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  • Adding an integer at the end of an input's name to get a specific url

    - by Gadgetster
    I am trying to get a url where I can retrieve the selected values from. For example, if I put a check mark on a and b then sumbit, I will get: index.php?category=1&&category=2 I want to get this instead: index.php?category0=1&&category1=2 So that I can later get this specific value with $_GET['category0'] Is there a way to add a counter for the selected checkboxes and add 0,1,2,3.. at the end of the name of its input? <form action="" method="get"> <!-- this will be a php loop instead of hardcored which will retrieve data from the db --> <label><input type="checkbox" name="category" value="1">a</label> <label><input type="checkbox" name="category" value="2">b</label> <label><input type="checkbox" name="category" value="3">c</label> <label><input type="checkbox" name="category" value="4">d</label> <label><input type="checkbox" name="category" value="5">e</label> <input type="submit"> </form>

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  • Why does PDO print my password when the connection fails?

    - by Joe Hopfgartner
    I have a simple website where I establish a connection to a Mysql server using PDO. $dbh = new PDO('mysql:host=localhost;dbname=DB;port=3306', 'USER', 'SECRET',array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8")); I had some traffic on my site and the servers connection limit was reached, and the website throw this error, with my PLAIN password in it! Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[08004] [1040] Too many connections' in /home/premiumize-me/html/index.php:64 Stack trace: #0 /home/premiumize-me/html/index.php(64): PDO-__construct('mysql:host=loca...', 'USER', 'SECRET', Array) #1 {main} thrown in /home/premiumize-me/html/index.php on line 64 Ironically I switched to PDO for security reasons, this really shocked me. Because this exact error is something you can provoke very easily on most sites using simple http flooding. I now wrapped my conenction into a try/catch clause, but still. I think this is catastrophic! So I am new to PDO and my questino is: What do I have to consider to be safe! How to I establish a connection in a secure way? Are there other known security holes like this one that I have to be aware of?

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  • destructor being called by subclass

    - by zero
    I'm currently learning more about php objects and constructors/destructors, but i've noticed in my code that the parent class's destructor is being called twice, I thought it was because i was extending the first class to my second class and that the second class was calling it, but this is what the php docs say about that: Like constructors, parent destructors will not be called implicitly by the engine. In order to run a parent destructor, one would have to explicitly call parent::__destruct() in the destructor body. so if it is not being called by the subclass then is it because by extended the first class that i've made a reference to the parent class making it call itself twice or I'm I way off base here? the code: <?php class test{ public $test1 = "this is a test of a pulic property"; private $test2 = "this is a test of a private property"; protected $test3 = "this is a test of a protected property"; const hello = 900000; function __construct($h){ //echo 'this is the constructor test '.$h; } function x($x2){ echo ' this is fn x'.$x2; } function y(){ print "this is fn y"; } } $obj = new test("this is an \"arg\" sent to instance of test"); class hey extends test{ function hey(){ $this->x('<br>from the host with the most'); echo ' <br>from hey class'.$this->test3; } } $obj2 = new hey(); echo $obj2::hello; ?>

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  • jQuery recursive function to upload many files while giving the user some feedback

    - by checcco
    Hi guys, I'm trying to write a jQuery function to let users upload many files at once. Here's the function I thought to give the user some feedback about the upload process progress. function uploadFiles(numbersOfFiles, start) { $("#info").html(start + " files uploaded"); $.post('upload.php', { start: start }, function (data) { start += 5; if (start < numbersOfFiles) { $("#info").html(start + " files uploaded"); uploadFiles(numbersOfFiles, start); } else { $("#info").html("All files have been uploaded"); } }); } The function calls a php script to upload 5 files, then if there are more files to upload it calls the script again. The whole process works. I've tried it with 100 files. The only thing that doesn't work is the #info div updating. The div get updated the first time and then again only to show "All files have been uploaded". So there's no feedback for the user about the uploading process. I can't understand why... Any help?

