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  • PHP PDO Parameters from a function returned array

    - by noko
    I've got a function written that runs a query based on parameters passed to the function. I can't seem to figure out why doing the following returns a result: function test($function_returned_array) { $variable = 'Hello World'; $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $variable); } While this doesn't return any results: function test2($function_returned_array) { $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $function_returned_array[0]); } $function_returned_array[0] is also equal to 'Hello World'. Shouldn't they both return the same results? When I echo the values of $variable and $function_returned_array[0], they are both 'Hello World' Here's the relevant parts of my PDO wrapper: public function query(&$query, $params) { $sth = $this->_db->prepare($query); if(is_null($params)) { $sth->execute(); } else if(is_array($params)) { $sth->execute($params); } else { $sth->execute(array($params)); } $this->_rows = $sth->rowCount(); $this->_counter++; return $sth; } public function get_array(&$query, $params, $style = PDO::FETCH_ASSOC) { $q = $this->query($query, $params); return $q->fetchAll($style); } I'm using PHP 5.3.5. Any help would be appreciated.

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  • C++ Recursive function that reverses the order of an array's indexes between two bounds

    - by CPT Kirk
    I am trying to write a recursive function that has three arguments; an array and two array indexes. The function should reverse the order of the values between the two indexes. I would like to understand what is happening instead of just being told an answer. Here is my code so far: #include <iostream> using namespace std; char switchAroo(char a[], int b1, int b2); int main() { char a[6] {'A', 'B', 'C', 'D', 'E', '\0'}; cout << a; switchAroo(a, 2, 5); return 0; } char switchAroo(char a [], int b1, int b2) { char temp; if (b1 == b2) cout << "The array after switchAroo is " << a << endl; else { temp = a[b1]; a[b1] = a[b2]; a[b2] = temp; b1++; b2--; return switchAroo(a, b1, b2); } } I am getting the following warning code: warning C4715: 'switchAroo' : not all control paths return a value Any help would be greatly appreciated.

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  • Put an array of Objects in nodes of another array of Objects [JAVA]

    - by zengr
    public class hello { public static void main(String[] args) { Object[] newarray = new Object[1]; Object[] obj = new Object[2]; obj[0] = "Number1"; //string value obj[1] = "Number2"; //string value newarray[0] = obj; //this works Object[] tmp_obj = new Object[2]; tmp_obj = newarray[0]; //obviously does not work System.out.println(tmp_obj[0]); //nope System.out.println(tmp_obj[1]); //nope } } So, now if I want to access the values "Number1" and "Number2" which are stored in obj[0] and obj[1]; obj is in newarray[0]. what should I do? Is this a possible? Thanks

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  • dreferencing 2 d array

    - by ashish-sangwan
    Please look at this peice of code :- #include<stdio.h> int main() { int arr[2][2]={1,2,3,4}; printf("%d %u %u",**arr,*arr,arr); return 0; } When i compiled and executed this program i got same value for arr and *arr which is the starting address of the 2 d array. For example:- 1 3214506 3214506 My question is why does dereferencing arr ( *arr ) does not print the value stored at the address contained in arr ?

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  • Duplicate array but maintain pointer links

    - by St. John Johnson
    Suppose I have an array of nodes (objects). I need to create a duplicate of this array that I can modify without affecting the source array. But changing the nodes will affect the source nodes. Basically maintaining pointers to the objects instead of duplicating their values. // node(x, y) $array[0] = new node(15, 10); $array[1] = new node(30, -10); $array[2] = new node(-2, 49); // Some sort of copy system $array2 = $array; // Just to show modification to the array doesn't affect the source array array_pop($array2); if (count($array) == count($array2)) echo "Fail"; // Changing the node value should affect the source array $array2[0]->x = 30; if ($array2[0]->x == $array[0]->x) echo "Goal"; What would be the best way to do this?

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  • Get Next and Previous Elements in JavaScript array...

    - by Belden
    I have a large array, with non-sequential IDs, that looks something like this: PhotoList[89725] = new Array(); PhotoList[89725]['ImageID'] = '89725'; PhotoList[89725]['ImageSize'] = '123'; PhotoList[89726] = new Array(); PhotoList[89726]['ImageID'] = '89726'; PhotoList[89726]['ImageSize'] = '234'; PhotoList[89727] = new Array(); PhotoList[89727]['ImageID'] = '89727'; PhotoList[89727]['ImageSize'] = '345'; Etc.... I'm trying to figure out, given an ID, how can I can get the next and previous ID... So that I could do something like this: <div id="current">Showing You ID: 89726 Size: 234</div> Get Prev Get Next Obviously, if we're at the end or beginning of the array we just a message...

