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  • Another application in the dialog in facebook?

    - by simple
    I have a fanpage which has a tab/facebook application, that renders some info from my server in this application(tab) I want to have button that will open up a dialog box where I would like to refer to another application. Is it possible? and any suggestion concerning how to implement this would be appreciated PS. the Application that I want to have inside the popup is going to ask to login first and if logged in show for for inviting friends

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  • SVN checkout browser

    - by phazei
    I've been looking all over for a SVN browser. Now I'm not talking about anything like WebSVN or TRAC, I don't want to browse the repository; I want to browse the checkout. I'm looking for a program that lets me browse the checkout (working copy) and shows me the info I'd normally need to SSH for. So I could mark specific files or folders for some commit button, or see the status, or view a diff between the working and a prev version. Basically a web GUI for a svn checkout. A [windows] program that can let you work on a remote checkout as if it were local would also work. Currently I have a checkout on my server running under dev.mysite.com. I log in via ftp and edit and upload the files. I also keep SSH open so I can do a svn st to see what files I've worked on and to commit changes. I want to work on the files on the same environment so I can't simply use a local checkout. But I don't want to need to work via SSH. Are there any apps such as I described? Like a repo browser but for checkouts to do commits. Like WebTortoiseSVN or such. Thanks

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  • Best Practice for Uploading Many (2000+) Images to A Server

    - by bob
    Hello, I have a general question about this. When you have a gallery, sometimes people need to upload 1000's of images at once. Most likely, it would be done through a .zip file. What is the best way to go about uploading this sort of thing to a server. Many times, server have timeouts etc. that need to be accounted for. I am wondering what kinds of things should I be looking out for and what is the best way to handle a large amount of images being uploaded. I'm guessing that you would allow a user to upload a zip file (assuming the timeout does not effect you), and this zip file is uploaded to a specific directory, lets assume in this case a directory is created for each user in the system. You would then unzip the directory on the server and scan the user's folder for any directories containing .jpg or .png or .gif files (etc.) and then import them into a table accordingly. I'm guessing labeled by folder name. What kind of server side troubles could I run into? I'm aware that there may be many issues. Even general ideas would be could so I can then research further. Thanks! Also, I would be programming in Ruby on Rails but I think this question applies accross any language.

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  • Adding an encapsulated email (like a forwarded email) from Zend Mail.

    - by Kieran
    I'm trying to get Zend_Mail to send an encapsulated message - as though it's forwarding an email. $attachedContent = "<h1>H1 Email</h1>"; $emailContent = "<h1>Email Content>"; $mail = new Zend_Mail(); $mail->setBodyText('text content'); $mail->setBodyHtml($emailContent); $mail->setFrom('[email protected]', 'GAS'); $mail->addTo('[email protected]', 'GAS'); $at = $mail->createAttachment($attachedContent); $at->type = 'message/rfc822; name="forwarded message"'; $at->disposition = Zend_Mime::DISPOSITION_INLINE; $at->encoding = Zend_Mime::ENCODING_7BIT; $mail->setSubject('Test'); $mail->send(); Mail clients are getting the email, rendering the normal HTML content, and displaying the forwarded message and rendering its contents, however, it's formatting like: <h1>Email Content</h1> Can you see what I'm doing wrong? I've not found anything online, and have tried my best to copy the formatting from looking at email source. Cheers, Kieran

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  • How to get elements from a page using Simple HTML DOM Parser

    - by sm56d
    Hi I am trying to parse a HTML page using the Simple HTML DOM Parser. This HTML page doesn't make use of IDs which makes it harder to refer to elements. On this page I am trying to get the Album name, Song title, download link and the album image. I have done this but I can't even get the Album names! $html = file_get_html('http://music.banadir24.com/singer/aasha_abdoo/247.html'); $article = $html->find('table td[class=title]', 0); foreach($article as $link){ echo $link; } This outputs: 1tdArrayArrayArray Artist Array I need to get this sort of output: Image Path Duniya Jamiila [URL] Macaan Badnoo [URL] Donimaayee [URL] ... Thanks all for any help Please note: This is legal as the songs are not bound by copyright and they are available to download freely, its just I need to download a lot of them and I can't sit there clicking a button all day. Having said that, its taken me an hour to get this far.

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  • how to obtain a stack trace when WAMP server crashes ?

