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  • Explanation of this SQL sanitization code

    - by Derek
    I got this from for a login form tutorial: function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } Could some one explain exactly what this does? I know that the 'clean' var is called up afterwards to sanitize the fields; I.e. $email = clean($_POST['email']);

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  • Why ClassCastException on JMS ConnectionFactory lookup in JNDI?

    - by Derek Mahar
    What might be the cause of the following ClassCastException in a standalone JMS client application when it attempts to retrieve a connection factory from the JNDI provider? Exception in thread "main" java.lang.ClassCastException: javax.naming.Reference cannot be cast to javax.jms.ConnectionFactory Here is an abbreviated version of the JMS client that includes only its start() and stop() methods. The exception occurs on the first line in method start() which attempts to retrieve the connection factory from the JNDI provider, a remote LDAP server. The JMS connection factory and destination objects are on a remote JMS server. class JmsClient { private ConnectionFactory connectionFactory; private Connection connection; private Session session; private MessageConsumer consumer; private Topic topic; public void stop() throws JMSException { consumer.close(); session.close(); connection.close(); } public void start(Context context, String connectionFactoryName, String topicName) throws NamingException, JMSException { // ClassCastException occurs when retrieving connection factory. connectionFactory = (ConnectionFactory) context.lookup(connectionFactoryName); connection = connectionFactory.createConnection("username","password"); session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE); topic = (Topic) context.lookup(topicName); consumer = session.createConsumer(topic); connection.start(); } private static Context getInitialContext() throws NamingException, IOException { String filename = "context.properties"; Properties props = new Properties(); props.load(new FileInputStream(filename)); return new InitialContext(props); } }

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  • parse results in MySQL via REGEX

    - by Derek Adair
    Hi, I'm a bit confused on the functionality of the REGEX support for MySQL and I have yet to find a solid example on how to separate a result with REGEX within an sql statement. Example: How could I pull data from a table emails that looks something like... +-------------------------+ |Emails | |-------------------------| |[email protected]| +-------------------------+ and return something through an sql statement that looks like... +------------------------------+ |Username | Domain | TLD | |-----------|------------|-----| |some.email | yourdomain | com | +------------------------------+

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  • Programmatically change the width/height of ColorBox onClick.

    - by Derek Adair
    Hi, I'm using the jquery plugin ColorBox. I have a page with several item listings. Each listing has a ColorBox attached to it. $("a.modalButton").each(function(){ $(this).colorbox({ width:"933px", height:"720px", iframe:true, onComplete:function(){ //remove the text from the close button //wasn't sure how else to do that $('#cboxClose').html(''); } }); }); In each ColorBox window there is an "email me" button. When it is clicked I replace the html content that is in the window with a form to email the listing. I would like the window to resize to fit the form after this button is clicked

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  • Can't get Xdebug to work on Windows 7

    - by Derek
    I installed the latest XAMPP package which includes PHP 5.3.0. I am trying to enable Xdebug, but it just won't work. Here's what I changed in the php.ini shipped with XAMPP: ; uncommented zend_extension = "X:\xampp\php\ext\php_xdebug.dll" ; added the following lines: xdebug.remote_enable=true xdebug.remote_host=localhost xdebug.remote_port=9000 xdebug.remote_handler=dbgp Apache starts fine, but when I open http://localhost/ in my browser, I get the following error If I click the Close the program button, the error message will reappear in a second as if it was in an infinite loop. I'd greatly appreciate any help in getting this to work. I am running a fresh install of Windows 7 Ultimate 64-bit. EDIT: From the result of phpinfo(): Zend Extension Build API220090626,TS,VC6 PHP Extension Build API20090626,TS,VC6 Debug Build no Thread Safety enabled

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  • Is this sufficient to prevent query injection while using SQL Server?