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  • Looping Through Database Query

    - by DrakeNET
    I am creating a very simple script. The purpose of the script is to pull a question from the database and display all answers associated with that particular question. We are dealing with two tables here and there is a foreign key from the question database to the answer database so answers are associated with questions. Hope that is enough explanation. Here is my code. I was wondering if this is the most efficient way to complete this or is there an easier way? <html> <head> <title>Advise Me</title> <head> <body> <h1>Today's Question</h1> <?php //Establish connection to database require_once('config.php'); require_once('open_connection.php'); //Pull the "active" question from the database $todays_question = mysql_query("SELECT name, question FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Variable to hold $todays_question aQID $questionID = mysql_query("SELECT commentID FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Print today's question echo $todays_question; //Print comments associated with today's question $sql = "SELECT commentID FROM approvedQuestions WHERE status = active"; $result_set = mysql_query($sql); $result_num = mysql_numrows($result_set); for ($a = 0; $a < $result_num; $a++) { echo $sql; } ?> </body> </html>

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  • NSRegularExpression for stripping HTML Tag

    - by Prazi
    I am developing a ebook reader app. I have the .ePUB file for the entire ebook where in each topic of the ebook is a html file. I want to implement the search functionality in the app. I am using NSRegularExpression class for searching. Please consider the following html code: <temp> I am temp in tempo with temptation </temp> Say for example in the above html code I just want to search for the word temp. Now in above code temp is appearing 5 times - <temp> </temp> temp tempo temptation. I am looking for a regular expression where I can only extract the whole word "temp". I don't want to consider the word temp in the html tags <temp> </temp>. I also don't want the word tempo and temptation to be considered. Thanks in advance

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  • UIWebview :: Text :: HTML :: JS

    - by user306089
    hello, 1- i load a text from a txt file 2- i show it into a html "file" 3- problem : 3-a : this code works : i create my page by code and i insert my text myText = ... loaded from an array of texts ...; NSString *myDescriptionHTML = [NSString stringWithFormat:@"<html> \n" "<head> \n" "<style type=\"text/css\"> \n" "body {font-family: \"%@\"; font-size: 1.0f + 'em'; color:#FFF;}\n" "</style> \n" "</head> \n" "<body id=\"myid\">%@</body> \n" "</html>", @"Arial", myText]; [self.myWebView loadHTMLString:myDescriptionHTML baseURL:nil]; 3-b but this one does not work : i load a html page already created and i inject my text into using JS : myText = ... loaded from an array of texts ...; [self.myWebView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"document.getElementById(\"myid\").innerHTML = \"%@\";", myText]]; 3-c but this one working : same as 3-b but i init my text with a string in the code itself : myText = @"hello all"; [self.myWebView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"document.getElementById(\"myid\").innerHTML = \"%@\";", myText]]; any help to understand what's wrong with 3-b ? thank you

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  • problem with accessing a php page

    - by EquinoX
    So I have a info.php page which is located on the folder /var/www/nginx-default, however when I go to my ip address/info.php, it always redirects me to this site: http://www.iana.org/domains/example/ is this because I have a virtual host that I called example? Here is my config for the example website: server { listen 80; server_name www.example.com; rewrite ^/(.*) http://example.com/$1 permanent; } server { listen 80; server_name example.com; access_log /var/www/example.com/logs/access.log; error_log /var/www/example.com/logs/error.log; location / { root /var/www/example.com/public/; index index.html; } } The way I access this site is by changing my /var/hosts in my macbook so that example.com is mapped to my server IP address... however now when I do xxx.xxx.xxx.xxx/info.php.. it redirects me to that site I posted above

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  • Only first word of two strings gets added to db

    - by dkgeld
    When trying to add words to a database via php, only the first word of both strings gets added. I send the text via this code: public void sendTextToDB() { valcom = editText1.getText().toString(); valnm = editText2.getText().toString(); t = new Thread() { public void run() { try { url = new URL("http://10.0.2.2/HB/hikebuddy.php?function=setcomm&comment="+valcom+"&name="+valnm); h = (HttpURLConnection)url.openConnection(); if( h.getResponseCode() == HttpURLConnection.HTTP_OK){ is = h.getInputStream(); }else{ is = h.getErrorStream(); } h.disconnect(); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); Log.d("Test", "CONNECTION FAILED 1"); } } }; t.start(); } When tested with spaces and commas etc. in a browser, the php function adds all text. The strings also return the full value when inserted into a dialog. How do I fix this? Thank you.

