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  • why save_model method doesn't work in admin.StackedInline?

    - by FurtiveFelon
    Hi all, I have a similar problem as a previously solved problem of mine, except this time solution doesn't seem to work: http://stackoverflow.com/questions/2991365/how-to-auto-insert-the-current-user-when-creating-an-object-in-django-admin Previously i used to override the save_model to stamp the user submitting the article. Now i need to do the same for comments, it doesn't seem to work anymore. Anyone have any ideas? Thanks a lot! Jason

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  • django admin site - filtering available objects for user

    - by JPG
    I have models that belong to some 'group' (Company class). I want to add users, who will also belong to a one group and should be able to edit/manage/add objects with membership in associated group. something like: class Company() class Something() company = ForeignKey(Company) user Microsoft_admin company = ForeignKey(Company) and this user should only see and edit objects belonging to associated Company in the Admin Interface. How to acomplish that?

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  • Django admin, filter objects by ManyToMany reference

    - by Nick Z
    Hello! There's photologue application, simple photo gallery for django, implementing Photo and Gallery objects. Gallery object has ManyToMany field, which references Photo objects. I need to be able to get list of all Photos for a given Gallery. Is it possible to add Gallery filter to Photo's admin page? If it's possible, how to do it best?

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  • Django admin default filter

    - by h3
    I know I already managed to do this but can't remember how nor I can't find any documentation about this.. How can apply a filter by default on a object list view in the admin ? I have an app which list quotes and those quotes have a status (ex: accepted, rejected, on hold ..). I want the filter set on status='accepted' by default that is..

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  • Setting custom SQL in django admin

    - by eugene y
    I'm trying to set up a proxy model in django admin. It will represent a subset of the original model. The code from models.py: class MyManager(models.Manager): def get_query_set(self): return super(MyManager, self).get_query_set().filter(some_column='value') class MyModel(OrigModel): objects = MyManager() class Meta: proxy = True Now instead of filter() I need to use a complex SELECT statement with JOINS. What's the proper way to inject it wholly to the custom manager?

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  • Django Custom Admin

    - by Harry
    Hello there Currently I have an app with a save method in its models.py . So I would like to change this so the models does not do the save() method, but rather have a separate view that will do this in die admin site. Can you please direct me in the correct direction? Thank you

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  • Server Admin is not allowing me to configure DNS