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  • read the dictionary value from array

    - by ben martin
    CALORIES = \ { 'Beef' : 200, \ 'Chicken' : 140, \ } class Food(): __slots__ = ( 'cal' # Calories ) def mkFood( name ): """Create and return a newly initialized Food item""" result = Food() result.cal = calorie in dict(CALORIES[1]) return result Is that a proper way to the value of the target item in Calories? Like getting 200, 140, such like that. result.cal = calorie in dict(CALORIES[1])

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  • Storing database records into array

    - by zerey
    I would want to create an array that will hold records retrieved from a database using a query of SELECT statement. The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function? alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..

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  • why doesnt this program print?

    - by Alex
    What I'm trying to do is to print my two-dimensional array but i'm lost. The first function is running perfect, the problem is the second or maybe the way I'm passing it to the "Print" function. #include <stdio.h> #include <stdlib.h> #define ROW 2 #define COL 2 //Memory allocation and values input void func(int **arr) { int i, j; arr = (int**)calloc(ROW,sizeof(int*)); for(i=0; i < ROW; i++) arr[i] = (int*)calloc(COL,sizeof(int)); printf("Input: \n"); for(i=0; i<ROW; i++) for(j=0; j<COL; j++) scanf_s("%d", &arr[i][j]); } //This is where the problem begins or maybe it's in the main void print(int **arr) { int i, j; for(i=0; i<ROW; i++) { for(j=0; j<COL; j++) printf("%5d", arr[i][j]); printf("\n"); } } void main() { int *arr; func(&arr); print(&arr); //maybe I'm not passing the arr right ? }

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  • Is it OK to run an array with 22k strings in a PHP code on a shared web host?

    - by kuchikoo
    I'm new to writing code so kindly bear with me if this is a very noobish question. A couple of days back I asked a question about a PHP code that matches the the query entered by users on my website to an array stored within the PHP code and displays the matched queries. Here is the code I'm talking about Now I've ended up with a rather large list (over 22k) of strings that have to be stored in the array. Is it ok to run it like this? I'm hosting the site on a shared hostgator package, will this cause my site to crash? I don't know too much about DBs but can I somehow store this on MySQL instead of having it in the code?

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  • Can somebody please explain this recursive function for me?

    - by capncoolio
    #include <stdio.h> #include <stdlib.h> void reprint(char *a[]) { if(*a) { printf("%d ",a); reprint(a+1); printf("%s ",*a); } } int main() { char *coll[] = {"C", "Objective", "like", "don't", "I", NULL}; reprint(coll); printf("\n"); return EXIT_SUCCESS; } As the more experienced will know, this prints the array in reverse. I don't quite understand how! I need help understanding what reprint(char *a[]) does. I understand pointer arithmetic to a degree, but from inserting printf's here and there, I've determined that the function increments up to the array end, and then back down to the start, only printing on the way down. However, I do not understand how it does this; all I've managed to understand by looking at the actual code is that if *a isn't NULL, then call reprint again, at the next index. Thanks guys!

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  • Moving x,y position of all array objects every frame in actionscript 3?

    - by Dylan Gallardo
    I have my code setup so that I have an movieclip in my library a class called "block" being duplicated multiple times and added into an array like this: function makeblock(e:Event){ newblock=new block; newblock.x=10; newblock.y=10; addChild(newblock); myarray[counter] = newblock; //adds a newblock object into array counter += 1; } Then I have a loop with a currently primitive way of handling my problem: stage.addEventListener(Event.ENTER_FRAME, gameloop); function gameloop(evt:Event):void { if (moveright==true){ myarray[0].x += 5; myarray[1].x += 5; myarray[2].x += 5 -(and so on)- My question is how can I change x,y values every frame for new objects duplicated into the array, along with the previous ones that were added. Of course with a more elegant way than writing it out myself... array[0].x += 5, array[1], array[2], array[3] etc. Ideally I would like this to go up to 500 or more array objects for one array so obviously I don't want to be writing it out individually haha, I also need it to be consistent with performance so using a for loop or something to loop through the whole array and move each x += 5 wouldn't work would it? Anyway, if anyone has any ideas that'd be great!

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  • Simple Array in java

    - by user1311590
    I need to create the following in my main method. Create an array of size 100 doubles. write a loop to sotr the number 150.0 - 249.0 in the 100 location. public class Lab6_2 { public static void main(String[] args) { double[] values; values = new double [100]; double i = 0; for(double i = 150.0; i<249.0;i++){ System.out.println(values[99]); } } }

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  • how to call array values based on the main id they linked to?