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  • How to evaluate json member using variable ?

    - by Miftah
    Hi i've got a problem evaluating json. My goal is to insert json member value to a function variable, take a look at this function func_load_session(svar){ var id = ''; $.getJSON('data/session.php?load='+svar, function(json){ eval('id = json.'+svar); }); return id; } this code i load session from php file that i've store beforehand. i store that session variable using dynamic var. <?php /* * format ?var=[nama_var]&val=[nilai_nama_var] */ $var = $_GET['var']; $val = $_GET['val']; $load = $_GET['load']; session_start(); if($var){ $_SESSION["$var"] = $val; echo "Store SESSION[\"$var\"] = '".$_SESSION["$var"]."'"; }else if($load){ echo $_SESSION["$load"]; } ?> using firebug, i get expected response but i also received error uncaught exception: Syntax error, unrecognized expression: ) pointing at this eval('id = json.'+svar); i wonder how to solve this

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  • inserts 'Array' into mysql table

    - by Noah Smith
    i want to insert an array into a mysql table. The array is produced by script scanning all the links, converting into absolute links and then displaying them in an array. i decided to mysql_query the array into the table but now i am stuck. it only posts 'Array', instead of every row from the array into a different row. Any ideas??! <?php require_once('simplehtmldom_1_5/simple_html_dom.php'); require_once('url_to_absolute/url_to_absolute.php'); $connect = mysql_connect("xxxx", "xxxx", "xxx") or die('Couldn\'t connect to MySQL Server: ' . mysql_error()); mysql_select_db("xxxx", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect )); $links = Array(); $URL = 'http://www.theqlick.com'; // change it for urls to grab // grabs the urls from URL $file = file_get_html($URL); foreach ($file->find('a') as $theelement) { $links[] = url_to_absolute($URL, $theelement->href); } print_r($links); mysql_query("INSERT INTO pages (url) VALUES ('$links[]')"); mysql_close($connect);

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  • how to fetch data using jquery

    - by user3566029
    I have tried to connect my index.php file in 000webhost.com using jQuery. From the site menu I have connected with 000webhost using FTP details available in 000webhost.com. When I tried to read data from jQuery it doesn’t working. Anyone please tell me what should I need to change? Should I need to connect my Dreamweaver database to webhost? If yes please explain? This is what I have done. index.php $mysql_host = "mysql0.000webhost.com"; $mysql_database = "a000000_mydb"; $mysql_user = "a000000_root"; $mysql_password = "******"; $conn=@mysql_connect ( $mysql_host,$mysql_user,$mysql_password )or die('aa'); mysql_select_db($mysql_database,$conn) or die('eoor on db'); $quer=mysql_query("SELECT * FROM sam"); $res=array(); while($row=mysql_fetch_row($quer)) { $res[]=$row; } print(json_encode($res)); return json_encode($res); mysql_close(); index.html $.get('public_html/index.php', function( data ) { alert( 'Successful' +data); });

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  • Zip multiple database PDF blob files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include '../config.php'; include '../connect.php'; $session = $_GET['session']; $query = "SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session = '$session'"; $result = mysql_query($query) or die('Error, query failed'); $files = array(); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { $files[] = "$username-$description.pdf"; } $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); exit(); ?>

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  • Trying to parse xml file for javascript quiz