    - by Derek Adair
    Hi, I have recently taken on a project in which I need to integrate with PHP/SQL Server. I am looking for the quickest and easiest function to prevent SQL injection on SQL Server as I prefer MySQL and do not anticipate many more SQL Server related projects. Is this function sufficient? $someVal = mssql_escape($_POST['someVal']); $query = "INSERT INTO tblName SET field = $someVal"; mssql_execute($query); function mssql_escape($str) { return str_replace("'", "''", $str); } If not, what additional steps should I take?

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  • Are there any differences between SQL Server and MySQL when it comes to preventing SQL injection?

    - by Derek Adair
    I am used to developing in PHP/MySQL and have no experience developing with SQL Server. I've skimmed over the PHP MSSQL documentation and it looks similar to MySQLi in some of the methods I read about. For example, with MySQL I utilize the function mysql_real_excape_string(). Is there a similar function with PHP/SQL Server? What steps do I need to take in order to protect against SQL injection with SQL Server? What are the differences between SQL Server and MySQL pertaining to SQL injection prevention? also - is this post accurate? is the escape string character for SQL Server a single quote?

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  • Can't get access to PHPmyAdmin after setting a root password and using Instant Rails

    - by Derek
    Wanted to get started with Ruby on Rails so I installed instant rails and set up a mysql password. Problem is now I can't get access to phpmyadmin. From the rails control panel, when I go to configure database (via PhpMyadmin) it opens up phpmyadmin with the message Error MySQL said: Documentation #1045 - Access denied for user 'root'@'localhost' (using password: NO) When I used to use XAMPP after setting a password instead of taking me directly within phpmyadmin (as it did without a password) it took me to the login screen instead. With instant rails that's not the case. Anyone had this problem when they first set a mysql password and using the instant rails package?

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  • is there a way using Ruby's net/http to post form data to an http proxy?

    - by Derek P.
    I have a basic Squid server setup and I am trying to use Ruby's Net::HTTP::Proxy class to send a POST of form data to a specified HTTP endpoint. I assumed I could do the following: Net::HTTP::Proxy(my_host, my_port).start(url.host) do |h| req = Net::HTTP::Post.new(url.path) req.form_data = { "xml" => xml } h.request(req) end But, alas, proxy vs. non-proxied Net::HTTP classes don't seem to use the proxy IP Address. my remote service responds telling me that it received a request from the wrong IP address, ie: not the proxy. I am looking for a specific way to write the procedure, so that I can successfully send a form post via a proxy. Help? :)

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  • MySQL INTO OUTFILE overide existing file?

    - by Derek Organ
    I've written a big sql script that creates a CSV file. I want to call a cronjob every night to create a fresh CSV file and have it available on the website. Say for example I'm store my file in '/home/sites/example.com/www/files/backup.csv' and my SQL is SELECT * INTO OUTFILE '/home/sites/example.com/www/files/backup.csv' FIELDS TERMINATED BY ',' OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY '\n' FROM ( .... MySQL gives me an error when the file already exists File '/home/sites/example.com/www/files/backup.csv' already exists Is there a way to make MySQL overwrite the file? I could have PHP detect if the file exists and delete it before creating it again but it would be more succinct if I can do it directly in MySQL.

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  • Alternative for PHPlivedocx?

    - by Derek
    Hello, Is there any other free alternatives to PHPliveDocx? I would like to create a Word document based on templates and user inputted data. The template will resides on the server and the client(online or c# windows application) will be used to collect user input. Once data has been collected, server-side script(PHP) will be used to generate a Word document. So far I have only found phplivedocx. However I'm not very comfortable at consuming web services from a server that I have no control over with (am I worrying too much?). I have also thought about using client to do the work (c# windows application, Open Office XML). But I'm not sure that's the right way of doing things. Any guidance/help will be really appreciated! Thanks!