    - by veronica george
    In page one, $add_id2=implode(',',$add_id); //result is 1,4 $item_type2=implode(',',$item_type_2); //result is 8,16 $final_total2=implode(',',$final); //result is 150,430 I pass these values via URL to the page two and store them in session. $_SESSION['cart'][$car]= array ('car'=>$car, 'loc_1'=>$location, array ( 'addon_id'=>$a_id, 'item_type'=>$item_type2, 'final_total'=>$final_t ) ); I call them like this, foreach($_SESSION['cart'] as $cart=>$things) { //display main array value like car id and location id echo $cart; foreach($things as $thing_1=>$thing_2) { foreach($thing_2['addon_id'] as $thi_2=>$thi_4) { //to display addons item for the car id //this is the id for each addon under the above car //echo $thi_2; //this is to echo addon id $thi_4; } } } The above loop works . the addon items array loops through inside main array which is car. If there were two addon items chosen then the addon array will loop twice. Now al I need to do is, How to make $item_type2 and $final_total2 display the value according to the addon id? PS: Same addon items can be chosen multiple times. They are identified uniquely by id(//echo $thi_2;). Thanks.

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  • function.array-diff problems!

    - by SKY
    Hi, im currently getting these error on my site: Warning: array_keys() [function.array-keys]: The first argument should be an array on line 43 Warning: Invalid argument supplied for foreach() on line 44 Warning: array_diff() [function.array-diff]: Argument #1 is not an array on line 47 Warning: array_diff() [function.array-diff]: Argument #1 is not an array on line 48 And the source are: 42. $tmp = $this->network->get_user_follows($this->user->id); 43. $tmp = array_keys($tmp->followers); 44. foreach($tmp as &$v) { $v = intval($v); } 45. $tmp2 = array_keys($this->network->get_group_members($g->id)); 46. foreach($tmp2 as &$v) { $v = intval($v); } 47. $tmp = array_diff($tmp, $tmp2); 48. $tmp = array_diff($tmp, array(intval($this->user->id))); I want to know what is the problem and how i fix it. Thanks!

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  • php weird bug where an array is not an array !

    - by iko
    I've been going mad trying to figure out why an array would not be an array in php. For a reason I can't understand I have a bug in a smarty class. The code is this : $compiled_tags = array(); for ($i = 0, $for_max = count($template_tags); $i < $for_max; $i++) { $this->_current_line_no += substr_count($text_blocks[$i], "\n"); // I tried array push instead to see // bug is here array_push($compiled_tags,$this->_compile_tag($template_tags[$i])); //$compiled_tags[] = $this->_compile_tag($template_tags[$i]); $this->_current_line_no += substr_count($template_tags[$i], "\n"); } the error message is Warning: array_push() expects parameter 1 to be array, integer given in .... OR before with [] Warning: Cannot use a scalar value as an array in .... I trying a var_debug on $compiled_tags and as soon I enter the for loop is not an array anymore but an integer. I tried renaming the variable, but same problem. I'm sure is something simple that I missed but I can't figure it out. Any help is (as always) welcomed !

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  • Modifying MySQL Where Statement Based on Array

    - by Ryan
    Using an array like this: $data = array ( 'host' => 1, 'country' => 'fr', ) I would like to create a MySQL query that uses the values of the array to form its WHERE clause like: SELECT * FROM table WHERE host = 1 and country = 'fr' How can I generate this query string to use with MySQL?

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  • C++ : Declaring the array size with a non-constant variable

    - by Jérôme
    I always thought that when declaring an array in C++, the size has to be a constant integer value. For instance : int MyArray[5]; // correct or const int ARRAY_SIZE = 6; int MyArray[ARRAY_SIZE]; // correct but int ArraySize = 5; int MyArray[ArraySize]; // incorrect Here is also what is explained in The C++ Programming Language, by Bjarne Stroustrup : The number of elements of the array, the array bound, must be a constant expression (§C.5). If you need variable bounds, use a vector(§3.7.1, §16.3). For example: void f(int i) { int v1[i]; // error : array size not a constant expression vector<int> v2[i]; // ok } But to my big surprise, the code above does compile fine on my system ! Here is what I tried to compile : void f(int i) { int v2[i]; } int main() { int i = 3; int v1[i]; f(5); } I got no error ! I'm using GCC v4.4.0. Is there something I'm missing ?

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  • : for displaying all elements in a multidimensional array in python 3.1.

    - by Leif Andersen
    I have a multidimensional array in python like: arr = [['foo', 1], ['bar',2]] Now, if I want to print out everything in the array, I could do: print(arr[:][:]) Or I could also just do print(arr). However, If I only wanted to print out the first element of each box (for arr, that would be 'foo', 'bar'), I would imagine I would do something like: print(arr[:][0]) however, that just prints out the first data blog (['foo', 1]), also, I tried reversing it (just in case): print(arr[0][:]) and I got the same thing. So, is there anyway that I can get it to print the first element in each tuple (other than: for tuple in arr: print(tuple[0]) )? Thanks.

