN TableName varchar(100) ) BEGIN SELECT * FROM @TableName; END I've also tried it w/o the @ sign and that just tells me that TableName doesn't exist...which I know :)

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  • "Invalid Column Name" error thrown by Access Reports?

    - by badpanda
    I am attempting to sum over a detail grouping on a specific field in Microsoft Access, and assign that sum to a field in the general grouping. When I try to run the report, I get an "Invalid Column Name" error with the detail field getting the error. Has anyone previously encountered this? If so, any ideas what might be causing it or how to solve it?

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  • Scala: getting the name of the class the trait is mixed in

    - by Alexey Romanov
    Given an instance of a class, we can obviously return its name: trait MixedInClassDiscovery { val className = this.getClass.getName } class AClass extends MixedInClassDiscovery { ... this.className // returns "AClass" ... } But this way uses reflection, once for every instance of AClass. Can the same be done once for every class, instead? One solution which comes to mind is to mix it into companion objects instead of classes themselves.

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  • 'Scanner' does not name a type error in g++

    - by Max
    Hi. I'm trying to compile code in g++ and I get the following errors: In file included from scanner.hpp:8, from scanner.cpp:5: parser.hpp:14: error: ‘Scanner’ does not name a type parser.hpp:15: error: ‘Token’ does not name a type Here's my g++ command: g++ parser.cpp scanner.cpp -Wall Here's parser.hpp: #ifndef PARSER_HPP #define PARSER_HPP #include <string> #include <map> #include "scanner.hpp" using std::string; class Parser { // Member Variables private: Scanner lex; // Lexical analyzer Token look; // tracks the current lookahead token // Member Functions <some function declarations> }; #endif and here's scanner.hpp: #ifndef SCANNER_HPP #define SCANNER_HPP #include <iostream> #include <cctype> #include <string> #include <map> #include "parser.hpp" using std::string; using std::map; enum { // reserved words BOOL, ELSE, IF, TRUE, WHILE, DO, FALSE, INT, VOID, // punctuation and operators LPAREN, RPAREN, LBRACK, RBRACK, LBRACE, RBRACE, SEMI, COMMA, PLUS, MINUS, TIMES, DIV, MOD, AND, OR, NOT, IS, ADDR, EQ, NE, LT, GT, LE, GE, // symbolic constants NUM, ID, ENDFILE, ERROR }; class Token { public: int tag; int value; string lexeme; Token() {tag = 0;} Token(int t) {tag = t;} }; class Num : public Token { public: Num(int v) {tag = NUM; value = v;} }; class Word : public Token { public: Word() {tag = 0; lexeme = "default";} Word(int t, string l) {tag = t; lexeme = l;} }; class Scanner { private: int line; // which line the compiler is currently on int depth; // how deep in the parse tree the compiler is map<string,Word> words; // list of reserved words and used identifiers // Member Functions public: Scanner(); Token scan(); string printTag(int); friend class Parser; }; #endif anyone see the problem? I feel like I'm missing something incredibly obvious.

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  • Zend_Services_Twitter, change the API Source name

    - by favo
    Hi, I am sending tweets to Twitter via Zend_Service_Twitter. The tweets appear with a note "via API". I want to set the API Source with a different name, is there already a functionality within the Zend Framework to change it? Or do I need to subclass to get this functionality? Thanks!

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