    - by App_beginner
    Hi I am trying to create a javascript quiz, that gets the questions from a xml file. At the moment I am only starting out trying to parse my xml file without any success. Can anyone point me to what I am doing wrong? <html> <head> <title>Test</title> </head> <body> <div class="items"> </div> <script type="text/javascript"> var quizXML = '<quiz><Sporsmal tekst="bla bla bla"/><alternativer><tekst>bla</tekst><tekst>bli</tekst><tekst correct="yes">ble</tekst></alternativer><Sporsmal tekst="More blah"/><alternativer><tekst>bla bla</tekst><tekst correct="yes">bli bli</tekst><tekst>ble ble</tekst></alternativer></quiz>' var quizDOM = $.xmlDOM( quizXML ); quizDOM.find('quiz > Sporsmal').each(function() { var sporsmalTekst = $(this).attr('tekst'); var qDiv = $("<div />") .addClass("item") .addClass("sporsmal") .appendTo($(".spmArr")); var sTekst = $("<h2/>") .html(sporsmalTekst) .appendTo(qDiv); } </script> </body> </html> When I try this in my browser the classes and div are not being created. And the page is just blank. Am i doing something wrong when I intialize the xml?

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  • Prevent empty form input array from being posted?

    - by user355295
    Sorry if this has been answered somewhere; I'm not quite sure how to phrase the problem to even look for help. Anyway, I have a form with three text input boxes, where the user will input three song titles. I have simple PHP set up to treat those input boxes as an array (because I may want, say, 100 song titles in the future) and write the song titles to another document. <form method="post"> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <button type="submit" name="submit" value="submit">Submit</button> </form> <?php if (isset($_POST['submit'])) { $open = fopen("test.html", "w"); if(empty($_POST['songs'])) { } else { $songs = $_POST['songs']; foreach($songs as $song) { fwrite($open, $song."<br />"); }; }; }; ?> This correctly writes the song titles to an external file. However, even when the input boxes are empty, the external file will still be written to (just with the <br />'s). I'd assumed that the if statement would ensure nothing would happen if the boxes were blank, but that's obviously not the case. I guess the array's not really empty like I thought it was, but I'm not really sure what implications that comes with. Any idea what I'm doing wrong? (And again, I am clueless when it comes to PHP, so forgive me if this has been answered a million times before, if I described it horribly, etc.)

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  • Disabled input text color

    - by Incidently
    Hi The simple HTML below displays differently in Firefox and WebKit-based browsers (I checked in Safari, Chrome and iPhone). In Firefox both border and text have the same color (#880000), but in Safari the text gets a bit lighter (as if it had some transparency applied to it). Can I somehow fix this (remove this transparency in Safari)? UPDATE: Thank you for your answers. I don't need this for my work anymore (instead of disabling, I'm replacing input elements with styled div elements), but I'm still curious why this happens and if there is any way to control this behaviour ... <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> <style type="text/css"> input:disabled{ border:solid 1px #880000; background-color:#ffffff; color:#880000; } </style> </head> <body> <form action=""> <input type="text" value="disabled input box" disabled="disabled"/> </form> </body> </html>

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  • getting webpage contents using curl_init not working for some links

    - by Manish
    I am using this code to get contents of a url entered:- class MetaTagParser { public $metadata; private $html; private $url; public function __construct($url) { $this->url=$url; $this->html= $this->file_get_contents_curl(); $this->set_title(); $this->set_meta_properties(); } public function file_get_contents_curl() { $ch = curl_init(); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_URL, $this->url); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); $data = curl_exec($ch); curl_close($ch); return $data; } public function set_title() { $doc = new DOMDocument(); @$doc->loadHTML($this->html); $nodes = $doc->getElementsByTagName('title'); $this->metadata['title'] = $nodes->item(0)->nodeValue; } this class works for some pages but for some url like this one - http://www.dnaindia.com/india/report_in-a-first-upa-govt-tweets-the-press_1745346 when I try to fetch data I get this error:-"Warning: get_meta_tags(http://www.dnaindia.com/india/report_in-a-first-upa-govt-tweets-the-press_1745346): failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden in C:\xampp\htdocs\prac\index.php on line 52" it is not working, any ideas why this is happening??

