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  • Error 49 bad bind variable oracle forms

    - by mysticfalls
    I would like to ask regarding this error... Error 49 at line 5, column 6 bad bind variable 'S_ORD.payment_type' Here is the code: DECLARE N NUMBER; v_credit S_CUSTOMER.credit_rating%type; BEGIN IF :S_ORD.payment_type = 'CREDIT' THEN SELECT credit_rating INTO v_credit FROM S_CUSTOMER WHERE :S_ORD.customer_id = id; IF v_credit NOT IN ('GOOD', 'EXCELLENT') THEN :S_ORD.payment_type:= 'CASH'; n:=SHOW_ALERT('Payment_Type_Alert'); END IF; END IF; END; I'm new to oracle forms so I'm not sure if I have a missing setup or anything. S_ORD table exist and has a column payment_type, which consists of 'CREDIT' and 'CASH' value. Thank you.

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  • sDesigning a database with flexible user profile

    - by Mughrabi
    I am working on a design where I can have flexible attributes for users and I am confused how to continue the design of the schema. I made a table where I kept system needed information: Table name: users id username password Now, I wish to create a profile table and have one to one relation where all the other attributes in profile table such as email, first name, last name, etc. My question is: is there a way to add a third table in which profiles will be flexible? In other words, if my clients need to create a new attribute he/she won't need any customization to the code.

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  • Query returning an ascending group number

    - by Dougman
    I have a query like below that has groups (COL1) and that group's values (COL2). select col1, col2 from (select 'A' col1, 1 col2 from dual union all select 'A' col1, 2 col2 from dual union all select 'B' col1, 1 col2 from dual union all select 'B' col1, 2 col2 from dual union all select 'C' col1, 1 col2 from dual union all select 'C' col1, 2 col2 from dual ) order by col1, col2; The output of this query looks like: COL1 COL2 ---- ---- A 1 A 2 B 1 B 2 C 1 C 2 What I need is a query that will return an ordered number increasing for each different group (COL1). It seems like there would be a simple way to accomplish this (maybe with analytics) but for some reason it is escaping me. GRPNUM COL1 COL2 ------ ---- ---- 1 A 1 1 A 2 2 B 1 2 B 2 3 C 1 3 C 2 I am running Oracle 10gR2.

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  • Creating a multi-row "table" as part of a SELECT

    - by Chad Birch
    I'm not really sure how to describe my question (thus the awful title), but it's related to this recent question. The problem would be easily solved if there was some way for me to create a "table" with 4 rows as part of my SELECT (to use with NOT IN or MINUS). What I mean is, I can do this: SELECT 1, 2, 3, 4; And will receive one row from the database: | 1 | 2 | 3 | 4 | But is there any way to receive the following (without using UNION, I don't really want a query that's potentially thousands of lines long with a long list)? | 1 | | 2 | | 3 | | 4 |

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  • Best way to get distinct values from large table

    - by derivation
    I have a db table with about 10 or so columns, two of which are month and year. The table has about 250k rows now, and we expect it to grow by about 100-150k records a month. A lot of queries involve the month and year column (ex, all records from march 2010), and so we frequently need to get the available month and year combinations (ie do we have records for april 2010?). A coworker thinks that we should have a separate table from our main one that only contains the months and years we have data for. We only add records to our main table once a month, so it would just be a small update on the end of our scripts to add the new entry to this second table. This second table would be queried whenever we need to find the available month/year entries on the first table. This solution feels kludgy to me and a violation of DRY. What do you think is the correct way of solving this problem? Is there a better way than having two tables?

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  • Entity diagram with tables that have foreign keys that point to a non-PK column do not show relation

    - by Jason Coyne
    I have two tables parent and child. If I make a foreign key on child that points to the primary key of parent, and then make an entity diagram, the relationship is shown correctly. If I make the foreign key point to a different column, the relationship is not shown. I have tried adding indexes to the column, but it does not have an effect. The database is sqlite, but I am not sure if that has an effect since its all hidden behind ADO.net. How do I get the relationship to work correctly?

