fill an array with Int like a Char; C++, cin object
- by Duknov007
This is a pretty simple question; first time poster and long time looker.
Here is my binary to decimal converter I wrote:
#include <iostream>
#include <cmath>
using namespace std;
const int MAX = 6;
int conv(int z[MAX], int l[6], int MAX);
int main()
{
int zelda[MAX];
const int d = 6;
int link[d];
cout << "Enter a binary number: \n";
int i = 0;
while (i < MAX && (cin >> zelda[i]).get()) //input loop
{
++i;
}
cout << conv(zelda, link, MAX);
cin.get();
return 0;
}
int conv(int zelda[MAX], int link[6], int MAX)
{
int sum = 0;
for (int t = 0; t < MAX; t++)
{
long int h, i;
for (int h = 5, i = 0; h >= 0; --h, ++i)
if (zelda[t] == 1)
link[h] = pow(2.0, i);
else
link[h] = 0;
sum += link[t];
}
return sum;
}
With the way the input loop is being handled, I have to press enter after each input of a number. I haven't added any error correction yet either (and some of my variables are vague), but would like to enter a binary say 111111 instead of 1 enter, 1 enter, 1 enter, etc to fill the array. I am open to any technique and other suggestions. Maybe input it as a string and convert it to an int?
I will keep researching. Thanks.