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  • Fill fields on a webpage

    - by MajuiF
    Hi everyone, I've already asked this question, but it's still too unclear to me, and it seems people haven't understood what I'm trying to do, so I'll try and be clearer. This website: https://www4.polymtl.ca/poly/poly.html is the website I want to fill. What I would like to be able to do, is modify the values of the "nip", "code", and "naissance" fields with text (for example, code being "majuif"). <input type=password name=code size=8 maxlength=8> <input type=password name=nip size=8 maxlength=8> <input type=password name=naissance size=8 maxlength=8> However, I don't know how to do that. And this is my problem. Should I write another HTML file - I don't know if the word "macro" can be used for that, but I'm pretty sure it can - and insert JavaScript in it? Please note that I'm not a professional in JavaScript or HTML, but I have basics, and still learning. Thanks, -Max.

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  • retrieve only sub-pages (wordpress)

    - by Radek
    I want to list all sub-pages only one level though of one particular page. I was reading Function Reference/get pages and thought that $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; will do the trick but it is not working. It lists all pages on the same level like the page I call that code from. If I omit parent option I will get all pages even with sub-pages that I want. But I want only sub-pages. The whole function is like function about_menu(){ if (is_page('about')){ $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; foreach($pages as $page) { ?> <h2><a href="<?php echo get_page_link($page->ID) ?>"><?php echo $page->post_title ?></a></h2> <?php } } } and mine is second one

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  • ajax form handling an array

    - by moata_u
    am trying to handle an array comes from php file after submitting the form data , the value of data after submitting the form is = ARRAY but i cant use this array in any way , any idea how can i handle this array !!!! Javascript : $('#file').live('change',function(){ $('#preview').html(''); $('#preview').html('<img src="loader.gif" />'); $('#data').ajaxForm(function(data){ $(data['toshow']).insertBefore('.pic_content').hide().fadeIn(1000); }).submit(); }); PHP : .... ....etc echo json_encode(array('toshow'=>somedata,'data'=>somedata)); data come from php file {"toshow":"\r\n\t\t\t\t\r\n\t\t<table class=\"out\">\r\n\t\t\t<tr ><td class=\"img\"><a title=\"2012-06-02 01-22-09\" rel=\"prettyPhoto\" href=\"img\/2012-06-02 01-22-09.284.jpg\"><img src=\"img\/thumb\/2012-06-02 01-22-09.284.jpg\"\/><\/a><\/td><\/tr>\r\n\t\t\t\r\n\t\t\t<td>\r\n\t\t\t\t<table cellSpacing=\"1\" cellPadding=\"0\">\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">2012-06-02 01-22-09<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">Download<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><a href=\"img\/2012-06-02 01-22-09.284.jpg\"><span class=\"click\">View<\/span><\/a><\/td><\/tr>\r\n\t\t\t\t<\/table>\r\n\t\t\t<\/td>\r\n\t\t\t<\/tr>\r\n\t\t<\/table>","span":"<span class='text'><img src='greencheck.png'\/>2012-06-02 01-22-09 Uploaded ,File Size =152Kb <\/span>"}

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  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

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  • Cannot Display Data from MySQL table

    - by MxmastaMills
    I've got a pretty standard call to a MySQL database and for some reason I can't get the code to work. Here's what I have: $mysqli = mysqli_connect("localhost","username","password"); if (!$mysqli) { die('Could not connect: ' . mysqli_error($mysqli)); } session_start(); $sql = "SELECT * FROM jobs ORDER BY id DESC"; $result = $mysqli->query($sql); $num_rows = mysqli_num_rows($result); Now, first, I know that it is connecting properly because I'm not getting the die method plus I added an else conditional in there previously and it checked out. Then the page displays but I get the errors: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 11 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 12 I've double-checked my database and there is a table called jobs with a row of "id" (it's the primary row). The thing that confuses me is this is code that I literally copied and pasted from another site I built and for some reason the code doesn't work on this one (I obviously copy and pasted it and then just changed the table name and rows accordingly). I saw the error and tried: $num_rows = $mysqli_result->num_rows; $row_array = $mysqli_result->fetch_array; and that fixed the errors but resulted in no data being passed (because obviously $mysqli_result has no value). I don't know why the error is calling for that (is it a difference in version of MySQL or PHP from the other site)? Can someone help me track down the problem? Thanks so much. Sorry if it's something super simple that I'm overlooking, I've been at it for a while.

