Search Results

Search found 56787 results on 2272 pages for 'jacob lehrbaum@oracle com'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 680/2272 | < Previous Page | 676 677 678 679 680 681 682 683 684 685 686 687  | Next Page >

  • Paypal's "Security header is not valid"

    - by Paypal
    I'm implementing the Express Checkout? I have no problem with the first two steps:SetExpressCheckout and GetExpressCheckout,but met the "Security header is not valid" at DoExpressCheckout. The API credentials are the same! I've fixed it by changing the $environment to live in DoExpressCheckout.(The difference is that it'll use https://api.sandbox.paypal.com/nvp/ instead of https://api-3t.$environment.paypal.com/nvp) But why? Is there something wrong with https://api-3t.$environment.paypal.com/nvp?

    Read the article

  • Capistrano SSH::AuthenticationFailed, not prompting for password

    - by Sparkmasterflex
    I've been using capistrano successfully for a while now and all of a sudden in every project I've lost the ability to deploy. Environment: os X (Mavericks) ruby 1.9.3p194 rvm (locally, not on server) rails 3.2 and up RubyGems 1.8.25 I'm not using rsa_keys or anything I want capistrano to prompt for user and password. Suddenly it has decided not to ask for a password, but does ask for user. Then it rolls back and gives me the following error. [deploy:update_code] exception while rolling back: Capistrano::ConnectionError, connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) connection failed for: sub.example.com (Net::SSH::AuthenticationFailed: Authentication failed for user [email protected]) This has occurred on my personal laptop and my iMac at work. It occurs when deploying to two different servers (both linux) I'm completely at a loss here. Any ideas?

    Read the article

  • How can I fit an Image into another imageview

    - by user1597833
    I have an imageview with a default image already set from the xml, and I want to change it's image pragmatically so that the new image will scale to the previous image size, both of the images are rounded. I have tried setting the scaleType attribute to different values before setting the new image but it didn't work. This is the xml: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" > <ImageView android:id="@+id/up_right_circle_firstiv" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" android:scaleType="fitXY" android:src="@drawable/circle_medium_up" /> This is the activity code: public class MainActivity extends Activity { ImageView middleCircle; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); middleCircle = (ImageView) findViewById(R.id.up_right_circle_firstiv); middleCircle.setImageResource(R.drawable.round_pic_one); } } Inside the activity. I have uploaded the screenshots: http://imgur.com/OM79T http://imgur.com/G7y3Q

    Read the article

  • How do I get the path of the current executed file in python?

    - by Sorin Sbarnea
    This may seam a newbie question but it is not. It looks that common approaches are not always working: Currently I know only two options but none of them looks to work an all cases. sys.argv[0] This means using path = os.path.abspath(os.path.dirname(sys.argv[0])) but this does not work if you are running from another python script from another directory, and this can really happen in real life. __file__ this means that path = os.path.abspath(os.path.dirname(__file__)) but I found that this doesn't work: py2exe that doesn't have a __file__ attribute but there is an workaround. when you run from IDLE with execute() there is no __file__ attribute OS X 10.6 where I get NameError: global name '__file__' is not defined Related questions with incomplete answers: http://stackoverflow.com/questions/1296501/python-find-path-to-file-being-run http://stackoverflow.com/questions/1483827/python-path-to-current-file-depends-on-how-i-execute-the-program http://stackoverflow.com/questions/2259503/how-to-know-the-path-of-the-running-script-in-python http://stackoverflow.com/questions/509742/python-chdir-to-dir-the-py-script-is-in

    Read the article

  • Remove .php extension (explicitly written) for friendly URL

    - by miquel
    htaccess to remove the .php extension of my site's files. RewriteEngine on RewriteBase / RewriteCond %{SCRIPT_FILENAME} !-d RewriteCond %{SCRIPT_FILENAME} !-f RewriteRule ^(.*)$ $1.php [L,QSA] Now, if I go to my site www.mysite.com/home works fine, it redirects to home.php but the URL is still friendly. But if I write this URL: www.mysite.com/home.php The home.php is served, and the URL is not friendly. How can I avoid this behavior? I want that if the user writes www.mysite.com/home.php, the URL displayed in the URL bar be www.mysite.com/home