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  • LINQ to SQL Web Application Best Practices

    - by derek
    In my experience building web applications, I've always used a n-tier approach. A DAL that gets data from the db and populates the objects, and BLL that gets objects from the DAL and performs any business logic required on them, and the website that gets it's display data from the BLL. I've recently started learning LINQ, and most of the examples show the queries occurring right from the Web Application code-behinds(it's possible that I've only seen overly simplified examples). In the n-tier architectures, this was always seen as a big no-no. I'm a bit unsure of how to architect a new Web Application. I've been using the Server Explorer and dbml designer in VS2008 to create the dbml and object relationships. It seems a little unclear to me if the dbml would be considered the DAL layer, if the website should call methods within a BLL, which then would do the LINQ queries, etc. What are some general architecture best practices, or approaches to creating a Web Application solution using LINQ to SQL?

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  • How can you replace a link's target in Greasemonkey?

    - by Derek
    I'm trying to write a script in Greasemonkey that will replace a link's target with something else, but with my limited Javascript knowledge I don't really know how to do this. Basically I'm trying to find all links containing a certain string of characters (ex: //a[contains(@href, 'xx')] ), and either replace them with another link, or append something to them (replacing 'abc123.com' with 'zyx987.com' or 'abc123.com' with 'abc123.com/folder'). If you could point me on the right path I'd greatly appreciate it.

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  • Where do you download a package with java.exe?

    - by Derek
    I was trying to run this java ee program with session beans which involves the 'ant' command apparently and when I try to run 'ant' it says... '"java.exe"' is not recognized as an internal or external command. Soooo I am thinking I need to get java.exe in order to use 'ant' properly. Where can I find it? What downloadable contains it?

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  • IDs necessary in update script not being stored (or even seen!?) (PHP MySQL)

    - by Derek
    Hi guys, I really need help with this one...have spent 3 hours trying to figure it out... Basically, I have 3 tables necessary for this function to work (the query and PHP)... Authors, Books and Users. An author can have many books, and a user can have many books - that's it. When the admin user selects to update a book, they are presented with a form, displaying the current data within the fields, very straight forward... However there is one tricky part, the admin user can change the author for a book (incase they make a mistake) and also change the user for which the book is associated with. When I select to update the single book information I am not getting any values what so ever for author_id or user_id. Meaning that when the user updates the book info, the associations with the user and author is being scrapped altogether (when before there was an association)... I cannot see why this is happening because I can clearly see the IDs for the users and authors for my option values (this is because they are in select dropdowns). Here is what my sql to retrieve the user ID is: SELECT user_id, name FROM users and then i have my select options which brings up all the users in the system: <label>This book belongs to:</label> <select name="name" id="name"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['name']?></option> <?php } ?> In the presented HTML form, I can select the users (by name) and within the source code I can see the IDs (for the value) matching against the names of the users. Finally, in my script that performs the update, I have this: $book_id = $_POST['book_id']; $bookname = $_POST['bookname']; $booklevel = $_POST['booklevel']; $author_id = $_POST['author_id']; $user_id = $_POST['user_id']; $sql = "UPDATE books SET bookname= '".$bookname."', booklevel= '".$booklevel."', author_id='".$author_id."', user_id= '".$user_id."' WHERE book_id = ".$book_id; The result of this query returns no value for either author_id or user_id... Obviously in this question I have given the information for the user stuff (with the HTML being displayed) but im guessing that I have the same problem with authors aswell... How can I get these ID's passed to the script so that the change can be acknowledge!! :(

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  • Ant error when trying to build file, can't find tools.jar ??

    - by Derek
    When I run ant it says: Unable to locate tools.jar. Expected to find it in C:\Program Files\Java\jre6\lib\tools.jar Buildfile: build.xml does not exist! Build failed What package can I use to download the file required C:\Program Files\Java\jre6\lib\tools.jar I just downloaded this one: jre-6u19-windows-i586-s.exe but unfortunately it appears that it was not on it...

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • Which programming languages support constant methods?