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  • Issue pushing object into an array JS

    - by Javacadabra
    I'm having an issue placing an object into my array in javascript. This is the code: $('.confirmBtn').click(function(){ //Get reference to the Value in the Text area var comment = $("#comments").val(); //Create Object var orderComment = { 'comment' : comment }; //Add Object to the Array productArray.push(orderComment); //update cookie $.cookie('order_cookie', JSON.stringify(productArray), { expires: 1, path: '/' }); }); However when I print the array this is the output: Array ( [0] => Array ( [stockCode] => CBL202659/A [quantity] => 8 ) [1] => Array ( [stockCode] => CBL201764 [quantity] => 6 ) [2] => TEST TEST ) I would like it to look like this: Array ( [0] => Array ( [stockCode] => CBL202659/A [quantity] => 8 ) [1] => Array ( [stockCode] => CBL201764 [quantity] => 6 ) [2] Array( [comment] => TEST TEST ) I added products to the array in a similar way and it worked fine: var productArray = []; // Will hold order Items $(".orderBtn").click(function(event){ //Check to ensure quantity > 0 if(quantity == 0){ console.log("Quantity must be greater than 0") }else{//It is so continue //Show the order Box $(".order-alert").show(); event.preventDefault(); //Get reference to the product clicked var stockCode = $(this).closest('li').find('.stock_code').html(); //Get reference to the quantity selected var quantity = $(this).closest('li').find('.order_amount').val(); //Order Item (contains stockCode and Quantity) - Can add whatever data I like here var orderItem = { 'stockCode' : stockCode, 'quantity' : quantity }; //Check if cookie exists if($.cookie('order_cookie') === undefined){ console.log("Creating new cookie"); //Add object to the Array productArray.push(orderItem);

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  • Sorting an array based on its value

    - by MaxerDude
    I have an Array, Sample: $array { [0] { [something]=1; [something2]=2; } [1] { [something]=2; [something2]=4; } [2] { [something]=5; [something2]=2; } } I want to order the array based on the key something; So it will look like: $array { [0] { [something]=5; [something2]=2; } [1] { [something]=2; [something2]=4; } [2] { [something]=1; [something2]=2; } }

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  • Extreamely fast way to clone the values of an array into a second array?

    - by George
    I am currently working on an application that is responsible for calculating random permutations of a multidemensional array. Currently the bulk of the time in the application is spent copying the array in each iteration (1 million iterations total). On my current system, the entire process takes 50 seconds to complete, 39 of those seconds spent cloning the array. My array cloning routine is the following: public static int[][] CopyArray(this int[][] source) { int[][] destination = new int[source.Length][]; // For each Row for (int y = 0; y < source.Length; y++) { // Initialize Array destination[y] = new int[source[y].Length]; // For each Column for (int x = 0; x < destination[y].Length; x++) { destination[y][x] = source[y][x]; } } return destination; } Is there any way, safe or unsafe, to achieve the same effect as above, much faster?

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  • ValueError: setting an array element with a sequence.

    - by MedicalMath
    This code: import numpy as p def firstfunction(): UnFilteredDuringExSummaryOfMeansArray = [] MeanOutputHeader=['TestID','ConditionName','FilterType','RRMean','HRMean','dZdtMaxVoltageMean','BZMean','ZXMean' ,'LVETMean','Z0Mean','StrokeVolumeMean','CardiacOutputMean','VelocityIndexMean'] dataMatrix = BeatByBeatMatrixOfMatrices[column] roughTrimmedMatrix = p.array(dataMatrix[1:,1:17]) trimmedMatrix = p.array(roughTrimmedMatrix,dtype=p.float64) myMeans = p.mean(trimmedMatrix,axis=0,dtype=p.float64) conditionMeansArray = [TestID,testCondition,'UnfilteredBefore',myMeans[3], myMeans[4], myMeans[6], myMeans[9] , myMeans[10], myMeans[11], myMeans[12], myMeans[13], myMeans[14], myMeans[15]] UnFilteredDuringExSummaryOfMeansArray.append(conditionMeansArray) secondfunction(UnFilteredDuringExSummaryOfMeansArray) return def secondfunction(UnFilteredDuringExSummaryOfMeansArray): RRDuringArray = p.array(UnFilteredDuringExSummaryOfMeansArray,dtype=p.float64)[1:,3] return firstfunction() Throws this error message: File "mypath\mypythonscript.py", line 3484, in secondfunction RRDuringArray = p.array(UnFilteredDuringExSummaryOfMeansArray,dtype=p.float64)[1:,3] ValueError: setting an array element with a sequence. However, this code works: import numpy as p a=range(24) b = p.reshape(a,(6,4)) c=p.array(b,dtype=p.float64)[:,2] I re-arranged the code a bit to put it into a cogent posting, but it should more or less have the same result. Can anyone show me what to do to fix the problem in the broken code above so that it stops throwing an error message?

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