    - by mithunmo
    Hello, Some times my WAMP server crashes . I get the following error. HTTP has encountered exception and needs to close. Unreferenced Memory. szAppName : httpd.exe szAppVer : 2.2.11.0 szModName : php5ts.dll szModVer : 5.3.0.0 offset : 0000c309 C:\DOCUME~1\blrcom\LOCALS~1\Temp\WERc677.dir00\httpd.exe.mdmp C:\DOCUME~1\blrcom\LOCALS~1\Temp\WERc677.dir00\appcompat.txt My question is how to obtain stack trace to debug this problem ? Should I use a windows debugger windows debugger or is there some setting in WAMP server configuration should i enable ?

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  • Trying to debug a symfony app showing the list of all the functions called, debug_backtrace() doesn'

    - by user248959
    Hi, im trying to debug a symfony app. I've added a debug_backtrace() calling to this function below. It outputs a list of functions called, but the save() function (that is just before the debug_backtrace() calling) is not that list.. why? any other way to debug that shows more things, in this case the save() calling ? protected function processForm(sfWebRequest $request, sfForm $form) { $form->bind($request->getParameter($form->getName())); if ($form->isValid()) { $sf_guard_user = $form->save(); var_dump(debug_backtrace()); die("fsdgsgsdf"); $this->redirect('guardausuario/edit?id='.$sf_guard_user- >getId()); } } Regards Javi

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  • Blogging Infrastructure using Zend Framework?

    - by Steve Griff
    Hi there folks, I'm researching the prospect of incorporating a blog into my site. Currently, my site is written using the Zend Framework so it's not just a case of using Wordpress and that be the end of it. I was wondering. Has someone already done what I'm thinking of doing and written a blog infrastructure with comments and so forth using ZF? Anyone got any suggestions? Thanks Steve

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  • Kohana Auth Module without ORM

    - by Asif
    Hi, I am using Kohana 3.0.3. I have been searching Auth module without ORM support,for couple of days. But didn't get any useful information. Could you please suggest and/or tutorial something here?

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  • Alternative to array_shift function

    - by SoLoGHoST
    Ok, I need keys to be preserved within this array and I just want to shift the 1st element from this array. Actually I know that the first key of this array will always be 1 when I do this: // Sort it by 1st group and 1st layout. ksort($disabled_sections); foreach($disabled_sections as &$grouplayout) ksort($grouplayout); Basically I'd rather not have to ksort it in order to grab this array where the key = 1. And, honestly, I'm not a big fan of array_shift, it just takes to long IMO. Is there another way. Perhaps a way to extract the entire array where $disabled_sections[1] is found without having to do a foreach and sorting it, and array_shift. I just wanna add $disabled[1] to a different array and remove it from this array altogether. While keeping both arrays keys structured the way they are. Technically, it would even be fine to do this: $array = array(); $array = $disabled_sections[1]; But it needs to remove it from $disabled_sections. Can I use something like this approach... $array = array(); $array = $disabled_sections[1]; $disabled_sections -= $disabled_sections[1]; Is something like the above even possible?? Thanks.

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  • CodeIgniter global variable

    - by Shishant
    Hello, I am using $data in all my views $this->load->view('my_view', $data); I have also autoload a Controller following this guide Extending Core Controller But I want to make $data global because in views there is a sidebar which is constant for whole project and displays info fetched through db in autoloaded controller Currently I have to manually write $data['todo'] for each and fetch info from autoloaded model. Thank You.

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  • problems with infinite loop

    - by Tom
    function addAds($n) { for ($i=0;$i<=$n;$i++) { while($row=mysql_fetch_array(mysql_query("SELECT * FROM users"))) { $aut[]=$row['name']; } $author=$aut[rand(0,mysql_num_rows(mysql_query("SELECT * FROM users")))]; $name="pavadinimas".rand(0,3600); $rnd=rand(0,1); if($rnd==0) { $type="siulo"; } else { $type="iesko"; } $text="tekstas".md5("tekstas".rand(0,8000)); $time=time()-rand(3600,86400); $catid=rand(1,9); switch ($catid) { case 1: $subid=rand(1,8); break; case 2: $subid=rand(9,16); break; case 3: $subid=rand(17,24); break; case 4: $subid=rand(25,32); break; case 5: $subid=rand(33,41); break; case 6: $subid=rand(42,49); break; case 7: $subid=rand(50,56); break; case 8: $subid=rand(57,64); break; case 9: $subid=rand(65,70); break; } mysql_query("INSERT INTO advert(author,name,type,text,time,catid,subid) VALUES('$author','$name','$type','$text','$time','$catid','$subid')") or die(mysql_error()); } echo "$n adverts successfully added."; } The problem with this function, is that it never loads. As I noticed, my while loop causes it. If i comment it, everything is ok. It has to get random user from my db and set it to variable $author.