    - by Clinton Blackmore
    We have a Mac OS X 10.5.8 Server running DNS (and a few other services). When I connect to it (using Server Admin 10.5.3 [which comes from the Server Admin 10.5.7 tools]), and click to look at the DNS settings, all appears normal -- it shows many reverse entries and two top-level domains. However, when I select one of our domains and open the disclosure triangle, the list is empty! [There should be over a dozen entries, and the reverse entries do show up.] If I then tell it I want to add, say, an A Record to the domain, almost everything disappears -- and I am left with a list showing our two domains, one with a disclosure triangle underneath it showing a single entry, and one reverse entry to correspond to the new A record. named appears to be working fine. DNS names resolve. It appears to simply be that Server Admin is having problems with the data on the computer. No one here would have manually created a DNS entry. Now, while I think I've backed up the DNS (I backed up /var/named/, /etc/named.conf, and /etc/dns/, as mentioned here), I'm really not sure if just replacing the files would restore the DNS settings we have if things go south. I am contemplating going to settings and changing the log level from "Information" to "Debug", but 1) I am just a little concerned that it might write a bad configuration to the disk, and 2) I think it would only affect named and not Server Admin, and, so far as I can tell, named is not having a problem. (Nothing looks strange in /Library/Logs/named.log when I open it via Console/Terminal. Oddly, though, when I click on the 'log' button for DNS in Server Admin, I see no text at all, just a fully white window. When I look at one of our secondary DNS servers, I am able to see the log file through Server Admin.) This entry appears in the system log when I run Server Admin on the server: Jun 17 09:02:08 od1 Server Admin[3892]: Unexpected call to doMarkConfigurationAsDirty by 'DNS' plugin during updateConfigurationViewFromDescription It seems to occur after I've looked at DNS, look at another service, and then click back on DNS. Think that the most likely cause is a corrupt configuration file, I glanced through all the files that I backed up, and none of them is obviously gobbledygook. Here are some oddities I find when running Server Admin from a remote computer to manage the DNS. When I click to see the log file for DNS, the server starts writing messages like these to its system.log: Jun 17 09:59:04 od1 kernel[0]: Limiting open port RST response from 252 to 250 packets per second Jun 17 09:59:06 od1 kernel[0]: Limiting open port RST response from 258 to 250 packets per second This stops when I click on a different service. The inderterminate progress indicator (the spinning wheel that appears beside the "Revert" and "Save" buttons in the bottom-right corner of Server Admin) looks really strange. As far as I can tell, instead of just spinning and waiting, it is being told to start spinning repeatedly, resulting in a jerky animation. Here are some of the messages being logged on the computer running Server Admin: At startup: *** ERROR: -[GRAxes computeLayout]:1124 - plotRect height = 0.000000 <= 0.0 *** *** ERROR: -[GRChartView computeLayout]:1194 - Layout for overlay axes (0x18758f50) failed. *** (These messages don't concern me too much as they go away for a while if you delete ~/Library/Preferences/com.apple.ServerAdmin.plist). At shutdown: 2010-06-17 10:02:17.202 Server Admin[7770:10b] *** -[GroupTextField windowDidResignKey:]: unrecognized selector sent to instance 0x16e12490 More concerning are these messages: 2010-06-17 09:59:47.269 Server Admin[7770:10b] Unexpected call to doMarkConfigurationAsDirty by 'DNS' plugin during updateConfigurationViewFromDescription Server Admin(7770,0xb0453000) malloc: *** error for object 0x1c115390: double free *** set a breakpoint in malloc_error_break to debug 2010-06-17 10:01:00.795 Server Admin[7770:10b] *** -[ServiceEntry sessionHost]: unrecognized selector sent to instance 0x2af500 Any thoughts on: what the problem is how I can troubleshoot it or how to fix it? If I do need to wipe out DNS and restart, is there a good way to do this?

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  • Rights and use of developed software

    - by Nils Munch
    I have been working on a piece of software for a company, that they wish to resell. There was an mail-based agreement upon a flat hourly rate for my work, and eager me chose to accept a rather low fee. Due to the stress and tempo of the task, a direct contract was never formed or signed. The software was developed locally on my machine, and I was pretty much alone with it, except by excellent help from StackOverflow when I got stuck. Now, the software is nearing completion, I suddenly hear that they have hired a new developer to make the same piece of software as me, and that I was expected to resign within long. Confused I ask around, and realize that the CEO of the company had informed the rest of the company that I was terminally ill and had cancer, and was expected to leave the company soon. Since I'm perfectly healthy, this confused me even more, until I realized what was going on. When I confronted my boss with this, I was no longer seen as a member of the company, and I left the same day, never to return. Later, I raised the question about my missing pay, since I had been working for quite a bit, and not received any payment for my software. I saw that they had already sold a fair copy of my software, and since it's not exactly sold cheap, the company should have plenty of gold to pay me. The company refused, and said that they owned the software, and everything it contained. That was a lot of drama, but my question is this: Who has the rights to the software ? The source code had my personal watermarks and copyrights inprinted, but they have since simply deleted it. The company claim that they have all the rights, because they have a website made about the product, where they write that they have "All rights reserved" in the bottom. My instinct tells me that if a company buys a service like this, and then refuses to pay their developer, then they should not be allowed to keep, and much less resell the product. I have not signed any agreements about giving the company the use of this product, I have made it in my own time and without help from the rest of the company. This all takes place in Denmark, Europe, but I would guess that the rules about this is somewhat universal. Im not the strongest person to legal-talk, so I might be wrong.