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  • is NATURAL JOIN any better than SELECT FROM WHERE in terms of performance ?

    - by ashy_32bit
    Today I got into a debate with my project manager about Cartesian products. He says a 'natural join' is somehow much better than using 'select from where' because the later cause the db engine to internally perform a Cartesian product but the former uses another approach that prevents this. As far as I know, the natural join syntax is not any different in anyway than 'select from where' in terms of performance or meaning, I mean you can use either based on your taste. SELECT * FROM table1,table2 WHERE table1.id=table2.id SELECT * FROM table1 NATURAL JOIN table2 please elaborate about the first query causing a Cartesian product but the second one being somehow more smart

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  • oracle query returns 4 duplicates of each row

    - by ajoe
    hello, I am Running a oracle query, it seems to work except that it returns 4 dupes of each result. here is the code: Select * from (Select a.*, rownum rnum From (SELECT NEW_USER.*, NEW_EHS_QUIZ_COMPLETE.datetime FROM NEW_USER, NEW_EHS_QUIZ_COMPLETE WHERE EXISTS(select * from NEW_EHS_QUIZ_COMPLETE where NEW_USER.id=NEW_EHS_QUIZ_COMPLETE.USER_ID) ORDER by last_name ASC ) a where rownum <= #pgtop# ) where rnum >= #pgbot# does anyone know why this isnt working properly? thanks in advance.

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  • Counting the instances of customers

    - by Mikae Combarado
    Say that I have a table with one column named CustomerId. The example of the instance of this table is : CustomerId 14 12 11 204 14 204 I want to write a query that counts the number of occurences of customer IDs. At the end, I would like to have a result like this : CustomerId NumberOfOccurences 14 2 12 1 11 1 204 2 14 1 I cannot think of a way to do this.

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  • entering data in sql database through asp

    - by sushant
    pass=session("password") Set objIns=server.CreateObject("adodb.connection") objIns.Open session("Psrconnect") inspass="Insert into passwords(pass) values ('&pass&')" objIns.Execute(inspass) i dont know what should be the syntax to pass the value stored in the variable. with this syntax, the value entered in the database is &pass&. can anyone plz help me out?

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  • dbo in SqlServer

    - by ala
    I'm converting database from Teradata to SqlServer. I've noticed all tables and procedures are named by the prefix "dbo." (e.g. "dbo.Table1"). I would like to know if and how I can get rid of "dbo" because it would make the conversion task a lot more easier.

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  • Query to check the consistency of records

    - by orunner
    I have four tables TableA: id1 id2 id3 value TableB: id1 desc TableC: id2 desc TableD: id3 desc What I need to do is to check if all combinations of id1 id2 id3 from table B C and D exist in the TableA. In other words, table A should contain all possible combinations of id1 id2 and id3 which are stored in the other three tables.

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  • How to differentiate two tables

    - by Nemat
    I have two tables and I want to get all records from one table that are different from the records in second table. Eg.: if we have four records in the first table like A,B,C,D and three records in the second table thats A,B,C then the answer of query should be D. I have tried "EXCEPT" operator but it doesn't work fine. Kindly help me in writing correct query for the given problem.

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  • How do I exclude outliers from an aggregate query?

    - by Margaret
    I'm creating a report comparing total time and volume across units. Here a simplification of the query I'm using at the moment: SELECT m.Unit, COUNT(*) AS Count, SUM(m.TimeInMinutes) AS TotalTime FROM main_table m WHERE m.unit <> '' AND m.TimeInMinutes > 0 GROUP BY m.Unit HAVING COUNT(*) > 15 However, I have been told that I need to exclude cases where the row's time is in the highest or lowest 5% to try and get rid of a few wacky outliers. (As in, remove the rows before the aggregates are applied.) How do I do that?