    Read the article

  • Compiling a list of audio + video players (flash / javascript / otehr) that I can embed into a websi

    - by FiveTools
    I'm compiling a list of audio + video players (flash / javascript / other) that I can embed into a website. flowplayer: http://flowplayer.org/ jw player: http://www.longtailvideo.com/players/ premium beat: http://www.premiumbeat.com/flash_resources/free_flash_music_player/ xspf web player: http://musicplayer.sourceforge.net/ yahoo media player: http://mediaplayer.yahoo.com/ any popular ones I'm missing? (anyone know if I can skin / customize any of them to operate similar to the Windows vista volume control?)

    Read the article

  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

    Read the article

  • Mod Rewriting Image Location Not Working Very Well

    - by Belgin Fish
    Hey, I'm trying to mod rewrite the image locations on my site, I'm just using this : rewriteRule ^thumbs/(.*)$ http://site2.com/images/$1 [L] so that I can redirect all image requests going from http://site1.com/thumbs/something to http://site2.com/thumbs/something But only some of the images are loading, and not all of them. Thanks!

    Read the article

  • ListView is Widget(View) or Layout(Viewgroup)?

    - by Manoj Maurya
    Hi All, I need your help to explore few topics in Android. My understanding is Widget is View and Layout is ViewGroups in Android. I described the problems as below- Please go through the below links- developer.android.com/guide/topics/ui/custom-components.html- (add http:// in the beginning) developer.android.com/resources/tutorials/views/index.html - (add http:// in the beginning) In the first link ListView is included as Widget and in the Second link ListView has been shown as Layout. So, is ListView is Widget(View) or Layout(Viewgroup)? Same is the case for Spinner in Andriod developer.android.com/resources/tutorials/views/hello-spinner.html- (add http:// in the beginning) (Link- says Spinner is Widget(View)) developer.android.com/guide/topics/ui/layout-objects.html- (add http:// in the beginning) says Spinner is Layout(ViewGroup) So, Spinner is View or ViewGroup? Please update me with your views?

    Read the article

  • Google Data Api returning an invalid access token

    - by kingdavies
    I'm trying to pull a list of contacts from a google account. But Google returns a 401. The url used for requesting an authorization code: String codeUrl = 'https://accounts.google.com/o/oauth2/auth' + '?' + 'client_id=' + EncodingUtil.urlEncode(CLIENT_ID, 'UTF-8') + '&redirect_uri=' + EncodingUtil.urlEncode(MY_URL, 'UTF-8') + '&scope=' + EncodingUtil.urlEncode('https://www.google.com/m8/feeds/', 'UTF-8') + '&access_type=' + 'offline' + '&response_type=' + EncodingUtil.urlEncode('code', 'UTF-8') + '&approval_prompt=' + EncodingUtil.urlEncode('force', 'UTF-8'); Exchanging the returned authorization code for an access token (and refresh token): String params = 'code=' + EncodingUtil.urlEncode(authCode, 'UTF-8') + '&client_id=' + EncodingUtil.urlEncode(CLIENT_ID, 'UTF-8') + '&client_secret=' + EncodingUtil.urlEncode(CLIENT_SECRET, 'UTF-8') + '&redirect_uri=' + EncodingUtil.urlEncode(MY_URL, 'UTF-8') + '&grant_type=' + EncodingUtil.urlEncode('authorization_code', 'UTF-8'); Http con = new Http(); Httprequest req = new Httprequest(); req.setEndpoint('https://accounts.google.com/o/oauth2/token'); req.setHeader('Content-Type', 'application/x-www-form-urlencoded'); req.setBody(params); req.setMethod('POST'); Httpresponse reply = con.send(req); Which returns a JSON array with what looks like a valid access token: { "access_token" : "{access_token}", "token_type" : "Bearer", "expires_in" : 3600, "refresh_token" : "{refresh_token}" } However when I try and use the access token (either in code or curl) Google returns a 401: curl -H "Authorization: Bearer {access_token}" https://www.google.com/m8/feeds/contacts/default/full/ Incidentally the same curl command but with an access token acquired via https://code.google.com/oauthplayground/ works. Which leads me to believe there is something wrong with the exchanging authorization code for access token request as the returned access token does not work. I should add this is all within the expires_in time frame so its not that the access_token has expired