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  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

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  • django-admin: creating,saving and relating a m2m model

    - by pastylegs
    I have two models: class Production(models.Model): gallery = models.ManyToManyField(Gallery) class Gallery(models.Model): name = models.CharField() I have the m2m relationship in my productions admin, but I want that functionality that when I create a new Production, a default gallery is created and the relationship is registered between the two. So far I can create the default gallery by overwriting the productions save: def save(self, force_insert=False, force_update=False): if not ( Gallery.objects.filter(name__exact="foo").exists() ): g = Gallery(name="foo") g.save() self.gallery.add(g) This creates and saves the model instance (if it doesn't already exist), but I don't know how to register the relationship between the two?

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  • Assigning a group while adding user in django-admin

    - by Lokharkey
    In my application, I have models that have the Users model as a Foreign key, eg: class Doctor(models.Model): username=models.ForeignKey(User, unique=True) ... In the admin site, when adding a new Doctor, I have the option of adding a new User next to the username field. This is exactly what I want, but in the dialog that opens, it asks for a username and password for the new user; I would also like to be able to assign a group to this new user. What would be the best way of doing this ? Thanks, lokharkey

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  • CodeIgniter & Datamapper as frontend, Django Admin as backend, database tables inconsistent

    - by Rasiel
    I created a database for a site i'm doing using Django as the admin backend. However because the server where the site is hosted on, won't be able to support Python, I find myself needing to do the front end in PHP and as such i've decided to use CodeIgniter along with Datamapper to map the models/relationship. However DataMapper requires the tables to be in a specific format for it to work, and Django maps its tables differently, using the App name as the prefix in the table. I've tried using the prefix & join_prefix vars in datamapper but still doesn't map them correctly. Has anyone used a combination of this? and if so how have the fixed the issue of db table names being inconsistent? Is there anything out there that i can use to make them work together?

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  • Modify on-the-fly verbose_name in a model field on django admin

    - by PerroVerd
    Hi I have this sample model working with the admin class Author(models.Model): name = models.CharField(_('Text in here'), max_length=100) with verbose_name set as ugettext_lazy 'Text in here', but sometimes, depending on the site_id i want to present a diferent verbose name, so I modified the init in this way def __init__(self, *args, **kwargs): super(Author, self).__init__(*args, **kwargs) #some logic in here self._meta.get_field('name').verbose_name = _('Other text') It works, displaying the 'Other text' instead the 'Text in here'... except for the very first time the author/add view is used. ¿Is it the right way to do it? ¿How can i fix the first time problem? Thanks in advance

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  • How to perform bulk update using rails admin

    - by Shubham Kedia
    ![enter image description here][2] I just have to perform a Bulk update for my products using the action which i have defined. While inspecting the link, it displays the following: onclick="jQuery('#bulk_action').val('bulk_add_to_categories'); jQuery('#bulk_form').submit(); return false;" But when I click on it I get this error. I need to do something like this I need to have an separate UI for all the products that have came from that bulk action, and then put them into the selected categories, but I am not able to do that. Can anyone help me on this? Any help would be great. I have seen lot of tutorial and read the rails admin github page but I was not able to find anything helpful. Please guide me.

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  • Retrieving related data in the Symfony Admin Generator

    - by bjoern
    I have a problem with the Admin Generator. The Table of Pages have the column sf_guard_user_id. The rest of the table looks as this part of the generator.yml in the line display, list: title: Pages display: [=title, sfGuardUser, views, state, privacy, created_at, updated_at] sort: [created_at, desc] fields: sfGuardUser: { label: Author } created_at: { label: Published, date_format: dd.MM.y } updated_at: { label: Updated, date_format: dd.MM.y } table_method: retrieveUserList Now the sf_guard_user_id is been replaced and the username ist displayed. Don't get me wrong, that works fine. But how can I get other variables from the sfGuarsUser relation? When I only add salt or another variable to display I get this, Unknown record property / related component "salt" on "simplePage" But why?

