Multi-select menu in bash script
- by am2605
I'm a bash newbie but I would like to create a script in which I'd like to allow the user to select multiple options from a list of options.
Essentially what I would like is something similar to the example below:
#!/bin/bash
OPTIONS="Hello Quit"
select opt in $OPTIONS; do
if [ "$opt" = "Quit" ]; then
echo done
exit
elif [ "$opt" = "Hello" ]; then
echo Hello World
else
clear
echo bad option
fi
done
(sourced from http://www.faqs.org/docs/Linux-HOWTO/Bash-Prog-Intro-HOWTO.html#ss9.1)
However my script would have more options, and I'd like to allow multiples to be selected. So somethig like this:
1) Option 1
2) Option 2
3) Option 3
4) Option 4
5) Done
Having feedback on the ones they have selected would also be great, eg plus signs next to ones they ahve already selected. Eg if you select "1" I'd like to page to clear and reprint:
1) Option 1 +
2) Option 2
3) Option 3
4) Option 4
5) Done
Then if you select "3":
1) Option 1 +
2) Option 2
3) Option 3 +
4) Option 4
5) Done
Also, if they again selected (1) I'd like it to "deselect" the option:
1) Option 1
2) Option 2
3) Option 3 +
4) Option 4
5) Done
And finally when Done is pressed I'd like a list of the ones that were selected to be displayed before the program exits, eg if the current state is:
1) Option 1
2) Option 2 +
3) Option 3 +
4) Option 4 +
5) Done
Pressing 5 should print:
Option 2, Option 3, Option 4
and the script terminate.
So my question - is this possible in bash, and if so is anyone able to provide a code sample?
Any advice would be much appreciated.