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  • Multiple/Sub quries with codeigniter

    - by user1011713
    I just started with Codeigniter and this is driving me nuts. I have a query that determines whether a user has bought any programs. I then have to use that program's type category to run and determine how many times he or she has recorded a query in another table. Sorry for the confusion but the code hopefully makes sense. I'm having problem returning the two arrays from my Model to my Controller to onto the view obviously. function specificPrograms() { $specific_sql = $this->db->query("SELECT program,created FROM `assessment` WHERE uid = $this->uid"); if($specific_sql->num_rows() > 0) { foreach ($specific_sql->result() as $specific) { $data[] = $specific; $this->type = $specific->program; } return $data; } $sub_sql = $this->db->query("SELECT id FROM othertable WHERE user_id_fk = $this->uid and type = '$this->type'"); if($sub_sql->num_rows() > 0) { foreach ($sub_sql->result() as $otherp) { $data[] = $otherp; } return $data; } } Then in my Controller I have, $data['specific'] = $this->user_model->specificPrograms(); $data['otherp'] = $this->user_model->specificPrograms(); Thanks for any help.

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  • android : SQL Exception while querying

    - by Ram
    Team, Can you please help me to understand why I m getting the following exception. 05-07 10:57:20.652: ERROR/AndroidRuntime(470): android.database.sqlite.SQLiteException: near "1": syntax error: , while compiling: SELECT Id,Name FROM act WHERE Id 1-IJUS-1 Thanks in advance,

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  • Firebird 2.1 + EXISTS = query bug?

    - by Atlas
    Using Delphi 2009 + Firebird 2.1.3. Database is ODS 11.1, default char set is UTF8. My prepared query is as follows: SELECT a.po_id, a.po_no FROM purchase_order a WHERE EXISTS (SELECT 1 FROM sales_order_item z1 JOIN purchase_order_item z2 ON z2.so_item_id = z1.so_item_id AND z2.po_id = a.po_id WHERE z1.so_id = :soid) ORDER BY a.po_no Now when I loop this say 1000 times because I have 1000 x so_id, the CPU usage get at 100% for FBSERVER.EXE Anyone encountered this problem?

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  • How can I select the required records?

    - by simple
    Tables: Product: [id, name, brand_id, is_published] Brand: [id, name, is_published] Awards: [id, name] ProductAwards [product_id, award_id] How do I select the list of PUBLISHED brands along with the number of AWARDS of brand's products that are Published. I am cool with all the part except issuing the "is_published" restriction when counting Awards. I hope this is clear; can anyone just suggest where to dig?

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  • Selecting distinct values from mysql with largest timestamp

    - by user987048
    I am building a mail system. The inbox is only supposed to grab the last message (one with the highest time value) of a concatenation of user and sender, where the user or sender is the user ID. Here is the table structure: CREATE TABLE IF NOT EXISTS `mail` ( `user` int(11) NOT NULL, `sender` int(11) NOT NULL, `body` text NOT NULL, `new` enum('0','1') NOT NULL default '1', `time` int(11) NOT NULL, KEY `user` (`user`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; So, with a table with the following data: user sender new time ***************************************** 1 0 0 5 1 0 0 6 2 1 0 7 1 0 1 8 1 2 0 9 1 0 1 11 1 2 1 12 I want to select the following: WHERE USER OR SENDER = X (in this case, 1) user sender new time ***************************************** 2 1 0 7 1 2 0 9 1 0 1 11 How would I go about doing something like this?

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  • Help with sql query

    - by user225269
    I have two tables: subject and student. I'm trying to count the number of subjects enrolled by each student. How do I do that?I'm trying the code below but it doesn't give the answer I need. Please help. SELECT COUNT( subject.SUBJECT ) , student.IDNO, student.FIRSTNAME, subject.SUBJECT FROM student, subject GROUP BY subject.SUBJECT LIMIT 0 , 30

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