    Read the article

  • <jaxrs:client> not getting autowired

    - by himangshu
    I am trying to build a restful client using jaxrs:client as defined in http://svn.apache.org/repos/asf/cxf/trunk/systests/jaxrs/src/test/resources/jaxrs_soap_rest/WEB-INF/beans.xml In my test class I am getting org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'com.abc.service.ExportServiceTest': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private com.bankbazaar.service.ExportService com.abc.service.ExportServiceTest.exportClient; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [com.abc.service.ExportService] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true), @org.springframework.beans.factory.annotation.Qualifier(value=exportClient)} this is my spring config However exportClient=(ExportService)applicationContext.getBean("exportClient"); this works. Thanks Himangshu

    Read the article

  • What proxy engine do it use??

    - by Nok Imchen
    Well, i've seached for thousands of proxies like glype etc... Just a few mins back, i came across this proxy site agentanon.com It is a very powerful proxy. You can check its proxify power by open the twitter signup page. Thi stwitter signup page works in no glype proxies. But agentanon.com supports the twitter signup page. Now, what i need help from us is: What script do agentanon.com use?? Note: I'm in no way affilated to agentanon.com or twitter !

    Read the article

  • protect (encrypt) password in the web.config file (asp.net)

    - by Hazro City
    <system.net> <mailSettings> <smtp from="email@domain.com" deliveryMethod="Network"> <network clientDomain="www.domain.com" host="smtp.live.com" defaultCredentials="false" port="25" userName=" email@domain.com " password="password" enableSsl="true" /> </smtp> </mailSettings> </system.net> This is the case where I need encryption for my password. I searched and googled much on the web but I can’t be able to encrypt anymore. Can anyone help me do this in a simple but secure way.

    Read the article

  • Ideas Needed for a Base Code System

    - by Tegan Snyder
    I've developed a PHP web application that is currently in need of a strategic restructuring. Currently when we setup new clients we give them the entire code base on a subdomain of our main domain and create a new table for them in the database. This results in each client having the entire codebase, meaning when we make bug changes, fixes we have to go back and apply them independently across all clients and this is a pain. What I'd like to create is a base code server that holds all the core PHP files. base.domain.com Then all of our clients (client.domain.com) will only need a few files: config.php would have the database connection information. index.php - displays the login box if session non-existant, otherwise it loads baseline code via remote includes to base.domain.com. My question is does my logic seem feasible? How do other people handle similar situations by having a base code? Also.... Is it even possbile to remotely include PHP files from base.domain.com and include them in client.domain.com? Thanks, Tegan

    Read the article

  • Why does JPA require a no-arg constructor for domain objects ?

    - by Jacques René Mesrine
    Why does JPA require a no-arg constructor for domain objects ? I am using eclipselink and just got this exception during deployment. Exception [EclipseLink-63] (Eclipse Persistence Services-1.1.0.r3639-SNAPSHOT): org.eclipse.persistence.exceptions.DescriptorException Exception Description: The instance creation method [com.me.model.UserVO.<Default Constructor>], with no parameters, does not exist, or is not accessible. Internal Exception: java.lang.NoSuchMethodException: com.me.model.UserVO.<init>() Descriptor: RelationalDescriptor(com.me.model.UserVO --> [DatabaseTable(user)])

    Read the article

  • setup apache virtualhost (windows)

    - by nightingale2k1
    Hi, How to setup virtualhost for multiple domain name on windows ? I will use it for my own test projects. I have 3 projects that I need to setup and at the moment I'm using xampplite for the portable apache. www.foo-bar.com -- direct to c:\xampplite\htdocs\foo-bar\ www.abcdef.com -- directo to c:\xampplite\htdocs\abcdef\ www.qwerty.com -- direct to c:\xampplite\htdocs\qwerty\web\ I also need to access on another project but it just like typing http://localhost/my-project/ how to write the vhost configuration for that ?