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  • Function within echo problem

    - by user74283
    Hi, I have a slight problem with the echo statement outputting wrongly. Forexample when i do echo "<div id=\"twitarea\">" . fetchtwitter($rss) . "</div>"; it displays function output but OUTSIDE of twitarea div. What is the cause of this behavior perhaps syntax? thanks in advance

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  • Extending DOMDocument and DOMNode: problem with return object

    - by Glauber Rocha
    I'm trying to extend the DOMDocument class so as to make XPath selections easier. I wrote this piece of code: class myDOMDocument extends DOMDocument { function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } These methods return a DOMNodeList and a DOMNode object, respectively. What I'd like to do now is to implement similar methods to the DOMNode objects. But obviously if I write a class (myDOMNode) that extends DOMNode, I won't be able to use these two extra methods on the nodes returned by myDOMDocument because they're DOMNode (and not myDOMNode) objects. I'm rather a beginner in object programming, I've tried various ideas but they all lead to a dead-end. Any hints? Thanks a lot in advance.

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  • PDO and SQL IN statements

    - by Sai
    Im using a sequel for search like this using PDOs $states = "'SC','SD'"; $sql = "select * from mytable where states in (:states)"; $params = array(':states'=>$states); and I use my function $result = $this->selectArrayAssoc($sql, $params); where my selectArrayAssoc function as following public function selectArrayAssoc($sql, $params = array()){ try{ $sth = $this->db->prepare($sql); $sth->execute($params); $result = $sth->setFetchMode(PDO::FETCH_ASSOC); return $sth->fetchAll(); }catch(PDOException $e){ print $e->getMessage(); //Log this to a file later when in production exit; } } it does not take the quoted variables, I think it is suppressing, in such cases how to deal with this.

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • Duplicate entries on mysql on insert using doctrine

    - by Nikos Galis
    Hi all! I am facing a very weird problem with mysql and doctrine [with help of codeIgniter]. I am trying to make a simple migration script taking all records from one table and after a little process, saving them to another. However, on my laptop [running windows and wamp] I get double numbers of the original table records to have been copied to the destination table. In my colleagues' laptops, everything works fine! We are all using mysql 5.0.86 [plus windows plus wamp]. Here is the code : function buggy_function(){ $this->db(); //get db connection $q = Doctrine_Query::create()->from('Oldtable r'); $oldrecords = $q->fetchArray(); $count = 0; foreach ($oldrecords as $oldrecord){ $newrecord = new NewTableClass(); $newrecord->password = md5($oldrecord['password']); $newrecord->save(); echo $newrecord->id. ' Id -> saved.' } } Simple as that! I have 39 records on the Old table and I am getting 78 records in the new table, which are exactly the same records, except from the unique primary key. It seems as if the script runs twice. But the output of the script is the following : 1 Id -> saved. 2 Id -> saved. ... ... 39 Id -> saved. Do you have any idea why this is happening? Any known bug for mysql? Thank you in advanced!'

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  • Adding a third table to a Join

    - by John
    Hello, This query works fine: $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10"; Would this work if I wanted to join a third MySQL table (called "comment") to it? $sqlStr = "SELECT s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username, count(c.comment) countComments FROM submission AS s, login AS l, comment AS c, WHERE s.loginid = l.loginid AND s.submissionid = c.submissionid ORDER BY s.datesubmitted DESC LIMIT 10"; Thanks in advance, John

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  • Creating nodes porgramatically in Drupal 6

    - by John
    Hey, I have been searching for how to create nodes in Drupal 6. I found some entries here on stackoverflow, but the questions seemed to either be for older versions or the solutions did not work for me. Ok, so here is my current process for trying to create $node = new stdClass(); $node->title = "test title"; $node->body = "test body"; $node->type= "story"; $node->created = time(); $node->changed = $node->created; $node->status = 1; $node->promote = 1; $node->sticky = 0; $node->format = 1; $node->uid = 1; node_save( $node ); When I execute this code, the node is created, but when I got the administration page, it throws the following errors: warning: Invalid argument supplied for foreach() in C:\wamp\www\steelylib\includes\menu.inc on line 258. warning: Invalid argument supplied for foreach() in C:\wamp\www\steelylib\includes\menu.inc on line 258. user warning: Duplicate entry '36' for key 1 query: INSERT INTO node_comment_statistics (nid, last_comment_timestamp, last_comment_name, last_comment_uid, comment_count) VALUES (36, 1269980590, NULL, 1, 0) in C:\wamp\www\steelylib\sites\all\modules\nodecomment\nodecomment.module on line 409. warning: Invalid argument supplied for foreach() in C:\wamp\www\steelylib\includes\menu.inc on line 258. warning: Invalid argument supplied for foreach() in C:\wamp\www\steelylib\includes\menu.inc on line 258. I've looked at different tutorials, and all seem to follow the same process. I'm not sure what I am doing wrong. I am using Drupal 6.15. When I roll back the database (to right before I made the changes) the errors are gone. Any help is appreciated!