    - by Derek Mahar
    Which programming languages other than C++ support the concept of a constant class method? That is, what languages allow the programmer to constrain a method in such a way that it is guaranteed not to change the state of an object to which the method is applied? Please provide examples or references in your answer.

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  • cycle through four list elements, applying an "active" class.

    - by Derek Adair
    Hi, I would like to cycle through four li elements that all contain tags, setting the appropriate class to "active" and remove the "active" class. I'm having a bit of trouble figuring out how to achieve this via jQuery. HTML: <ul class="liveMenu"> <li id="leftScroll"></li> <li id="liveButton_1"><a class="buttons" href="#featured_1"></a></li> <li id="liveButton_2"><a class="buttons" href="#featured_2"></a></li> <li id="liveButton_3"><a class="buttons" href="#featured_3"></a></li> <li id="liveButton_4"><a class="buttons" href="#featured_4"></a></li> <li id="rightScroll"></li> </ul> jquery: var index = 0; $("#rightScroll").click(function(){ if(index != 3){ index++; } else { index = 0; } //this part is untested, it should work though $("a.active").removeClass("active"); //this is where I am getting hung up //I need something like... $.each("li.buttons", function(i){ if(i == index){ $(this).addClass("active"); } }); }); $("#leftScroll").click(function(){ if(index != 0){ index--; } else { index = 3; } $.each("li.items", function(i){ if(i == index){ $(this).addClass("active"); } }); }); any help would be greatly appreciated. Thankyou.

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  • Does Hibernate's GenericGenerator cause update and saveOrUpdate to always insert instead of update?

    - by Derek Mahar
    When using GenericGenerator to generate unique identifiers, do Hibernate session methods update() and saveOrUpdate() always insert instead of update table rows, even when the given object has an existing identifier (where the identifier is also the table primary key)? Is this the correct behaviour? public class User { private String id; private String name; public User(String id, String name) { this.id = id; this.name = name; } @GenericGenerator(name="generator", strategy="guid")@Id @GeneratedValue(generator="generator") @Column(name="USER_ID", unique=true, nullable=false) public String getId() { return this.id; } public void setId(String id) { this.id = id; } @Column(name="USER_NAME", nullable=false, length=20) public String getUserName() { return this.userName; } public void setUserName(String userName) { this.userName = userName; } } class UserDao extends AbstractDaoHibernate { public void updateUser(final User user) { HibernateTemplate ht = getHibernateTemplate(); ht.saveOrUpdate(user); } }

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  • TFS 2010 Build gives WorkItemStore error when Create Work Item on Failure is enabled

    - by Derek Morrison
    I'm using TFS 2010 Build. I have a build definition that uses the DefaultTemplate.xaml template that's stock in TFS 2010, and the Create Work Item on Failure property is set to True in the build definition. I deliberately made a change in my project that breaks the build. When the build runs, I see the compilation error reflected in the TFS Build log within Visual Studio, but I get the error "Value cannot be null. Parameter name: WorkItemStore" when TFS Build next tries to generate a Work Item for the broken build. I tracked down the activity in DefaultTemplate.xaml (see the rather lengthy path to it below) where the Work Item is created for a broken build, and I see it uses the Microsoft.TeamFoundation.Build.Workflow.Activities.OpenWorkItem class to create the Work Item. The appropriate values seemed to be filled out in the Properties window for the Create Work Item activity, so I don't see where I can pass WorkItemStore to it and I don't even know appropriate values for this setting. Path to the Create Work Item activity: Process Sequence Run On Agent Try Compile, Test, and Associate Changesets and Work Items Sequence Compile, Test, and Associate Changesets and Work Items Try Compile and Test Compile and Test For Each Configuration in BuildSettings.PlatformConfigurations Compile and Test for Configuration If BuildSettings.HasProjectsToBuild For Each Project in BuildSettings.ProjectsToBuild Try to Compile the Project Handle Exception If CreateWorkItem Create Work Item for non-Shelveset Builds Create Work Item

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