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  • Admin section in CakePHP

    - by Nicklas Ansman
    I'm having a hard time understanding how the CakePHP admin system works. Should all controllers who has an action which requires login include AuthComponent or just the one who handles the login/logout? Let's say I want to protect the add action of a controller. First I create admin_add() in the controller and then in the beforeFilter() method I check if $this->Session->check('Auth.User') is set a redirect based on this? Turns out it was better to just controll this with $this->Auth->allow() What is the easiest way to return to the URL the user was trying to access? Is there a better way than setting a session variable? Turns out it does this automagically :) If someone has a good tutorial for this I would happily read it :) I've already read this tutorial but I found it to be a little to basic and the CakePHP-docs are not that great on this topic either.

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  • How to limit choice field options based on another choice field in django admin

    - by umnik700
    I have the following models: class Category(models.Model): name = models.CharField(max_length=40) class Item(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) class Demo(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) item = models.ForeignKey(Item) In the admin interface when creating a new Demo, after user picks category from the dropdown, I would like to limit the number of choices in the "items" drop-down. If user selects another category then the item choices should update accordingly. I would like to limit item choices right on the client, before it even hits the form validation on the server. This is for usability, because the list of items could be 1000+ being able to narrow it down by category would help to make it more manageable. Is there a "django-way" of doing it or is custom JavaScript the only option here?

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  • Django admin output extra HTML in ModelSite

    - by VoteyDisciple
    Ultimately, I want to add an <iframe> to the display of a particular model on Django's admin page. Django is already rendering the form for this model correctly, but I want to add this <iframe> in addition to Django's form. The src attribute needs to involve the primary key for the currently-displayed record. I've learned how to properly override the change_form.html template through Django's documentation, and I can add markup to the right block, but I can't figure out how to access the primary key value. (No amount of determined Googling has helped at all.) Alternatively, is there a direct way to specify that I want to produce extra output in my ModelSite definition?

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  • Ajax foreign key filter in Django admin interface

    - by Googol
    http://blog.philippmetzler.com/?p=52 Just tried django-ajax-filtered-fields and like it very much. I’m looking for a solution for this problem: My model looks like this: class Song(models.Model): Album = models.ForeignKey(Album) class Artist(models.Model): album = models.ForeignKey(Album) song = models.ForeignKey(Song, blank=True, null=True) So the user has to define a topic. He can also define a subtopic but doesn’t have to. The subtopic belongs to a topic. In the admin interface I’d like to limit the choices for subtopic based upon what he selects in topics. That should change dynamically with AJAX. I will have a closer look to django-ajax-filtered-fields but didn’t find a solution to that specific problem. Perhaps it’s another usecase for django-ajax-filtered-fields in general? Or do you know another solution to my specific requirements?

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  • Customising Symfony Admin Generator Form

    - by Rich
    Hi, I've generated the backend of my application, and am now just 'jazzing' the forms up (adding correct labels, validation rules etc). One thing I'd like to do is add a map (Google) which updates the marker as an address is entered into the form, then allows the user to drag it to correct the lat/lng should it be a little off. My question is, how can I customise the output of the form - I've read the docs (1.0,1.1,1.2 also) and it all seems very confusing. Customising forms not generated with the admin generator I know how to do using renderRow(); etc; but finding a way to add a little bit of HTML to the forms is making my eyes hurt! There's so much out of date stuff on the web regarding Symfony it's hard to know what to trust! If anyone can point me in the right direction that'd be great. Best Regards, Rich

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  • Django admin page dropdowns

    - by zen
    I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

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  • Django admin return to page after save

    - by Thordin9
    Hi all, I have 3 pages of items listed in my django application admin. After i edit one of them (lets say it is in page 2) and save my changes, i return to page 1 of my listing. How can i make it so i return to the page the item is in? I looked into some similar questions here at stackoverflow and i believe that i need to use javascript to send a httpresponse with the location header. But how i can determine the page the item is in? any help is appreciated

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