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  • Nested While Loop for mysql_fetch_array not working as I expected

    - by Ayush Saraf
    I m trying to make feed system for my website, in which i have got i data from the database using mysql_fetch_array system and created a while loop for mysql_fetch_array and inside tht loop i have repeated the same thing again another while loop, but the problem is that the nested while loop only execute once and dont repeat the rows.... here is the code i have used some function and OOP but u will get wht is the point! i thought of an alternative but not yet tried vaz i wanna the way out this way only i.e. using a for loopo insted of while loop that mite wrk... public function get_feeds_from_my_friends(){ global $Friends; global $User; $friend_list = $Friends->create_friend_list_ids(); $sql = "SELECT feeds.id, feeds.user_id, feeds.post, feeds.date FROM feeds WHERE feeds.user_id IN (". $friend_list. ") ORDER BY feeds.id DESC"; $result = mysql_query($sql); while ($rows = mysql_fetch_array($result)) { $id = $rows['user_id']; $dp = $User->user_detail_by_id($id, "dp"); $user_name = $User->full_name_by_id($id); $post_id = $rows['id']; $final_result = "<div class=\"sharedItem\">"; $final_result .= "<div class=\"item\">"; $final_result .= "<div class=\"imageHolder\"><img src=\"". $dp ."\" class=\"profilePicture\" /></div>"; $final_result .= "<div class=\"txtHolder\">"; $final_result .= "<div class=\"username\"> " . $user_name . "</div>"; $final_result .= "<div class=\"userfeed\"> " . $rows['post'] . "</div>"; $final_result .= "<div class=\"details\">" . $rows['date'] . "</div>"; $final_result .= "</div></div>"; $final_result .= $this->get_comments_for_feed($post_id); $final_result .= "</div>"; echo $final_result; } } public function get_comments_for_feed($feed_id){ global $User; $sql = "SELECT feeds.comments FROM feeds WHERE feeds.id = " . $feed_id . " LIMIT 1"; $result = mysql_query($sql); $result = mysql_fetch_array($result); $result = $result['comments']; $comment_list = get_array_string_from_feild($result); $sql = "SELECT comment_feed.user_id, comment_feed.comment, comment_feed.date FROM comment_feed "; $sql .= "WHERE comment_feed.id IN(" . $comment_list . ") ORDER BY comment_feed.date DESC"; $result = mysql_query($sql); if(empty($result)){ return "";} else { while ($rows = mysql_fetch_array($result)) { $id = $rows['user_id']; $dp = $User->user_detail_by_id($id, "dp"); $user_name = $User->full_name_by_id($id); return "<div class=\"comments\"><div class=\"imageHolder\"><img src=\"". $dp ."\" class=\"profilePicture\" /></div> <div class=\"txtHolder\"> <div class=\"username\"> " . $user_name . "</div> <div class=\"userfeed\"> " . $rows['comment'] . "</div> <div class=\"details\">" . $rows['date'] . "</div> </div></div>"; } } }

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  • Lightweight PHP5 based template class/system

    - by Wizzard
    Hi there. Looking at using a template system for a new project, it's only a small site and don't want to use the overhead and 'complexity' of smarty. I don't really like template systems that force you to make use of another language just to make it easier for designers (apparently). Something like this http://www.namepros.com/code/517342-php5-template-class.html is what Im looking at but something which is a bit more robust and proven.

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  • class composition instead of object composition?

    - by fayer
    I want a class property to be reference to another class, not its object and then use this property to call the class's static methods. class Database { private static $log; public static function addLog($LogClass) { self::$log = $LogClass; } public static function log() { self::$log::write(); // seems not possible to write it like this } } any suggestions how i can accomplish this? cause i have no reason making them objects, i want to use the classes for it.

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