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  • Need help making a div appear on the bottom of the screen while the rest of the divs scroll

    - by user1896600
    It's hard to describe my specific problem without just showing you the HTML code. The HTML source can be seen easily from clicking "View Source" while seeing the page http://techdot.us/projects/jeopardy/view.php. The CSS is located here: http://techdot.us/projects/jeopardy/style/gameStyle.css. My main goal is to have the main content table rows/columns appear on the majority of the screen (everything except 69px, to be exact). So, the bottom 69px contains an informational panel that is supposed to stay on the bottom of the screen, even when the user scrolls down the page. Scrolling is supposed to, in theory, trigger the majority of the content to go down the page normally, except the bottom bar which stays static. I have achieved this effect on the website. However, there is a big problem. On smaller screens (as you can simulate by resizing the window), some of the main table gets cut off. It seems that my CSS solution is a botch, and, in effect, does not accomplish my main goal. The bottom bar should not cut off part of the table from the main content div (gameTable), but the main content div should display all of its content in a scrollable fashion. My CSS at the moment works as long as the viewer's screen is a certain pixel height. This is definitely not permanent. Thank you SO much for the help. I really appreciate it and totally understand that I'm being a total pain by just throwing down tons of CSS and HTML code to edit.

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  • Parameter error with Mysqli

    - by Morgan Green
    When I run this Query I recieve Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/morgan58/public_html/wow/includes/index/index_admin.php on line 188 SELECT * FROM characters WHERE id=5 Warning: mysqli_free_result() expects parameter 1 to be mysqli_result, boolean given in /home/morgan58/public_html/wow/includes/index/index_admin.php on line 194 The Query is running and it is strying to select the correct information, but for on the actual output it's giving me a fetch_array error; if anyone can see where the error lies it'd be much appreciated. Thank you. <?php $adminid= $admin->get_id(); $characterdb= 'characters'; $link = mysqli_connect("$server", "$user", "$pass", "$characterdb"); if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } $query = "SELECT * FROM characters WHERE id=$adminid"; $result = mysqli_query($link, $query); while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) { echo $query; echo $row['name']; } mysqli_free_result($result); mysqli_close($link); ?>

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  • Page does update with details from the database after i hit a button

    - by swathi
    I have a code and the way it should work is,when they click on NEW CUSTOMER,it takes them to test1.php where in they enter the details and they hit submit.it saves all the details in properly in the database and when i go back and hit REFRESH ,it should come up with the customer details which they had entered in previously. But what happens is, when i click on the REFRESH,it refreshes the same old page which is empty.I wanted to find out where am i missing the logic.Thanks in advance. The sample code would be <tr> <td class="tdvisitbig" colspan="5">THIS IS A TEST</td> </tr> <tr> <td class='tdvisitbig' colspan="5"><input type="button" onClick="openVisit('test1.php?id=<?=$key?>&name=<?=$name?>');return false;" value="NEW CUSTOMER" class="submit">&nbsp;<input type="button" value="REFRESH" name="add_xyz" class="submit" onClick="document.add.target='_self';document.add.action='test3.php?redirect=visit&section=test page';document.add.submit();"></td> </tr> <? $q = "SELECT address,customernum,status FROM customer WHERE name='$name' ORDER BY customernum"; $r = mysql_query( $q , $Link ); while( $rw = mysql_fetch_assoc( $r ) ) { extract( $rw ); ?> <tr> <? } ?>

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