    Read the article

  • root path for multiple controllers on rails routes

    - by Lee
    I have two resource controllers where I am using a slug to represent the ID. (friendly_id gem). I am able to have the show path for one resource on the route but not for two at the same time. ie. root :to => 'home#index' match '/:id' => "properties#show" match '/:id' => "contents#show" Basically I want urls like, # Content domain.com/about-us domain.com/terms # Property domain.com/unique-property-name domain.com/another-unique-property-name Whatever resource I put on top works. Is there a way to do this? Thanks in advace if you can help.

    Read the article

  • Why can't I put a jquery-ui progressbar inside a div with fixed position?

    - by Matthew
    I started the source from this progressbar example, and it works fine. My only change was to set the width of the progressbar to "20%". <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="progressbar"></div> </body> </html> I then put the progressbar inside another div, and used css to fix that div in the upper-right-hand corner. <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <style type="text/css"> #testContainer { position : fixed; top : 6; right : 6; } </style> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="testContainer"> <div id="progressbar"></div> </div> </body> </html> The progressbar becomes a slim vertical line on the left side of the screen. What am I doing wrong? I'm new to web development in general, and jquery in particular, so please forgive me if this is a stupid question.

    Read the article

  • c# how to add smtp hotmail account to send mail

    - by leventkalayz
    I wrote some codes so as to send e mail but I can only send mail from gmail account to gmail account also, I want to use hotmail accounts how can i do it? thanks It is SmtpClient SmtpServer = new SmtpClient("smtp.gmail.com"); mail.From = new MailAddress("kalaylevent@gmail.com"); mail.To.Add("kalaylevent@gmail.com"); mail.Subject = "Test Mail - 1"; mail.IsBodyHtml = true; string htmlBody; htmlBody = "Write some HTML code here"; mail.Body = htmlBody; SmtpServer.Port = 587; SmtpServer.Credentials = new System.Net.NetworkCredential("kalaylevent@gmail.com", "mypassword"); SmtpServer.EnableSsl = true; SmtpServer.Send(mail);

    Read the article

  • display image in image control

    - by KareemSaad
    I had Image control and I added code to display images But there is not any image displayed ASPX: <body> <form id="form1" runat="server"> <div dir='<%= sDirection %>'> <div id="ContentImage" runat="server"> <asp:Image ID="Image2" runat="server" /> </div> </div> </form> </body> C#: using (System.Data.SqlClient.SqlConnection con = Connection.GetConnection()) { string Sql = "Select Image From AboutUsData Where Id=@Id"; System.Data.SqlClient.SqlCommand com = new System.Data.SqlClient.SqlCommand(Sql, con); com.CommandType = System.Data.CommandType.Text; com.Parameters.Add(Parameter.NewInt("@Id", Request.QueryString["Id"].ToString())); System.Data.SqlClient.SqlDataReader dr = com.ExecuteReader(); if (dr.Read() && dr != null) { Image1.ImageUrl = dr["Image"].ToString(); } }

    Read the article

  • problem with twitter api friends_timeline

    - by siznax
    i can get my user_timeline fine: curl -u user:pwd http://www.twitter.com/statuses/user_timeline/user.json {blob of tweets} but when i try to get the friends_timeline, i get an auth error: curl -u user:pwd http://www.twitter.com/statuses/friends_timeline.json {"request":"\/statuses\/friends_timeline.json", "error":"Could not authenticate you."} do i just not understand the documentation? http://apiwiki.twitter.com/REST+API+Documentation#friendstimeline

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 676 677 678 679 680 681 682 683 684 685 686 687  | Next Page >